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Chapter 1

GST [Goods and Services Tax]

Class - 10 Concise Mathematics Selina



Exercise 1(A)

Question 1(a)

The marked price of an article is ₹ 1500 and discount on it is 20%. How much money will be paid for this article, if rate of GST is 18% ?

  1. ₹ 2124

  2. ₹ 1416

  3. ₹ 1770

  4. ₹ 216

Answer

Given,

M.P. = ₹ 1500

Discount = 20%

Rate of G.S.T. = 18%

Discounted price = M.P. - Discount

= 1500 - 20100×1500\dfrac{20}{100} \times 1500

= 1500 - 300

= ₹ 1200.

G.S.T. on discounted price

= G.S.T.100\dfrac{G.S.T.}{100} % ×Discounted price=18100×1200\times \text{Discounted price} = \dfrac{18}{100} \times 1200 = ₹ 216.

Money paid for article = Discounted price + G.S.T.

= ₹ 1200 + ₹ 216 = ₹ 1416.

Hence, Option 2 is the correct option.

Question 1(b)

The following bill shows the GST rates and the marked price of articles A and B.

ArticlesMarked priceRate of GST
A₹ 10005%
B₹ 200012%

The total amount to be paid for the above bill is :

  1. ₹ 490

  2. ₹ 290

  3. ₹ 3290

  4. ₹ 3510

Answer

For article A :

M.P. = ₹ 1000

Rate of G.S.T. = 5%

G.S.T. = G.S.T.100\dfrac{G.S.T.}{100} % ×M.P.=5100×1000\times M.P. = \dfrac{5}{100} \times 1000 = ₹ 50.

Amount = M.P. + G.S.T. = ₹ 1000 + ₹ 50 = ₹ 1050.

For article B :

M.P. = ₹ 2000

Rate of G.S.T. = 12%

G.S.T. = G.S.T.100\dfrac{G.S.T.}{100} % ×M.P.=12100×2000\times M.P. = \dfrac{12}{100} \times 2000 = ₹ 240.

Amount = M.P. + G.S.T. = ₹ 2000 + ₹ 240 = ₹ 2240.

Total bill for article A and B = ₹ 1050 + ₹ 2240 = ₹ 3290.

Hence, Option 3 is the correct option.

Question 1(c)

A dealer in Rajasthan supplies goods and services to a dealer in Punjab. If the rate of G.S.T. is 28%. then the rate of SGST is :

  1. 28%

  2. 14%

  3. 0%

  4. none of these

Answer

The transaction from Rajasthan to Punjab is an inter-state transaction.

In inter-state transaction :

SGST = Nil = 0%.

Hence, Option 3 is the correct option.

Question 1(d)

In case of inter-state sales of goods or services, if GST rate is 18%, then :

  1. IGST = 9%

  2. SGST = 9%

  3. CGST = 9%

  4. IGST = 18%

Answer

In case of inter-state sales of goods or services, if GST rate is 18%, then :

SGST = 0%

CGST = 0%

IGST = 18%

Hence, Option 4 is the correct option.

Question 1(e)

The marked price of an article is ₹ 2000. The G.S.T. on the article is 12% and discount is ₹ 500, the total amount to be paid is :

  1. ₹ 2800

  2. ₹ 1680

  3. ₹ 1370

  4. ₹ 1740

Answer

Given,

M.P. = ₹ 2000

Discount = ₹ 500

Rate of G.S.T. = 12%

Discounted price = M.P. - Discount

= ₹ 2000 - ₹ 500

= ₹ 1500.

G.S.T. on discounted price

= G.S.T.100\dfrac{G.S.T.}{100} % ×Discounted price=12100×1500\times \text{Discounted price} = \dfrac{12}{100} \times 1500 = ₹ 180.

Money paid for article = Discounted price + G.S.T.

= ₹ 1500 + ₹ 180 = ₹ 1680.

Hence, Option 2 is the correct option.

Question 2

For the following transaction within Delhi, fill in the blanks to find the amount of bill :

MRP = ₹12,000

Discount = 30%

GST% = 18%

Discount = ...............

Discounted value = ...............

CGST = ...............

SGST = ...............

IGST = ...............

Amount of bill = ...............

Answer

Given,

M.R.P. = ₹12,000

Discount = 30%

∴ Discount = 30100×12000\dfrac{30}{100} \times ₹12000 = ₹ 3600.

Discounted value = ₹ 12000 - ₹ 3600 = ₹ 8400.

Given, GST% = 18%, so

CGST = 9% and SGST = 9%.

Since, transactions are within a particular state i.e., Delhi so, IGST = Nil.

∴ CGST = 9100×8400\dfrac{9}{100} \times ₹ 8400 = ₹ 756.

∴ SGST = 9100×8400\dfrac{9}{100} \times ₹ 8400 = ₹ 756.

Amount of bill = Discounted price + CGST + SGST = ₹ 8400 + ₹ 756 + ₹ 756 = ₹ 9912.

Hence, Discount = ₹ 3600, Discounted value = ₹ 8400, CGST = ₹ 756 and SGST = ₹ 756, IGST = ₹ 0, Amount of bill = ₹ 9912.

Question 3

For the following transaction from Delhi to Jaipur, fill in the blanks to find the amount of bill :

MRP = ₹ 50,000

Discount = 20%

GST = 28%

Discount = ...............

Discounted value = ...............

CGST = ...............

SGST = ...............

IGST = ...............

Amount of bill = ...............

Answer

Given,

M.R.P. = ₹50,000

Discount = 20%

∴ Discount = 20100×50000\dfrac{20}{100} \times ₹50000 = ₹ 10000.

Discounted value = ₹ 50000 - ₹ 10000 = ₹ 40000.

Since transactions are inter state hence,

CGST = Nil and SGST = Nil.

IGST = 28%.

∴ IGST = 28100×40000\dfrac{28}{100} \times ₹ 40000 = ₹ 11200.

Amount of bill = Discounted price + IGST = ₹ 40000 + ₹ 11200 = ₹ 51200.

Hence, Discount = ₹ 10000, Discounted value = ₹ 40000, CGST = SGST = ₹ 0, IGST = ₹ 11200, Amount of bill = ₹ 51200.

Question 4

A computer mechanic in Delhi charges repairing cost from five different persons A, B, C, D and E with certain discounts.

