Chemistry
In the activity series of metals — M is a metal above hydrogen in the activity series and it's oxide has the formula M2O. M2O when dissolved in water forms the corresponding hydroxide which is a good conductor of electricity. In the above context, answer the following :
(i) What kind of combination exists between M and O?
(ii) State the number of electrons in the outermost shell of M ?
(iii) Name the group to which M belongs.
Answer
Given, M is a metal
(i) Electrovalent bond exits between M and O because the bond is formed between a metal and non-metal due to oppositely charged ions.
(ii) Number of electrons in the outer most shell of M is 1. It is so because the valency of O is -2 and as 2 atoms of M combine with O to form M2O, hence we can say that M has 1 valence electron.
(iii) M belongs to group 1 [1A] because there is 1 electron in the outer most shell.
Related Questions
Give reasons for the following:
Atomic size of an element depends on the nuclear charge of that element.
Give reasons for the following:
Down a group electronegativity should increase with increase in nuclear charge but it is seen that the electronegativity decreases.
Give reasons for the following:
If combining atoms have nearly similar electronegativities the bond between them is covalent.
Arrange the following elements as per the guidelines in brackets.
- Na, Cl, Mg, P [in decreasing order of atomic size]
- C, Li, F, N [in increasing order of electronegativity]
- Cl, Al, Na, S [in increasing order of ionization potential]
- Li, F, C, O [in increasing order of electron affinity]
- Ar, He, Ne [in increasing order of number of electron shells]