In the figure, given below, CP bisects angle ACB. Show that DP bisects angle ADB.

In the figure, given below, AD = BC, ∠BAC = 30° and ∠CBD = 70°. Find :

(i) ∠BCD

(ii) ∠BCA

(iii) ∠ABC

(iv) ∠ADB

In the given figure, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD = 32°. Find :

(i) ∠OBD

(ii) ∠AOB

(iii) ∠BED

In the figure given, O is the centre of the circle. ∠DAE = 70°. Find giving suitable reasons, the measure of

(i) ∠BCD

(ii) ∠BOD

(iii) ∠OBD