The repairing costs and the corresponding discounts are as given below:

Name of the personsABCDE
Repairing cost (in ₹)5,5006,2504,8007,2003,500
Discount %3040302040

If the rate of GST is 18%, find the total money (including GST) received by the mechanic.

Answer

We know that, Discounted value % = 100% - Discount %.

Name of the personsRepairing cost (in ₹)Discount %Discounted value %Discounted value
A5,500307070100\dfrac{70}{100} x 5,500 = 3850
B6,250406060100\dfrac{60}{100} x 6,250 = 3750
C4,800307070100\dfrac{70}{100} x 4,800 = 3360
D7,200208080100\dfrac{80}{100} x 7,200 = 5760
E3,500406060100\dfrac{60}{100} x 3,500 = 2100
Total18820

GST = 18%.

GST = 18100×18820\dfrac{18}{100} \times 18820 = ₹3387.60

Total money = ₹18820 + ₹3387.60 = ₹22207.60

Hence, the total money received by mechanic = ₹22207.60

Question 5

Find the amount of bill for the following intra-state transaction of goods/services. The GST rate is 5%.

Answer

Quantity (No.of items)MRP of each item (in ₹)Discount%
3645010
4872020
6030030
2436020

Answer

Discount value % = 100 % - Discount %

Given,

GST = 5%

∴ CGST = SGST = 2.5%.

Construct the table as under :

Quantity (No.of items)MRP of each item (in ₹)Total value
(Qty x MRP)
Discount%Discounted valueCGST (in ₹)SGST (in ₹)Total value (Discounted Value + CGST + SGST)
36450162001090100×16200\dfrac{90}{100} \times 16200 = 145802.5100×14580\dfrac{2.5}{100} \times 14580 = 364.50364.5015309
48720345602080100×34560\dfrac{80}{100} \times 34560 = 276482.5100×27648\dfrac{2.5}{100} \times 27648 = 691.20691.2029030.40
60300180003070100×18000\dfrac{70}{100} \times 18000 = 126002.5100×12600\dfrac{2.5}{100} \times 12600 = 31531513230
2436086402080100×8640\dfrac{80}{100} \times 8640 = 69122.5100×6912\dfrac{2.5}{100} \times 6912 = 172.80172.807257.60
Total64827

Hence, the total amount = ₹ 64,827.

Question 6

Find the amount of bill for the following inter-state transaction of goods/services. The GST rate is 18%.

Quantity (No. of items)354720
MRP of each item (in ₹)420600320
Discount %101020

Answer

Since, the transaction is inter-state,

∴ CGST = SGST = Nil.

IGST = 18%.

Quantity (No.of items)MRP of each item (in ₹)Total value
(Qty x MRP)
Discount%Discounted valueIGST (in ₹)Total value (Discounted Value + IGST)
35420147001090100×14700=13230\dfrac{90}{100} \times 14700 = 1323018100×13230\dfrac{18}{100} \times 13230 = 2381.4015611.40
47600282001090100×28200\dfrac{90}{100} \times 28200 = 2538018100×25380\dfrac{18}{100} \times 25380 = 4568.4029948.40
2035070002080100×7000\dfrac{80}{100} \times 7000 = 560018100×5600\dfrac{18}{100} \times 5600 = 10086608
Total52167.80

Hence, the total amount = ₹ 52167.80.

Question 7

Find the amount of bill for the following intra-state transaction of goods/services.

MRP (in ₹)1200015000950018000
Discount%30203040
CGST%69142.5

Answer

Discount value % = 100 % - Discount %

CGST = SGST.

Construct the table as under :

MRP of each item (in ₹)Discount%Discounted valueCGST%CGST (in ₹)SGST (in ₹)Total value (Discounted Value + CGST + SGST)
120003070100×12000\dfrac{70}{100} \times 12000 = 840066100×8400\dfrac{6}{100} \times 8400 = 5045049408
150002080100×15000\dfrac{80}{100} \times 15000 = 1200099100×12000\dfrac{9}{100} \times 12000 = 1080108014160
95003070100×9500\dfrac{70}{100} \times 9500 = 66501414100×6650\dfrac{14}{100} \times 6650 = 9319318512
180004060100×18000\dfrac{60}{100} \times 18000 = 108002.52.5100×10800\dfrac{2.5}{100} \times 10800 = 27027011340
Total43420

Hence, the total amount = ₹ 43420.

Question 8

For the data given above in question no. 6, find the amount of bill for the inter-state transaction.

Answer

Discount value % = 100 % - Discount %

IGST = 2CGST%

Construct the table as under :

MRP of each item (in ₹)Discount%Discounted valueIGST(%)IGST (in ₹)Total value (Discounted Value + IGST)
120003070100×12000\dfrac{70}{100} \times 12000 = 84002 × 6% = 12%12100×8400\dfrac{12}{100} \times 8400 = 10089408
150002080100×15000\dfrac{80}{100} \times 15000 = 120002 × 9% = 18%18100×12000\dfrac{18}{100} \times 12000 = 216014160
95003070100×9500\dfrac{70}{100} \times 9500 = 66502 × 14% = 28%28100×6650\dfrac{28}{100} \times 6650 = 18628512
180004060100×18000\dfrac{60}{100} \times 18000 = 108002 × 2.5% = 5%5100×10800\dfrac{5}{100} \times 10800 = 54011340
Total43420

Hence, the total amount = ₹ 43420.

Question 9

A dealer in Mumbai supplied some identical items at the following prices to a dealer in Delhi. Find the total amount of bill.

Rate per item (in ₹)Quantity (no. of items)Discount %SGST %
180109
26020209
310309
17520309

Answer

Discounted% = 100% - Discount%.

