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Chapter 1

Goods & Services Tax — Exercise 1(A)

Class - 10 Concise Mathematics Selina



Exercise 1(A)

Question 1(a)

The marked price of an article is ₹ 1500 and discount on it is 20%. How much money will be paid for this article, if rate of GST is 18% ?

  1. ₹ 2124

  2. ₹ 1416

  3. ₹ 1770

  4. ₹ 216

Answer

Given,

M.P. = ₹ 1500

Discount = 20%

Rate of G.S.T. = 18%

Discounted price = M.P. - Discount

= 1500 - 20100×1500\dfrac{20}{100} \times 1500

= 1500 - 300

= ₹ 1200.

G.S.T. on discounted price

= G.S.T.100\dfrac{G.S.T.}{100} % ×Discounted price=18100×1200\times \text{Discounted price} = \dfrac{18}{100} \times 1200 = ₹ 216.

Money paid for article = Discounted price + G.S.T.

= ₹ 1200 + ₹ 216 = ₹ 1416.

Hence, Option 2 is the correct option.

Question 1(b)

The following bill shows the GST rates and the marked price of articles A and B.

ArticlesMarked priceRate of GST
A₹ 10005%
B₹ 200012%

The total amount to be paid for the above bill is :

  1. ₹ 490

  2. ₹ 290

  3. ₹ 3290

  4. ₹ 3510

Answer

For article A :

M.P. = ₹ 1000

Rate of G.S.T. = 5%

G.S.T. = G.S.T.100\dfrac{G.S.T.}{100} % ×M.P.=5100×1000\times M.P. = \dfrac{5}{100} \times 1000 = ₹ 50.

Amount = M.P. + G.S.T. = ₹ 1000 + ₹ 50 = ₹ 1050.

For article B :

M.P. = ₹ 2000

Rate of G.S.T. = 12%

G.S.T. = G.S.T.100\dfrac{G.S.T.}{100} % ×M.P.=12100×2000\times M.P. = \dfrac{12}{100} \times 2000 = ₹ 240.

Amount = M.P. + G.S.T. = ₹ 2000 + ₹ 240 = ₹ 2240.

Total bill for article A and B = ₹ 1050 + ₹ 2240 = ₹ 3290.

Hence, Option 3 is the correct option.

Question 1(c)

The GST of an article is reduced from 12% to 5% and due to this, the price paid for the article is cut down by ₹ 14. The original price of the article is:

  1. ₹ 50

  2. ₹ 98

  3. ₹ 100

  4. ₹ 200

Answer

Let the original price of the article (excluding GST) be x.

The price paid when the GST is 12% = x + 12% of x

= x + 12x100\dfrac{12x}{100}

= x + 0.12x

= 1.12x

The price paid when the GST is 5% = x + 5% of x

= x + 5x100\dfrac{5x}{100}

= x + 0.05x

= 1.05x

Given,

The difference in the price paid is ₹ 14.

1.12x - 1.05x = 14

0.07x = 14

x = 140.07\dfrac{14}{0.07}

x = 200.

The original price of the article is ₹ 200.

Hence, Option 4 is the correct option.

Question 1(d)

A dealer in Rajasthan supplies goods and services to a dealer in Punjab. If the rate of G.S.T. is 28%. then the rate of SGST is :

  1. 28%

  2. 14%

  3. 0%

  4. none of these

Answer

The transaction from Rajasthan to Punjab is an inter-state transaction.

In inter-state transaction :

SGST = Nil = 0%.

Hence, Option 3 is the correct option.

Question 1(e)

In case of inter-state sales of goods or services, if GST rate is 18%, then :

  1. IGST = 9%

  2. SGST = 9%

  3. CGST = 9%

  4. IGST = 18%

Answer

In case of inter-state sales of goods or services, if GST rate is 18%, then :

SGST = 0%

CGST = 0%

IGST = 18%

Hence, Option 4 is the correct option.

Question 1(f)

The marked price of an article is ₹ 1,375. If the CGST is charged at rate of 4%, then the price of the article including GST is :

  1. ₹ 55

  2. ₹ 110

  3. ₹ 1,430

  4. ₹ 1,485

Answer

Given,

Marked price of an article = ₹ 1,375

CGST Rate: 4%

CGST = 4% of 1,375

= 4100×1375\dfrac{4}{100} \times 1375

= ₹ 55

SGST = 4% of 1,375

= 4100×1375\dfrac{4}{100} \times 1375

= ₹ 55

Total GST of article = CGST + SGST = ₹ 55 + ₹ 55 = ₹ 110.

Total Price including GST of an article = Marked price + GST

= ₹ 1,375 + ₹ 110 = ₹ 1,485.

Hence, Option 4 is the correct option.

Question 1(g)

The marked price of an article is ₹ 2,000. The G.S.T. on the article is 12% and discount is ₹ 500, the total amount to be paid is :

  1. ₹ 2800

  2. ₹ 1680

  3. ₹ 1370

  4. ₹ 1740

Answer

Given,

M.P. = ₹ 2000

Discount = ₹ 500

Rate of G.S.T. = 12%

Discounted price = M.P. - Discount

= ₹ 2000 - ₹ 500

= ₹ 1500.

