Find the sum of all multiples of 7 lying between 300 and 700.

. The numbers which are divisible by 7 between 300 and 700 are, = 43 × 7, 44 × 7, 45 × 7, ............, 99 × 7. = 301, 308, 315, .........., 693. The above sequence is an A.P. with common difference = 7 and first term = 301 and last term = 693. Let n be no. of terms, ∴ a n = a + (n - 1)d ⇒ 693 = 301 + (n - 1)7 ⇒ 693 = 301 + 7n - 7 ⇒ 693 = 7n + 294 ⇒ 693 - 294 = 7n ⇒ 7n = 399 ⇒ n = 57. Hence, sum = 28329.

Can 2n² - 7 be the n^th term of an A.P. Explain.

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Find the sum of the A.P.; 14, 21, 28, ……., 168.

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The first term of an A.P. is 20 and the sum of its first seven terms is 2100; find the 31^st term of this A.P.

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Find the sum of last 8 terms of the A.P.
-12, -10, -8, …….., 58.

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Mathematics

Find the sum of all multiples of 7 lying between 300 and 700.

AP

Related Questions

Can 2n² - 7 be the n^th term of an A.P. Explain.

Find the sum of the A.P.; 14, 21, 28, ……., 168.

The first term of an A.P. is 20 and the sum of its first seven terms is 2100; find the 31^st term of this A.P.

Find the sum of last 8 terms of the A.P.
-12, -10, -8, …….., 58.

Mathematics

Find the sum of all multiples of 7 lying between 300 and 700.

AP

Related Questions

Can 2n2 - 7 be the nth term of an A.P. Explain.

Find the sum of the A.P.; 14, 21, 28, ……., 168.

The first term of an A.P. is 20 and the sum of its first seven terms is 2100; find the 31st term of this A.P.

Find the sum of last 8 terms of the A.P.-12, -10, -8, …….., 58.

Can 2n² - 7 be the n^th term of an A.P. Explain.

The first term of an A.P. is 20 and the sum of its first seven terms is 2100; find the 31^st term of this A.P.

Find the sum of last 8 terms of the A.P.
-12, -10, -8, …….., 58.