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Chapter 12

Fundamental Concepts of Algebra — Exercise 12(E)

Class - 6 RS Aggarwal Mathematics Solutions



Exercise 12(E)

Question 1(i)

Add:

9x,7x9x, 7x

Answer

Adding,

⇒9x+7x⇒(9+7)x⇒16x\Rightarrow 9x + 7x\\[1em] \Rightarrow (9 + 7)x\\[1em] \Rightarrow \bm{16x}

Hence, 9x+7x=16x\bm{9x + 7x = 16x}

Question 1(ii)

Add:

13p,6p,2p13p, 6p, 2p

Answer

Adding,

⇒13p+6p+2p⇒(13+6+2)p⇒21p\Rightarrow 13p + 6p + 2p\\[1em] \Rightarrow (13 + 6 + 2)p\\[1em] \Rightarrow \bm{21p}

Hence, 13p+6p+2p=21p\bm{13p + 6p + 2p = 21p}

Question 1(iii)

Add:

8xy,7xy,xy8xy, 7xy, xy

Answer

Adding,

⇒8xy+7xy+xy⇒(8+7+1)xy⇒16xy\Rightarrow 8xy + 7xy + xy\\[1em] \Rightarrow (8 + 7 + 1)xy\\[1em] \Rightarrow \bm{16xy}

Hence, 8xy+7xy+xy=16xy\bm{8xy + 7xy + xy = 16xy}

Question 1(iv)

Add:

5y,−13y5y, -13y

Answer

Adding,

⇒5y+(−13y)⇒(5−13)y⇒−8y\Rightarrow 5y + (-13y)\\[1em] \Rightarrow (5 - 13)y\\[1em] \Rightarrow \bm{-8y}

Hence, 5y+(−13y)=−8y\bm{5y + (-13y) = -8y}

Question 1(v)

Add:

4x2,−9x24x^2, -9x^2

Answer

Adding,

⇒4x2+(−9x2)⇒(4−9)x2⇒−5x2\Rightarrow 4x^2 + (-9x^2)\\[1em] \Rightarrow (4 - 9)x^2\\[1em] \Rightarrow \bm{-5x^2}

Hence, 4x2+(−9x2)=−5x2\bm{4x^2 + (-9x^2) = -5x^2}

Question 1(vi)

Add:

3a2b,−5a2b3a^2b, -5a^2b

Answer

Adding,

⇒3a2b+(−5a2b)⇒(3−5)a2b⇒−2a2b\Rightarrow 3a^2b + (-5a^2b)\\[1em] \Rightarrow (3 - 5)a^2b\\[1em] \Rightarrow \bm{-2a^2b}

Hence, 3a2b+(−5a2b)=−2a2b\bm{3a^2b + (-5a^2b) = -2a^2b}

Question 1(vii)

Add:

12mn,2mn\dfrac{1}{2}mn, 2mn

Answer

Adding,

⇒12mn+2mn⇒(12+2)mn⇒1+42mn⇒52mn\Rightarrow \dfrac{1}{2}mn + 2mn\\[1em] \Rightarrow \left(\dfrac{1}{2} + 2\right)mn\\[1em] \Rightarrow \dfrac{1 + 4}{2}mn\\[1em] \Rightarrow \bm{\dfrac{5}{2}mn}

Hence, 12mn+2mn=52mn\bm{\dfrac{1}{2}mn + 2mn = \dfrac{5}{2}mn}

Question 1(viii)

Add:

13x2y,3x2y\dfrac{1}{3}x^2y, 3x^2y

Answer

Adding,

⇒13x2y+3x2y⇒(13+3)x2y⇒1+93x2y⇒103x2y\Rightarrow \dfrac{1}{3}x^2y + 3x^2y\\[1em] \Rightarrow \left(\dfrac{1}{3} + 3\right)x^2y\\[1em] \Rightarrow \dfrac{1 + 9}{3}x^2y\\[1em] \Rightarrow \bm{\dfrac{10}{3}x^2y}

Hence, 13x2y+3x2y=103x2y\bm{\dfrac{1}{3}x^2y + 3x^2y = \dfrac{10}{3}x^2y}

Question 1(ix)

