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Chapter 12

Fundamental Concepts of Algebra — Exercise 12(D)

Class - 6 Concise Mathematics Selina



Exercise 12(D)

Question 1

Fill in the blanks:

(i) 6×36 \times 3 = ............... and 6x×3x6x \times 3x = ...............

(ii) 6×36 \times 3 = ............... and 6x2×3x36x^2 \times 3x^3 = ...............

(iii) 5×45 \times 4 = ............... and 5x×4y5x \times 4y = ...............

(iv) 4×74 \times 7 = ............... and 4ax×7x4ax \times 7x = ...............

(v) 6×26 \times 2 = ............... and 6xy×2xy6xy \times 2xy = ...............

(vi) 12×412 \times 4 = ............... and 12ax2×4ax12ax^2 \times 4ax = ...............

(vii) 1×81 \times 8 = ............... and a2xy2×8a3x2ya^2xy^2 \times 8a^3x^2y = ...............

(viii) 15×315 \times 3 = ............... and 15x×3x5y215x \times 3x^5y^2 = ...............

Answer

The product of the given monomials = (product of their numeral coefficients) × (product of their literals), and in multiplication the powers of like factors are added.

(i) 6×3=6 \times 3 = 18 and 6x×3x=(6×3)(x×x)=18x26x \times 3x = (6 \times 3)(x \times x) = \bm{18x^2}.

(ii) 6×3=6 \times 3 = 18 and 6x2×3x3=(6×3)(x2+3)=18x56x^2 \times 3x^3 = (6 \times 3)(x^{2+3}) = \bm{18x^5}.

(iii) 5×4=5 \times 4 = 20 and 5x×4y=(5×4)(x×y)=20xy5x \times 4y = (5 \times 4)(x \times y) = \bm{20xy}.

(iv) 4×7=4 \times 7 = 28 and 4ax×7x=(4×7)(a×x1+1)=28ax24ax \times 7x = (4 \times 7)(a \times x^{1+1}) = \bm{28ax^2}.

(v) 6×2=6 \times 2 = 12 and 6xy×2xy=(6×2)(x1+1×y1+1)=12x2y26xy \times 2xy = (6 \times 2)(x^{1+1} \times y^{1+1}) = \bm{12x^2y^2}.

(vi) 12×4=12 \times 4 = 48 and 12ax2×4ax=(12×4)(a1+1×x2+1)=48a2x312ax^2 \times 4ax = (12 \times 4)(a^{1+1} \times x^{2+1}) = \bm{48a^2x^3}.

(vii) 1×8=1 \times 8 = 8 and a2xy2×8a3x2y=(1×8)(a2+3×x1+2×y2+1)=8a5x3y3a^2xy^2 \times 8a^3x^2y = (1 \times 8)(a^{2+3} \times x^{1+2} \times y^{2+1}) = \bm{8a^5x^3y^3}.

(viii) 15×3=15 \times 3 = 45 and 15x×3x5y2=(15×3)(x1+5×y2)=45x6y215x \times 3x^5y^2 = (15 \times 3)(x^{1+5} \times y^2) = \bm{45x^6y^2}.

Question 2

Fill in the blanks:

(i) 4x×6x×24x \times 6x \times 2 = ...............

(ii) 3ab×6ax3ab \times 6ax = ...............

(iii) x×2x2×3x3x \times 2x^2 \times 3x^3 = ...............

(iv) 5×5a35 \times 5a^3 = ...............

(v) 6×6x2×6x2y26 \times 6x^2 \times 6x^2y^2 = ...............

(vi) 8x×3x−8x \times −3x = ...............

(vii) 5×3x×5x2−5 \times −3x \times 5x^2 = ...............

(viii) 8×4xy2×3x3y28 \times −4xy^2 \times 3x^3y^2 = ...............

(ix) 4x×5xy×3z−4x \times 5xy \times 3z = ...............

(x) 5x×2x2y×7y3×2x3y25x \times 2x^2y \times −7y^3 \times 2x^3y^2 = ...............

Answer

The product of the given monomials = (product of their numeral coefficients) × (product of their literals), and in multiplication the powers of like factors are added.

(i) 4x×6x×2=(4×6×2)(x1+1)=48x24x \times 6x \times 2 = (4 \times 6 \times 2)(x^{1+1}) = \bm{48x^2}.

