Factorise by taking out the common factors :

2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y)

Given,

2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y)

= 2(2x - 5y)[3x + 4y - 3(x - y)]

= 2(2x - 5y)[3x + 4y - 3x + 3y]

= 2(2x - 5y) × 7y

= 14y(2x - 5y).

Hence, 2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y) = 14y(2x - 5y).