Add:

5ab2,−ab25ab^2, -ab^2

Answer

Adding,

⇒5ab2+(−ab2)⇒(5−1)ab2⇒4ab2\Rightarrow 5ab^2 + (-ab^2)\\[1em] \Rightarrow (5 - 1)ab^2\\[1em] \Rightarrow \bm{4ab^2}

Hence, 5ab2+(−ab2)=4ab2\bm{5ab^2 + (-ab^2) = 4ab^2}

Question 2(i)

Add:

5a,−3a,4a5a, -3a, 4a

Answer

Adding,

⇒5a+(−3a)+4a⇒(5−3+4)a⇒6a\Rightarrow 5a + (-3a) + 4a\\[1em] \Rightarrow (5 - 3 + 4)a\\[1em] \Rightarrow \bm{6a}

Hence, 5a+(−3a)+4a=6a\bm{5a + (-3a) + 4a = 6a}

Question 2(ii)

Add:

−2b,b,−3b-2b, b, -3b

Answer

Adding,

⇒(−2b)+b+(−3b)⇒(−2+1−3)b⇒−4b\Rightarrow (-2b) + b + (-3b)\\[1em] \Rightarrow (-2 + 1 - 3)b\\[1em] \Rightarrow \bm{-4b}

Hence, (−2b)+b+(−3b)=−4b\bm{(-2b) + b + (-3b) = -4b}

Question 2(iii)

Add:

4ab,−5ab,−3ab4ab, -5ab, -3ab

Answer

Adding,

⇒4ab+(−5ab)+(−3ab)⇒(4−5−3)ab⇒−4ab\Rightarrow 4ab + (-5ab) + (-3ab)\\[1em] \Rightarrow (4 - 5 - 3)ab\\[1em] \Rightarrow \bm{-4ab}

Hence, 4ab+(−5ab)+(−3ab)=−4ab\bm{4ab + (-5ab) + (-3ab) = -4ab}

Question 2(iv)

Add:

6xy2,−8xy2,−3xy26xy^2, -8xy^2, -3xy^2

Answer

Adding,

⇒6xy2+(−8xy2)+(−3xy2)⇒(6−8−3)xy2⇒−5xy2\Rightarrow 6xy^2 + (-8xy^2) + (-3xy^2)\\[1em] \Rightarrow (6 - 8 - 3)xy^2\\[1em] \Rightarrow \bm{-5xy^2}

Hence, 6xy2+(−8xy2)+(−3xy2)=−5xy2\bm{6xy^2 + (-8xy^2) + (-3xy^2) = -5xy^2}

Question 2(v)

Add:

4m2n,−m2n,−6m2n4m^2n, -m^2n, -6m^2n

Answer

Adding,

⇒4m2n+(−m2n)+(−6m2n)⇒(4−1−6)m2n⇒−3m2n\Rightarrow 4m^2n + (-m^2n) + (-6m^2n)\\[1em] \Rightarrow (4 - 1 - 6)m^2n\\[1em] \Rightarrow \bm{-3m^2n}

Hence, 4m2n+(−m2n)+(−6m2n)=−3m2n\bm{4m^2n + (-m^2n) + (-6m^2n) = -3m^2n}

Question 2(vi)

Add:

2xyz,−5xyz,−xyz2xyz, -5xyz, -xyz

Answer

Adding,

⇒2xyz+(−5xyz)+(−xyz)⇒(2−5−1)xyz⇒−4xyz\Rightarrow 2xyz + (-5xyz) + (-xyz)\\[1em] \Rightarrow (2 - 5 - 1)xyz\\[1em] \Rightarrow \bm{-4xyz}

Hence, 2xyz+(−5xyz)+(−xyz)=−4xyz\bm{2xyz + (-5xyz) + (-xyz) = -4xyz}

Question 3(i)

Add:

−6x,−9x-6x, -9x

Answer

Adding,

⇒(−6x)+(−9x)⇒(−6−9)x⇒−15x\Rightarrow (-6x) + (-9x)\\[1em] \Rightarrow (-6 - 9)x\\[1em] \Rightarrow \bm{-15x}