(ii) 3ab×6ax=(3×6)(a1+1×b×x)=18a2bx3ab \times 6ax = (3 \times 6)(a^{1+1} \times b \times x) = \bm{18a^2bx}.

(iii) x×2x2×3x3=(1×2×3)(x1+2+3)=6x6x \times 2x^2 \times 3x^3 = (1 \times 2 \times 3)(x^{1+2+3}) = \bm{6x^6}.

(iv) 5×5a3=(5×5)a3=25a35 \times 5a^3 = (5 \times 5)a^3 = \bm{25a^3}.

(v) 6×6x2×6x2y2=(6×6×6)(x2+2×y2)=216x4y26 \times 6x^2 \times 6x^2y^2 = (6 \times 6 \times 6)(x^{2+2} \times y^2) = \bm{216x^4y^2}.

(vi) 8x×3x=(8×3)(x1+1)=24x2-8x \times -3x = (-8 \times -3)(x^{1+1}) = \bm{24x^2}.

(vii) 5×3x×5x2=(5×3×5)(x1+2)=75x3-5 \times -3x \times 5x^2 = (-5 \times -3 \times 5)(x^{1+2}) = \bm{75x^3}.

(viii) 8×4xy2×3x3y2=(8×4×3)(x1+3×y2+2)=96x4y48 \times -4xy^2 \times 3x^3y^2 = (8 \times -4 \times 3)(x^{1+3} \times y^{2+2}) = \bm{-96x^4y^4}.

(ix) 4x×5xy×3z=(4×5×3)(x1+1×y×z)=60x2yz-4x \times 5xy \times 3z = (-4 \times 5 \times 3)(x^{1+1} \times y \times z) = \bm{-60x^2yz}.

(x) 5x×2x2y×7y3×2x3y2=(5×2×7×2)(x1+2+3×y1+3+2)=140x6y65x \times 2x^2y \times -7y^3 \times 2x^3y^2 = (5 \times 2 \times -7 \times 2)(x^{1+2+3} \times y^{1+3+2}) = \bm{-140x^6y^6}.

Question 3(i)

Find the value of:

3x3×5x43x^3 \times 5x^4

Answer

Solving,

3x3×5x4(3×5)(x3+4)15x7\Rightarrow 3x^3 \times 5x^4 \\[1em] \Rightarrow (3 \times 5)(x^{3+4}) \\[1em] \Rightarrow 15x^7

Hence, 3x3×5x4=15x7\bm{3x^3 \times 5x^4 = 15x^7}.

Question 3(ii)

Find the value of:

5a2×7a75a^2 \times 7a^7

Answer

Solving,

5a2×7a7(5×7)(a2+7)35a9\Rightarrow 5a^2 \times 7a^7 \\[1em] \Rightarrow (5 \times 7)(a^{2+7}) \\[1em] \Rightarrow 35a^9

Hence, 5a2×7a7=35a9\bm{5a^2 \times 7a^7 = 35a^9}.

Question 3(iii)

Find the value of:

3abc×6ac33abc \times 6ac^3

Answer

Solving,

3abc×6ac3(3×6)(a1+1×b×c1+3)18a2bc4\Rightarrow 3abc \times 6ac^3 \\[1em] \Rightarrow (3 \times 6)(a^{1+1} \times b \times c^{1+3}) \\[1em] \Rightarrow 18a^2bc^4

Hence, 3abc×6ac3=18a2bc4\bm{3abc \times 6ac^3 = 18a^2bc^4}.

Question 3(iv)

Find the value of:

a2b2×5a3b4a^2b^2 \times 5a^3b^4

Answer

Solving,

a2b2×5a3b4(1×5)(a2+3×b2+4)5a5b6\Rightarrow a^2b^2 \times 5a^3b^4 \\[1em] \Rightarrow (1 \times 5)(a^{2+3} \times b^{2+4}) \\[1em] \Rightarrow 5a^5b^6

Hence, a2b2×5a3b4=5a5b6\bm{a^2b^2 \times 5a^3b^4 = 5a^5b^6}.

Question 3(v)

Find the value of:

2x2y3×5x3y42x^2y^3 \times 5x^3y^4

Answer

Solving,

2x2y3×5x3y4(2×5)(x2+3×y3+4)10x5y7\Rightarrow 2x^2y^3 \times 5x^3y^4 \\[1em] \Rightarrow (2 \times 5)(x^{2+3} \times y^{3+4}) \\[1em] \Rightarrow 10x^5y^7

Hence, 2x2y3×5x3y4=10x5y7\bm{2x^2y^3 \times 5x^3y^4 = 10x^5y^7}.