IGST% = 2SGST%

Quantity (No.of items)Rate per item (in ₹)Total valueDiscount%Discounted valueIGST%IGST (in ₹)Total value (Discounted Value + IGST)
10180180018001818100×1800\dfrac{18}{100} \times 1800 = 3242124
2026052002080100×5200\dfrac{80}{100} \times 5200 = 41601818100×4160\dfrac{18}{100} \times 4160 = 748.804908.80
30310930093001818100×9300\dfrac{18}{100} \times 9300 = 167410974
2017535003070100×3500=2450\dfrac{70}{100} \times 3500 = 24501818100×2450\dfrac{18}{100} \times 2450 = 4412891
Total20897.80

Hence, the amount of bill = ₹ 20897.80

Question 10

M/s Unique traders, Delhi, provided the following services to M/s Geeta Trading Company in Agra (U.P.). Find the amount of bill :

Number of services8121016
Cost of each service (in ₹)680320260420
GST%5121812

Answer

Construct the table as under :

Number of servicesCost of each service (in ₹)Total value of serviceIGST%IGST (in ₹)Total (total value of service + IGST)
8680544055100×5440\dfrac{5}{100} \times 5440 = 2725712
1232038401212100×3840\dfrac{12}{100} \times 3840 = 460.804300.80
1026026001818100×2600\dfrac{18}{100} \times 2600 = 4683068
1642067201212100×6720\dfrac{12}{100} \times 6720 = 806.407526.40
Total20607.20

Hence, the amount of bill = ₹ 20607.20

Question 11

The tax invoice of a telecom service in Surat shows cost of services provided by it as ₹ 750. If the GST rate is 18%, find the amount of the bill.

Answer

Cost of services = ₹ 750,

GST = 18%,

GST = 18100×750\dfrac{18}{100} \times 750 = ₹ 135.

Amount = ₹ 750 + ₹ 135 = ₹ 885.

Hence, the amount of bill = ₹ 885.

Question 12

Ms. Pratima took Health Insurance Policy for her family and paid ₹ 900 as SGST. Find the total annual premium, including GST, paid by her for this policy. The rate of GST being 18%.

Answer

Given, GST = 18%,

∴ SGST = 9%.

Let annual premium be ₹ x.

Given, SGST = ₹ 900.

900=9100×xx=900×1009x=10000.\therefore 900 = \dfrac{9}{100} \times x \\[1em] \Rightarrow x = \dfrac{900 \times 100}{9} \\[1em] \Rightarrow x = 10000.

We know that, CGST = SGST.

∴ Amount = Premium + CGST + SGST = ₹ 10000 + ₹ 900 + ₹ 900 = ₹ 11800.

Hence, the annual premium including GST = ₹ 11800.

Question 13

Mr. Malik went on a tour of Goa. He took a room in a hotel for two days at the rate of ₹ 5000 per day. On the same day, his friend John also joined him. The hotel provided an extra bed charging ₹ 1000 per day for the bed. How much GST, at the rate of 28% is charged by the hotel in the bill to Mr. Malik, for both the days?

Answer

Total charge of room for one day = ₹ 5000 + ₹ 1000 = ₹ 6000.

Charge for 2 days = 2 × 6000 = ₹ 12000.

GST = 28%,

∴ GST = 28100×12000\dfrac{28}{100} \times 12000 = ₹ 3360.

Hence, the amount of GST charged in the bill = ₹ 3360.

Exercise 1(B)

Question 1(a)

Under G.S.T. 'value addition' refers to :

  1. cost plus tax plus profit

  2. cost plus tax

  3. expense plus profit

  4. tax plus profit

Answer

Under G.S.T. 'value addition' refers to expense plus profit.

Hence, Option 3 is the correct option.

Question 1(b)

If the rate of GST is 18%, the IGST for an inter-state sale is:

  1. 9%

  2. 18%

  3. 6%

  4. 12%

Answer

Option 2 is the correct option.

Reason

In the case of inter-state sale, rate of GST = rate of IGST

⇒ IGST = 18%

Hence, the IGST for an inter-state sale = 18%.

Question 1(c)

If a dealer supplies goods worth ₹ 3,000 to another local dealer with 28% GST, then the tax levied under CGST is:

  1. ₹ 270

  2. ₹ 540

  3. ₹ 840

  4. ₹ 420

Answer

Option 4 is the correct option.

Reason

Cost of goods = ₹ 3,000

GST rate = 28%

Since, it is a local (intra-state) supply, the GST is equally divided between CGST and SGST.

CSGT = SGST = GST2=282\dfrac{GST}{2} = \dfrac{28}{2}% = 14%

The tax levied under CGST = 14% of ₹ 3,000

= 14100×3,000\dfrac{14}{100} \times 3,000

= 14 x 30 = ₹ 420

Hence, the tax levied under CGST = ₹ 420

Question 1(d)

For a registered dealer, if the input tax is ₹ x and output tax is ₹ y, then the tax liability on the dealer is:

  1. ₹ x

  2. ₹ (x - y)

  3. ₹(y - x)

  4. ₹ y

Answer

Option 3 is the correct option.

Reason

Given, input tax = ₹ x

output tax = ₹ y

Tax liability = Output tax - Input tax

= ₹ (y - x)

Hence, the tax liability on the dealer is ₹ (y - x).

Question 2

Fill in the blanks :

When the goods/services are sold for ₹ 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.

As per GST system

(a) S.P. (excluding GST) at station A = ..........

(b) CGST = ................

     SGST = ................

(c) C.P. (excluding GST) at station B = ............

(d) If profit = ₹ 5,000

S.P. at station B = .............

Now the same goods/services are moved under inter state transaction from station B to station C and the rate of tax is 12%.

(e) GST = ..........

(f) C.P. (excluding GST) at station C = ..........

Answer

When the goods/services are sold for ₹ 15000 under intra-state transaction from station A to station B and the rate of GST is 12%.

As per GST system

(a) S.P. (excluding GST) at station A = ₹ 15000

(b) CGST = 6% of 15000 = 6100×15000\dfrac{6}{100} \times 15000 = ₹ 900

     SGST = 6% of 15000 = 6100×15000\dfrac{6}{100} \times 15000 = ₹ 900.

(c) C.P. (excluding GST) at station B = ₹ 15000

(d) If profit = ₹ 5000

S.P. at station B = ₹ 15000 + ₹ 5000 = ₹ 20000.

(e) GST = 12% of ₹ 20000 = 12100×20000\dfrac{12}{100} \times 20000 = ₹ 2400.

(f) C.P. (excluding GST) at station C = ₹ 20000.

Question 3

Goods/services are sold from Agra (U.P.) to Kanpur (U.P.) for ₹ 20,000 and then Kanpur to Jaipur (Rajasthan). If the rate of GST is 18% and the profit made at Kanpur is ₹ 5,000, find :

The net GST payable by the dealer at Kanpur (GST received - GST paid).

Answer

When the goods are sold from Agra to Kanpur it is an intra-state transaction.

For dealer in Agra

S.P. = ₹ 20,000

CGST = 9% of ₹ 20,000 = ₹ 1800

SGST = CGST = ₹ 1800.