G.S.T. on discounted price

= G.S.T.100\dfrac{G.S.T.}{100} % ×Discounted price=12100×1500\times \text{Discounted price} = \dfrac{12}{100} \times 1500 = ₹ 180.

Money paid for article = Discounted price + G.S.T.

= ₹ 1500 + ₹ 180 = ₹ 1680.

Hence, Option 2 is the correct option.

Question 2

For the following transaction within Delhi, fill in the blanks to find the amount of bill :

MRP = ₹12,000

Discount = 30%

GST% = 18%

Discount = ...............

Discounted value = ...............

CGST = ...............

SGST = ...............

IGST = ...............

Amount of bill = ...............

Answer

Given,

M.R.P. = ₹12,000

Discount = 30%

∴ Discount = 30100×12000\dfrac{30}{100} \times ₹12000 = ₹ 3600.

Discounted value = ₹ 12000 - ₹ 3600 = ₹ 8400.

Given, GST% = 18%, so

CGST = 9% and SGST = 9%.

Since, transactions are within a particular state i.e., Delhi so, IGST = Nil.

∴ CGST = 9100×8400\dfrac{9}{100} \times ₹ 8400 = ₹ 756.

∴ SGST = 9100×8400\dfrac{9}{100} \times ₹ 8400 = ₹ 756.

Amount of bill = Discounted price + CGST + SGST = ₹ 8400 + ₹ 756 + ₹ 756 = ₹ 9912.

Hence, Discount = ₹ 3600, Discounted value = ₹ 8400, CGST = ₹ 756 and SGST = ₹ 756, IGST = ₹ 0, Amount of bill = ₹ 9912.

Question 3

For the following transaction from Delhi to Jaipur, fill in the blanks to find the amount of bill :

MRP = ₹ 50,000

Discount = 20%

GST = 28%

Discount = ...............

Discounted value = ...............

CGST = ...............

SGST = ...............

IGST = ...............

Amount of bill = ...............

Answer

Given,

M.R.P. = ₹50,000

Discount = 20%

∴ Discount = 20100×50000\dfrac{20}{100} \times ₹50000 = ₹ 10000.

Discounted value = ₹ 50000 - ₹ 10000 = ₹ 40000.

Since transactions are inter state hence,

CGST = Nil and SGST = Nil.

IGST = 28%.

∴ IGST = 28100×40000\dfrac{28}{100} \times ₹ 40000 = ₹ 11200.

Amount of bill = Discounted price + IGST = ₹ 40000 + ₹ 11200 = ₹ 51200.

Hence, Discount = ₹ 10000, Discounted value = ₹ 40000, CGST = SGST = ₹ 0, IGST = ₹ 11200, Amount of bill = ₹ 51200.

Question 4

Find the amount of bill for the following intra-state transaction of goods/services.

MRP (in ₹)1200015000950018000
Discount%30203040
CGST%69142.5

Answer

Discount value % = 100 % - Discount %

CGST = SGST.

Construct the table as under :

MRP of each item (in ₹)Discount%Discounted valueCGST%CGST (in ₹)SGST (in ₹)Total value (Discounted Value + CGST + SGST)
120003070100×12000\dfrac{70}{100} \times 12000 = 840066100×8400\dfrac{6}{100} \times 8400 = 5045049408
150002080100×15000\dfrac{80}{100} \times 15000 = 1200099100×12000\dfrac{9}{100} \times 12000 = 1080108014160
95003070100×9500\dfrac{70}{100} \times 9500 = 66501414100×6650\dfrac{14}{100} \times 6650 = 9319318512
180004060100×18000\dfrac{60}{100} \times 18000 = 108002.52.5100×10800\dfrac{2.5}{100} \times 10800 = 27027011340
Total43420

Hence, the total amount = ₹ 43420.

Question 5

For the data given above in question no. 4, find the amount of bill for the inter-state transaction.

Answer

Discount value % = 100 % - Discount %

IGST = 2CGST%

Construct the table as under :

MRP of each item (in ₹)Discount%Discounted valueIGST(%)IGST (in ₹)Total value (Discounted Value + IGST)
120003070100×12000\dfrac{70}{100} \times 12000 = 84002 × 6% = 12%12100×8400\dfrac{12}{100} \times 8400 = 10089408
150002080100×15000\dfrac{80}{100} \times 15000 = 120002 × 9% = 18%18100×12000\dfrac{18}{100} \times 12000 = 216014160
95003070100×9500\dfrac{70}{100} \times 9500 = 66502 × 14% = 28%28100×6650\dfrac{28}{100} \times 6650 = 18628512
180004060100×18000\dfrac{60}{100} \times 18000 = 108002 × 2.5% = 5%5100×10800\dfrac{5}{100} \times 10800 = 54011340
Total43420

Hence, the total amount = ₹ 43420.

