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Chapter 9

Ratio & Proportion — Statement I-II Type Questions

Class - 6 Concise Mathematics Selina



Statement I-II Type Questions

Question 11

Statement 1 : Two numbers AA and BB are in the ratio 3 : 5, then A=35×BA = \dfrac{3}{5} × B.

Statement 2 : A3=B5\dfrac{A}{3} = \dfrac{B}{5}

Which of the following options is correct?

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Answer

Given,

AA and BB are in the ratio 3 : 5.

AB=35\dfrac{A}{B} = \dfrac{3}{5}

A=35×B\Rightarrow A = \dfrac{3}{5} × B.

So, Statement 1 is true.

From A:BA : B = 3 : 5, we get AB=35\dfrac{A}{B} = \dfrac{3}{5}, which on cross multiplication gives 5A=3B5A = 3B, i.e. A3=B5\dfrac{A}{3} = \dfrac{B}{5}.

So, Statement 2 is true.

Hence, option 1 is the correct option.

Question 12

Statement 1 : If m:nm : n = 5 : 4, then 5m:4n5m : 4n = 25 : 16

Statement 2 : 5m:4n=5m4n=54×54=25:165m : 4n = \dfrac{5m}{4n} = \dfrac{5}{4} \times \dfrac{5}{4} = 25 : 16

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Answer

Given,

m:nm : n = 5 : 4, i.e. mn=54\dfrac{m}{n} = \dfrac{5}{4}.

Solving,

5m:4n=5m4n=54×mn=54×54=2516=25:16\Rightarrow 5m : 4n = \dfrac{5m}{4n} \\[1em] = \dfrac{5}{4} \times \dfrac{m}{n} \\[1em] = \dfrac{5}{4} \times \dfrac{5}{4} \\[1em] = \dfrac{25}{16} \\[1em] = 25 : 16

So, Statement 2 is true.

From the working above, 5m:4n5m : 4n = 25 : 16.

So, Statement 1 is true.

Hence, option 1 is the correct option.

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