When the product is sold from Kanpur to Jaipur it is an intra-state transaction.

For dealer in Kanpur

Input-tax credit (ITC) = ₹ 1800 + ₹ 1800 = ₹ 3600.

C.P. (excluding GST) = ₹ 20000 + ₹ 5000 = ₹ 25000.

IGST = 18% of ₹ 25000 = ₹ 4500.

∴ Net GST payable at Kanpur = Output GST - Input-tax credit = ₹ 4500 - ₹ 3600 = ₹ 900.

Hence, the net GST payable at Kanpur is ₹ 900.

Question 4

Goods/services are sold from Kota (Rajasthan) to Mumbai for ₹ 20000 and then from Mumbai to Pune. If the rate of GST is 12% and the profit made at Mumbai is ₹ 5000; find the net GST paid at Pune, if the dealer at Pune does not sell the goods further.

Answer

First transaction is an inter-state transaction

For dealer in Mumbai

C.P. = ₹ 20000

IGST = 12% of ₹ 20000 = ₹ 2400

Given,

Profit = ₹ 5000

S.P. = ₹ 20000 + ₹ 5000 = ₹ 25000.

Second transaction is an intra-state transaction

Now for dealer in Pune

C.P. = ₹ 25000

CGST = 6% of ₹ 25000 = ₹ 1500.

SGST = CGST = ₹ 1500.

∴ GST paid by end user at Pune is ₹ 1500 + ₹ 1500 = ₹ 3000.

Hence, GST paid by dealer at Pune is ₹ 3000.

Question 5

A is a dealer in Banaras (U.P.). He supplies goods/services, worth ₹ 8000 to a dealer B in Agra (U.P.) Dealer B in turn, supplies the same goods/services to a dealer C in Patna (Bihar) at a profit of ₹ 1200. Find the input and output taxes for the dealer C under GST system; if the rate of GST is 18% and C does not sells his goods/services further.

Answer

According to question,

For dealer A (intra-state transaction)

S.P. = ₹ 8000

For dealer B

C.P. = ₹ 8000

CGST = 9% of ₹ 8000 = ₹ 720

SGST = 9% of ₹ 8000 = ₹ 720

Given, Profit = ₹ 1200

S.P. = ₹ 8000 + ₹ 1200 = ₹ 9200.

For dealer C (inter-state transaction)

C.P. = ₹ 9200

IGST = 18% of ₹ 9200 = 18100×9200\dfrac{18}{100} \times 9200 = ₹ 1656.

∴ Input tax = ₹ 1656.

As the dealer in Patna does not sell product,

∴ Output tax = ₹ 0.

Hence, the input tax = ₹ 1656 and output tax = ₹ 0.

Question 6

A is a dealer in Meerut (UP). He supplies goods/services, worth ₹ 15000 to dealer B in Ratlam (MP). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur (MP) at a profit of ₹ 3000. If the rate of tax (under the GST system) is 18%, find :

(i) the cost (excluding GST) of goods/services to the dealer C in Jabalpur (assuming that the dealer C does not sell the goods/services further).

(ii) net tax payable by dealer B.

Answer

For A (case of inter-state transaction)

S.P. in Meerut = ₹ 15000

IGST = 18% of 15000 = 18100×15000\dfrac{18}{100} \times ₹ 15000 = ₹ 2700.

Input tax for B = ₹ 2700.

Given profit on selling to C = ₹ 3000

∴ S.P. in Ratlam = ₹ 15000 + ₹ 3000 = ₹ 18000.

For C (case of intra-state transaction)

C.P. = ₹ 18000

CGST = 9% of ₹ 18000 = 9100×18000\dfrac{9}{100} \times 18000 = ₹ 1620

SGST = CGST = ₹ 1620.

(i) Cost for dealer C = S.P. for dealer in Ratlam + GST = ₹ 18000 + ₹ 1620 + ₹ 1620 = ₹ 21240.

Hence, the cost of goods/services for dealer C = ₹ 21240.

(ii) Output tax for B = CGST + SGST = ₹ 1620 + ₹ 1620 = ₹ 3240

∴ Net GST payable by dealer B = Output tax - Input tax = ₹ 3240 - ₹ 2700 = ₹ 540.

Hence, the net tax payable by dealer = ₹ 540.

Question 7

A dealer X in Hapur (UP) supplies goods/services, worth ₹ 50,000 to some other dealer Y in the same city. Now the dealer Y supplies the same goods/services to dealer Z in Calcutta at a profit of ₹ 20,000. Find :

(i) Output and input taxes for the dealer Y

(ii) Net GST payable by dealer Y.

[The rate of GST at each stage is 28%]

Answer

According to question we have,

For dealer X (intra-state transaction)

SP = ₹ 50000

For dealer Y (intra-state transaction)

CP = ₹ 50000

CGST = 14% of 50000 = 14100×50000\dfrac{14}{100} \times 50000 = ₹ 7000

SGST = 14% of 50000 = 14100×50000\dfrac{14}{100} \times 50000 = ₹ 7000

Input tax = ₹ 7000 + ₹ 7000 = ₹ 14000

Profit of dealer Y = ₹ 20000

S.P. of dealer Y = ₹ 50000 + ₹ 20000 = ₹ 70000.

For dealer Z (inter-state transaction)

CP = ₹ 70000

IGST = 28% of ₹ 70000 = 28100×70000\dfrac{28}{100} \times 70000 = ₹ 19600

(i) Output tax for Y = Input tax for Z = ₹ 19600.

Input tax of dealer Y = ₹ 14000.

Hence, for dealer Y, Output tax = ₹ 19600 and Input tax = ₹ 14000.

(ii) Net GST payable by dealer Y = Output tax - Input tax

= ₹ 19600 - ₹ 14000 = ₹ 5600.

Hence, net GST payable for Y = ₹ 5600.

Question 8

Consultancy services, worth ₹ 50000 are transferred from Delhi to Kolkata at the rate of GST 18% and then Kolkata to Nainital (with profit = ₹ 20000) at the same rate of GST. Find the output tax at

(i) Delhi

(ii) Kolkata

(iii) Nainital

Answer

(i) Delhi to Calcutta (Transaction is an inter state transaction)

IGST = 18% of ₹ 50000 = 18100×50000\dfrac{18}{100} \times 50000 = ₹ 9000.

