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Mathematics

Factorise :

2(ab + cd) - a2 - b2 + c2 + d2

Factorisation

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Answer

Given,

    2(ab + cd) - a2 - b2 + c2 + d2

= 2ab + 2cd - a2 - b2 + c2 + d2

= c2 + d2 + 2cd - (a2 + b2 - 2ab)

= (c + d)2 - (a - b)2

= (c + d + a - b)[c + d - (a - b)]

= (c + d + a - b)(c + d - a + b).

Hence, 2(ab + cd) - a2 - b2 + c2 + d2 = (c + d + a - b)(c + d - a + b).

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