Biology
Assertion (A): Herkogamous flowers favour cross-pollination as these flowers have a structural barrier between the male and female reproductive parts.
Reason (R): Pansy is an example of a herkogamous flower which has a hood covering the stigma.
- A is True and R is False.
- A is False and R is True.
- Both A and R are True.
- Both A and R are False.
Answer
Both A and R are True.
Reason — Herkogamy refers to the presence of a physical barrier between the anthers and stigma in a bisexual flower. This adaptation prevents self-pollination.
In Pansy, the stigma is covered by a hood-like structure, making it a good example of herkogamy.
Related Questions
Look at the table given below and identify the kind of pollination that usually occurs in the flower mentioned.
Flower Kind of pollination Hibiscus P Hydrilla Q Wheat R - P — Entomophily, Q — Hydrophily, R — Anemophily
- P — Hydrophily, Q — Elephophily, R — Anemophily
- P — Ornithophily, Q — Anemophily, R — Elephophily
- P — Ornithophily, Q — Hydrophily, R — Entomophily
Assertion (A): Autogamy and allogamy are the two kinds of self-pollination.
Reason (R): Self-pollination occurs within the same flower or two flowers of the same plant.
- A is True and R is False.
- A is False and R is True.
- Both A and R are True.
- Both A and R are False.
Assertion (A): Entomophilous flowers are not brightly coloured and often dull green in colour.
Reason (R): The pollinating agents of entomophilous flowers are usually water, wind and birds.
- A is True and R is False.
- A is False and R is True.
- Both A and R are True.
- Both A and R are False.
Assertion (A): One polar nucleus fuses with two sperm nuclei of a flower and develop into an endosperm during the process of fertilization.
Reason (R): The large central cell of the embryo sac contains two polar nuclei, which fuse with one male nucleus. This process is termed as 'triple fusion'.
- A is True and R is False.
- A is False and R is True.
- Both A and R are True.
- Both A and R are False.