Hence, the output tax in Delhi = ₹ 9000.

(ii) For Calcutta,

C.P. = ₹ 50000

Profit in sending to Nainital = ₹ 20000

S.P. = ₹ 50000 + ₹ 20000 = ₹ 70000.

Transaction is an inter state transaction

IGST = 18100×70000\dfrac{18}{100} \times 70000 = ₹ 12600

Hence, the output tax in Calcutta = ₹ 12600.

(iii) Since, the dealer in Nainital does transfer the services further

Hence, output tax = ₹ 0

Hence, the output tax in Nainital = ₹ 0.

Question 9

For a trader, marked price of a refrigerator = ₹ 15,680 exclusive of GST, (GST is 12%). Gagan, a customer for this refrigerator, asks the trader to reduce the marked price of the refrigerator to such an extent that its reduced price plus GST on it is equal to marked price of the refrigerator. Find the required reduction.

Answer

Let the new M.P. of refrigerator be ₹ x.

According to question,

x+12x+12100x=15680112100x=15680x=15680×100112x=14,000.\Rightarrow x + 12% \text{ of } x = 15680 \\[1em] \Rightarrow x + \dfrac{12}{100}x = 15680 \\[1em] \Rightarrow \dfrac{112}{100}x = 15680 \\[1em] \Rightarrow x = \dfrac{15680 \times 100}{112} \\[1em] \Rightarrow x = ₹ 14,000.

Reduction in price = ₹ 15680 - ₹ 14000 = ₹ 1680.

Hence, the required reduction in price = ₹ 1680.

Test Yourself

Question 1(a)

A retailer purchased an item for ₹ 8000 from a wholesaler and sells to a customer at 15% profit. The sales are intra-state and the rate of GST is 10%. The amount of GST paid by the customer is :

  1. ₹ 460

  2. ₹ 920

  3. ₹ 1840

  4. ₹ 92

Answer

Given,

Cost price for retailer = ₹ 8000

Profit % = 15%

Selling price for retailer = C.P. + Profit

= ₹ 8000 + ₹ 15100×8000\dfrac{15}{100} \times 8000

= ₹ 8000 + ₹ 1200

= ₹ 9200.

For intra -state transaction :

S.G.S.T. = C.G.S.T. % = G.S.T.2=102\dfrac{G.S.T.}{2} = \dfrac{10}{2} = 5%

S.G.S.T. = C.G.S.T. = 5100×S.P.=5100×9200\dfrac{5}{100} \times S.P. = \dfrac{5}{100} \times 9200 = ₹ 460.

Total G.S.T. paid by customer = S.G.S.T. + C.G.S.T. = ₹ 460 + ₹ 460 = ₹ 920.

Hence, Option 2 is the correct option.

Question 1(b)

A retailer purchased an item for ₹ 8000 from a wholesaler ad sells to a customer at 15% profit. The sales are inter-state and the rate of GST paid by the customer is 10%. The amount of GST paid by customer is :

  1. ₹ 460

  2. ₹ 920

  3. ₹ 1840

  4. ₹ 92

Answer

Given,

Cost price for retailer = ₹ 8000

Profit % = 15%

Selling price for retailer = C.P. + Profit

= ₹ 8000 + ₹ 15100×8000\dfrac{15}{100} \times 8000

= ₹ 8000 + ₹ 1200

= ₹ 9200.

For inter -state transaction :

S.G.S.T. % = C.G.S.T. % = Nil

I.G.S.T. % = G.S.T. = 10%

I.G.S.T. = I.G.S.T.100\dfrac{I.G.S.T.}{100} % ×S.P.=10100×9200\times S.P. = \dfrac{10}{100} \times 9200 = ₹920.

Hence, Option 2 is the correct option.

Question 1(c)

The cost of certain services is ₹ 10,000, excluding GST = ₹ 1800. The rate of GST is :

  1. 12%

  2. 5%

  3. 18%

  4. 28%

Answer

Given,

C.P. of articles = ₹ 10,000

We know that,

GST = Rate of G.S.T.100×C.P.\dfrac{\text{Rate of G.S.T.}}{100} \times C.P.

Substituting values we get :

1800=Rate of G.S.T.100×10000Rate of G.S.T.=1800×10010000Rate of G.S.T.=18\Rightarrow 1800 = \dfrac{\text{Rate of G.S.T.}}{100} \times 10000 \\[1em] \Rightarrow \text{Rate of G.S.T.} = \dfrac{1800 \times 100}{10000} \\[1em] \Rightarrow \text{Rate of G.S.T.} = 18 %.

Hence, Option 3 is the correct option.

Question 1(d)

Manu purchases some goods for ₹ 2000 and sells them for ₹ 2500. If the rate of GST is 18%, the tax liability on Manu is :

  1. ₹ 360

  2. ₹ 450

  3. ₹ 90

  4. ₹ 900

Answer

Given,

For Manu :

C.P. = ₹ 2000

S.P. = ₹ 2500

Tax paid by Manu = G.S.T.100×C.P.=18100×2000\dfrac{G.S.T.}{100} \times C.P. = \dfrac{18}{100} \times 2000 = ₹ 360.

Tax charged by Manu = G.S.T.100×S.P.=18100×2500\dfrac{G.S.T.}{100} \times S.P. = \dfrac{18}{100} \times 2500 = ₹ 450.

Tax liability on Manu = Tax charged - Tax paid = ₹ 450 - ₹ 360 = ₹ 90.

Hence, Option 3 is the correct option.

Question 1(e)

Reena buys a certain goods for ₹ 4000 and sells them to Ashok at a profit of ₹ 500. If Ashok des not sell the goods further and rate of GST = 5%, the output GST for Ashok is :

  1. ₹ 225

  2. ₹ 175

  3. ₹ 25

  4. ₹ 00

Answer

Cost price for Reena = ₹ 4000

Input G.S.T. for Reena = G.S.T.100\dfrac{G.S.T.}{100} % ×\times C.P. for Reena

= 5100×4000\dfrac{5}{100} \times 4000 = ₹ 200.

Profit made by Reena on selling = ₹ 500

Cost price for Ashok = S.P. for Reena = ₹ 4000 + ₹ 500 = ₹ 4500.

Output G.S.T. means GST charged on the sales made by a dealer.

