Mathematics

2 tables and 3 chairs together cost ₹ 1,075 and 3 tables and 8 chairs together cost ₹ 1,875. The cost of 4 tables and 5 chairs together will be :
₹ 2,750
₹ 2,705
₹ 2,075
₹ 2,057

Linear Equations

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Answer

Let ₹ x be the cost of table and ₹ y be cost of the chair.

Given,

2 tables and 3 chairs together cost ₹ 1,075.

⇒ 2x + 3y = 1075 …….(1)

3 tables and 8 chairs together cost ₹ 1,875.

⇒ 3x + 8y = 1875 …….(2)

Multiplying equation (1) by 3, we get :

⇒ 3(2x + 3y) = 1075 × 3

⇒ 6x + 9y = 3225 ……(3)

Multiplying equation (2) by 2,

⇒ 2(3x + 8y) = 1875 × 2

⇒ 6x + 16y = 3750 ….(4)

Subtracting equation (3) from (4) we get,

⇒ (6x + 16y) - (6x + 9y) = 3750 - 3225

⇒ 6x + 16y - 6x - 9y = 525

⇒ 7y = 525

⇒ y = $\dfrac{525}{7}$ = ₹ 75.

Substituting value of y in equation (1), we get :

⇒ 2x + 3(75) = 1075

⇒ 2x + 225 = 1075

⇒ 2x = 1075 - 225

⇒ 2x = 850

⇒ x = $\dfrac{850}{2}$ = ₹ 425.

The cost of 4 tables and 5 chairs,

⇒ 4x + 5y = 4 × 425 + 5 × 75

= 1700 + 375 = ₹ 2,075.

Hence, option 3 is the correct option.

Answered By

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Mathematics

2 tables and 3 chairs together cost ₹ 1,075 and 3 tables and 8 chairs together cost ₹ 1,875. The cost of 4 tables and 5 chairs together will be :
₹ 2,750
₹ 2,705
₹ 2,075
₹ 2,057

Linear Equations

Answer

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2 tables and 3 chairs together cost ₹ 1,075 and 3 tables and 8 chairs together cost ₹ 1,875. The cost of 4 tables and 5 chairs together will be :₹ 2,750₹ 2,705₹ 2,075₹ 2,057

Linear Equations

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₹ 2,750
₹ 2,705
₹ 2,075
₹ 2,057

The solution of $\sqrt{5}x - \sqrt{7}y = 0$ and $\sqrt{3}y + \sqrt{13}x = 0$ is :
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