Question 6

A dealer in Mumbai supplied some identical items at the following prices to a dealer in Delhi. Find the total amount of bill.

Rate per item (in ₹)Quantity (no. of items)Discount %SGST %
180109
26020209
310309
17520309

Answer

Discounted% = 100% - Discount%.

IGST% = 2SGST%

Quantity (No.of items)Rate per item (in ₹)Total valueDiscount%Discounted valueIGST%IGST (in ₹)Total value (Discounted Value + IGST)
10180180018001818100×1800\dfrac{18}{100} \times 1800 = 3242124
2026052002080100×5200\dfrac{80}{100} \times 5200 = 41601818100×4160\dfrac{18}{100} \times 4160 = 748.804908.80
30310930093001818100×9300\dfrac{18}{100} \times 9300 = 167410974
2017535003070100×3500=2450\dfrac{70}{100} \times 3500 = 24501818100×2450\dfrac{18}{100} \times 2450 = 4412891
Total20897.80

Hence, the amount of bill = ₹ 20897.80

Question 7

M/s Unique traders, Delhi, provided the following services to M/s Geeta Trading Company in Agra (U.P.). Find the amount of bill :

Number of services8121016
Cost of each service (in ₹)680320260420
GST%5121812

Answer

Construct the table as under :

Number of servicesCost of each service (in ₹)Total value of serviceIGST%IGST (in ₹)Total (total value of service + IGST)
8680544055100×5440\dfrac{5}{100} \times 5440 = 2725712
1232038401212100×3840\dfrac{12}{100} \times 3840 = 460.804300.80
1026026001818100×2600\dfrac{18}{100} \times 2600 = 4683068
1642067201212100×6720\dfrac{12}{100} \times 6720 = 806.407526.40
Total20607.20

Hence, the amount of bill = ₹ 20607.20

Question 8

Find the total amount of the following :

Note : 20% discount is allowed on an article if 80 or more such articles are purchased.

ArticlesM.P.(₹)QuantityGST
A1801205%
B1205012%

Answer

For article A,

Given, M.P. = ₹ 180

Quantity purchased = 120

Quantity 120 > 80, 20% discount is allowed

Discount on each article = 20100×180\dfrac{20}{100} \times 180 = ₹ 36

Selling price = ₹ 180 - ₹ 36 = ₹ 144

Total value = ₹ 144 × 120 = ₹ 17,280

GST = 5% of ₹ 17,280

= 5100×17,280=864\dfrac{5}{100} \times 17,280 = ₹ 864.

Total amount = Total value + GST

= ₹ 17,280 + ₹ 864 = ₹ 18,144.

For article B,

Given, M.P. = ₹ 120

Quantity purchased = 50

Quantity 50 < 80, No discount allowed.

Total value = ₹ 120 × 50 = ₹ 6,000

GST = 12% of ₹ 6,000

= 12100×6,000=720\dfrac{12}{100} \times 6,000 = ₹ 720.

Total amount = Total value + GST

= ₹ 6,000 + ₹ 720 = ₹ 6,720.

Final bill = ₹ 18,144 + ₹ 6,720 = ₹ 24,864

Hence, the amount of bill = ₹ 24,864.

Question 9

The tax invoice of a telecom service in Surat shows cost of services provided by it as ₹ 750. If the GST rate is 18%, find the amount of the bill.

Answer

Cost of services = ₹ 750,

GST = 18%,

GST = 18100×750\dfrac{18}{100} \times 750 = ₹ 135.

Amount = ₹ 750 + ₹ 135 = ₹ 885.

Hence, the amount of bill = ₹ 885.

Question 10

Ms. Pratima took Health Insurance Policy for her family and paid ₹ 900 as SGST. Find the total annual premium, including GST, paid by her for this policy. The rate of GST being 18%.

Answer

Given, GST = 18%,

∴ SGST = 9%.

Let annual premium be ₹ x.

Given, SGST = ₹ 900.

900=9100×xx=900×1009x=10000.\therefore 900 = \dfrac{9}{100} \times x \\[1em] \Rightarrow x = \dfrac{900 \times 100}{9} \\[1em] \Rightarrow x = 10000.

We know that, CGST = SGST.

∴ Amount = Premium + CGST + SGST = ₹ 10000 + ₹ 900 + ₹ 900 = ₹ 11800.

Hence, the annual premium including GST = ₹ 11800.

Question 11

Mr. Malik went on a tour of Goa. He took a room in a hotel for two days at the rate of ₹ 5000 per day. On the same day, his friend John also joined him. The hotel provided an extra bed charging ₹ 1000 per day for the bed. How much GST, at the rate of 28% is charged by the hotel in the bill to Mr. Malik, for both the days?

Answer

Total charge of room for one day = ₹ 5000 + ₹ 1000 = ₹ 6000.

Charge for 2 days = 2 × 6000 = ₹ 12000.

GST = 28%,

∴ GST = 28100×12000\dfrac{28}{100} \times 12000 = ₹ 3360.

Hence, the amount of GST charged in the bill = ₹ 3360.

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