Output G.S.T. for Reena = G.S.T.100\dfrac{G.S.T.}{100} % ×\times S.P. for Reena

= 5100×4500\dfrac{5}{100} \times 4500 = ₹ 225.

This ₹225 is output GST for Reena and input GST for Ashok.

The question says that Ashok does not sell the goods further

Since Ashok makes no sale, he does not charge any GST to anyone.
So, his output GST = ₹0.

Hence, Option 4 is the correct option.

Question 1(f)

The marked price of an article is ₹ 1,000, which is available at a discount of 20% with GST rate 12%.

Assertion (A): The GST on the sale = 12% of discounted value.

Reason (R): The GST on the transaction = (100 - 20 + 12)% of marked price.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true and R is the correct reason for A.

  4. Both A and R are true and R is the incorrect reason for A.

Answer

Option 1 is the correct option.

Reason

Given, MP = ₹ 1,000

Discount = 20%

GST = 12%

Discount = 20% of ₹ 1,000

= 20100\dfrac{20}{100} x 1,000 = ₹ 200

Price after discount = ₹ 1,000 - 200 = ₹ 800

GST on the discounted price = 12% of price after discount

= 12100\dfrac{12}{100} x 800 = ₹ 96

∴ Assertion (A) is true.

The GST on the transaction = (100 - 20 + 12)% of marked price

= 92% of marked price

= 92100\dfrac{92}{100} x 1,000 = ₹ 920

As, ₹ 96 ≠ ₹ 920

∴ Reason (R) is false.

Hence, A is true, R is false.

Question 1(g)

For a trader X, GST paid is ₹ 600 and GST collected is ₹ 720.

Assertion (A): GST paid by the trader to the Government is ₹ 120.

Reason (R): GST deposited with the Government
= Output Tax - Input tax
= GST collected - GST paid

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true and R is the correct reason for A.

  4. Both A and R are true and R is incorrect reason for A.

Answer

Option 3 is the correct option.

Reason

Given,

Output tax = ₹720

Input tax = ₹600

Tax liability = Output tax - Input tax

= ₹ (720 - 600) = ₹ 120

Hence, Both A and R are true and R is the correct reason for A.

Question 1(h)

The invoice value of a toy is ₹ 4,220 and rate of GST is 5%.

Statement (1): GST paid = 5% of ₹ 4,220

Statement (2): The taxable value of the toy = 100105\dfrac{100}{105} × ₹ 4,220

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Answer

Option 4 is the correct option.

Reason

Given,

Invoice value = ₹ 4,220

GST = 5%

According to statement 1, GST paid = 5% of ₹ 4,220

Invoice value includes the GST. Therefore, GST is not calculated on ₹ 4,220 directly.

So, statement 1 is false.

According to statement 2, the taxable value of the toy = 100105\dfrac{100}{105} × ₹ 4,220

Let the taxable value of the toy be xx.

Since, invoice value includes the GST,

Invoice value = xx + 5% of xx

= x+5100×xx + \dfrac{5}{100} \times x

= x+0.05xx + 0.05x

= 1.05x1.05x

Given, Invoice Value = ₹ 4,220, we have,

1.05x=4220x=11.05×4220x=100105×42201.05x = 4220 \\[1em] x = \dfrac{1}{1.05} \times 4220 \\[1em] x = \dfrac{100}{105} \times 4220

∴ Taxable value of the toy = 100105×4220\dfrac{100}{105} \times ₹ 4220

∴ Statement 2 is true.

Hence, statement 1 is false, and statement 2 is true.

Question 1(i)

Assertion (A) : A dealer in Indore (M.P.) sells goods worth ₹ 75,000 to a dealer in Jaipur (Rajasthan). If the rate of GST is 18%, then the CGST share of Rajasthan is 9% of ₹ 75,000.

Reason (R) : In inter-state transaction, GST is 18% of the whole transaction.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

The Assertion is false because in interstate transaction the rate of CGST = Nil.

The Reason is true because in an inter-state transaction, the GST rate is 18% of the whole transaction value.

Hence, Option 2 is the correct option.

Question 2

Mrs. Sharma bought the following articles from a departmental store.

ItemsMarked priceDiscountRate of GST
Face-cream₹ 35012%12%
Hair oil₹ 720-5%
Telecom powder₹ 22518%18%

Find the :

(i) total GST paid

(ii) total billing amount including GST.

Answer

By formula,

Discount = Discount100\dfrac{\text{Discount}}{100} % ×M.P.\times M.P.

Discounted price = M.P. - Discount

GST = Rate of GST100×\dfrac{\text{Rate of GST}}{100} \times Discounted price

ItemsMarked priceDiscount %Rate of GSTDiscountDiscounted priceGST
Face-cream₹ 35012%12%12% of ₹ 350 = ₹ 42₹ 30812% of ₹ 308 = ₹ 36.96
Hair oil₹ 720-5%0₹ 7205% of ₹ 720 = ₹ 36
Telecom powder₹ 22518%18%18% of ₹ 225 = ₹ 40.5₹ 184.518% of ₹184.5 = ₹ 33.21

(i) From table,

Total G.S.T. = ₹ 36.96 + ₹ 36 + ₹ 33.21 = ₹ 106.17

Hence, total GST paid = ₹ 106.17

(ii) From table,

Total discounted price = ₹ 308 + ₹ 720 + ₹ 184.5 = 1212.50

Total bill = Total Discounted price + Total GST = ₹ 1212.50 + ₹ 106.17 = ₹ 1318.67

Hence, total bill = ₹ 1318.67

Question 3

Ashraf went to see a movie. He wanted to purchase a movie ticket for ₹ 80. As the ticket for ₹ 80 was not available, he purchased a ticket for ₹ 120 of upper class. How much extra GST did he pay for the ticket? (GST for a ticket below ₹ 100 is 18% and for a ticket above ₹ 100 is 28%).

Answer

GST on ₹ 80 ticket = 18100×80\dfrac{18}{100} \times 80 = ₹ 14.40

GST on ₹ 120 ticket = 28100×120\dfrac{28}{100} \times 120 = ₹ 33.60

Difference between GST = ₹ 33.60 - ₹ 14.40 = ₹ 19.20

Hence Ashraf paid ₹ 19.20 extra GST for the ticket.

Question 4

A shopkeeper sells an AC to Ms. Alka for ₹ 31200 including GST at the rate of 28%. If the shopkeeper and Ms. Alka both are from the same city, find for the shopkeeper :

(i) total amount of GST

(ii) taxable value of A.C.

