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Chapter 5

Quadratic Equations — Assertion-Reason Type Questions

Class - 10 RS Aggarwal Mathematics Solutions



Assertion-Reason Type Questions

Question 1

Assertion (A): The discriminant of the quadratic equation x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0 is greater than zero.

Reason (R): If the discriminant of a quadratic equation is greater than zero, the quadratic equation has real and distinct roots.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0

Comparing x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0 with ax2 + bx + c = 0 we get,

a = 1, b = 222\sqrt{2} and c = 1.

We know that,

Discriminant (D) = b2 - 4ac = (22)2(2\sqrt{2})^2 - 4 × (1) × (1)

= 8 - 4 = 4; which is positive.

Since, D = 4 > 0, the discriminant is greater than zero.

So, Assertion (A) is true.

D > 0 Real and distinct roots

D = 0 Real and equal roots

D < 0 Imaginary roots

If Discriminant is grater than zero,

Real and distinct roots

So, Reason (R) is true.

Thus, Both A and R are true, but R is not the correct explanation of A.

Hence, option 2 is the correct option.

Question 2

Assertion (A): The quadratic equation 3kx2 - 4kx + 4 = 0 has equal roots, if k = 3.

Reason (R): For equal roots of a quadratic equation, we must have D = 0.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

⇒ 3kx2 - 4kx + 4 = 0

when k = 3

⇒ 3 × (3) × x2 - 4 × (3) × x + 4 = 0

⇒ 9x2 - 12x + 4 = 0

Comparing 9x2 - 12x + 4 = 0 with ax2 + bx + c = 0 we get,

a = 9, b = -12 and c = 4.

We know that,

Discriminant (D) = b2 - 4ac

= (-12)2 - 4 × (9) × (4)

= 144 - 144 = 0.

Therefore, the equation has rational and equal roots.

So, Assertion (A) is true.

The Discriminant is given by b2 - 4ac, if the discriminant of any quadratic equation is zero. Then it is said have equal and real roots.

So, Reason (R) is true.

Thus, both A and R are true and R is the correct explanation of A.

Hence, option 1 is the correct option.

Question 3

Assertion (A): The roots of the quadratic equation 3x2 + 7x + 8 = 0 are imaginary.

Reason (R): The discriminant of a quadratic equation is always positive.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

⇒ 3x2 + 7x + 8 = 0

Comparing 3x2 + 7x + 8 = 0 with ax2 + bx + c = 0 we get,

a = 3, b = 7 and c = 8.

We know that,

Discriminant (D) = b2 - 4ac

= (7)2 - 4 × (3) × (8)

= 49 - 96 = -47; which is negative.

Therefore, the equation has imaginary and unequal roots.

So, Assertion (A) is true.

The Discriminant of quadratic equation can be positive, negative or equal to zero.

So, Reason (R) is false.

A is true, R is false.

Hence, option 3 is the correct option.

Question 4

Assertion (A): The roots of the quadratic equation 8x2 + 2x - 3 = 0 are -12\dfrac{1}{2} and 34\dfrac{3}{4}.

Reason (R): The roots of the quadratic equation ax2 + bx + c = 0 are given by x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

⇒ 8x2 + 2x - 3 = 0

Comparing equation 8x2 + 2x - 3 = 0 with ax2 + bx + c = 0, we get :

a = 8, b = 2 and c = -3.

By formula,

x = b±b24ac2a\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Substituting values we get :

x=(2)±(2)24×(8)×(3)2×(8)=2±4+9616=2±10016=2±1016=2+1016 or 21016=816 or 1216=12 or 34.\Rightarrow x = \dfrac{-(2) \pm \sqrt{(2)^2 - 4 \times (8) \times (-3)}}{2 \times (8)} \\[1em] = \dfrac{-2 \pm \sqrt{4 + 96}}{16} \\[1em] = \dfrac{-2 \pm \sqrt{100}}{16} \\[1em] = \dfrac{-2 \pm 10}{16} \\[1em] = \dfrac{-2 + 10}{16} \text{ or } \dfrac{-2 - 10}{16} \\[1em] = \dfrac{8}{16} \text{ or } \dfrac{-12}{16} \\[1em] = \dfrac{1}{2} \text{ or } \dfrac{-3}{4}.

Thus, A is false, R is true.

Hence, option 4 is the correct option.

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