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Chapter 6

Set Concepts — Exercise 6(D)

Class - 7 Concise Mathematics Selina



Exercise 6(D)

Question 1

If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find :

(i) A ∪ B

(ii) A ∩ B

(iii) A − B

(iv) B − A.

Answer

A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}.

(i) A ∪ B = {all elements of A and of B} = {4, 5, 6, 7, 8, 10, 12}

(ii) A ∩ B = {elements common to A and B} = {6, 8}

(iii) A − B = {elements of A which are not in B} = {4, 5, 7}

(iv) B − A = {elements of B which are not in A} = {10, 12}

Question 2

If A = {3, 5, 7, 9, 11} and B = {4, 7, 10}, find :

(i) n(A)

(ii) n(B)

(iii) A ∪ B and n(A ∪ B)

(iv) A ∩ B and n(A ∩ B)

Answer

A = {3, 5, 7, 9, 11} and B = {4, 7, 10}.

(i) A has 5 elements. n(A) = 5

(ii) B has 3 elements. n(B) = 3

(iii) A ∪ B = {3, 4, 5, 7, 9, 10, 11}

A ∪ B = {3, 4, 5, 7, 9, 10, 11} and n(A ∪ B) = 7

(iv) A ∩ B = {elements common to A and B} = {7}

A ∩ B = {7} and n(A ∩ B) = 1

Question 3

If A = {2, 4, 6, 8} and B = {3, 6, 9, 12}, find :

(i) (A ∩ B) and n(A ∩ B)

(ii) (A − B) and n(A − B)

(iii) n(B)

Answer

A = {2, 4, 6, 8} and B = {3, 6, 9, 12}.

(i) A ∩ B = {elements common to A and B} = {6}

A ∩ B = {6} and n(A ∩ B) = 1

(ii) A − B = {elements of A which are not in B} = {2, 4, 8}

A − B = {2, 4, 8} and n(A − B) = 3

(iii) B has 4 elements. n(B) = 4

Question 4

If P = {x : x is a factor of 12} and Q = {x : x is a factor of 16}, find :

(i) n(P)

(ii) n(Q)

(iii) Q − P and n(Q − P)

Answer

P = {x : x is a factor of 12} = {1, 2, 3, 4, 6, 12}.

Q = {x : x is a factor of 16} = {1, 2, 4, 8, 16}.

(i) P has 6 elements. n(P) = 6

(ii) Q has 5 elements. n(Q) = 5

(iii) Q − P = {elements of Q which are not in P} = {8, 16}

Q − P = {8, 16} and n(Q − P) = 2

Question 5

M = {x : x is a natural number between 0 and 8} and N = {x : x is a natural number from 5 to 10}. Find :

(i) M − N and n(M − N)

(ii) N − M and n(N − M)

Answer

M = {x : x is a natural number between 0 and 8} = {1, 2, 3, 4, 5, 6, 7}.

N = {x : x is a natural number from 5 to 10} = {5, 6, 7, 8, 9, 10}.

(i) M − N = {elements of M which are not in N} = {1, 2, 3, 4}

M − N = {1, 2, 3, 4} and n(M − N) = 4

(ii) N − M = {elements of N which are not in M} = {8, 9, 10}

N − M = {8, 9, 10} and n(N − M) = 3

Question 6

If A = {x : x is a natural number divisible by 2 and x < 16} and B = {x : x is a whole number divisible by 3 and x < 18}, find :

(i) n(A)

(ii) n(B)

(iii) A ∩ B and n(A ∩ B)

(iv) n(A − B)

Answer

A = {x : x is a natural number divisible by 2 and x < 16} = {2, 4, 6, 8, 10, 12, 14}.

B = {x : x is a whole number divisible by 3 and x < 18} = {0, 3, 6, 9, 12, 15}.

(i) A has 7 elements. n(A) = 7

(ii) B has 6 elements. n(B) = 6

(iii) A ∩ B = {elements common to A and B} = {6, 12}

A ∩ B = {6, 12} and n(A ∩ B) = 2

(iv) A − B = {elements of A which are not in B} = {2, 4, 8, 10, 14}

n(A − B) = 5

Question 7

Let A and B be two sets such that n(A) = 75, n(B) = 65 and n(A ∩ B) = 45, find :

(i) n(A ∪ B)

(ii) n(A − B)

(iii) n(B − A)

Answer

Given n(A) = 75, n(B) = 65 and n(A ∩ B) = 45.

(i) n(A ∪ B) = n(A) + n(B) − n(A ∩ B)

= 75 + 65 − 45

= 140 − 45

n(A ∪ B) = 95

(ii) n(A − B) = n(A) − n(A ∩ B)

= 75 − 45

n(A − B) = 30

(iii) n(B − A) = n(B) − n(A ∩ B)

= 65 − 45

n(B − A) = 20

Question 8

Let A and B be two sets such that n(A) = 45, n(B) = 38 and n(A ∪ B) = 70, find :

(i) n(A ∩ B)

(ii) n(A − B)

(iii) n(B − A)

Answer

Given n(A) = 45, n(B) = 38 and n(A ∪ B) = 70.

(i) n(A ∩ B) = n(A) + n(B) − n(A ∪ B)

= 45 + 38 − 70

= 83 − 70

n(A ∩ B) = 13

(ii) n(A − B) = n(A) − n(A ∩ B)

= 45 − 13

n(A − B) = 32

(iii) n(B − A) = n(B) − n(A ∩ B)

= 38 − 13

n(B − A) = 25

Question 9

Let n(A) = 30, n(B) = 27 and n(A ∪ B) = 45, find :

(i) n(A ∩ B)

(ii) n(A − B)

Answer

Given n(A) = 30, n(B) = 27 and n(A ∪ B) = 45.

(i) n(A ∩ B) = n(A) + n(B) − n(A ∪ B)

= 30 + 27 − 45

= 57 − 45

n(A ∩ B) = 12

(ii) n(A − B) = n(A) − n(A ∩ B)

= 30 − 12

n(A − B) = 18

Question 10

Let n(A) = 31, n(B) = 20 and n(A ∩ B) = 6, find :

(i) n(A − B)

(ii) n(B − A)

(iii) n(A ∪ B)

Answer

Given n(A) = 31, n(B) = 20 and n(A ∩ B) = 6.

(i) n(A − B) = n(A) − n(A ∩ B)

= 31 − 6

n(A − B) = 25

(ii) n(B − A) = n(B) − n(A ∩ B)

= 20 − 6

n(B − A) = 14

(iii) n(A ∪ B) = n(A) + n(B) − n(A ∩ B)

= 31 + 20 − 6

= 51 − 6

n(A ∪ B) = 45

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