(iii) amount of CGST

(iv) amount of SGST

Answer

(i) Let S.P. of A.C. be x.

According to question,

x+28100×x=31200100x+28x100=31200128x100=31200x=31200×100128x=24375.\Rightarrow x + \dfrac{28}{100} \times x = 31200 \\[1em] \Rightarrow \dfrac{100x + 28x}{100} = 31200 \\[1em] \Rightarrow \dfrac{128x}{100} = 31200 \\[1em] \Rightarrow x = \dfrac{31200 \times 100}{128} \\[1em] \Rightarrow x = ₹ 24375.

GST = S.P.(including GST) - S.P.(excluding GST) = ₹ 31200 - ₹ 24375 = ₹ 6825.

Hence, the total amount of GST = ₹ 6825.

(ii) From part (i) we get,

The taxable value of A.C. = ₹ 24375.

(iii) Given, GST = 28%.

∴ CGST = 14%.

14100×24375=3412.50\Rightarrow \dfrac{14}{100} \times 24375 = ₹ 3412.50

Hence, CGST = ₹ 3412.50

(iv) Given, GST = 28%.

∴ SGST = 14%.

14100×24375=3412.50\Rightarrow \dfrac{14}{100} \times 24375 = ₹ 3412.50

Hence, SGST = ₹ 3412.50

Question 5

A wholesaler dealing in electric goods, sells an article at its printed price of ₹ 45,000 to a dealer at 10% discount. The dealer sells the same article to a consumer at a discount of 4% on its printed price. If the sales are intra-state and the rate of GST is 18%, find :

(i) the amount of tax, under GST, paid by the dealer to the central and state governments.

(ii) the amount of tax, under GST, received by central and state governments.

(iii) the total amount, inclusive of tax, paid by the consumer for the article.

Answer

For wholesaler :

Marked price = ₹ 45000

Discount = 10% = 10100×45000\dfrac{10}{100} \times 45000 = ₹ 4500

S.P. = M.P. - Discount = ₹ 45000 - ₹ 4500 = ₹ 40500.

For dealer :

C.P. = ₹ 40500

Discount = 4% = 4100×45000\dfrac{4}{100} \times 45000 = ₹ 1800

S.P. = M.P. - Discount = ₹ 45000 - ₹ 1800 = 43200.

(i) Tax paid by dealer under GST = Output tax - Input tax

= Tax on S.P. - Tax on C.P.

= 18% of 43200 - 18% of 40500

= 18100×4320018100×40500\dfrac{18}{100} \times 43200 - \dfrac{18}{100} \times 40500

= ₹ (7776 - 7290)

= ₹ 486.

CGST = SGST = GST2\dfrac{\text{GST}}{2} = 4862\dfrac{486}{2} = ₹ 243

Hence, the tax paid by dealer to central government = ₹ 243 and to state government = ₹ 243.

(ii) GST paid by dealer = 18% of ₹ 43200 = 18100×43200\dfrac{18}{100} \times 43200 = ₹ 7776

∴ GST received by government = ₹ 7776

CGST = SGST = GST2\dfrac{\text{GST}}{2} = 77762\dfrac{7776}{2} = ₹ 3,888

Hence, amount of tax received by central government = ₹ 3,888 and by state government = ₹ 3,888.

(iii) For consumer :

C.P. = S.P. for dealer = ₹ 43200

GST paid by the consumer = 18% of 43200 = ₹ 7776

∴ Total amount paid by consumer = ₹ 43200 + ₹ 7776 = ₹ 50976.

Hence, the total amount paid by consumer = ₹ 50976.

Question 6

Rohit purchased an article and paid GST of ₹ 10,400. He sold the article to Manish and collected GST of ₹ 11,000. Geeta purchased the same article from Manish and paid GST of ₹ 11,800. Find the amount of SGST and CGST payable at each stage if each transaction is intra state.

Answer

For Rohit,

Input tax = ₹ 10400

Output tax = ₹ 11000

GST paid by Rohit = Output tax - Input tax = ₹ 11000 - ₹ 10400 = ₹ 600.

We know that,

CGST = SGST = GST2\dfrac{\text{GST}}{2} = 6002\dfrac{600}{2} = ₹ 300.

For Manish,

Input tax = ₹ 11000

Output tax = ₹ 11800

GST paid by Manish = Output tax - Input tax = ₹ 11800 - ₹ 11000 = ₹ 800.

We know that,

CGST = SGST = GST2\dfrac{\text{GST}}{2} = 8002\dfrac{800}{2} = ₹ 400.

Hence, the amount of SGST and CGST payable at each stage is ₹ 300 and ₹ 400.

Question 7

A retailer buys a T.V. from a manufacturer for ₹ 25000. He marks the price of the T.V. 20% above his cost price and sells it to a consumer at 10% discount on the, marked price. If the sales are inter-state and rate of GST is 12%, find :

(i) the marked price of the TV.

(ii) consumer's cost price of TV inclusive of tax under GST.

(iii) GST paid by the retailer to the Central and State Governments.

Answer

(i) Given,

Retailer marks the price of the T.V. 20% above his cost price

∴ M.P. = ₹ 25000 + 20% of ₹ 25000

= ₹ 25000 + 20100×25000\dfrac{20}{100} \times 25000

= ₹ 25000 + ₹ 5000 = ₹ 30000.

Hence, the marked price of the TV = ₹ 30000.

(ii) M.P. = ₹ 30000

Discount = 10%

C.P. (without tax) = ₹ 30000 - 10% of ₹ 30000

= ₹ 30000 - ₹ 3000 = ₹ 27000.

GST paid by consumer = 12% of ₹ 27000 = 12100×27000\dfrac{12}{100} \times 27000 = ₹ 3240

∴ Consumer's cost price of TV inclusive of tax = ₹ 27000 + ₹ 3240 = ₹ 30240.

Hence, consumer's cost price of TV inclusive of tax under GST = ₹ 30240.

(iii) For retailer :

Input tax = 12% of ₹ 25000 = 12100×25000\dfrac{12}{100} \times 25000 = ₹ 3000

Output tax = 12% of ₹ 27000 = 12100×27000\dfrac{12}{100} \times 27000 = ₹ 3240

GST paid by retailer = Output tax - Input tax = ₹ 3240 - ₹ 3000 = ₹ 240.

