Mathematics
Factorise :
a2b2 + 8ab - 9
Factorisation
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Answer
Given,
a2b2 + 8ab - 9
= a2b2 + 9ab - ab - 9
= ab(ab + 9) - 1(ab + 9)
= (ab + 9)(ab - 1).
Hence, a2b2 + 8ab - 9 = (ab + 9)(ab - 1).
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Factorise :
a2b2 + 8ab - 9
12 Likes
Given,
a2b2 + 8ab - 9
= a2b2 + 9ab - ab - 9
= ab(ab + 9) - 1(ab + 9)
= (ab + 9)(ab - 1).
Hence, a2b2 + 8ab - 9 = (ab + 9)(ab - 1).
Answered By
7 Likes