Computer Applications
Two strings, city1 and city2, are compared using city1.compareTo(city2), and the result is less than zero. What does this indicate?
Java String Handling
2 Likes
Answer
city1 appears before city2 in an alphabetical list.
Reason — The method compareTo(String s) in Java compares two strings lexicographically. It returns:
- A negative value if the calling string (
city1) comes before the argument string (city2) in alphabetical order. - 0 if the two strings are equal.
- A positive value if the calling string (
city1) comes after the argument string (city2) in alphabetical order.
If the result is less than zero, it indicates that city1 appears before city2 lexicographically (alphabetically).
Answered By
2 Likes
Related Questions
Write a program in Java to enter any sentence. Also ask the user to enter a word. Print the number of times the word entered is present in the sentence. If the word is not present in the sentence, then print an appropriate message.
Which of the following returns a String?
- length()
- charAt(int)
- replace(char, char)
- indexOf(String)