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Chapter 4

Fractions — Assertion-Reason Questions

Class - 6 RS Aggarwal Mathematics Solutions



Exercise 4(I) — Assertion-Reason Questions

Question 1

Assertion (A): The sum of two fractions is always a fraction.

Reason (R): For two fractions ab and cd\dfrac{a}{b} \text{ and } \dfrac{c}{d}, we have ab+cd=ad+bcbd\dfrac{a}{b} + \dfrac{c}{d} = \dfrac{ad + bc}{bd}

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).

  3. Assertion (A) is true but Reason (R) is false.

  4. Assertion (A) is false but Reason (R) is true.

Answer

According to assertion; the sum of two fractions is always a fraction.

Example - the two fractions are 12\dfrac{1}{2} and 32\dfrac{3}{2}

Now, 12+32=42=2\dfrac{1}{2} + \dfrac{3}{2} = \dfrac{4}{2} = 2

∴ Assertion (A) is false.

For two fractions abandcd\dfrac{a}{b} \text{and} \dfrac{c}{d}, we have ab+cd\dfrac{a}{b} + \dfrac{c}{d}

LCM of b and d = bd

a×db×d+c×bd×b=adbd+cbbd=ad+cbbd\dfrac{a \times d}{b \times d} + \dfrac{c \times b}{d \times b} = \dfrac{ad}{bd} + \dfrac{cb}{bd} = \dfrac{ad + cb}{bd}

∴ Reason (R) is true.

Hence, option 4 is the correct option.

Question 2

Assertion (A): Half of a number is obtained by dividing it by 2.

Reason (R): The fractions xy\dfrac{x}{y} and yx\dfrac{y}{x} are multiplicative inverse of each other.

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).

  3. Assertion (A) is true but Reason (R) is false.

  4. Assertion (A) is false but Reason (R) is true.

Answer

According to assertion, half of a number is obtained by dividing it by 2.

half of n is n2\dfrac{n}{2}, which is exactly dividing by 2.

∴ Assertion (A) is true.

According to reason, the fractions xy\dfrac{x}{y} and yx\dfrac{y}{x} are multiplicative inverse of each other.

xy×yxx×yy×xx×yy×x1.\Rightarrow \dfrac{x}{y} \times \dfrac{y}{x}\\[1em] \Rightarrow \dfrac{x \times y}{y \times x}\\[1em] \Rightarrow \dfrac{x \times y}{y \times x}\\[1em] \Rightarrow 1.

∴ Reason (R) is true.

∴ Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).

Hence, option 2 is the correct option.

Question 3

Assertion (A): The sum of the fractions represented by the shaded and unshaded portion is 1.

The sum of the fractions represented by the shaded and unshaded portion is 1. Fractions, R.S. Aggarwal Mathematics Solutions ICSE Class 6.

Reason (R): We can only add like fractions.

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).

  3. Assertion (A) is true but Reason (R) is false.

  4. Assertion (A) is false but Reason (R) is true.

Answer

According to assertion, the sum of the fractions represented by the shaded and unshaded portion is 1.

Fraction of shaded portion = 59\dfrac{5}{9}

Fraction of unshaded portion = 49\dfrac{4}{9}

Sum of fraction of shaded portion + unshaded portion = 59+49=5+49=99=1\dfrac{5}{9} + \dfrac{4}{9} = \dfrac{5 + 4}{9} = \dfrac{9}{9} = 1.

∴ Assertion (A) is true.

According to reason, we can only add like fractions.

We can add any fractions (like or unlike), but if they are unlike fractions we first convert them to like fractions (common denominator) and then add.

∴ Reason (R) is false.

Hence, option 3 is the correct option.

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