Factorise : a 2 b 2 + 8ab - 9

Given, a 2 b 2 + 8ab - 9 = a 2 b 2 + 9ab - ab - 9 = ab(ab + 9) - 1(ab + 9) = (ab + 9)(ab - 1). Hence, a 2 b 2 + 8ab - 9 = (ab + 9)(ab - 1).

Mathematics

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Given,

a²b² + 8ab - 9

= a²b² + 9ab - ab - 9

= ab(ab + 9) - 1(ab + 9)

= (ab + 9)(ab - 1).

Hence, a²b² + 8ab - 9 = (ab + 9)(ab - 1).

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