Question 3(vi)

Find the value of:

abc×bcdabc \times bcd

Answer

Solving,

abc×bcda×b1+1×c1+1×dab2c2d\Rightarrow abc \times bcd \\[1em] \Rightarrow a \times b^{1+1} \times c^{1+1} \times d \\[1em] \Rightarrow ab^2c^2d

Hence, abc×bcd=ab2c2d\bm{abc \times bcd = ab^2c^2d}.

Question 4(i)

Multiply:

a+ba + b by abab

Answer

Solving,

a+b×aba2b+ab2\begin{array}{rrrr} &a &+& b \\ \times & &&ab \\ \hline &a^2b &+& ab^2 \end{array}

Hence, (a+b)×ab=a2b+ab2\bm{(a + b) \times ab = a^2b + ab^2}.

Question 4(ii)

Multiply:

3ab4b3ab - 4b by 3ab3ab

Answer

Solving,

3ab4b×3ab9a2b212ab2\begin{array}{rrrr} &3ab &-& 4b \\ \times & &&3ab \\ \hline &9a^2b^2 &-& 12ab^2 \end{array}

Hence, (3ab4b)×3ab=9a2b212ab2\bm{(3ab - 4b) \times 3ab = 9a^2b^2 - 12ab^2}.

Question 4(iii)

Multiply:

2xy5by2xy - 5by by 4bx4bx

Answer

Solving,

2xy5by×4bx8bx2y20b2xy\begin{array}{rrrr} &2xy &-& 5by \\ \times & &&4bx \\ \hline &8bx^2y &-& 20b^2xy \end{array}

Hence, (2xy5by)×4bx=8bx2y20b2xy\bm{(2xy - 5by) \times 4bx = 8bx^2y - 20b^2xy}.

Question 4(iv)

Multiply:

4x+2y4x + 2y by 3xy3xy

Answer

Solving,

4x+2y×3xy12x2y+6xy2\begin{array}{rrrr} &4x &+& 2y \\ \times & &&3xy \\ \hline &12x^2y &+& 6xy^2 \end{array}

Hence, (4x+2y)×3xy=12x2y+6xy2\bm{(4x + 2y) \times 3xy = 12x^2y + 6xy^2}.

Question 4(v)

Multiply:

x2xx^2 - x by 2x2x

Answer

Solving,

x2x×2x2x32x2\begin{array}{rrrr} &x^2 &-& x \\ \times & &&2x \\ \hline &2x^3 &-& 2x^2 \end{array}

Hence, (x2x)×2x=2x32x2\bm{(x^2 - x) \times 2x = 2x^3 - 2x^2}.

Question 4(vi)

Multiply:

1+4x1 + 4x by xx

Answer

Solving,

1+4x×xx+4x2\begin{array}{rrrr} &1 &+& 4x \\ \times & &&x \\ \hline &x &+& 4x^2 \end{array}

Hence, (1+4x)×x=x+4x2\bm{(1 + 4x) \times x = x + 4x^2}.

Question 4(vii)

Multiply:

9xy2+3x2y9xy^2 + 3x^2y by 5xy5xy

Answer

Solving,

9xy2+3x2y×5xy45x2y3+15x3y2\begin{array}{rrrr} &9xy^2 &+& 3x^2y \\ \times & &&5xy \\ \hline &45x^2y^3 &+& 15x^3y^2 \end{array}

Hence, (9xy2+3x2y)×5xy=45x2y3+15x3y2\bm{(9xy^2 + 3x^2y) \times 5xy = 45x^2y^3 + 15x^3y^2}.

Question 4(viii)

Multiply:

6x5y6x - 5y by 3axy3axy

Answer

Solving,

6x5y×3axy18ax2y15axy2\begin{array}{rrrr} &6x &-& 5y \\ \times & &&3axy \\ \hline &18ax^2y &-& 15axy^2 \end{array}

Hence, (6x5y)×3axy=18ax2y15axy2\bm{(6x - 5y) \times 3axy = 18ax^2y - 15axy^2}.

