If sin A = √3/2 and cos B = √3/2 , find the value of : tan A - tan B/1 + tan A tan B .

Given: i.e., ∴ If length of OM = x unit, length of AO = 2x unit. In Δ AMO, ⇒ AO2 = AM2 \+ MO2 (∵ AO is hypotenuse) ⇒ (2x)2 = (x)2 \+ AM2 ⇒ 4x2 = 3x2 \+ AM2 ⇒ AM2 = 4x2 \- 3x2 ⇒ AM2 = x2 ⇒ AM = ⇒ AM = x tan And, cos i.e. ∴ If length of XB = y unit, length of YB = 2y unit. In Δ BXY, ⇒ YB2 = YX2 \+ BX2 (∵ YB is hypotenuse) ⇒ (2y)2 = (y)2 \+ XY2 ⇒ 4y2 = 3y2 \+ XY2 ⇒ XY2 = 4y2 \- 3y2 ⇒ XY2 = y2 ⇒ XY = ⇒ XY = y tan Now, Hence, .

If sec (90° - 3A).cos 48° = 1 and 0 ≤ 3A ≤ 90°; find the value of angle A.

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In △ABC, angle C is 90° then find the value of sin (A + B).

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If sec A sin A = 0, find the value of cos A.

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Find angle A, if sec 2A = cosec (A + 48°).

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Mathematics

If sin A = √3/2 and cos B = √3/2 , find the value of : tan A - tan B/1 + tan A tan B .

Trigonometric Identities

Related Questions

If sec (90° - 3A).cos 48° = 1 and 0 ≤ 3A ≤ 90°; find the value of angle A.

In △ABC, angle C is 90° then find the value of sin (A + B).

If sec A sin A = 0, find the value of cos A.

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