Computer Applications
(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J kg-1 K-1.
(b) How much heat energy will be required to increase the temperature of the vessel in part (a) from 25°C to 35°C?
Answer
(a) Given,
mass (m) = 150 g = 0.15 kg
specific heat capacity (c) = 410 J kg-1 K-1
We know that,
Heat capacity (C') = Mass (m) × specific heat capacity (c)
Substituting the values in the formula above we get,
C' = 0.15 x 410 = 61.5 J K-1
Hence, heat capacity of a copper vessel = 61.5 J K-1
(b) Change in temperature = 35°C – 25°C = 10°C = 10 K
Energy required to increase the temperature of vessel Q = ?
From relation,
Q = m x c x △T
Substituting the values in the formula above we get,
Q = 0.15 x 410 x 10 = 615 J
Hence, heat energy required to increase the temperature of the vessel = 615 J
Related Questions
Calculate the total amount of heat energy required to convert 100 g of ice at -10° C completely into water at 100° C. Specific heat capacity of ice = 2.1 J g-1 K-1, specific heat capacity of water = 4.2 J g-1 K-1, specific latent heat of ice = 336 J g-1.
The amount of heat energy required to convert 1 kg of ice at -10° C completely to water at 100° C is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg-1 K-1, Specific heat capacity of water is 4200 J kg-1 K-1.
200 g of ice at 0° C converts into water at 0° C in 1 minute when heat is supplied to it at a constant rate. In how much time, 200 g of water at 0° C will change to 20° C? Take specific latent heat of ice = 336 J g-1.
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