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Chapter 21

Volume & Surface Area of Solids — Assertion-Reason Type Questions

Class - 10 RS Aggarwal Mathematics Solutions



Assertion–Reason Type Questions

Question 1

Assertion (A) : Slant height of a cone of height 4 cm and radius 3 cm is (4 + 3) cm = 7 cm.

Reason (R) : Curved surface area of a cone of radius r and slant height l is πrl.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given, radius r = 3 cm and height h = 4 cm.

By formula, l2 = h2 + r2 = 42 + 32 = 16 + 9 = 25

⇒ l = 25\sqrt{25} = 5 cm.

So, the slant height is 5 cm, not (4 + 3) = 7 cm.

∴ Assertion (A) is false.

The curved surface area of a cone of radius r and slant height l is πrl.

∴ Reason (R) is true.

Hence, option 4 is the correct option.

Question 2

Assertion (A) : The maximum volume of a cone that can be carved out of a solid hemisphere of radius r is 13\dfrac{1}{3} πr3.

Reason (R) : For a cone of radius r and height h, slant height is given by h2+r2\sqrt{h^2 + r^2}.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

The cone of maximum volume that can be carved out of a solid hemisphere of radius r has the same base radius r and the same height r.

The maximum volume of a cone that can be carved out of a solid hemisphere of radius r. Volume And Surface Area of solid RSA Mathematics Solutions ICSE Class 10.

Volume of cone = 13\dfrac{1}{3} πr2h = 13\dfrac{1}{3} πr2 × r = 13\dfrac{1}{3} πr3.

∴ Assertion (A) is true.

For a cone of radius r and height h, slant height l = h2+r2\sqrt{h^2 + r^2}.

∴ Reason (R) is true.

Reason (R) is a correct statement, but it states the slant-height formula, which is not used to establish the maximum volume in the Assertion. So, R is not the correct explanation of A.

Hence, option 2 is the correct option.

Question 3

Assertion (A) : The total surface area of a right circular cone of slant height 13 cm and radius 5 cm is 90 π cm2.

Reason (R) : Curved surface area of a right circular cone is given by πr(l + r).

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given, radius r = 5 cm and slant height l = 13 cm.

Total surface area of cone = πr(l + r) = π × 5 × (13 + 5) = π × 5 × 18 = 90π cm2.

∴ Assertion (A) is true.

The expression πr(l + r) is the formula for the total surface area of a cone, whereas the curved surface area of a cone is πrl. So, Reason (R) wrongly calls πr(l + r) the curved surface area.

∴ Reason (R) is false.

Hence, option 3 is the correct option.

Question 4

Assertion (A) : Two solid spheres of radii 2 cm and 4 cm are melted and recast into a cone of radius 6 cm. The height of the cone so obtained will be 8 cm.

Reason (R) : When we convert one solid into another, the volume of the two solids remains the same.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Total volume of the two spheres = 43\dfrac{4}{3} π(2)3 + 43\dfrac{4}{3} π(4)3 = 43\dfrac{4}{3} π(8 + 64) = 43\dfrac{4}{3} π × 72 = 96π cm3.

Let the height of the cone be h cm. Radius of cone = 6 cm.

Volume of cone = 13\dfrac{1}{3} π(6)2h = 12πh.

On recasting, the volume remains the same.

⇒ 12πh = 96π ⇒ h = 8 cm.

∴ Assertion (A) is true.

When one solid is converted (melted and recast) into another, the volume remains unchanged, and this is exactly the principle used to find the height.

∴ Reason (R) is true and is the correct explanation of A.

Hence, option 1 is the correct option.

Question 5

A solid sphere is cut into two identical hemispheres.

Assertion (A): The total volume of two hemispheres is equal to the volume of the original sphere.

Reason (R): The total surface area of two hemispheres together is equal to the surface area of the original sphere.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

By formula,

Volume of sphere = 43πr3\dfrac{4}{3} \pi r^3

Given,

A solid sphere is cut into two identical hemispheres.

Volume of hemisphere = 23πr3\dfrac{2}{3} \pi r^3

Volume of two identical hemispheres = 2×23πr32 \times \dfrac{2}{3} \pi r^3

= 43πr3\dfrac{4}{3} \pi r^3

Thus, volume of a sphere = volume of two identical hemispheres.

So assertion (A) is true.

We know that,

Surface area of sphere = 4πr2

When a sphere is cut into two hemispheres, two new flat circular surfaces are created,

Surface area of a single hemisphere = Curved surface area + Area of its flat circular face

= 2πr2 + πr2

= 3πr2

Total surface area of two hemispheres = 2 × 3πr2 = 6πr2.

Thus, the surface area of the original sphere ≠ the total surface area of the two hemispheres.

So reason (R) is false.

(A) is true, (R) is false.

Hence, option 3 is the correct option.

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