Hence, (−6x)+(−9x)=−15x\bm{(-6x) + (-9x) = -15x}

Question 3(ii)

Add:

−3y,−y,−7y-3y, -y, -7y

Answer

Adding,

⇒(−3y)+(−y)+(−7y)⇒(−3−1−7)y⇒−11y\Rightarrow (-3y) + (-y) + (-7y)\\[1em] \Rightarrow (-3 - 1 - 7)y\\[1em] \Rightarrow \bm{-11y}

Hence, (−3y)+(−y)+(−7y)=−11y\bm{(-3y) + (-y) + (-7y) = -11y}

Question 3(iii)

Add:

−8xy,−4xy,6xy-8xy, -4xy, 6xy

Answer

Adding,

⇒(−8xy)+(−4xy)+6xy⇒(−8−4+6)xy⇒−6xy\Rightarrow (-8xy) + (-4xy) + 6xy\\[1em] \Rightarrow (-8 - 4 + 6)xy\\[1em] \Rightarrow \bm{-6xy}

Hence, (−8xy)+(−4xy)+6xy=−6xy\bm{(-8xy) + (-4xy) + 6xy = -6xy}

Question 3(iv)

Add:

7m2n,−2m2n,−3m2n7m^2n, -2m^2n, -3m^2n

Answer

Adding,

⇒7m2n+(−2m2n)+(−3m2n)⇒(7−2−3)m2n⇒2m2n\Rightarrow 7m^2n + (-2m^2n) + (-3m^2n)\\[1em] \Rightarrow (7 - 2 - 3)m^2n\\[1em] \Rightarrow \bm{2m^2n}

Hence, 7m2n+(−2m2n)+(−3m2n)=2m2n\bm{7m^2n + (-2m^2n) + (-3m^2n) = 2m^2n}

Question 3(v)

Add:

−2ab2,−8ab2,5ab2-2ab^2, -8ab^2, 5ab^2

Answer

Adding,

⇒(−2ab2)+(−8ab2)+5ab2⇒(−2−8+5)ab2⇒−5ab2\Rightarrow (-2ab^2) + (-8ab^2) + 5ab^2\\[1em] \Rightarrow (-2 - 8 + 5)ab^2\\[1em] \Rightarrow \bm{-5ab^2}

Hence, (−2ab2)+(−8ab2)+5ab2=−5ab2\bm{(-2ab^2) + (-8ab^2) + 5ab^2 = -5ab^2}

Question 3(vi)

Add:

12yz,2yz,−yz\dfrac{1}{2}yz, 2yz, -yz

Answer

Adding,

⇒12yz+2yz+(−yz)⇒(12+2−1)yz⇒1+4−22yz⇒32yz\Rightarrow \dfrac{1}{2}yz + 2yz + (-yz)\\[1em] \Rightarrow \left(\dfrac{1}{2} + 2 - 1\right)yz\\[1em] \Rightarrow \dfrac{1 + 4 - 2}{2}yz\\[1em] \Rightarrow \bm{\dfrac{3}{2}yz}

Hence, 12yz+2yz+(−yz)=32yz\bm{\dfrac{1}{2}yz + 2yz + (-yz) = \dfrac{3}{2}yz}

Question 3(vii)

Add:

5a3,−3a3,−12a35a^3, -3a^3, -\dfrac{1}{2}a^3

Answer

Adding,

⇒5a3+(−3a3)+(−12a3)⇒(5−3−12)a3⇒10−6−12a3⇒32a3\Rightarrow 5a^3 + (-3a^3) + \left(-\dfrac{1}{2}a^3\right)\\[1em] \Rightarrow \left(5 - 3 - \dfrac{1}{2}\right)a^3\\[1em] \Rightarrow \dfrac{10 - 6 - 1}{2}a^3\\[1em] \Rightarrow \bm{\dfrac{3}{2}a^3}

Hence, 5a3+(−3a3)+(−12a3)=32a3\bm{5a^3 + (-3a^3) + \left(-\dfrac{1}{2}a^3\right) = \dfrac{3}{2}a^3}

Question 3(viii)

Add:

