Multiple Choice Questions
Out of the algebraic expressions, 8−5x,x2−53x+x212,8−x5 and 8.7, the polynomials are:
8−5x,8−x5 and 8.7
8−x and x2−53x+x212
8−5x and 8.7
x2−53x+x212 and 8−x5
Answer
x212=12x−2 and x5=5x−1 have negative exponents of x, so those two expressions are not polynomials. In 8−5x and 8.7, the exponents of x are whole numbers.
Hence, option 3 is the correct option.
The value of 3y(x3−z) for x=2,y=3 and z=5 is:
117
27
36
none of these
Answer
Substituting x=2,y=3 and z=5,
⇒3y(x3−z)⇒3(3)[(2)3−5]⇒9(8−5)=9×3=27.
Hence, option 2 is the correct option.
The sum of 4x+8x2+1,13−x2 and 6x−10−8x2 is:
−x2+10x+4
x2−10x−4
−x2−10x+4
x2+10x−4
Answer
Solving,
⇒(4x+8x2+1)+(13−x2)+(6x−10−8x2)⇒(8−1−8)x2+(4+6)x+(1+13−10)⇒−x2+10x+4.
Hence, option 1 is the correct option.
(3x2+7−6x)−(3x−4x2−15) is equal to:
−x2−3x−5
7x2−9x+22
x2+3x+5
7x2−9x−22
Answer
Solving,
⇒(3x2+7−6x)−(3x−4x2−15)⇒3x2+7−6x−3x+4x2+15⇒7x2−9x+22.
Hence, option 2 is the correct option.
(5x3y2z5)×(−4x2y3) is equal to:
20x5y5z5
−20x3yz5
−20x5y5z5
−9x3y3z5
Answer
Solving,
⇒(5x3y2z5)×(−4x2y3)⇒(5×−4)×x3+2×y2+3×z5⇒−20x5y5z5.
Hence, option 3 is the correct option.
(3x−4y)×(5x−6y) is equal to:
15x2+2xy+24y2
15x2−2xy+24y2
15x2+30xy+24y2
15x2−38xy+24y2
Answer
Solving,
⇒(3x−4y)(5x−6y)⇒15x2−18xy−20xy+24y2⇒15x2−38xy+24y2.
Hence, option 4 is the correct option.
(x−1)(x2+x+1) is equal to:
x3−1
x3+1
x3−x+1
x3+x+1
Answer
Solving,
⇒(x−1)(x2+x+1)⇒x3+x2+x−x2−x−1⇒x3−1.
Hence, option 1 is the correct option.
(x+1)(x2−x+1) is equal to:
x3−1
x3+1
x3−x+1
x3+x+1
Answer
Solving,
⇒(x+1)(x2−x+1)⇒x3−x2+x+x2−x+1⇒x3+1.
Hence, option 2 is the correct option.
(−63x5y3z10)÷(−7x2y5z7) is equal to:
−9x3z÷y2
9x3y2z
9x3z3÷y2
−9x3y2z
Answer
Solving,
⇒−7x2y5z7−63x5y3z10⇒9×x5−2×y3−5×z10−7⇒y29x3z3
Hence, option 3 is the correct option.
(4x3y−12x2y2)÷(−4xy) is equal to:
4x2+3xy
4x2−3x
−x2+3xy
−x2−3xy
Answer
Solving,
⇒−4xy4x3y−12x2y2⇒−4xy4x3y−−4xy12x2y2⇒−x2+3xy
Hence, option 3 is the correct option.
2x−2(x+3)+4(x−1) is equal to:
−4x−10
−4x+10
4x+10
4x−10
Answer
Solving,
⇒2x−2(x+3)+4(x−1)⇒2x−2x−6+4x−4⇒4x−10.
Hence, option 4 is the correct option.
The degree of (8−x)×(3−2x) is:
2
2x2
−19x
none of these
Answer
Solving,
⇒(8−x)(3−2x)⇒24−16x−3x+2x2⇒2x2−19x+24.
The highest power of x is 2, so the degree is 2.
Hence, option 1 is the correct option.
In expression 3xy2−5yz+2yz2, the coefficient of x is:
3y2−5yz+2yz2
y2−2yz2
3y2
3y2−5yz
Answer
Only the term 3xy2 contains x, and 3xy2=(3y2)×x. So the coefficient of x is 3y2.
Hence, option 3 is the correct option.
(9+x+2x2)−(3x2−5x)−(3+2x−x2) is equal to:
6+4x
6−4x
x2+4x+6
x2−4x−6
Answer
Solving,
⇒(9+x+2x2)−(3x2−5x)−(3+2x−x2)⇒9+x+2x2−3x2+5x−3−2x+x2⇒(2−3+1)x2+(1+5−2)x+(9−3)⇒6+4x.
Hence, option 1 is the correct option.
For x=2, the value of the expression 3(4x−1)−2(5−2x) is:
-19
19
10
-10
Answer
Substituting x=2,
3(4x−1)−2(5−2x)=3(8−1)−2(5−4)=3(7)−2(1)=21−2=19.
Hence, option 2 is the correct option.