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Chapter 13

Framing Algebraic Expressions — Exercise 13(D)

Class - 6 Concise Mathematics Selina



Exercise 13(D)

Question 1(i)

Solve :

2x+5=172x + 5 = 17

Answer

Solving,

⇒2x+5=17⇒2x=17−5⇒2x=12⇒x=122⇒x=6.\Rightarrow 2x + 5 = 17 \\[1em] \Rightarrow 2x = 17 - 5 \\[1em] \Rightarrow 2x = 12 \\[1em] \Rightarrow x = \dfrac{12}{2} \\[1em] \Rightarrow x = 6.

Hence, x=6\bm{x} = 6.

Question 1(ii)

Solve :

3y−2=13y - 2 = 1

Answer

Solving,

⇒3y−2=1⇒3y=1+2⇒3y=3⇒y=33⇒y=1.\Rightarrow 3y - 2 = 1 \\[1em] \Rightarrow 3y = 1 + 2 \\[1em] \Rightarrow 3y = 3 \\[1em] \Rightarrow y = \dfrac{3}{3} \\[1em] \Rightarrow y = 1.

Hence, y=1\bm{y} = 1.

Question 1(iii)

Solve :

5p+4=295p + 4 = 29

Answer

Solving,

⇒5p+4=29⇒5p=29−4⇒5p=25⇒p=255⇒p=5.\Rightarrow 5p + 4 = 29 \\[1em] \Rightarrow 5p = 29 - 4 \\[1em] \Rightarrow 5p = 25 \\[1em] \Rightarrow p = \dfrac{25}{5} \\[1em] \Rightarrow p = 5.

Hence, p=5\bm{p} = 5.

Question 1(iv)

Solve :

4a−3=−274a - 3 = -27

Answer

Solving,

⇒4a−3=−27⇒4a=−27+3⇒4a=−24⇒a=−244⇒a=−6.\Rightarrow 4a - 3 = -27 \\[1em] \Rightarrow 4a = -27 + 3 \\[1em] \Rightarrow 4a = -24 \\[1em] \Rightarrow a = \dfrac{-24}{4} \\[1em] \Rightarrow a = -6.

Hence, a=−6\bm{a} = -6.

Question 1(v)

Solve :

2z+3=−192z + 3 = -19

Answer

Solving,

⇒2z+3=−19⇒2z=−19−3⇒2z=−22⇒z=−222⇒z=−11.\Rightarrow 2z + 3 = -19 \\[1em] \Rightarrow 2z = -19 - 3 \\[1em] \Rightarrow 2z = -22 \\[1em] \Rightarrow z = \dfrac{-22}{2} \\[1em] \Rightarrow z = -11.

Hence, z=−11\bm{z} = -11.

Question 1(vi)

Solve :

7m−1=207m - 1 = 20

Answer

Solving,

⇒7m−1=20⇒7m=20+1⇒7m=21⇒m=217⇒m=3.\Rightarrow 7m - 1 = 20 \\[1em] \Rightarrow 7m = 20 + 1 \\[1em] \Rightarrow 7m = 21 \\[1em] \Rightarrow m = \dfrac{21}{7} \\[1em] \Rightarrow m = 3.

Hence, m=3\bm{m} = 3.

Question 1(vii)

Solve :

2.4x−3=4.22.4x - 3 = 4.2

Answer

Solving,

⇒2.4x−3=4.2⇒2.4x=4.2+3⇒2.4x=7.2⇒x=7.22.4⇒x=3.\Rightarrow 2.4x - 3 = 4.2 \\[1em] \Rightarrow 2.4x = 4.2 + 3 \\[1em] \Rightarrow 2.4x = 7.2 \\[1em] \Rightarrow x = \dfrac{7.2}{2.4} \\[1em] \Rightarrow x = 3.

Hence, x=3\bm{x} = 3.

