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Mathematics

Find the inclination of the line whose slope is :

(i) 0

(ii) 3\sqrt{3}

(iii) 0.7646

(iv) 1.0875

Straight Line Eq

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Answer

(i) 0

Let inclination be θ.

By formula,

⇒ m = tan θ

⇒ 0 = tan θ

⇒ tan θ = tan 0°

⇒ θ = 0°.

Hence, inclination of line = 0°.

(ii) 3\sqrt{3}

Let inclination be θ.

By formula,

⇒ m = tan θ

3\sqrt{3} = tan θ

⇒ tan θ = tan 60°

⇒ θ = 60°.

Hence, inclination of line = 60°.

(iii) 0.7646

Let inclination be θ.

By formula,

⇒ m = tan θ

⇒ 0.7646 = tan θ

⇒ tan θ = tan 37° 24'

⇒ θ = 37° 24'.

Hence, inclination of line = 37° 24'.

(iv) 1.0875

Let inclination be θ.

By formula,

⇒ m = tan θ

⇒ 1.0875 = tan θ

⇒ tan θ = tan 47° 24'

⇒ θ = 47° 24'.

Hence, inclination of line = 47° 24'.

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