Hence, GST paid by the retailer to the Central Government = ₹ 240 and state government = ₹ 0.

Question 8

A dealer buys an article at a discount of 30% from the wholesaler, the marked price being ₹ 6,000. The dealer sells it to a consumer at a discount of 10% on the marked price. If the sales are intra-state and rate of GST is 5%, find :

(i) the total amount paid by the consumer for the article.

(ii) the tax under GST paid by the dealer to the state government.

(iii) the amount of tax under GST received by the central government.

Answer

(i) For consumer,

M.P. = ₹ 6000

Discount = 10%

C.P. = M.P. - 10% of M.P. = ₹ 6000 - 10% of ₹ 6000 = ₹ 6000 - ₹ 10100×6000\dfrac{10}{100} \times 6000 = ₹ 6000 - ₹ 600 = ₹ 5400.

GST paid by consumer = 5% of ₹ 5400 = 5100×5400\dfrac{5}{100} \times 5400 = ₹ 270.

Amount = ₹ 5400 + ₹ 270 = ₹ 5670.

Hence, the total amount paid by consumer for the article = ₹ 5670.

(ii) For dealer :

M.P. = ₹ 6000

Discount = 30%

C.P. = M.P. - 30% of M.P. = ₹ 6000 - 30% of ₹ 6000 = ₹ 6000 - 30100×6000\dfrac{30}{100} \times ₹ 6000 = ₹ 6000 - ₹ 1800 = ₹ 4200.

Input tax = 5% of ₹ 4200 = 5100×4200\dfrac{5}{100} \times 4200 = ₹ 210.

Output tax = GST paid by consumer = ₹ 270

Tax paid by dealer = Output tax - Input tax = ₹ 270 - ₹ 210 = ₹ 60.

SGST = GST2\dfrac{\text{GST}}{2} = 602\dfrac{60}{2} = ₹ 30

Hence, tax paid by dealer to state government = ₹ 30.

(iii) GST received by government = GST paid by consumer = ₹ 270.

CGST = GST2\dfrac{\text{GST}}{2} = 2702\dfrac{270}{2} = ₹ 135.

Hence, amount of tax received by central government = ₹ 135.

Question 9

A shopkeeper in Punjab buys an article at a printed price of ₹ 20,000 from a wholesaler in Delhi. The shopkeeper sells the article to a customer in Punjab at a profit of 25% on the cost price. If the rate of GST is 18%, find :

(i) the price of the article (inclusive of GST) for the shopkeeper.

(ii) the amount of tax under GST received, paid by the shopkeeper to the government.

Answer

(i) M.P. = ₹ 20000

For shopkeeper,

Cost price = ₹ 20000

GST = 18% of ₹ 20000 = 18100×20000\dfrac{18}{100} \times 20000 = ₹ 3600.

Price of article = ₹ 20000 + ₹ 3600 = ₹ 23600.

Hence, the price of the article (inclusive of GST) for the shopkeeper is ₹ 23600.

(ii) For consumer,

Cost price = ₹ 20000 + 25% of ₹ 20000

= ₹ 20000 + 25100×20000\dfrac{25}{100} \times 20000

= ₹ 20000 + ₹ 5000

= ₹ 25000.

GST paid by consumer = 18% of ₹ 25000

= 18100×25000\dfrac{18}{100} \times 25000

= ₹ 4500.

Output tax for shopkeeper = Tax paid by consumer = ₹ 4500.

Input tax for shopkeeper = ₹ 3600.

∴ Tax paid by shopkeeper to government = Output tax - Input tax = ₹ 4500 - ₹ 3600 = ₹ 900.

Hence, the amount of tax under GST paid by shopkeeper to government = ₹ 900.

Question 10

A shopkeeper bought an A.C. from a distributor at a discount of 25% on the list price of ₹ 64,000. The shopkeeper sells the A.C. to a consumer at the list price. If the sales are intra-state and the rate of GST is 18%, then find :

(i) the S.P. of the A.C., including GST by the distributor.

(ii) the tax paid by the distributor to the State government.

(iii) the tax under GST paid by the shopkeeper to the Central government.

(iv) the tax under GST received by the state government.

(v) The price including tax under GST of the A.C. paid by the customer.

Answer

M.P. of A.C. = ₹ 64000

(i) For distributor

S.P. of A.C. (without GST) = ₹ 64000 - ₹ 25% of ₹ 64000 = ₹ 64000 - 25100×64000\dfrac{25}{100} \times 64000 = ₹ 64000 - ₹ 16000 = ₹ 48000.

GST = 18% of ₹ 48000 = 18100×48000\dfrac{18}{100} \times 48000 = ₹ 8640.

S.P. (with GST) = ₹ 48000 + ₹ 8640 = ₹ 56640.

Hence, the S.P. = ₹ 56640.

(ii) GST paid by distributor = ₹ 8640.

Tax paid by distributor to State government = 86402\dfrac{8640}{2} = ₹ 4320.

Hence, the tax paid by distributor to State government = ₹ 4320.

(iii) For shopkeeper :

C.P. = S.P. for distributor = ₹ 48000

Input tax = 18% of ₹ 48000 = 18100×48000\dfrac{18}{100} \times 48000 = ₹ 8640.

Output tax = Tax paid by consumer

C.P. for consumer = ₹ 64000

GST paid by consumer = 18% of ₹ 64000 = 18100×64000\dfrac{18}{100} \times 64000 = ₹ 11520.

Output tax = ₹ 11520.

Tax paid by shopkeeper under GST to government = Output tax - Input tax = ₹ 11520 - ₹ 8640 = ₹ 2880

CGST = GST2\dfrac{\text{GST}}{2} = 28802\dfrac{2880}{2} = ₹ 1440.

Hence, the tax under GST paid by the shopkeeper to the Central government = ₹ 1440.

(iv) Tax received by state government = SGST paid by consumer

= GST paid by consumer2\dfrac{\text{GST paid by consumer}}{2}

= 115202\dfrac{11520}{2} = ₹ 5760.

Hence, the tax received by State government = ₹ 5760.

(v) The price including tax under GST of the A.C. paid by the customer

= C.P. for customer + GST paid by consumer

= ₹ 64000 + 18% of ₹ 64000

= ₹ 64000 + ₹ 11520

= ₹ 75520.

Hence, the price including tax under GST of the A.C. paid by the customer = ₹ 75520.

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