Question 1(viii)

Solve :

4m+9.4=54m + 9.4 = 5

Answer

Solving,

⇒4m+9.4=5⇒4m=5−9.4⇒4m=−4.4⇒m=−4.44⇒m=−1.1.\Rightarrow 4m + 9.4 = 5 \\[1em] \Rightarrow 4m = 5 - 9.4 \\[1em] \Rightarrow 4m = -4.4 \\[1em] \Rightarrow m = \dfrac{-4.4}{4} \\[1em] \Rightarrow m = -1.1.

Hence, m=−1.1\bm{m} = -1.1.

Question 1(ix)

Solve :

6y+4=−4.46y + 4 = -4.4

Answer

Solving,

⇒6y+4=−4.4⇒6y=−4.4−4⇒6y=−8.4⇒y=−8.46⇒y=−1.4.\Rightarrow 6y + 4 = -4.4 \\[1em] \Rightarrow 6y = -4.4 - 4 \\[1em] \Rightarrow 6y = -8.4 \\[1em] \Rightarrow y = \dfrac{-8.4}{6} \\[1em] \Rightarrow y = -1.4.

Hence, y=−1.4\bm{y} = -1.4.

Question 2(i)

Solve :

x3−5=2\dfrac{x}{3} - 5 = 2

Answer

Solving,

⇒x3−5=2⇒x3=2+5⇒x3=7⇒x=7×3⇒x=21.\Rightarrow \dfrac{x}{3} - 5 = 2 \\[1em] \Rightarrow \dfrac{x}{3} = 2 + 5 \\[1em] \Rightarrow \dfrac{x}{3} = 7 \\[1em] \Rightarrow x = 7 \times 3 \\[1em] \Rightarrow x = 21.

Hence, x=21\bm{x} = 21.

Question 2(ii)

Solve :

y2−3=8\dfrac{y}{2} - 3 = 8

Answer

Solving,

⇒y2−3=8⇒y2=8+3⇒y2=11⇒y=11×2⇒y=22.\Rightarrow \dfrac{y}{2} - 3 = 8 \\[1em] \Rightarrow \dfrac{y}{2} = 8 + 3 \\[1em] \Rightarrow \dfrac{y}{2} = 11 \\[1em] \Rightarrow y = 11 \times 2 \\[1em] \Rightarrow y = 22.

Hence, y=22\bm{y} = 22.

Question 2(iii)

Solve :

z7+1=212\dfrac{z}{7} + 1 = 2\dfrac{1}{2}

Answer

Solving,

⇒z7+1=212⇒z7+1=52⇒z7=52−1⇒z7=5−22⇒z7=32⇒z=32×7⇒z=212=1012.\Rightarrow \dfrac{z}{7} + 1 = 2\dfrac{1}{2} \\[1em] \Rightarrow \dfrac{z}{7} + 1 = \dfrac{5}{2} \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{5}{2} - 1 \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{5 - 2}{2} \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{3}{2} \\[1em] \Rightarrow z = \dfrac{3}{2} \times 7 \\[1em] \Rightarrow z = \dfrac{21}{2} = 10\dfrac{1}{2}.

Hence, z=1012\bm{z} = 10\dfrac{1}{2}.

Question 2(iv)

Solve :

a2.4−5=2.4\dfrac{a}{2.4} - 5 = 2.4

Answer

Solving,

⇒a2.4−5=2.4⇒a2.4=2.4+5⇒a2.4=7.4⇒a=7.4×2.4⇒a=17.76.\Rightarrow \dfrac{a}{2.4} - 5 = 2.4 \\[1em] \Rightarrow \dfrac{a}{2.4} = 2.4 + 5 \\[1em] \Rightarrow \dfrac{a}{2.4} = 7.4 \\[1em] \Rightarrow a = 7.4 \times 2.4 \\[1em] \Rightarrow a = 17.76.

Hence, a=17.76\bm{a} = 17.76.