Question 5(i)

Multiply:

x+yz-x + y - z and 2x-2x

Answer

Solving,

x+yz×2x2x22xy+2xz\begin{array}{rrrrrr} &-x &+& y &-& z \\ \times & &&&&-2x \\ \hline &2x^2 &-& 2xy &+& 2xz \end{array}

Hence, (x+yz)×(2x)=2x22xy+2xz\bm{(-x + y - z) \times (-2x) = 2x^2 - 2xy + 2xz}.

Question 5(ii)

Multiply:

xyyzxy - yz and x2yz2x^2yz^2

Answer

Solving,

xyyz×x2yz2x3y2z2x2y2z3\begin{array}{rrrr} &xy &-& yz \\ \times & &&x^2yz^2 \\ \hline &x^3y^2z^2 &-& x^2y^2z^3 \end{array}

Hence, (xyyz)×x2yz2=x3y2z2x2y2z3\bm{(xy - yz) \times x^2yz^2 = x^3y^2z^2 - x^2y^2z^3}.

Question 5(iii)

Multiply:

2xyz+3xy2xyz + 3xy and 2y2z-2y^2z

Answer

Solving,

2xyz+3xy×2y2z4xy3z26xy3z\begin{array}{rrrr} &2xyz &+& 3xy \\ \times & &&-2y^2z \\ \hline &-4xy^3z^2 &-& 6xy^3z \end{array}

Hence, (2xyz+3xy)×(2y2z)=4xy3z26xy3z\bm{(2xyz + 3xy) \times (-2y^2z) = -4xy^3z^2 - 6xy^3z}.

Question 5(iv)

Multiply:

3xy2+4x2y-3xy^2 + 4x^2y and xy-xy

Answer

Solving,

3xy2+4x2y×xy3x2y34x3y2\begin{array}{rrrr} &-3xy^2 &+& 4x^2y \\ \times & &&-xy \\ \hline &3x^2y^3 &-& 4x^3y^2 \end{array}

Hence, (3xy2+4x2y)×(xy)=3x2y34x3y2\bm{(-3xy^2 + 4x^2y) \times (-xy) = 3x^2y^3 - 4x^3y^2}.

Question 5(v)

Multiply:

4xy4xy and x2y3x2y2-x^2y - 3x^2y^2

Answer

Solving,

x2y3x2y2×4xy4x3y212x3y3\begin{array}{rrrr} &-x^2y &-& 3x^2y^2 \\ \times & &&4xy \\ \hline &-4x^3y^2 &-& 12x^3y^3 \end{array}

Hence, 4xy×(x2y3x2y2)=4x3y212x3y3\bm{4xy \times (-x^2y - 3x^2y^2) = -4x^3y^2 - 12x^3y^3}.

Question 6(i)

Multiply:

3a+4b5c3a + 4b - 5c and 3a3a

Answer

Solving,

3a+4b5c×3a9a2+12ab15ac\begin{array}{rrrrrr} &3a &+& 4b &-& 5c \\ \times & &&&&3a \\ \hline &9a^2 &+& 12ab &-& 15ac \end{array}

Hence, (3a+4b5c)×3a=9a2+12ab15ac\bm{(3a + 4b - 5c) \times 3a = 9a^2 + 12ab - 15ac}.

Question 6(ii)

Multiply:

5xy-5xy and xy26x2y-xy^2 - 6x^2y

Answer

Solving,

xy26x2y×5xy5x2y3+30x3y2\begin{array}{rrrr} &-xy^2 &-& 6x^2y \\ \times & &&-5xy \\ \hline &5x^2y^3 &+& 30x^3y^2 \end{array}

Hence, 5xy×(xy26x2y)=5x2y3+30x3y2\bm{-5xy \times (-xy^2 - 6x^2y) = 5x^2y^3 + 30x^3y^2}.

Question 7(i)

Multiply:

x+2x + 2 and x+10x + 10

Answer

Solving,

(x+2)(x+10)x2+10x+2x+20x2+12x+20.\Rightarrow (x + 2)(x + 10) \\[1em] \Rightarrow x^2 + 10x + 2x + 20 \\[1em] \Rightarrow x^2 + 12x + 20.

Hence, (x+2)(x+10)=x2+12x+20\bm{(x + 2)(x + 10) = x^2 + 12x + 20}.

Question 7(ii)

Multiply:

x+5x + 5 and x3x - 3

Answer

Solving,

(x+5)(x3)x23x+5x15x2+2x15.\Rightarrow (x + 5)(x - 3) \\[1em] \Rightarrow x^2 - 3x + 5x - 15 \\[1em] \Rightarrow x^2 + 2x - 15.