−12a2,−13a2,2a2-\dfrac{1}{2}a^2, -\dfrac{1}{3}a^2, 2a^2

Answer

Adding,

⇒(−12a2)+(−13a2)+2a2⇒(−12−13+2)a2⇒−3−2+126a2⇒76a2\Rightarrow \left(-\dfrac{1}{2}a^2\right) + \left(-\dfrac{1}{3}a^2\right) + 2a^2\\[1em] \Rightarrow \left(-\dfrac{1}{2} - \dfrac{1}{3} + 2\right)a^2\\[1em] \Rightarrow \dfrac{-3 - 2 + 12}{6}a^2\\[1em] \Rightarrow \bm{\dfrac{7}{6}a^2}

Hence, (−12a2)+(−13a2)+2a2=76a2\bm{\left(-\dfrac{1}{2}a^2\right) + \left(-\dfrac{1}{3}a^2\right) + 2a^2 = \dfrac{7}{6}a^2}

Question 4

Find the sum of the following algebraic expressions:

8a−3b+11c,5b−6a+7c8a - 3b + 11c, 5b - 6a + 7c and 9c+2a−8b9c + 2a - 8b.

Answer

Adding columnwise, we get:

8a−3b+11c−6a+5b+7c+2a−8b+9c4a−6b+27c\begin{array}{rrrr} & 8a & - 3b & + 11c \\ & -6a & + 5b & + 7c \\ {+} & 2a & - 8b & + 9c \\ \hline & 4a & - 6b & + 27c \end{array}

Hence, the required sum is 4a−6b+27c\bm{4a - 6b + 27c}.

Question 5

Find the sum of the following algebraic expressions:

3y+4z−6x,2x−4y+z3y + 4z - 6x, 2x - 4y + z and 5z−8y−x5z - 8y - x.

Answer

Adding columnwise, we get:

−6x+3y+4z2x−4y+z+−x−8y+5z−5x−9y+10z\begin{array}{rrrr} & -6x & + 3y & + 4z \\ & 2x & - 4y & + z \\ {+} & -x & - 8y & + 5z \\ \hline & -5x & - 9y & + 10z \end{array}

Hence, the required sum is −5x−9y+10z\bm{-5x - 9y + 10z}.

Question 6

Find the sum of the following algebraic expressions:

8x−5y+3z,6y−11x−z,7y−2z8x - 5y + 3z, 6y - 11x - z, 7y - 2z and x−2yx - 2y.

Answer

Adding columnwise, we get:

8x−5y+3z−11x+6y−z7y−2z+x−2y−2x+6y\begin{array}{rrrr} & 8x &- 5y &+ 3z \\ & -11x &+ 6y &- z \\ & & 7y &- 2z \\ {+} &x &- 2y& \\ \hline &-2x &+ 6y& \end{array}

Hence, the required sum is −2x+6y\bm{-2x + 6y}.

Question 7

Find the sum of the following algebraic expressions:

10x2+8x−7,3x−13x2+510x^2 + 8x - 7, 3x - 13x^2 + 5 and 9−6x−5x29 - 6x - 5x^2.

Answer

Adding columnwise, we get:

10x2+8x−7−13x2+3x+5+−5x2−6x+9−8x2+5x+7\begin{array}{rrrr} & 10x^2 & + 8x & - 7 \\ & -13x^2 & + 3x & + 5 \\ {+} & -5x^2 & - 6x & + 9 \\ \hline & -8x^2 & + 5x & + 7 \end{array}

Hence, the required sum is −8x2+5x+7\bm{-8x^2 + 5x + 7}.

Question 8

Find the sum of the following algebraic expressions:

5x3−8x2+6x−3,x2−2x+155x^3 - 8x^2 + 6x - 3, x^2 - 2x + 15 and 16−2x316 - 2x^3.

Answer

Adding columnwise, we get:

5x3−8x2+6x−3x2−2x+15+−2x3+163x3−7x2+4x+28\begin{array}{rrrrr} & 5x^3 & - 8x^2 & + 6x & - 3 \\ & & x^2 & - 2x & + 15 \\ {+} & -2x^3 & & & + 16 \\ \hline & 3x^3 & - 7x^2 & + 4x & + 28 \end{array}

Hence, the required sum is 3x3−7x2+4x+28\bm{3x^3 - 7x^2 + 4x + 28}.