Question 2(v)

Solve :

b1.6+3=−2.5\dfrac{b}{1.6} + 3 = -2.5

Answer

Solving,

⇒b1.6+3=−2.5⇒b1.6=−2.5−3⇒b1.6=−5.5⇒b=−5.5×1.6⇒b=−8.8.\Rightarrow \dfrac{b}{1.6} + 3 = -2.5 \\[1em] \Rightarrow \dfrac{b}{1.6} = -2.5 - 3 \\[1em] \Rightarrow \dfrac{b}{1.6} = -5.5 \\[1em] \Rightarrow b = -5.5 \times 1.6 \\[1em] \Rightarrow b = -8.8.

Hence, b=−8.8\bm{b} = -8.8.

Question 2(vi)

Solve :

m4−4.6=−3.1\dfrac{m}{4} - 4.6 = -3.1

Answer

Solving,

⇒m4−4.6=−3.1⇒m4=−3.1+4.6⇒m4=1.5⇒m=1.5×4⇒m=6.\Rightarrow \dfrac{m}{4} - 4.6 = -3.1 \\[1em] \Rightarrow \dfrac{m}{4} = -3.1 + 4.6 \\[1em] \Rightarrow \dfrac{m}{4} = 1.5 \\[1em] \Rightarrow m = 1.5 \times 4 \\[1em] \Rightarrow m = 6.

Hence, m=6\bm{m} = 6.

Question 3(i)

Solve :

−8m−2=−10-8m - 2 = -10

Answer

Solving,

⇒−8m−2=−10⇒−8m=−10+2⇒−8m=−8⇒m=−8−8⇒m=1.\Rightarrow -8m - 2 = -10 \\[1em] \Rightarrow -8m = -10 + 2 \\[1em] \Rightarrow -8m = -8 \\[1em] \Rightarrow m = \dfrac{-8}{-8} \\[1em] \Rightarrow m = 1.

Hence, m=1\bm{m} = 1.

Question 3(ii)

Solve :

4x+2x=3+54x + 2x = 3 + 5

Answer

Solving,

⇒4x+2x=3+5⇒6x=8⇒x=86⇒x=43=113.\Rightarrow 4x + 2x = 3 + 5 \\[1em] \Rightarrow 6x = 8 \\[1em] \Rightarrow x = \dfrac{8}{6} \\[1em] \Rightarrow x = \dfrac{4}{3} = 1\dfrac{1}{3}.

Hence, x=113\bm{x} = 1\dfrac{1}{3}.

Question 3(iii)

Solve :

4x−x+5=84x - x + 5 = 8

Answer

Solving,

⇒4x−x+5=8⇒3x+5=8⇒3x=8−5⇒3x=3⇒x=1.\Rightarrow 4x - x + 5 = 8 \\[1em] \Rightarrow 3x + 5 = 8 \\[1em] \Rightarrow 3x = 8 - 5 \\[1em] \Rightarrow 3x = 3 \\[1em] \Rightarrow x = 1.

Hence, x=1\bm{x} = 1.

Question 3(iv)

Solve :

6x+2=2x+106x + 2 = 2x + 10

Answer

Solving,

⇒6x+2=2x+10⇒6x−2x=10−2⇒4x=8⇒x=84⇒x=2.\Rightarrow 6x + 2 = 2x + 10 \\[1em] \Rightarrow 6x - 2x = 10 - 2 \\[1em] \Rightarrow 4x = 8 \\[1em] \Rightarrow x = \dfrac{8}{4} \\[1em] \Rightarrow x = 2.

Hence, x=2\bm{x} = 2.

Question 3(v)

Solve :

18−(2a−12)=8a18 - (2a - 12) = 8a

Answer

Solving,

⇒18−(2a−12)=8a⇒18−2a+12=8a⇒30−2a=8a⇒30=8a+2a⇒30=10a⇒a=3010⇒a=3.\Rightarrow 18 - (2a - 12) = 8a \\[1em] \Rightarrow 18 - 2a + 12 = 8a \\[1em] \Rightarrow 30 - 2a = 8a \\[1em] \Rightarrow 30 = 8a + 2a \\[1em] \Rightarrow 30 = 10a \\[1em] \Rightarrow a = \dfrac{30}{10} \\[1em] \Rightarrow a = 3.

Hence, a=3\bm{a} = 3.

