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Chapter 13

Framing Algebraic Expressions — Exercise 13(D)

Class - 6 Concise Mathematics Selina



Exercise 13(D)

Question 1(i)

Solve :

2x+5=172x + 5 = 17

Answer

Solving,

2x+5=172x=1752x=12x=122x=6.\Rightarrow 2x + 5 = 17 \\[1em] \Rightarrow 2x = 17 - 5 \\[1em] \Rightarrow 2x = 12 \\[1em] \Rightarrow x = \dfrac{12}{2} \\[1em] \Rightarrow x = 6.

Hence, x=6\bm{x} = 6.

Question 1(ii)

Solve :

3y2=13y - 2 = 1

Answer

Solving,

3y2=13y=1+23y=3y=33y=1.\Rightarrow 3y - 2 = 1 \\[1em] \Rightarrow 3y = 1 + 2 \\[1em] \Rightarrow 3y = 3 \\[1em] \Rightarrow y = \dfrac{3}{3} \\[1em] \Rightarrow y = 1.

Hence, y=1\bm{y} = 1.

Question 1(iii)

Solve :

5p+4=295p + 4 = 29

Answer

Solving,

5p+4=295p=2945p=25p=255p=5.\Rightarrow 5p + 4 = 29 \\[1em] \Rightarrow 5p = 29 - 4 \\[1em] \Rightarrow 5p = 25 \\[1em] \Rightarrow p = \dfrac{25}{5} \\[1em] \Rightarrow p = 5.

Hence, p=5\bm{p} = 5.

Question 1(iv)

Solve :

4a3=274a - 3 = -27

Answer

Solving,

4a3=274a=27+34a=24a=244a=6.\Rightarrow 4a - 3 = -27 \\[1em] \Rightarrow 4a = -27 + 3 \\[1em] \Rightarrow 4a = -24 \\[1em] \Rightarrow a = \dfrac{-24}{4} \\[1em] \Rightarrow a = -6.

Hence, a=6\bm{a} = -6.

Question 1(v)

Solve :

2z+3=192z + 3 = -19

Answer

Solving,

2z+3=192z=1932z=22z=222z=11.\Rightarrow 2z + 3 = -19 \\[1em] \Rightarrow 2z = -19 - 3 \\[1em] \Rightarrow 2z = -22 \\[1em] \Rightarrow z = \dfrac{-22}{2} \\[1em] \Rightarrow z = -11.

Hence, z=11\bm{z} = -11.

Question 1(vi)

Solve :

7m1=207m - 1 = 20

Answer

Solving,

7m1=207m=20+17m=21m=217m=3.\Rightarrow 7m - 1 = 20 \\[1em] \Rightarrow 7m = 20 + 1 \\[1em] \Rightarrow 7m = 21 \\[1em] \Rightarrow m = \dfrac{21}{7} \\[1em] \Rightarrow m = 3.

Hence, m=3\bm{m} = 3.

Question 1(vii)

Solve :

2.4x3=4.22.4x - 3 = 4.2

Answer

Solving,

2.4x3=4.22.4x=4.2+32.4x=7.2x=7.22.4x=3.\Rightarrow 2.4x - 3 = 4.2 \\[1em] \Rightarrow 2.4x = 4.2 + 3 \\[1em] \Rightarrow 2.4x = 7.2 \\[1em] \Rightarrow x = \dfrac{7.2}{2.4} \\[1em] \Rightarrow x = 3.

Hence, x=3\bm{x} = 3.

Question 1(viii)

Solve :

4m+9.4=54m + 9.4 = 5

Answer

Solving,

4m+9.4=54m=59.44m=4.4m=4.44m=1.1.\Rightarrow 4m + 9.4 = 5 \\[1em] \Rightarrow 4m = 5 - 9.4 \\[1em] \Rightarrow 4m = -4.4 \\[1em] \Rightarrow m = \dfrac{-4.4}{4} \\[1em] \Rightarrow m = -1.1.

Hence, m=1.1\bm{m} = -1.1.

Question 1(ix)

Solve :

6y+4=4.46y + 4 = -4.4

Answer

Solving,

6y+4=4.46y=4.446y=8.4y=8.46y=1.4.\Rightarrow 6y + 4 = -4.4 \\[1em] \Rightarrow 6y = -4.4 - 4 \\[1em] \Rightarrow 6y = -8.4 \\[1em] \Rightarrow y = \dfrac{-8.4}{6} \\[1em] \Rightarrow y = -1.4.

Hence, y=1.4\bm{y} = -1.4.

Question 2(i)

Solve :

x35=2\dfrac{x}{3} - 5 = 2

Answer

Solving,

x35=2x3=2+5x3=7x=7×3x=21.\Rightarrow \dfrac{x}{3} - 5 = 2 \\[1em] \Rightarrow \dfrac{x}{3} = 2 + 5 \\[1em] \Rightarrow \dfrac{x}{3} = 7 \\[1em] \Rightarrow x = 7 \times 3 \\[1em] \Rightarrow x = 21.

