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Chapter 10

Percentage — Multiple Choice Questions

Class - 6 RS Aggarwal Mathematics Solutions



Exercise 10(D) - Multiple Choice Questions

Question 1

What per cent of 850 is 36?

  1. 6%

  2. 8%

  3. 44174\dfrac{4}{17}%

  4. 12%

Answer

Required percentage = (36850×100)\left(\dfrac{36}{850} \times 100\right)%

=3600850= \dfrac{3600}{850}%

=7217= \dfrac{72}{17}%

=4417= 4\dfrac{4}{17}%

Hence, option 3 is the correct option.

Question 2

What per cent of 65 is 78?

  1. 5%

  2. 13%

  3. 120%

  4. 113%

Answer

Required percentage = (7865×100)\left(\dfrac{78}{65} \times 100\right)%

=780065= \dfrac{7800}{65}%

= 120%

Hence, option 3 is the correct option.

Question 3

If 15% of x = 9, then x = ?

  1. 20

  2. 30

  3. 135

  4. 60

Answer

15% of x = 9

15100×x=9x=9×10015x=90015x=60\Rightarrow \dfrac{15}{100} \times x = 9\\[1em] \Rightarrow x = \dfrac{9 \times 100}{15}\\[1em] \Rightarrow x = \dfrac{900}{15}\\[1em] \Rightarrow x = 60

Hence, option 4 is the correct option.

Question 4

6236\dfrac{2}{3}% when expressed as a ratio, is:

  1. 20 : 3

  2. 9 : 2

  3. 1 : 15

  4. none of these

Answer

6236\dfrac{2}{3}% = 203\dfrac{20}{3}%

203×1100203001151:15\Rightarrow \dfrac{20}{3} \times \dfrac{1}{100}\\[1em] \Rightarrow \dfrac{20}{300}\\[1em] \Rightarrow \dfrac{1}{15}\\[1em] \Rightarrow 1 : 15

Hence, option 3 is the correct option.

Question 5

162316\dfrac{2}{3}% when expressed as a fraction, is:

  1. 503\dfrac{50}{3}

  2. 16\dfrac{1}{6}

  3. 23\dfrac{2}{3}

  4. none of these

Answer

162316\dfrac{2}{3}% = 503\dfrac{50}{3}%

503×11005030016\Rightarrow \dfrac{50}{3} \times \dfrac{1}{100}\\[1em] \Rightarrow \dfrac{50}{300}\\[1em] \Rightarrow \dfrac{1}{6}

Hence, option 2 is the correct option.

Question 6

6.5, when expressed as a percentage, is:

  1. 65%

  2. 650%

  3. 6.5%

  4. 0.65%

Answer

To convert a decimal into a percentage, multiply it by 100 and put the % sign.

⇒ 6.5

⇒ (6.5 × 100)%

⇒ 650%

Hence, option 2 is the correct option.

Question 7

35\dfrac{3}{5}, when expressed as a percentage, is:

  1. 60%

  2. 6%

  3. 0.6%

  4. 600%

Answer

To convert a fraction into a percentage, multiply it by 100 and put the % sign.

35\Rightarrow \dfrac{3}{5}

(35×100)\Rightarrow \left(\dfrac{3}{5} \times 100\right)%

3005\Rightarrow \dfrac{300}{5}%

60\Rightarrow 60%

Hence, option 1 is the correct option.

Question 8

What percent is 27 paise of ₹ 1.80?

  1. 20%

  2. 15%

  3. 32\dfrac{3}{2}%

  4. none of these

Answer

We know, ₹ 1 = 100 paise, so ₹ 1.80 = (1.80 × 100) paise = 180 paise.

Required percentage = (27180×100)\left(\dfrac{27}{180} \times 100\right)%

=2700180= \dfrac{2700}{180}%

= 15%

Hence, option 2 is the correct option.

Question 9

What per cent is 48 cm of 1.5 m?

  1. 32%

  2. 72%

  3. 64%

  4. 46%

Answer

We know, 1 m = 100 cm, so 1.5 m = (1.5 × 100) cm = 150 cm.

Required percentage = (48150×100)\left(\dfrac{48}{150} \times 100\right)%

=4800150= \dfrac{4800}{150}%

= 32%

Hence, option 1 is the correct option.

Question 10

What per cent is 175 g of 2.5 kg?

  1. 14%

  2. 21%

  3. 7%

  4. 28%

Answer

We know, 1 kg = 1000 g, so 2.5 kg = (2.5 × 1000) g = 2500 g.

Required percentage = (1752500×100)\left(\dfrac{175}{2500} \times 100\right)%

=175002500= \dfrac{17500}{2500}%

= 7%

Hence, option 3 is the correct option.

Question 11

The price of a bicycle is reduced from ₹ 4000 to ₹ 3500. The percentage decrease in the price is:

  1. 7.5%

  2. 8.5%

  3. 12.5%

  4. 142714\dfrac{2}{7}%

Answer

Original price = ₹ 4000 and reduced price = ₹ 3500.

Decrease in price = ₹ (4000 − 3500) = ₹ 500.

Percentage decrease = (DecreaseOriginal price×100)\left(\dfrac{\text{Decrease}}{\text{Original price}} \times 100\right)%

=(5004000×100)= \left(\dfrac{500}{4000} \times 100\right)%

=500004000= \dfrac{50000}{4000}%

= 12.5%

Hence, option 3 is the correct option.

Question 12

80% of teachers in a school are females and the number of male teachers is 25. The number of female teachers is:

  1. 90

  2. 100

  3. 115

  4. 125

Answer

Let the total number of teachers be x.

Percentage of female teachers = 80%.

Percentage of male teachers = (100 − 80)% = 20%.

Then, 20% of x = 25

20100×x=25x=25×10020x=125\Rightarrow \dfrac{20}{100} \times x = 25\\[1em] \Rightarrow x = \dfrac{25 \times 100}{20}\\[1em] \Rightarrow x = 125

Number of female teachers = 80% of 125

=80100×125=10000100=100= \dfrac{80}{100} \times 125\\[1em] = \dfrac{10000}{100}\\[1em] = 100

Hence, option 2 is the correct option.

Question 13

A mixture of milk and water contains 8 parts of milk and 2 parts of water. The percentage of milk in the mixture is:

  1. 8%

  2. 20%

  3. 40%

  4. 80%

Answer

Total parts in the mixture = 8 + 2 = 10.

Out of 10 parts, milk = 8 parts.

Percentage of milk in the mixture = (810×100)\left(\dfrac{8}{10} \times 100\right)%

=80010= \dfrac{800}{10}%

= 80%

Hence, option 4 is the correct option.

Question 14

An alloy contains 35% zinc, 20% copper and rest nickel. In 1.5 kg of alloy, the quantity of nickel is:

  1. 825 g

  2. 765 g

  3. 675 g

  4. 575 g

Answer

Percentage of zinc and copper = (35 + 20)% = 55%.

Percentage of nickel = (100 − 55)% = 45%.

We know, 1 kg = 1000 g, so 1.5 kg = 1500 g.

Quantity of nickel in 1.5 kg of alloy = 45% of 1500 g

=45100×1500=67500100=675 g= \dfrac{45}{100} \times 1500\\[1em] = \dfrac{67500}{100}\\[1em] = 675 \text{ g}

Hence, option 3 is the correct option.

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