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Chapter 13

Framing Algebraic Expressions — Multiple Choice Questions

Class - 6 Concise Mathematics Selina



Multiple Choice Questions

Question 1

Perimeter of a regular pentagon is xx m, its each side is :

  1. 5x5x m

  2. (x5)(x - 5) m

  3. 5x\dfrac{5}{x} m

  4. x5\dfrac{x}{5} m

Answer

A regular pentagon has 5 equal sides.

∴ Each side = Perimeter5=x5\dfrac{\text{Perimeter}}{5} = \dfrac{x}{5} m

Hence, option 4 is the correct option.

Question 2

x[yz(xyz)]x - [y - {z - (x - \overline{y - z})}] is :

  1. 0

  2. z-z

  3. x-x

  4. y-y

Answer

Solving,

x[yz(xyz)]x[yz(xy+z)]x[yzx+yz]x[yyx]x[yy+x]xx=0.\Rightarrow x - [y - {z - (x - \overline{y - z})}] \\[1em] \Rightarrow x - [y - {z - (x - y + z)}] \\[1em] \Rightarrow x - [y - {z - x + y - z}] \\[1em] \Rightarrow x - [y - {y - x}] \\[1em] \Rightarrow x - [y - y + x] \\[1em] \Rightarrow x - x = 0.

Hence, option 1 is the correct option.

Question 3

If a=2a = 2 and b=1,abbab = 1, a^b - b^a is equal to :

  1. 3

  2. –1

  3. 0

  4. 1

Answer

Substituting aa = 2 and bb = 1,

abba=211221=1.\Rightarrow a^{b} - b^{a} = 2^{1} - 1^{2} \\[1em] \Rightarrow 2 - 1 = 1.

Hence, option 4 is the correct option.

Question 4

If a=3,b=3a = 3, b = -3 and c=1c = 1, then 2ab+3c2a - b + 3c is equal to :

  1. 6

  2. 3

  3. 12

  4. 9

Answer

Substituting aa = 3, bb = −3 and cc = 1,

2ab+3c=2(3)(3)+3(1)6+3+3=12.\Rightarrow 2a - b + 3c = 2(3) - (-3) + 3(1) \\[1em] \Rightarrow 6 + 3 + 3 = 12.

Hence, option 3 is the correct option.

Question 5

If x=3x = 3 and y=2y = 2, then the value of x2y÷xy2x^2y \div xy^2 is :

  1. 6

  2. 23\dfrac{2}{3}

  3. 32\dfrac{3}{2}

  4. none of these

Answer

Solving,

x2y÷xy2x2yxy2xy32.\Rightarrow x^{2}y \div xy^{2} \\[1em] \Rightarrow \dfrac{x^{2}y}{xy^{2}} \\[1em] \Rightarrow \dfrac{x}{y} \\[1em] \Rightarrow \dfrac{3}{2}.

Hence, option 3 is the correct option.

Question 6

If 3x2=73x - 2 = 7, the value of xx is :

  1. 53\dfrac{5}{3}

  2. 3

  3. 0

  4. none of these

Answer

Solving,

3x2=73x=7+23x=9x=3.\Rightarrow 3x - 2 = 7 \\[1em] \Rightarrow 3x = 7 + 2 \\[1em] \Rightarrow 3x = 9 \\[1em] \Rightarrow x = 3.

Hence, option 2 is the correct option.

Question 7

If x3+7=11\dfrac{x}{3} + 7 = 11, the value of xx is :

  1. 25

  2. –12

  3. 12

  4. –10

Answer

Solving,

x3+7=11x3=117x3=4x=4×3=12.\Rightarrow \dfrac{x}{3} + 7 = 11 \\[1em] \Rightarrow \dfrac{x}{3} = 11 - 7 \\[1em] \Rightarrow \dfrac{x}{3} = 4 \\[1em] \Rightarrow x = 4 \times 3 = 12.

Hence, option 3 is the correct option.

Question 8

The equation for a number multiplied by 3 and the result divided by 2 is 12, is :

  1. x×32\dfrac{x \times 3}{2} = 12

  2. x×23\dfrac{x \times 2}{3} = 12

  3. x×33\dfrac{x \times 3}{3} = 12

  4. none of these

Answer

Let the number be xx.

The number multiplied by 3 = x×3x \times 3

This result divided by 2 = x×32\dfrac{x \times 3}{2}

∴ The required equation is x×32=12\dfrac{x \times 3}{2} = 12.

Hence, option 1 is the correct option.

Question 9

If 9.5=x4.79.5 = x - 4.7, then xx is equal to :

  1. 4.8

  2. 14.2

  3. 4.2

  4. –4.8

Answer

Solving,

9.5=x4.79.5+4.7=xx=14.2.\Rightarrow 9.5 = x - 4.7 \\[1em] \Rightarrow 9.5 + 4.7 = x \\[1em] \Rightarrow x = 14.2.

Hence, option 2 is the correct option.

Question 10

The sum of three consecutive integers is 21, integers are :

  1. 6, 7 and 8

  2. 5, 6 and 10

  3. 4, 8 and 9

  4. 8, 10 and 3

Answer

Let the three consecutive integers be x,x+1x, x + 1 and x+2x + 2.

x+(x+1)+(x+2)=213x+3=213x=18x=6.\Rightarrow x + (x + 1) + (x + 2) = 21 \\[1em] \Rightarrow 3x + 3 = 21 \\[1em] \Rightarrow 3x = 18 \\[1em] \Rightarrow x = 6.

∴ The integers are 6, 7 and 8.

Hence, option 1 is the correct option.

Question 11

The difference of two natural numbers is 2 and their sum is 14, the numbers are :

  1. 4 and 10

  2. 6 and 8

  3. 5 and 9

  4. 7 and 9

Answer

Let the smaller number be xx, then the larger number = xx + 2.

x+(x+2)=142x+2=142x=12x=6.\Rightarrow x + (x + 2) = 14 \\[1em] \Rightarrow 2x + 2 = 14 \\[1em] \Rightarrow 2x = 12 \\[1em] \Rightarrow x = 6.

∴ The numbers are 6 and 6 + 2 = 8.

Hence, option 2 is the correct option.

Question 12

A number xx is decreased by 12 and then the new number obtained is multiplied by 2; the result is 30. The equation for this statement is :

  1. x12×2=30x - 12 \times 2 = 30

  2. x212=30\dfrac{x}{2} - 12 = 30

  3. (x12)×2=30(x - 12) \times 2 = 30

  4. x12÷2=30x - 12 \div 2 = 30

Answer

The number xx decreased by 12 = (xx − 12)

This new number multiplied by 2 = (xx − 12) × 2

∴ The required equation is (xx − 12) × 2 = 30.

Hence, option 3 is the correct option.

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