Question 3(vi)

Solve :

3x+5+2x+6+x=4x+213x + 5 + 2x + 6 + x = 4x + 21

Answer

Solving,

⇒3x+5+2x+6+x=4x+21⇒6x+11=4x+21⇒6x−4x=21−11⇒2x=10⇒x=102⇒x=5.\Rightarrow 3x + 5 + 2x + 6 + x = 4x + 21 \\[1em] \Rightarrow 6x + 11 = 4x + 21 \\[1em] \Rightarrow 6x - 4x = 21 - 11 \\[1em] \Rightarrow 2x = 10 \\[1em] \Rightarrow x = \dfrac{10}{2} \\[1em] \Rightarrow x = 5.

Hence, x=5\bm{x} = 5.

Question 3(vii)

Solve :

3.5x−9−3=x+13.5x - 9 - 3 = x + 1

Answer

Solving,

⇒3.5x−9−3=x+1⇒3.5x−12=x+1⇒3.5x−x=1+12⇒2.5x=13⇒x=132.5⇒x=265=515.\Rightarrow 3.5x - 9 - 3 = x + 1 \\[1em] \Rightarrow 3.5x - 12 = x + 1 \\[1em] \Rightarrow 3.5x - x = 1 + 12 \\[1em] \Rightarrow 2.5x = 13 \\[1em] \Rightarrow x = \dfrac{13}{2.5} \\[1em] \Rightarrow x = \dfrac{26}{5} = 5\dfrac{1}{5}.

Hence, x=515\bm{x} = 5\dfrac{1}{5}.

Question 3(viii)

Solve :

8x+6+2x−4=4x+88x + 6 + 2x - 4 = 4x + 8

Answer

Solving,

⇒8x+6+2x−4=4x+8⇒10x+2=4x+8⇒10x−4x=8−2⇒6x=6⇒x=66⇒x=1.\Rightarrow 8x + 6 + 2x - 4 = 4x + 8 \\[1em] \Rightarrow 10x + 2 = 4x + 8 \\[1em] \Rightarrow 10x - 4x = 8 - 2 \\[1em] \Rightarrow 6x = 6 \\[1em] \Rightarrow x = \dfrac{6}{6} \\[1em] \Rightarrow x = 1.

Hence, x=1\bm{x} = 1.

Question 3(ix)

Solve :

−m+(3m−6m)=−8−14-m + (3m - 6m) = -8 - 14

Answer

Solving,

⇒−m+(3m−6m)=−8−14⇒−m+(−3m)=−22⇒−m−3m=−22⇒−4m=−22⇒m=−22−4⇒m=112=512.\Rightarrow -m + (3m - 6m) = -8 - 14 \\[1em] \Rightarrow -m + (-3m) = -22 \\[1em] \Rightarrow -m - 3m = -22 \\[1em] \Rightarrow -4m = -22 \\[1em] \Rightarrow m = \dfrac{-22}{-4} \\[1em] \Rightarrow m = \dfrac{11}{2} = 5\dfrac{1}{2}.

Hence, m=512\bm{m} = 5\dfrac{1}{2}.

Question 3(x)

Solve :

5x−14=x−(24+4x)5x - 14 = x - (24 + 4x)

Answer

Solving,

⇒5x−14=x−(24+4x)⇒5x−14=x−24−4x⇒5x−14=−3x−24⇒5x+3x=−24+14⇒8x=−10⇒x=−108⇒x=−54=−114.\Rightarrow 5x - 14 = x - (24 + 4x) \\[1em] \Rightarrow 5x - 14 = x - 24 - 4x \\[1em] \Rightarrow 5x - 14 = -3x - 24 \\[1em] \Rightarrow 5x + 3x = -24 + 14 \\[1em] \Rightarrow 8x = -10 \\[1em] \Rightarrow x = \dfrac{-10}{8} \\[1em] \Rightarrow x = -\dfrac{5}{4} = -1\dfrac{1}{4}.

Hence, x=−114\bm{x} = -1\dfrac{1}{4}.

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