Mathematics
Five years ago, Bharat was thrice as old as Rajat. Ten years later, Bharat will be twice as old as Rajat. The difference between their present ages is :
10 years
20 years
30 years
35 years
Answer
Let x be Bharat's present age and y be Rajat's present age,
Given,
Five years ago, Bharat was thrice as old as Rajat.
⇒ x - 5 = 3(y - 5)
⇒ x - 5 = 3y - 15
⇒ x = 3y - 15 + 5
⇒ x = 3y - 10 ….(1)
Given,
Ten years later, Bharat will be twice as old as Rajat,
⇒ x + 10 = 2(y + 10)
⇒ x + 10 = 2y + 20
⇒ x = 2y + 20 - 10
⇒ x = 2y + 10 ….(2)
Substituting value of x from equation (1) in x = 2y + 10, we get :
⇒ 3y - 10 = 2y + 10
⇒ 3y - 2y = 10 + 10
⇒ y = 20 years.
Substituting value of y in equation (1), we get :
⇒ x = 3y - 10
⇒ x = 3(20) - 10
⇒ x = 60 - 10
⇒ x = 50 years.
The difference between their present ages = x - y = 50 - 20 = 30 years.
Hence, option 3 is the correct option.
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The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Then the original number is :
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A bag contains some one-rupee coins and some fifty-paisa coins. The total amount is ₹ 140. If half of the one-rupee coins are replaced by fifty-paisa coins, then the amount becomes ₹ 115. The coins of each type in the bag initially, were :
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