Computer Applications
Two strings, city1 and city2, are compared using city1.compareTo(city2), and the result is less than zero. What does this indicate?
Answer
city1 appears before city2 in an alphabetical list.
Reason — The method compareTo(String s) in Java compares two strings lexicographically. It returns:
- A negative value if the calling string (
city1) comes before the argument string (city2) in alphabetical order. - 0 if the two strings are equal.
- A positive value if the calling string (
city1) comes after the argument string (city2) in alphabetical order.
If the result is less than zero, it indicates that city1 appears before city2 lexicographically (alphabetically).
Related Questions
The output of the statement "talent".compareTo("genius") is:
- 11
- –11
- 0
- 13
The output of the statement "CONCENTRATION".indexOf('T') is:
- 9
- 7
- 6
- (-1)
Define a class to accept a string and convert the same to uppercase, create and display the new string by replacing each vowel by immediate next character and every consonant by the previous character. The other characters remain the same.
Example:
Input : #IMAGINATION@2024
Output : #JLBFJMBSJPM@2024