Mathematics
Find the equation of a line parallel to 2y = 6x + 7 and passing through (-1, 1)
Answer
We know that,
Slope of parallel lines are equal.
Slope of line parallel to line 2y = 6x + 7 is 3.
By point-slope form :
⇒ y - y1 = m(x - x1)
⇒ y - 1 = 3[x - (-1)]
⇒ y - 1 = 3[x + 1]
⇒ y - 1 = 3x + 3
⇒ y = 3x + 3 + 1
⇒ y = 3x + 4.
Hence, equation of line parallel to 2y = 6x + 7 and passing through (–1, 1) is y = 3x + 4.
Related Questions
If the coordinates of the vertex A of a square ABCD are (3, -2) and the equation of diagonal BD is 3x - 7y + 6 = 0, find the equation of the diagonal AC. Also find the coordinates of the centre of the square.
If the lines kx - y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.
A line segment joining P (2, -3) and Q (0, -1) is cut by the x-axis at the point R. A line AB cuts the y-axis at T(0, 6) and is perpendicular to PQ at S. Find the :
(a) equation of line PQ
(b) equation of line AB
(c) coordinates of points R and S.
Find the coordinates of the centroid P of the △ ABC, whose vertices are A(-1, 3), B(3, -1) and C(0, 0). Hence, find the equation of a line passing through P and parallel to AB.