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Chapter 12

Fundamental Concepts of Algebra — Assertion Reason Type Questions

Class - 6 Concise Mathematics Selina



Assertion Reason Type Questions

Question 12

Assertion (A): Since, 2 − 5 + 8 = 5

⇒2x−5y+8z=5xyz\Rightarrow 2x − 5y + 8z = 5xyz

Reason (R): Only the like terms can be added or subtracted together.

∴2x−5y+8z\therefore 2x − 5y + 8z can not be added to get the single term.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

In 2x−5y+8z2x - 5y + 8z, the terms 2x,−5y2x, -5y and 8z8z are unlike terms, so they cannot be combined into a single term. Thus, 2x−5y+8z≠5xyz2x - 5y + 8z \neq 5xyz and Assertion (A) is false.

As only like terms (terms having the same literal coefficients) can be added or subtracted to get a single term, and so 2x−5y+8z2x - 5y + 8z cannot be added to get a single term. So, Reason (R) is true.

Hence, option 2 is the correct option.

Question 13

Assertion (A): (5x2−7x)−(x2+x)+(−3x2+5x)(5x^2 − 7x) − (x^2 + x) + (−3x^2 + 5x) is equal to x2−3xx^2 − 3x.

Reason (R): Given expression

=5x2−7x−x2−x−3x2+5x= 5x^2 − 7x − x^2 − x − 3x^2 + 5x

=(5−1−3)x2+(−7−1+5)x= (5 − 1 − 3)x^2 + (−7 − 1 + 5)x

=x2−3x= x^2 − 3x

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

Solving,

⇒(5x2−7x)−(x2+x)+(−3x2+5x)⇒5x2−7x−x2−x−3x2+5x⇒(5−1−3)x2+(−7−1+5)x⇒x2−3x\Rightarrow (5x^2 - 7x) - (x^2 + x) + (-3x^2 + 5x) \\[1em] \Rightarrow 5x^2 - 7x - x^2 - x - 3x^2 + 5x \\[1em] \Rightarrow (5 - 1 - 3)x^2 + (-7 - 1 + 5)x \\[1em] \Rightarrow x^2 - 3x

So, Assertion (A) is true.

The steps shown in Reason (R) are correct, so Reason (R) is true.

Hence, option 3 is the correct option.

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