Hence, (x+5)(x3)=x2+2x15\bm{(x + 5)(x - 3) = x^2 + 2x - 15}.

Question 7(iii)

Multiply:

x5x - 5 and x+3x + 3

Answer

Solving,

(x5)(x+3)x2+3x5x15x22x15.\Rightarrow (x - 5)(x + 3) \\[1em] \Rightarrow x^2 + 3x - 5x - 15 \\[1em] \Rightarrow x^2 - 2x - 15.

Hence, (x5)(x+3)=x22x15\bm{(x - 5)(x + 3) = x^2 - 2x - 15}.

Question 7(iv)

Multiply:

x5x - 5 and x3x - 3

Answer

Solving,

(x5)(x3)x23x5x+15x28x+15.\Rightarrow (x - 5)(x - 3) \\[1em] \Rightarrow x^2 - 3x - 5x + 15 \\[1em] \Rightarrow x^2 - 8x + 15.

Hence, (x5)(x3)=x28x+15\bm{(x - 5)(x - 3) = x^2 - 8x + 15}.

Question 7(v)

Multiply:

2x+y2x + y and x+3yx + 3y

Answer

Solving,

(2x+y)(x+3y)2x2+6xy+xy+3y22x2+7xy+3y2.\Rightarrow (2x + y)(x + 3y) \\[1em] \Rightarrow 2x^2 + 6xy + xy + 3y^2 \\[1em] \Rightarrow 2x^2 + 7xy + 3y^2.

Hence, (2x+y)(x+3y)=2x2+7xy+3y2\bm{(2x + y)(x + 3y) = 2x^2 + 7xy + 3y^2}.

Question 7(vi)

Multiply:

3x5y3x - 5y and x+6yx + 6y

Answer

Solving,

(3x5y)(x+6y)3x2+18xy5xy30y23x2+13xy30y2.\Rightarrow (3x - 5y)(x + 6y) \\[1em] \Rightarrow 3x^2 + 18xy - 5xy - 30y^2 \\[1em] \Rightarrow 3x^2 + 13xy - 30y^2.

Hence, (3x5y)(x+6y)=3x2+13xy30y2\bm{(3x - 5y)(x + 6y) = 3x^2 + 13xy - 30y^2}.

Question 7(vii)

Multiply:

x+9yx + 9y and x5yx - 5y

Answer

Solving,

(x+9y)(x5y)x25xy+9xy45y2x2+4xy45y2.\Rightarrow (x + 9y)(x - 5y) \\[1em] \Rightarrow x^2 - 5xy + 9xy - 45y^2 \\[1em] \Rightarrow x^2 + 4xy - 45y^2.

Hence, (x+9y)(x5y)=x2+4xy45y2\bm{(x + 9y)(x - 5y) = x^2 + 4xy - 45y^2}.

Question 7(viii)

Multiply:

2x+5y2x + 5y and 2x+5y2x + 5y

Answer

Solving,

(2x+5y)(2x+5y)4x2+10xy+10xy+25y24x2+20xy+25y2.\Rightarrow (2x + 5y)(2x + 5y) \\[1em] \Rightarrow 4x^2 + 10xy + 10xy + 25y^2 \\[1em] \Rightarrow 4x^2 + 20xy + 25y^2.

Hence, (2x+5y)(2x+5y)=4x2+20xy+25y2\bm{(2x + 5y)(2x + 5y) = 4x^2 + 20xy + 25y^2}.

Question 8(i)

Multiply:

3abc3abc and 5a2b2c-5a^2b^2c

Answer

Solving,

3abc×5a2b2c15a3b3c2\begin{array}{rr} &3abc \\ \times &-5a^2b^2c \\ \hline &-15a^3b^3c^2 \end{array}

Hence, 3abc×(5a2b2c)=15a3b3c2\bm{3abc \times (-5a^2b^2c) = -15a^3b^3c^2}.

Question 8(ii)

Multiply:

xy+zx - y + z and 2x-2x

Answer

Solving,

xy+z×2x2x2+2xy2xz\begin{array}{rrrrrr} &x &-& y &+& z \\ \times & &&&&-2x \\ \hline &-2x^2 &+& 2xy &-& 2xz \end{array}

Hence, (xy+z)×(2x)=2x2+2xy2xz\bm{(x - y + z) \times (-2x) = -2x^2 + 2xy - 2xz}.

