KnowledgeBoat Logo
|
OPEN IN APP

Chapter 5

Quadratic Equations — Assertion-Reason Type Questions

Class - 10 ML Aggarwal Understanding ICSE Mathematics



Assertion-Reason Type Questions

Question 1

Assertion (A): Every quadratic equation ax2 + bx + c = 0, a ≠ 0, a, b and c are all real numbers has two real roots.

Reason (R): Every quadratic equation ax2 + bx + c = 0, a ≠ 0, a, b and c are all real numbers has two real roots if b2 - 4ac ≥ 0.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Answer

The quadratic equation: ax2 + bx + c = 0.

The expression b2 - 4ac is called the discriminant (D).

When,

  1. D > 0; two distinct real roots

  2. D = 0; real and equal roots

  3. D < 0; then roots are imaginary

thus, assertion (A) is false but reason(R) is true.

Hence, option 2 is the correct option.

Question 2

Assertion (A): The quadratic equation 4x2 + 12x + 15 = 0, has no real roots.

Reason (R): The quadratic equation ax2 + bx + c = 0, has real roots iff its 'discriminant' = b2 - 4ac ≥ 0.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Answer

For, the quadratic equation: ax2 + bx + c = 0. The equation has real roots if

b2 - 4ac ≥ 0

So, reason (R) is true.

Comparing equation 4x2 + 12x + 15 = 0, with ax2 + bx + c = 0, we get :

a = 4, b = 12, c = 15

D = b2 - 4ac

= 122 - 4 x 4 x 15

= 144 - 240 = -96.

Since, D < 0, so the equation has no real roots.

So, assertion (A) is true and reason (R) correctly explains assertion (A).

Thus, both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

Question 3

Assertion (A): The equation 9x2 + 6x - k = 0 has real roots if k ≥ -1.

Reason (R): The quadratic equation ax2 + bx + c = 0 has real roots if 'discriminant' = b2 - 4ac > 0.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Answer

We know that,

The quadratic equation ax2 + bx + c = 0 has real roots if 'discriminant' = b2 - 4ac ≥ 0.

So, reason (R) is false.

Given, 9x2 + 6x - k = 0

Comparing above equation with ax2 + bx + c = 0, we get :

a = 9, b = 6 and c = -k

If the equation has real roots, then D ≥ 0

⇒ b2 - 4ac ≥ 0

⇒ 62 - 4 x 9 x (-k) ≥ 0

⇒ 36 + 36k ≥ 0

⇒ 36k ≥ -36

⇒ k ≥ -3636\dfrac{36}{36}

⇒ k ≥ -1

So, assertion (A) is true.

Thus, Assertion (A) is true, but Reason (R) is false.

Hence, option 1 is the correct option.

Question 4

Consider the polynomial 2x2 - 3x + 5

Assertion (A): Factorisation of the above polynomial is not possible.

Reason (R): Discriminant 'b2 - 4ac' is negative.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Answer

Given,

Polynomial : 2x2 - 3x + 5

Discriminant (D) = b2 - 4ac

= (-3)2 - 4 x 2 x 5

= 9 - 40

= -31.

So, reason (R) is true.

Since the discriminant is negative, this quadratic has no real roots and cannot be factorized into linear factors with real coefficients.

So, assertion (A) is true and reason (R) correctly explains assertion (A).

Thus, both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

Question 5

Consider the following equation k2x2 - 2kx + 1 = 0

Assertion (A): This equation has real roots for all non-zero values of k.

Reason (R): The discriminant of this equation is zero.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Answer

Given,

Equation : k2x2 - 2kx + 1 = 0

Comparing above equation with ax2 + bx + c = 0, we get :

a = k2, b = -2k and c = 1

Discriminant (D) = b2 - 4ac

= (-2k)2 - 4 x k2 x 1

= 4k2 - 4k2

= 0.

So, reason (R) is true.

Since, D = 0 this means the equation has one repeated real root.

So, assertion (A) is true and reason (R) correctly explains assertion (A).

Thus, both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

PrevNext