If log2y = x and log3z = x, find 72x in terms of y and z.
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Given,
log2y = x and log3z = x
⇒ y = 2x and z = 3x.
(72)x = (23.32)x
= (2)3x.(3)2x
= (2x)3.(3x)2
= (y)3.(z)2
Hence, (72)x = y3.z2.
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Simplify the following :
log a3 - log a2