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Chapter 12

Fundamental Concepts of Algebra — Multiple Choice Questions

Class - 6 Concise Mathematics Selina



Multiple Choice Questions

Question 1

Coefficient of xx in xyz−xyz is:

  1. xyz−xyz

  2. yz−yz

  3. yzyz

  4. xy−xy

Answer

Any factor or group of factors of a product is the coefficient of the remaining factors.

xyz=(yz)×x-xyz = (-yz) \times x, so the coefficient of xx in xyz-xyz is yz-yz.

Hence, option 2 is the correct option.

Question 2

Numeral coefficient in 8x÷7z−8x \div 7z is:

  1. 56−56

  2. 78-\dfrac{7}{8}

  3. 87-\dfrac{8}{7}

  4. 15−15

Answer

If a factor of a product is a numerical quantity, it is called the numeral coefficient of the remaining factors.

Solving,

8x÷7z8x7z(87)×xz\Rightarrow -8x \div 7z \\[1em] \Rightarrow \dfrac{-8x}{7z} \\[1em] \Rightarrow \left(\dfrac{-8}{7}\right) \times \dfrac{x}{z}

So, the numeral coefficient is 87-\dfrac{8}{7}.

Hence, option 3 is the correct option.

Question 3

The degree of polynomial 8x+xy317xz8x + xy^3 − 17xz is:

  1. 3

  2. 1

  3. 2

  4. 4

Answer

The degree of a polynomial is the greatest of the exponents (powers) of its various terms.

Degrees of the terms are 1, (1 + 3) = 4 and (1 + 1) = 2. The greatest is 4.

Hence, option 4 is the correct option.

Question 4

Which term is not a monomial:

  1. x3yx^3y

  2. xyxy

  3. 5+y2x5 + y^2x

  4. 25yx325yx^3

Answer

An expression with only one term is a monomial. Each of x3y,xyx^3y, xy and 25yx325yx^3 has one term, whereas 5+y2x5 + y^2x has two terms, so it is a binomial and not a monomial.

Hence, option 3 is the correct option.

Question 5

The constant term in the algebraic expression 4(x2+1)+5(x+1)+54(x^2 + 1) + 5(x + 1) + 5 is:

  1. 5

  2. 14

  3. 9

  4. 10

Answer

Solving,

4(x2+1)+5(x+1)+54x2+4+5x+5+54x2+5x+14\Rightarrow 4(x^2 + 1) + 5(x + 1) + 5 \\[1em] \Rightarrow 4x^2 + 4 + 5x + 5 + 5 \\[1em] \Rightarrow 4x^2 + 5x + 14

The term which does not contain any variable is the constant term, i.e. 14.

Hence, option 2 is the correct option.

Question 6

The number of terms in the expression 5x+5÷x+x5x + 5 \div x + x is:

  1. 2

  2. 4

  3. 5

  4. 3

Answer

Solving,

5x+5÷x+x5x+5x+x(5+1)x+5x6x+5x\Rightarrow 5x + 5 \div x + x \\[1em] \Rightarrow 5x + \dfrac{5}{x} + x \\[1em] \Rightarrow (5 + 1)x + \dfrac{5}{x} \\[1em] \Rightarrow 6x + \dfrac{5}{x}

On adding the like terms 5x5x and xx, the expression has the two terms 6x6x and 5x\dfrac{5}{x}.

Hence, option 1 is the correct option.

Question 7

3x22x+5x2+73x^2 - \dfrac{2}{x} + \dfrac{5}{x^2} + 7 is a:

  1. monomial

  2. multinomial

  3. binomial

  4. trinomial

Answer

The given expression has the four terms 3x2,2x,5x23x^2, -\dfrac{2}{x}, \dfrac{5}{x^2} and 7. An expression with two or more than two terms is a multinomial.

Hence, option 2 is the correct option.

Question 8

4xy+6z(3x4y+5z)4x − y + 6z − (3x − 4y + 5z) is equal to:

  1. 7x5y+11z7x − 5y + 11z

  2. x+3y+11zx + 3y + 11z

  3. x+3y+zx + 3y + z

  4. x3y+zx − 3y + z

Answer

Solving,

4xy+6z(3x4y+5z)4xy+6z3x+4y5z(43)x+(1+4)y+(65)zx+3y+z\Rightarrow 4x - y + 6z - (3x - 4y + 5z) \\[1em] \Rightarrow 4x - y + 6z - 3x + 4y - 5z \\[1em] \Rightarrow (4 - 3)x + (-1 + 4)y + (6 - 5)z \\[1em] \Rightarrow x + 3y + z

Hence, option 3 is the correct option.

Question 9

(x+y)(y+z)+(z+x)(x + y) − (y + z) + (z + x) is equal to:

  1. 2x+yz2x + y − z

  2. 2xy+z2x − y + z

  3. 2x+y+z2x + y + z

  4. 2x2x

Answer

Solving,

(x+y)(y+z)+(z+x)x+yyz+z+x(1+1)x+(11)y+(1+1)z2x\Rightarrow (x + y) - (y + z) + (z + x) \\[1em] \Rightarrow x + y - y - z + z + x \\[1em] \Rightarrow (1 + 1)x + (1 - 1)y + (-1 + 1)z \\[1em] \Rightarrow 2x

Hence, option 4 is the correct option.

Question 10

(3x2y)×(50xy2)÷(25x2y2)(3x^2y) \times (50xy^2) \div (25x^2y^2) is equal to:

  1. 6xy26xy^2

  2. 6xy6xy

  3. 6x2y6x^2y

  4. none of these

Answer

Solving,

(3x2y)×(50xy2)÷(25x2y2)(3×50)(x2+1×y1+2)25x2y2150x3y325x2y26x32y326xy\Rightarrow (3x^2y) \times (50xy^2) \div (25x^2y^2) \\[1em] \Rightarrow \dfrac{(3 \times 50)(x^{2+1} \times y^{1+2})}{25x^2y^2} \\[1em] \Rightarrow \dfrac{150x^3y^3}{25x^2y^2} \\[1em] \Rightarrow 6x^{3-2}y^{3-2} \\[1em] \Rightarrow 6xy

Hence, option 2 is the correct option.

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