Mathematics
Five years ago, Bharat was thrice as old as Rajat. Ten years later, Bharat will be twice as old as Rajat. The difference between their present ages is :
10 years
20 years
30 years
35 years
Linear Equations
2 Likes
Answer
Let x be Bharat's present age and y be Rajat's present age,
Given,
Five years ago, Bharat was thrice as old as Rajat.
⇒ x - 5 = 3(y - 5)
⇒ x - 5 = 3y - 15
⇒ x = 3y - 15 + 5
⇒ x = 3y - 10 ….(1)
Given,
Ten years later, Bharat will be twice as old as Rajat,
⇒ x + 10 = 2(y + 10)
⇒ x + 10 = 2y + 20
⇒ x = 2y + 20 - 10
⇒ x = 2y + 10 ….(2)
Substituting value of x from equation (1) in x = 2y + 10, we get :
⇒ 3y - 10 = 2y + 10
⇒ 3y - 2y = 10 + 10
⇒ y = 20 years.
Substituting value of y in equation (1), we get :
⇒ x = 3y - 10
⇒ x = 3(20) - 10
⇒ x = 60 - 10
⇒ x = 50 years.
The difference between their present ages = x - y = 50 - 20 = 30 years.
Hence, option 3 is the correct option.
Answered By
3 Likes
Related Questions
2 tables and 3 chairs together cost ₹ 1,075 and 3 tables and 8 chairs together cost ₹ 1,875. The cost of 4 tables and 5 chairs together will be :
₹ 2,750
₹ 2,705
₹ 2,075
₹ 2,057
The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Then the original number is :
90
18
81
54
A bag contains some one-rupee coins and some fifty-paisa coins. The total amount is ₹ 140. If half of the one-rupee coins are replaced by fifty-paisa coins, then the amount becomes ₹ 115. The coins of each type in the bag initially, were :
one-rupee coins = 100 and fifty-paisa coins = 80
one-rupee coins = 80 and fifty-paisa coins = 100
one-rupee coins = 110 and fifty-paisa coins = 80
one-rupee coins = 70 and fifty-paisa coins = 90
X takes 3 hours more than Y to walk a distance of 30 km, but if X doubles his race, he is able to be ahead of Y by hours, then the speed of their walking will be :
X’s speed = km/hr, Y’s speed = 5 km/hr
X’s speed = 5 km/hr, Y’s speed = km/hr
X’s speed = 10 km/hr, Y’s speed = km/hr
X’s speed = km/hr, Y’s speed = 10 km/hr