Question 8(iii)

Multiply:

2x3y5z2x - 3y - 5z and 2y-2y

Answer

Solving,

2x3y5z×2y4xy+6y2+10yz\begin{array}{rrrrrr} &2x &-& 3y &-& 5z \\ \times & &&&&-2y \\ \hline &-4xy &+& 6y^2 &+& 10yz \end{array}

Hence, (2x3y5z)×(2y)=4xy+6y2+10yz\bm{(2x - 3y - 5z) \times (-2y) = -4xy + 6y^2 + 10yz}.

Question 8(iv)

Multiply:

8xyz+10x2yz3-8xyz + 10x^2yz^3 and xyzxyz

Answer

Solving,

8xyz+10x2yz3×xyz8x2y2z2+10x3y2z4\begin{array}{rrrr} &-8xyz &+& 10x^2yz^3 \\ \times & &&xyz \\ \hline &-8x^2y^2z^2 &+& 10x^3y^2z^4 \end{array}

Hence, (8xyz+10x2yz3)×xyz=8x2y2z2+10x3y2z4\bm{(-8xyz + 10x^2yz^3) \times xyz = -8x^2y^2z^2 + 10x^3y^2z^4}.

Question 8(v)

Multiply:

xyzxyz and 13xy2z+15x2yz6xyz2-13xy^2z + 15x^2yz - 6xyz^2

Answer

Solving,

13xy2z+15x2yz6xyz2×xyz13x2y3z2+15x3y2z26x2y2z3\begin{array}{rrrrrr} &-13xy^2z &+& 15x^2yz &-& 6xyz^2 \\ \times & &&&&xyz \\ \hline &-13x^2y^3z^2 &+& 15x^3y^2z^2 &-& 6x^2y^2z^3 \end{array}

Hence, xyz×(13xy2z+15x2yz6xyz2)=13x2y3z2+15x3y2z26x2y2z3\bm{xyz \times (-13xy^2z + 15x^2yz - 6xyz^2) = -13x^2y^3z^2 + 15x^3y^2z^2 - 6x^2y^2z^3}.

Question 8(vi)

Multiply:

4abc5a2bc6ab2c4abc - 5a^2bc - 6ab^2c and 2abc2-2abc^2

Answer

Solving,

4abc5a2bc6ab2c×2abc28a2b2c3+10a3b2c3+12a2b3c3\begin{array}{rrrrrr} &4abc &-& 5a^2bc &-& 6ab^2c \\ \times & &&&&-2abc^2 \\ \hline &-8a^2b^2c^3 &+& 10a^3b^2c^3 &+& 12a^2b^3c^3 \end{array}

Hence, (4abc5a2bc6ab2c)×(2abc2)=8a2b2c3+10a3b2c3+12a2b3c3\bm{(4abc - 5a^2bc - 6ab^2c) \times (-2abc^2) = -8a^2b^2c^3 + 10a^3b^2c^3 + 12a^2b^3c^3}.

Question 9(i)

Find the product of:

xyabxy - ab and xy+abxy + ab

Answer

Solving,

(xyab)(xy+ab)xy×xy+xy×abab×xyab×abx2y2+abxyabxya2b2x2y2a2b2.\Rightarrow (xy - ab)(xy + ab) \\[1em] \Rightarrow xy \times xy + xy \times ab - ab \times xy - ab \times ab \\[1em] \Rightarrow x^2y^2 + abxy - abxy - a^2b^2 \\[1em] \Rightarrow x^2y^2 - a^2b^2.

Hence, (xyab)(xy+ab)=x2y2a2b2\bm{(xy - ab)(xy + ab) = x^2y^2 - a^2b^2}.

Question 9(ii)

Find the product of:

2abc3xy2abc - 3xy and 2abc+3xy2abc + 3xy

Answer

Solving,

(2abc3xy)(2abc+3xy)2abc×2abc+2abc×3xy3xy×2abc3xy×3xy4a2b2c2+6abcxy6abcxy9x2y24a2b2c29x2y2.\Rightarrow (2abc - 3xy)(2abc + 3xy) \\[1em] \Rightarrow 2abc \times 2abc + 2abc \times 3xy - 3xy \times 2abc - 3xy \times 3xy \\[1em] \Rightarrow 4a^2b^2c^2 + 6abcxy - 6abcxy - 9x^2y^2 \\[1em] \Rightarrow 4a^2b^2c^2 - 9x^2y^2.

