Mathematics
Factorise :
2(ab + cd) - a2 - b2 + c2 + d2
Factorisation
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Answer
Given,
2(ab + cd) - a2 - b2 + c2 + d2
= 2ab + 2cd - a2 - b2 + c2 + d2
= c2 + d2 + 2cd - (a2 + b2 - 2ab)
= (c + d)2 - (a - b)2
= (c + d + a - b)[c + d - (a - b)]
= (c + d + a - b)(c + d - a + b).
Hence, 2(ab + cd) - a2 - b2 + c2 + d2 = (c + d + a - b)(c + d - a + b).
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