Hence, x=21\bm{x} = 21.

Question 2(ii)

Solve :

y23=8\dfrac{y}{2} - 3 = 8

Answer

Solving,

y23=8y2=8+3y2=11y=11×2y=22.\Rightarrow \dfrac{y}{2} - 3 = 8 \\[1em] \Rightarrow \dfrac{y}{2} = 8 + 3 \\[1em] \Rightarrow \dfrac{y}{2} = 11 \\[1em] \Rightarrow y = 11 \times 2 \\[1em] \Rightarrow y = 22.

Hence, y=22\bm{y} = 22.

Question 2(iii)

Solve :

z7+1=212\dfrac{z}{7} + 1 = 2\dfrac{1}{2}

Answer

Solving,

z7+1=212z7+1=52z7=521z7=522z7=32z=32×7z=212=1012.\Rightarrow \dfrac{z}{7} + 1 = 2\dfrac{1}{2} \\[1em] \Rightarrow \dfrac{z}{7} + 1 = \dfrac{5}{2} \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{5}{2} - 1 \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{5 - 2}{2} \\[1em] \Rightarrow \dfrac{z}{7} = \dfrac{3}{2} \\[1em] \Rightarrow z = \dfrac{3}{2} \times 7 \\[1em] \Rightarrow z = \dfrac{21}{2} = 10\dfrac{1}{2}.

Hence, z=1012\bm{z} = 10\dfrac{1}{2}.

Question 2(iv)

Solve :

a2.45=2.4\dfrac{a}{2.4} - 5 = 2.4

Answer

Solving,

a2.45=2.4a2.4=2.4+5a2.4=7.4a=7.4×2.4a=17.76.\Rightarrow \dfrac{a}{2.4} - 5 = 2.4 \\[1em] \Rightarrow \dfrac{a}{2.4} = 2.4 + 5 \\[1em] \Rightarrow \dfrac{a}{2.4} = 7.4 \\[1em] \Rightarrow a = 7.4 \times 2.4 \\[1em] \Rightarrow a = 17.76.

Hence, a=17.76\bm{a} = 17.76.

Question 2(v)

Solve :

b1.6+3=2.5\dfrac{b}{1.6} + 3 = -2.5

Answer

Solving,

b1.6+3=2.5b1.6=2.53b1.6=5.5b=5.5×1.6b=8.8.\Rightarrow \dfrac{b}{1.6} + 3 = -2.5 \\[1em] \Rightarrow \dfrac{b}{1.6} = -2.5 - 3 \\[1em] \Rightarrow \dfrac{b}{1.6} = -5.5 \\[1em] \Rightarrow b = -5.5 \times 1.6 \\[1em] \Rightarrow b = -8.8.

Hence, b=8.8\bm{b} = -8.8.

Question 2(vi)

Solve :

m44.6=3.1\dfrac{m}{4} - 4.6 = -3.1

Answer

Solving,

m44.6=3.1m4=3.1+4.6m4=1.5m=1.5×4m=6.\Rightarrow \dfrac{m}{4} - 4.6 = -3.1 \\[1em] \Rightarrow \dfrac{m}{4} = -3.1 + 4.6 \\[1em] \Rightarrow \dfrac{m}{4} = 1.5 \\[1em] \Rightarrow m = 1.5 \times 4 \\[1em] \Rightarrow m = 6.

Hence, m=6\bm{m} = 6.

Question 3(i)

Solve :

8m2=10-8m - 2 = -10

Answer

Solving,

8m2=108m=10+28m=8m=88m=1.\Rightarrow -8m - 2 = -10 \\[1em] \Rightarrow -8m = -10 + 2 \\[1em] \Rightarrow -8m = -8 \\[1em] \Rightarrow m = \dfrac{-8}{-8} \\[1em] \Rightarrow m = 1.

Hence, m=1\bm{m} = 1.

Question 3(ii)

Solve :

4x+2x=3+54x + 2x = 3 + 5

Answer

Solving,

4x+2x=3+56x=8x=86x=43=113.\Rightarrow 4x + 2x = 3 + 5 \\[1em] \Rightarrow 6x = 8 \\[1em] \Rightarrow x = \dfrac{8}{6} \\[1em] \Rightarrow x = \dfrac{4}{3} = 1\dfrac{1}{3}.

Hence, x=113\bm{x} = 1\dfrac{1}{3}.

Question 3(iii)

Solve :

4xx+5=84x - x + 5 = 8

Answer

Solving,

4xx+5=83x+5=83x=853x=3x=1.\Rightarrow 4x - x + 5 = 8 \\[1em] \Rightarrow 3x + 5 = 8 \\[1em] \Rightarrow 3x = 8 - 5 \\[1em] \Rightarrow 3x = 3 \\[1em] \Rightarrow x = 1.

