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Chapter 5

Exponents — Multiple Choice Questions

Class - 7 Concise Mathematics Selina



Multiple Choice Questions

Question 1

(23)3\left(-\dfrac{2}{3}\right)^{-3} is equal to :

  1. 278\dfrac{27}{8}

  2. 827\dfrac{-8}{27}

  3. 278\dfrac{-27}{8}

  4. 827\dfrac{8}{27}

Answer

Solving,

(23)3=(32)3=(3)×(3)×(3)2×2×2=278\Rightarrow \left(-\dfrac{2}{3}\right)^{-3}\\[1em] = \left(-\dfrac{3}{2}\right)^{3}\\[1em] = \dfrac{(-3) \times (-3) \times (-3)}{2 \times 2 \times 2}\\[1em] = \dfrac{-27}{8}

Hence, Option 3 is the correct option.

Question 2

(-3)2 ÷ (12)3\left(-\dfrac{1}{2}\right)^3 is equal to :

  1. 98-\dfrac{9}{8}

  2. 98\dfrac{9}{8}

  3. -72

  4. 72

Answer

Solving,

(3)2÷(12)3=9÷(18)=9×(8)=72\Rightarrow (-3)^2 ÷ \left(-\dfrac{1}{2}\right)^3\\[1em] = 9 ÷ \left(-\dfrac{1}{8}\right)\\[1em] = 9 \times (-8)\\[1em] = -72

Hence, Option 3 is the correct option.

Question 3

The reciprocal of (-2)5 is :

  1. -32

  2. 132-\dfrac{1}{32}

  3. 32

  4. 132\dfrac{1}{32}

Answer

Solving,

⇒ (-2)5 = (-2) × (-2) × (-2) × (-2) × (-2) = -32.

Reciprocal of -32 = 132=132\dfrac{1}{-32} = -\dfrac{1}{32}

Hence, Option 2 is the correct option.

Question 4

If (15)3×(15)x+3\left(\dfrac{1}{5}\right)^3 \times \left(\dfrac{1}{5}\right)^{x+3} = 5-2, then x is equal to :

  1. 4

  2. 14\dfrac{1}{4}

  3. 14-\dfrac{1}{4}

  4. -4

Answer

Solving,

(15)3×(15)x+3=52(15)3+x+3=52(15)x+6=52(51)x+6=525(x+6)=52\Rightarrow \left(\dfrac{1}{5}\right)^3 \times \left(\dfrac{1}{5}\right)^{x+3} = 5^{-2}\\[1em] \Rightarrow \left(\dfrac{1}{5}\right)^{3 + x + 3} = 5^{-2}\\[1em] \Rightarrow \left(\dfrac{1}{5}\right)^{x + 6} = 5^{-2}\\[1em] \Rightarrow (5^{-1})^{x + 6} = 5^{-2}\\[1em] \Rightarrow 5^{-(x + 6)} = 5^{-2}

Comparing the powers of the same base,

⇒ -(x + 6) = -2

⇒ x + 6 = 2

⇒ x = -4

Hence, Option 4 is the correct option.

Question 5

40 + 60 - 80 is equal to :

  1. 0

  2. 1

  3. 2

  4. 12-\dfrac{1}{2}

Answer

As any non-zero base raised to the power zero is equal to 1,

⇒ 40 + 60 - 80

⇒ 1 + 1 - 1

⇒ 1.

Hence, Option 2 is the correct option.

Question 6

(23)2 ÷ (22)4 is equal to :

  1. 4

  2. -4

  3. 14-\dfrac{1}{4}

  4. 14\dfrac{1}{4}

Answer

Solving,

⇒ (23)2 ÷ (22)4

= 23 × 2 ÷ 22 × 4

= 26 ÷ 28

= 26-8

= 2-2

= 122=14\dfrac{1}{2^2} = \dfrac{1}{4}

Hence, Option 4 is the correct option.

Question 7

If (23)x=24332\left(-\dfrac{2}{3}\right)^x = -\dfrac{243}{32}, then x is equal to :

  1. -5

  2. 5

  3. 15\dfrac{1}{5}

  4. 15-\dfrac{1}{5}

Answer

Solving,

(23)x=24332(23)x=3525(23)x=(32)5(23)x=(23)5\Rightarrow \left(-\dfrac{2}{3}\right)^x = -\dfrac{243}{32}\\[1em] \Rightarrow \left(-\dfrac{2}{3}\right)^x = -\dfrac{3^5}{2^5}\\[1em] \Rightarrow \left(-\dfrac{2}{3}\right)^x = \left(-\dfrac{3}{2}\right)^5\\[1em] \Rightarrow \left(-\dfrac{2}{3}\right)^x = \left(-\dfrac{2}{3}\right)^{-5}

Comparing the powers of the same base,

⇒ x = -5.

Hence, Option 1 is the correct option.

Question 8

(-4)3 ÷ (4)4 is equal to :

  1. 4

  2. -4

  3. 14-\dfrac{1}{4}

  4. 14\dfrac{1}{4}

Answer

Solving,

(4)3÷(4)4=(4)344=64256=14\Rightarrow (-4)^3 ÷ (4)^4\\[1em] = \dfrac{(-4)^3}{4^4}\\[1em] = \dfrac{-64}{256}\\[1em] = -\dfrac{1}{4}

Hence, Option 3 is the correct option.

