If tan x = 1(1/3), find the value of : 4 sin^2x - 3 cos^2x + 2

Given: ∴ If length of BC = 4a unit, length of AB = 3a unit. In Δ ABC, ⇒ AC2 = BC2 \+ AB2 (∵ AC is hypotenuse) ⇒ AC2 = (4a)2 \+ (3a)2 ⇒ AC2 = 16a2 \+ 9a2 ⇒ AC2 = 25a2 ⇒ AC = ⇒ AC = 5a sin x = cos x = Now, 4 sin2x - 3 cos2x + 2 Hence, 4 sin2x - 3 cos2x + 2 =