Mathematics
Factorise by taking out the common factors :
2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y)
Factorisation
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Answer
Given,
2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y)
= 2(2x - 5y)[3x + 4y - 3(x - y)]
= 2(2x - 5y)[3x + 4y - 3x + 3y]
= 2(2x - 5y) × 7y
= 14y(2x - 5y).
Hence, 2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y) = 14y(2x - 5y).
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