Hence, (2abc3xy)(2abc+3xy)=4a2b2c29x2y2\bm{(2abc - 3xy)(2abc + 3xy) = 4a^2b^2c^2 - 9x^2y^2}.

Question 9(iii)

Find the product of:

a+bca + b - c and 2a3b2a - 3b

Answer

Solving,

(a+bc)(2a3b)a(2a3b)+b(2a3b)c(2a3b)2a23ab+2ab3b22ac+3bc2a2ab2ac3b2+3bc.\Rightarrow (a + b - c)(2a - 3b) \\[1em] \Rightarrow a(2a - 3b) + b(2a - 3b) - c(2a - 3b) \\[1em] \Rightarrow 2a^2 - 3ab + 2ab - 3b^2 - 2ac + 3bc \\[1em] \Rightarrow 2a^2 - ab - 2ac - 3b^2 + 3bc.

Hence, (a+bc)(2a3b)=2a2ab2ac3b2+3bc\bm{(a + b - c)(2a - 3b) = 2a^2 - ab - 2ac - 3b^2 + 3bc}.

Question 9(iv)

Find the product of:

5x6y7z5x - 6y - 7z and 2x+3y2x + 3y

Answer

Solving,

(5x6y7z)(2x+3y)5x(2x+3y)6y(2x+3y)7z(2x+3y)10x2+15xy12xy18y214xz21yz10x2+3xy14xz18y221yz.\Rightarrow (5x - 6y - 7z)(2x + 3y) \\[1em] \Rightarrow 5x(2x + 3y) - 6y(2x + 3y) - 7z(2x + 3y) \\[1em] \Rightarrow 10x^2 + 15xy - 12xy - 18y^2 - 14xz - 21yz \\[1em] \Rightarrow 10x^2 + 3xy - 14xz - 18y^2 - 21yz.

Hence, (5x6y7z)(2x+3y)=10x2+3xy14xz18y221yz\bm{(5x - 6y - 7z)(2x + 3y) = 10x^2 + 3xy - 14xz - 18y^2 - 21yz}.

Question 9(v)

Find the product of:

5x6y7z5x - 6y - 7z and 2x+3y+z2x + 3y + z

Answer

Solving,

(5x6y7z)(2x+3y+z)5x(2x+3y+z)6y(2x+3y+z)7z(2x+3y+z)10x2+15xy+5zx12xy18y26yz14zx21yz7z210x2+3xy9zx18y227yz7z2.\Rightarrow (5x - 6y - 7z)(2x + 3y + z) \\[1em] \Rightarrow 5x(2x + 3y + z) - 6y(2x + 3y + z) - 7z(2x + 3y + z) \\[1em] \Rightarrow 10x^2 + 15xy + 5zx - 12xy - 18y^2 - 6yz - 14zx - 21yz - 7z^2 \\[1em] \Rightarrow 10x^2 + 3xy - 9zx - 18y^2 - 27yz - 7z^2.

Hence, (5x6y7z)(2x+3y+z)=10x2+3xy9zx18y227yz7z2\bm{(5x - 6y - 7z)(2x + 3y + z) = 10x^2 + 3xy - 9zx - 18y^2 - 27yz - 7z^2}.

Question 9(vi)

Find the product of:

2a+3b4c2a + 3b - 4c and abca - b - c

Answer

Solving,

(2a+3b4c)(abc)2a(abc)+3b(abc)4c(abc)2a22ab2ac+3ab3b23bc4ac+4bc+4c22a2+ab6ac3b2+bc+4c2.\Rightarrow (2a + 3b - 4c)(a - b - c) \\[1em] \Rightarrow 2a(a - b - c) + 3b(a - b - c) - 4c(a - b - c) \\[1em] \Rightarrow 2a^2 - 2ab - 2ac + 3ab - 3b^2 - 3bc - 4ac + 4bc + 4c^2 \\[1em] \Rightarrow 2a^2 + ab - 6ac - 3b^2 + bc + 4c^2.

Hence, (2a+3b4c)(abc)=2a2+ab6ac3b2+bc+4c2\bm{(2a + 3b - 4c)(a - b - c) = 2a^2 + ab - 6ac - 3b^2 + bc + 4c^2}.

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