Question 9

Find the sum of the following algebraic expressions:

3x2−15x+73,−14x2+13x−16,−2x2−12x+1153x^2 - \dfrac{1}{5}x + \dfrac{7}{3}, -\dfrac{1}{4}x^2 + \dfrac{1}{3}x - \dfrac{1}{6}, -2x^2 - \dfrac{1}{2}x + \dfrac{1}{15}

Answer

Collecting the like terms, we get:

Coefficient of x2=3−14−2=1−14=4−14=34x^2 = 3 - \dfrac{1}{4} - 2 = 1 - \dfrac{1}{4} = \dfrac{4 - 1}{4} = \dfrac{3}{4}

Coefficient of x=−15+13−12=−6+10−1530=−1130x = -\dfrac{1}{5} + \dfrac{1}{3} - \dfrac{1}{2} = \dfrac{-6 + 10 - 15}{30} = -\dfrac{11}{30}

Constant term =73−16+115=70−5+230=6730= \dfrac{7}{3} - \dfrac{1}{6} + \dfrac{1}{15} = \dfrac{70 - 5 + 2}{30} = \dfrac{67}{30}

Hence, the required sum is 34x2−1130x+6730\bm{\dfrac{3}{4}x^2 - \dfrac{11}{30}x + \dfrac{67}{30}}.

Question 10

Find the sum of the following algebraic expressions:

2a2−3ab+4bc,6ab−a2−5bc2a^2 - 3ab + 4bc, 6ab - a^2 - 5bc and 13bc−8a2+ab13bc - 8a^2 + ab.

Answer

Adding columnwise, we get:

2a2−3ab+4bc−a2+6ab−5bc+−8a2+ab+13bc−7a2+4ab+12bc\begin{array}{rrrr} & 2a^2 & - 3ab & + 4bc \\ & -a^2 & + 6ab & - 5bc \\ {+} & -8a^2 & + ab & + 13bc \\ \hline & -7a^2 & + 4ab & + 12bc \end{array}

Hence, the required sum is −7a2+4ab+12bc\bm{-7a^2 + 4ab + 12bc}.

Question 11

Find the sum of the following algebraic expressions:

6x2+2xy−y2,xy−x2−2y26x^2 + 2xy - y^2, xy - x^2 - 2y^2 and 5y2−8x2+3xy5y^2 - 8x^2 + 3xy.

Answer

Adding columnwise, we get:

6x2+2xy−y2−x2+xy−2y2+−8x2+3xy+5y2−3x2+6xy+2y2\begin{array}{rrrr} & 6x^2 & + 2xy & - y^2 \\ & -x^2 & + xy & - 2y^2 \\ {+} & -8x^2 & + 3xy & + 5y^2 \\ \hline & -3x^2 & + 6xy & + 2y^2 \end{array}

Hence, the required sum is −3x2+6xy+2y2\bm{-3x^2 + 6xy + 2y^2}.

Question 12

Find the sum of the following algebraic expressions:

2x2−3y2+6z2,y2−2x2+z2,z2−6x2−8y22x^2 - 3y^2 + 6z^2, y^2 - 2x^2 + z^2, z^2 - 6x^2 - 8y^2 and x2−y2x^2 - y^2.

Answer

Adding columnwise, we get:

2x2−3y2+6z2−2x2+y2+z2−6x2−8y2+z2+x2−y2−5x2−11y2+8z2\begin{array}{rrrr} & 2x^2 & - 3y^2 & + 6z^2 \\ & -2x^2 & + y^2 & + z^2 \\ & -6x^2 & - 8y^2 & + z^2 \\ {+} & x^2 & - y^2 & \\ \hline & -5x^2 & - 11y^2 & + 8z^2 \end{array}

Hence, the required sum is −5x2−11y2+8z2\bm{-5x^2 - 11y^2 + 8z^2}.

Question 13

Find the sum of the following algebraic expressions:

6m2n+3mn−2n2,n2−mn−m2n6m^2n + 3mn - 2n^2, n^2 - mn - m^2n and mn−3n2−4m2nmn - 3n^2 - 4m^2n.