Hence, x=1\bm{x} = 1.

Question 3(iv)

Solve :

6x+2=2x+106x + 2 = 2x + 10

Answer

Solving,

6x+2=2x+106x2x=1024x=8x=84x=2.\Rightarrow 6x + 2 = 2x + 10 \\[1em] \Rightarrow 6x - 2x = 10 - 2 \\[1em] \Rightarrow 4x = 8 \\[1em] \Rightarrow x = \dfrac{8}{4} \\[1em] \Rightarrow x = 2.

Hence, x=2\bm{x} = 2.

Question 3(v)

Solve :

18(2a12)=8a18 - (2a - 12) = 8a

Answer

Solving,

18(2a12)=8a182a+12=8a302a=8a30=8a+2a30=10aa=3010a=3.\Rightarrow 18 - (2a - 12) = 8a \\[1em] \Rightarrow 18 - 2a + 12 = 8a \\[1em] \Rightarrow 30 - 2a = 8a \\[1em] \Rightarrow 30 = 8a + 2a \\[1em] \Rightarrow 30 = 10a \\[1em] \Rightarrow a = \dfrac{30}{10} \\[1em] \Rightarrow a = 3.

Hence, a=3\bm{a} = 3.

Question 3(vi)

Solve :

3x+5+2x+6+x=4x+213x + 5 + 2x + 6 + x = 4x + 21

Answer

Solving,

3x+5+2x+6+x=4x+216x+11=4x+216x4x=21112x=10x=102x=5.\Rightarrow 3x + 5 + 2x + 6 + x = 4x + 21 \\[1em] \Rightarrow 6x + 11 = 4x + 21 \\[1em] \Rightarrow 6x - 4x = 21 - 11 \\[1em] \Rightarrow 2x = 10 \\[1em] \Rightarrow x = \dfrac{10}{2} \\[1em] \Rightarrow x = 5.

Hence, x=5\bm{x} = 5.

Question 3(vii)

Solve :

3.5x93=x+13.5x - 9 - 3 = x + 1

Answer

Solving,

3.5x93=x+13.5x12=x+13.5xx=1+122.5x=13x=132.5x=265=515.\Rightarrow 3.5x - 9 - 3 = x + 1 \\[1em] \Rightarrow 3.5x - 12 = x + 1 \\[1em] \Rightarrow 3.5x - x = 1 + 12 \\[1em] \Rightarrow 2.5x = 13 \\[1em] \Rightarrow x = \dfrac{13}{2.5} \\[1em] \Rightarrow x = \dfrac{26}{5} = 5\dfrac{1}{5}.

Hence, x=515\bm{x} = 5\dfrac{1}{5}.

Question 3(viii)

Solve :

8x+6+2x4=4x+88x + 6 + 2x - 4 = 4x + 8

Answer

Solving,

8x+6+2x4=4x+810x+2=4x+810x4x=826x=6x=66x=1.\Rightarrow 8x + 6 + 2x - 4 = 4x + 8 \\[1em] \Rightarrow 10x + 2 = 4x + 8 \\[1em] \Rightarrow 10x - 4x = 8 - 2 \\[1em] \Rightarrow 6x = 6 \\[1em] \Rightarrow x = \dfrac{6}{6} \\[1em] \Rightarrow x = 1.

Hence, x=1\bm{x} = 1.

Question 3(ix)

Solve :

m+(3m6m)=814-m + (3m - 6m) = -8 - 14

Answer

Solving,

m+(3m6m)=814m+(3m)=22m3m=224m=22m=224m=112=512.\Rightarrow -m + (3m - 6m) = -8 - 14 \\[1em] \Rightarrow -m + (-3m) = -22 \\[1em] \Rightarrow -m - 3m = -22 \\[1em] \Rightarrow -4m = -22 \\[1em] \Rightarrow m = \dfrac{-22}{-4} \\[1em] \Rightarrow m = \dfrac{11}{2} = 5\dfrac{1}{2}.

Hence, m=512\bm{m} = 5\dfrac{1}{2}.

Question 3(x)

Solve :

5x14=x(24+4x)5x - 14 = x - (24 + 4x)

Answer

Solving,

5x14=x(24+4x)5x14=x244x5x14=3x245x+3x=24+148x=10x=108x=54=114.\Rightarrow 5x - 14 = x - (24 + 4x) \\[1em] \Rightarrow 5x - 14 = x - 24 - 4x \\[1em] \Rightarrow 5x - 14 = -3x - 24 \\[1em] \Rightarrow 5x + 3x = -24 + 14 \\[1em] \Rightarrow 8x = -10 \\[1em] \Rightarrow x = \dfrac{-10}{8} \\[1em] \Rightarrow x = -\dfrac{5}{4} = -1\dfrac{1}{4}.

Hence, x=114\bm{x} = -1\dfrac{1}{4}.

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