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Chapter 9

Unitary Method — Multiple Choice Questions

Class - 6 RS Aggarwal Mathematics Solutions



Exercise 9(B) - Multiple Choice Questions

Question 1

If the cost of 14 pens is ₹378, what is the cost of 8 such pens?

  1. ₹212

  2. ₹214

  3. ₹216

  4. ₹218

Answer

Cost of 14 pens = ₹ 378

Cost of 1 pen = ₹ (37814)\Big(\dfrac{378}{14}\Big) = ₹ 27 [Less pens, Less cost]

Cost of 8 pens = ₹ (27 x 8) = ₹ 216 [More pens, More cost]

Hence, option 3 is the correct option.

Question 2

A rail journey of 50 km costs ₹160. How much will a journey of 80 km cost?

  1. ₹260

  2. ₹256

  3. ₹280

  4. none of these

Answer

Cost of a journey of 50 km = ₹ 160

Cost of a journey of 1 km = ₹ (16050)=(165)\Big(\dfrac{160}{50}\Big) = \Big(\dfrac{16}{5}\Big) [Less distance, Less cost]

Cost of a journey of 80 km = ₹ (165×80)\Big(\dfrac{16}{5} \times 80 \Big) = ₹ (16 x 16) = ₹ 256 [More distance, More cost]

Hence, option 2 is the correct option.

Question 3

A car consumes 6 litres of petrol in covering 81 km. How much distance will it cover in 10 litres?

  1. 108 km

  2. 124 km

  3. 135 km

  4. 141 km

Answer

In 6 litres of petrol, distance covered = 81 km

In 1 litre of petrol, distance covered = (816) km =(272)\Big(\dfrac{81}{6}\Big) \text{ km }= \Big(\dfrac{27}{2}\Big) km [Less petrol, Less distance]

In 10 litres of petrol, distance covered = (272×10)\Big(\dfrac{27}{2} \times 10 \Big) km = (27 x 5) km = 135 km [More petrol, More distance]

Hence, option 3 is the correct option.

Question 4

A car covers 450 km in 4124\dfrac{1}{2} hours. How much time will it take in covering 350 km?

  1. 3 hours

  2. 3143\dfrac{1}{4} hours

  3. 3123\dfrac{1}{2} hours

  4. 4 hours

Answer

Time taken to cover 450 km = 412 hours =(92)4\dfrac{1}{2} \text{ hours }= \Big(\dfrac{9}{2}\Big) hours

Time taken to cover 1 km = (92×1450) hours =(1100)\Big(\dfrac{9}{2} \times \dfrac{1}{450}\Big) \text{ hours }= \Big(\dfrac{1}{100}\Big) hours [Less distance, Less time]

Time taken to cover 350 km

= (1100×350)\Big(\dfrac{1}{100} \times 350 \Big) hours

= (72)\Big(\dfrac{7}{2}\Big) hours

= 3123\dfrac{1}{2} hours [More distance, More time]

Hence, option 3 is the correct option.

Question 5

If the cost of 5 bars of soap is ₹85, what will be the cost of 1 dozen such bars?

  1. ₹238

  2. ₹204

  3. ₹198

  4. ₹208

Answer

1 dozen = 12 bars

Cost of 5 bars of soap = ₹ 85

Cost of 1 bar of soap = ₹ (855)\Big(\dfrac{85}{5}\Big) = ₹ 17 [Less bars, Less cost]

Cost of 12 bars of soap = ₹ (17 x 12) = ₹ 204 [More bars, More cost]

Hence, option 2 is the correct option.

Question 6

If the cost of 6 note-books is ₹282, what is the cost of 8 such note-books?

  1. ₹376

  2. ₹243

  3. ₹348

  4. ₹364

Answer

Cost of 6 note-books = ₹ 282

Cost of 1 note-book = ₹ (2826)\Big(\dfrac{282}{6}\Big) = ₹ 47 [Less note-books, Less cost]

Cost of 8 note-books = ₹ (47 x 8) = ₹ 376 [More note-books, More cost]

Hence, option 1 is the correct option.

Question 7

If the cost of 16 oranges is ₹124, how many oranges can be bought for ₹155?

  1. 18

  2. 24

  3. 20

  4. none of these

Answer

For ₹ 124, oranges bought = 16

For ₹ 1, oranges bought = (16124)=(431)\Big(\dfrac{16}{124}\Big) = \Big(\dfrac{4}{31}\Big) [Less money, Less oranges]

For ₹ 155, oranges bought = (431×155)\Big(\dfrac{4}{31} \times 155 \Big) = (4 x 5) = 20 [More money, More oranges]

Hence, option 3 is the correct option.

Question 8

If the cost of 20 packets of 8 pencils each is ₹400, what is the cost of 25 packets of 12 pencils each?

  1. ₹725

  2. ₹750

  3. ₹735

  4. ₹760

Answer

Number of pencils in 20 packets of 8 pencils each = (20 x 8) = 160

Number of pencils in 25 packets of 12 pencils each = (25 x 12) = 300

Now, cost of 160 pencils = ₹ 400

Cost of 1 pencil = ₹ (400160)=(52)\Big(\dfrac{400}{160}\Big) = \Big(\dfrac{5}{2}\Big) [Less pencils, Less cost]

Cost of 300 pencils = ₹ (52×300)\Big(\dfrac{5}{2} \times 300 \Big) = ₹ (5 x 150) = ₹ 750 [More pencils, More cost]

Hence, option 2 is the correct option.

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