Answer

Adding columnwise, we get:

6m2n+3mn−2n2−m2n−mn+n2+−4m2n+mn−3n2m2n+3mn−4n2\begin{array}{rrrr} & 6m^2n & + 3mn & - 2n^2 \\ & -m^2n & - mn & + n^2 \\ {+} & -4m^2n & + mn & - 3n^2 \\ \hline & m^2n & + 3mn & - 4n^2 \end{array}

Hence, the required sum is m2n+3mn−4n2\bm{m^2n + 3mn - 4n^2}.

Question 14(i)

Simplify:

2m3−5m2+3m−6−5m3+2m2−8m+2+6m+52m^3 - 5m^2 + 3m - 6 - 5m^3 + 2m^2 - 8m + 2 + 6m + 5.

Answer

Given,

2m3−5m2+3m−6−5m3+2m2−8m+2+6m+52m^3 - 5m^2 + 3m - 6 - 5m^3 + 2m^2 - 8m + 2 + 6m + 5

Re-arranging and collecting the like terms, we get:

⇒(2m3−5m3)+(−5m2+2m2)+(3m−8m+6m)+(−6+2+5)⇒(2−5)m3+(−5+2)m2+(3−8+6)m+1⇒−3m3−3m2+m+1\Rightarrow (2m^3 - 5m^3) + (-5m^2 + 2m^2) + (3m - 8m + 6m) + (-6 + 2 + 5)\\[1em] \Rightarrow (2 - 5)m^3 + (-5 + 2)m^2 + (3 - 8 + 6)m + 1\\[1em] \Rightarrow \bm{-3m^3 - 3m^2 + m + 1}

Hence, the simplified expression is −3m3−3m2+m+1\bm{-3m^3 - 3m^2 + m + 1}.

Question 14(ii)

Simplify:

2x4−5x3+2x−5+6x3−3x+7−x4−2x3+22x^4 - 5x^3 + 2x - 5 + 6x^3 - 3x + 7 - x^4 - 2x^3 + 2.

Answer

Given,

2x4−5x3+2x−5+6x3−3x+7−x4−2x3+22x^4 - 5x^3 + 2x - 5 + 6x^3 - 3x + 7 - x^4 - 2x^3 + 2

Re-arranging and collecting the like terms, we get:

⇒(2x4−x4)+(−5x3+6x3−2x3)+(2x−3x)+(−5+7+2)⇒(2−1)x4+(−5+6−2)x3+(2−3)x+4⇒x4−x3−x+4\Rightarrow (2x^4 - x^4) + (-5x^3 + 6x^3 - 2x^3) + (2x - 3x) + (-5 + 7 + 2)\\[1em] \Rightarrow (2 - 1)x^4 + (-5 + 6 - 2)x^3 + (2 - 3)x + 4\\[1em] \Rightarrow \bm{x^4 - x^3 - x + 4}

Hence, the simplified expression is x4−x3−x+4\bm{x^4 - x^3 - x + 4}.

Question 14(iii)

Simplify:

3p2−2pq+5p−4q+5pq−3p+4p2+3q3p^2 - 2pq + 5p - 4q + 5pq - 3p + 4p^2 + 3q.

Answer

Given,

3p2−2pq+5p−4q+5pq−3p+4p2+3q3p^2 - 2pq + 5p - 4q + 5pq - 3p + 4p^2 + 3q

Re-arranging and collecting the like terms, we get:

⇒(3p2+4p2)+(−2pq+5pq)+(5p−3p)+(−4q+3q)⇒(3+4)p2+(−2+5)pq+(5−3)p+(−4+3)q⇒7p2+3pq+2p−q\Rightarrow (3p^2 + 4p^2) + (-2pq + 5pq) + (5p - 3p) + (-4q + 3q)\\[1em] \Rightarrow (3 + 4)p^2 + (-2 + 5)pq + (5 - 3)p + (-4 + 3)q\\[1em] \Rightarrow \bm{7p^2 + 3pq + 2p - q}

Hence, the simplified expression is 7p2+3pq+2p−q\bm{7p^2 + 3pq + 2p - q}.

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