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Chapter 14

Simple Linear Equations — Assertion Reasons Type Questions

Class - 7 Concise Mathematics Selina



Assertion Reasons Type Questions

Question 17

Assertion (A): Solution of 05x+214x+4=57 is 157\dfrac{0\cdot5x+2}{1\cdot4x+4} = \dfrac{5}{7} \text{ is } -1\dfrac{5}{7}.

Reason (R): ax+bax + b = 0, a0a \neq 0, a,ba, b ∈ R is a linear equation involving one variable.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

Solving,

0.5x+21.4x+4=577(0.5x+2)=5(1.4x+4)3.5x+14=7x+201420=7x3.5x6=3.5xx=63.5=127=157.\Rightarrow \dfrac{0.5x + 2}{1.4x + 4} = \dfrac{5}{7} \\[1em] \Rightarrow 7(0.5x + 2) = 5(1.4x + 4) \\[1em] \Rightarrow 3.5x + 14 = 7x + 20 \\[1em] \Rightarrow 14 - 20 = 7x - 3.5x \\[1em] \Rightarrow -6 = 3.5x \\[1em] \Rightarrow x = \dfrac{-6}{3.5} = -\dfrac{12}{7} = -1\dfrac{5}{7}.

So, Assertion (A) is true.

ax+b=0ax + b = 0, where a0a \neq 0 and a,ba, b ∈ R, is indeed a linear equation in one variable. So, Reason (R) is true.

Hence, option 3 is the correct option.

Question 18

Assertion (A): The equation 4(2x5)(x3)=(4x3)(2x+1)4(2x - 5)(x - 3) = (4x - 3)(2x + 1) is not a linear equation.

Reason (R): An equation in which the greatest exponent of the variable after simplification is one, is called a linear equation in one unknown.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

Solving,

4(2x5)(x3)=(4x3)(2x+1)4(2x26x5x+15)=8x2+4x6x38x244x+60=8x22x3.\Rightarrow 4(2x - 5)(x - 3) = (4x - 3)(2x + 1) \\[1em] \Rightarrow 4(2x^{2} - 6x - 5x + 15) = 8x^{2} + 4x - 6x - 3 \\[1em] \Rightarrow 8x^{2} - 44x + 60 = 8x^{2} - 2x - 3.

On simplifying, the terms 8x28x^2 cancel out and we get 44x+60=2x3−44x + 60 = −2x − 3, in which the greatest exponent of xx is one.

So, the given equation is a linear equation and Assertion (A) is false.

An equation in which the greatest exponent of the variable after simplification is one, is called a linear equation in one unknown. So, Reason (R) is true.

Hence, option 2 is the correct option.

Question 19

Assertion (A): Thrice a number when subtracted from 73, gives 7. The number is 68.

Reason (R): For solving a word problem involving one unknown, we first write the statement in equation form in terms of one unknown and then solve the equation to find the value of the unknown.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

Let the number be xx.

Solving,

733x=7737=3x66=3xx=22.\Rightarrow 73 - 3x = 7 \\[1em] \Rightarrow 73 - 7 = 3x \\[1em] \Rightarrow 66 = 3x \\[1em] \Rightarrow x = 22.

Since the number is 22 and not 68, Assertion (A) is false.

The method described for solving a word problem involving one unknown is correct. So, Reason (R) is true.

Hence, option 2 is the correct option.

Question 20

Assertion (A): Given 7x3=3x+97x - 3 = 3x + 9

7x3x7x - 3x = 9 + 3 [Transposing -3 to RHS and transposing 3x3x to LHS]

Reason (R): Transposition is a process of taking any term of an equation from one side to the other side with its sign changed.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

Answer

On transposing −3 to R.H.S. it becomes +3, and on transposing 3x3x to L.H.S. it becomes −3x3x.

Solving,

7x3=3x+97x3x=9+3.\Rightarrow 7x - 3 = 3x + 9 \\[1em] \Rightarrow 7x - 3x = 9 + 3.

So, Assertion (A) is true.

Transposition is indeed the process of taking a term of an equation from one side to the other side with its sign changed. So, Reason (R) is true.

Hence, option 3 is the correct option.

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