Question 9

70 × 5 - (-2)3 - 80 is equal to :

  1. 12

  2. -12

  3. 112\dfrac{1}{12}

  4. 112-\dfrac{1}{12}

Answer

Solving,

⇒ 70 × 5 - (-2)3 - 80

⇒ (1 × 5) - (-8) - 1

⇒ 5 + 8 - 1

⇒ 12.

Hence, Option 1 is the correct option.

Question 10

If (910)2×(109)5=(910)1m\left(\dfrac{9}{10}\right)^2 \times \left(\dfrac{10}{9}\right)^5 = \left(\dfrac{9}{10}\right)^{1-m}, then m is equal to :

  1. 4

  2. -4

  3. 14\dfrac{1}{4}

  4. 14-\dfrac{1}{4}

Answer

Solving,

(910)2×(109)5=(910)1m(910)2×(910)5=(910)1m(910)25=(910)1m(910)3=(910)1m\Rightarrow \left(\dfrac{9}{10}\right)^2 \times \left(\dfrac{10}{9}\right)^5 = \left(\dfrac{9}{10}\right)^{1-m}\\[1em] \Rightarrow \left(\dfrac{9}{10}\right)^2 \times \left(\dfrac{9}{10}\right)^{-5} = \left(\dfrac{9}{10}\right)^{1-m}\\[1em] \Rightarrow \left(\dfrac{9}{10}\right)^{2 - 5} = \left(\dfrac{9}{10}\right)^{1-m}\\[1em] \Rightarrow \left(\dfrac{9}{10}\right)^{-3} = \left(\dfrac{9}{10}\right)^{1-m}

Comparing the powers of the same base,

⇒ 1 - m = -3

⇒ m = 4

Hence, Option 1 is the correct option.

Question 11

(35)1÷(52)1\left(\dfrac{3}{5}\right)^{-1} \div \left(\dfrac{-5}{2}\right)^{-1} is equal to :

  1. 256\dfrac{25}{6}

  2. 256-\dfrac{25}{6}

  3. 625\dfrac{6}{25}

  4. 625-\dfrac{6}{25}

Answer

Solving,

(35)1÷(52)1=53÷(25)=53×(52)=256\Rightarrow \left(\dfrac{3}{5}\right)^{-1} \div \left(\dfrac{-5}{2}\right)^{-1}\\[1em] = \dfrac{5}{3} \div \left(-\dfrac{2}{5}\right)\\[1em] = \dfrac{5}{3} \times \left(-\dfrac{5}{2}\right)\\[1em] = -\dfrac{25}{6}

Hence, Option 2 is the correct option.

Question 12

If (-3)x - 1 = - 243, then (243)x-6 is equal to :

  1. (243)-12

  2. 243

  3. 0

  4. 1

Answer

Solving,

⇒ (-3)x - 1 = -243

⇒ (-3)x - 1 = (-3)5

Comparing the powers of the same base,

⇒ x - 1 = 5

⇒ x = 6

Now,

⇒ (243)x-6 = (243)6 - 6 = (243)0 = 1.

Hence, Option 4 is the correct option.

Question 13

{(52)3 × 54} ÷ 53 is equal to :

  1. 513

  2. 57

  3. 521

  4. none of these

Answer

⇒ {(52)3 × 54} ÷ 53

⇒ {52 × 3 × 54} ÷ 53

⇒ {56 × 54} ÷ 53

⇒ 56 + 4 ÷ 53

⇒ 510 ÷ 53

⇒ 510 - 3

⇒ 57.

Hence, Option 2 is the correct option.

Question 14

If (3-1) × x = (6)-1, then the value of x is :

  1. 12\dfrac{1}{2}

  2. 12-\dfrac{1}{2}

  3. 2

  4. -2

Answer

Solving,

(31)×x=(6)113×x=16x=16×3x=36x=12\Rightarrow (3^{-1}) \times x = (6)^{-1}\\[1em] \Rightarrow \dfrac{1}{3} \times x = \dfrac{1}{6}\\[1em] \Rightarrow x = \dfrac{1}{6} \times 3\\[1em] \Rightarrow x = \dfrac{3}{6}\\[1em] \Rightarrow x = \dfrac{1}{2}

Hence, Option 1 is the correct option.

Question 15

If (-9)-1 ÷ x = (18)-1, then the value of x is :

  1. 2

  2. -2

  3. 12\dfrac{1}{2}

  4. 12-\dfrac{1}{2}

Answer

Solving,

(9)1÷x=(18)119÷x=11819×1x=1181x=118×(9)1x=9181x=12x=2\Rightarrow (-9)^{-1} ÷ x = (18)^{-1}\\[1em] \Rightarrow -\dfrac{1}{9} ÷ x = \dfrac{1}{18}\\[1em] \Rightarrow -\dfrac{1}{9} \times \dfrac{1}{x} = \dfrac{1}{18}\\[1em] \Rightarrow \dfrac{1}{x} = \dfrac{1}{18} \times (-9)\\[1em] \Rightarrow \dfrac{1}{x} = -\dfrac{9}{18}\\[1em] \Rightarrow \dfrac{1}{x} = -\dfrac{1}{2}\\[1em] \Rightarrow x = -2

Hence, Option 2 is the correct option.

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