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Chapter 1

Number System — Multiple Choice Questions

Class - 6 RS Aggarwal Mathematics Solutions



Exercise 1(F) — Multiple Choice Questions

Question 1

The place value of 7 in the numeral 25,79,206 is

  1. 7

  2. 79,206

  3. 70,000

  4. 257

Answer

The numeral is 25,79,206.

Let's look at the place values from right to left (Indian system):

6 is in the Ones place

0 is in the Tens place

2 is in the Hundreds place

9 is in the Thousands place

7 is in the Ten Thousands place

5 is in the Lakhs place

2 is in the Ten Lakhs place

The digit 7 is in the Ten Thousands place.

Therefore, its place value is 7 × 10,000 = 70,000.

Hence, option 3 is the correct option.

Question 2

The face value of 4 in the numeral 36,43,908 is

  1. 40,000

  2. 4

  3. 364

  4. 43,908

Answer

The numeral is 36,43,908.

The face value of a digit is the digit itself, regardless of its position in the number.

In the numeral 36,43,908, the digit 4 is present.

The face value of 4 is simply 4.

Hence, option 2 is the correct option.

Question 3

The difference between the place-value and the face value of 6 in the numeral 32,53,619 is

  1. 19

  2. 594

  3. 613

  4. 600

Answer

The numeral is 32,53,619.

Place Value of 6:

In the numeral 32,53,619, the digit 6 is in the Hundreds place.

So, its place value is 6 × 100 = 600.

Face Value of 6:

The face value of a digit is the digit itself.

So, the face value of 6 is 6.

Difference between Place Value and Face Value:

Difference = Place Value - Face Value

Difference = 600 − 6 = 594

Hence, option 2 is the correct option.

Question 4

The smallest counting number is

  1. 0

  2. 1

  3. 10

  4. 11

Answer

Counting numbers (also known as natural numbers) are the numbers we use for counting objects. They start from 1.

0 is a whole number, but not a counting number in the mathematical sense.

Hence, option 2 is the correct option.

Question 5

The whole number whose successor is 53,100 is

  1. 53,101

  2. 53,099

  3. 53,000

  4. none of these

Answer

The successor of a number is obtained by adding 1 to that number.

Let the whole number be 'x'.

Its successor is given as 53,100.

So, we have the equation:

⇒ x + 1 = 53,100

To find x, subtract 1 from 53,100:

⇒ x = 53,100 - 1

⇒ x = 53,099

The whole number whose successor is 53,100 is 53,099.

Hence, option 2 is the correct option.

Question 6

The difference between the largest number of 3-digits and the smallest number of 3-digits formed by the digits 3, 0 and 8 is

  1. 495

  2. 765

  3. 522

  4. 450

Answer

To make the largest number, arrange the digits in descending order: 8, 3, 0.

The largest number = 830.

To make the smallest 3-digit number, the hundreds digit cannot be 0. So, place the next smallest digit (3) in the hundreds place, followed by the remaining digits in ascending order (0, 8).

The smallest number = 308.

Difference = Largest number - Smallest number

= 830 - 308

= 522.

Hence, option 3 is the correct option.

Question 7

How many 7 digit numbers are there in all?

  1. 90,00,000

  2. 90,00,001

  3. 89,99,999

  4. 10,00,000

Answer

The largest 7-digit number = 9,999,999.

The smallest 7-digit number = 1,000,000.

Total Count = (Largest Number - Smallest Number) + 1

Total 7-digit numbers = 9,999,999 - 1,000,000 + 1

= 8,999,999 + 1

= 9,000,000

Hence, option 1 is the correct option.

Question 8

What comes just before 10,00,000?

  1. 99,999

  2. 99,99,999

  3. 9,99,999

  4. none of these

Answer

The number that comes just before 10,00,000

= 10,00,000 - 1

= 9,99,999.

Hence, option 3 is the correct option.

Question 9

The largest number of 4 digits which is exactly divisible by 25 is

  1. 1,000

  2. 10,000

  3. 9,950

  4. 9,975

Answer

The largest number of 4 digits is 9,999.

To find the largest 4-digit number exactly divisible by 25, we divide 9,999 by 25:

9999 ÷ 25 = 25 × 399 + 24

The remainder is 24.

To get a number exactly divisible by 25, we subtract this remainder from 9,999:

9999 − 24 = 9975

So, the largest 4-digit number exactly divisible by 25 is 9,975.

Hence, option 4 is the correct option.

Question 10

The number which when divided by 23 gives 17 as quotient and 19 as remainder, is

  1. 413

  2. 412

  3. 411

  4. none of these

Answer

By formula,

Dividend = Divisor × Quotient + Remainder

= 23 × 17 + 19

= 391 + 19

= 410.

Hence, option 4 is the correct option.

Question 11

The sum of the successor and the predecessor of a number is 1326. The number is

  1. 663

  2. 662

  3. 664

  4. 661

Answer

Let the number be N.

The successor of the number is N + 1.

The predecessor of the number is N − 1.

According to the problem, the sum of the successor and the predecessor is 1326:

⇒ (N + 1) + (N − 1) = 1326

⇒ N + 1 + N − 1 = 1326

⇒ 2N = 1326

⇒ N = 13262\dfrac{1326}{2}

⇒ N = 663

Hence, option 1 is the correct option.

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