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Mathematics

If the lines kx - y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.

Straight Line Eq

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Answer

1st equation :

⇒ kx - y + 4 = 0

⇒ y = kx + 4

Slope (s1) : k

2nd equation :

⇒ 2y = 6x + 7

⇒ y = 62x+72\dfrac{6}{2}x + \dfrac{7}{2}

⇒ y = 3x + 72\dfrac{7}{2}

Slope (s2) : 3

We know that,

Product of slope of perpendicular lines = -1

⇒ k × 3 = -1

⇒ k = 13-\dfrac{1}{3}

Hence, k = 13-\dfrac{1}{3}.

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