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Chapter 13

Fundamental Concepts of Algebra — Exercise 13(B)

Class - 7 Concise Mathematics Selina



Exercise 13(B)

Question 1

Fill in the blanks:

(i) 8x+5x=8x + 5x = .............

(ii) 8x−5x=8x - 5x = .............

(iii) 6xy2+9xy2=6xy^2 + 9xy^2 = .............

(iv) 6xy2−9xy2=6xy^2 - 9xy^2 = .............

(v) The sum of 8a,6a8a, 6a and 5b=5b = .....................

(vi) The addition of 5,7xy,65, 7xy, 6 and 3xy=3xy = ....................

(vii) 4a+3b−7a+4b=4a + 3b - 7a + 4b = ....................

(viii) −15x+13x+8=- 15x + 13x + 8 = ....................

(ix) 6x2y+13xy2−4x2y+2xy2=6x^2y + 13xy^2 - 4x^2y + 2xy^2 = ....................

(x) 16x2−9x2=16x^2 - 9x^2 = .................... and 25xy2−17xy2=25xy^2 - 17xy^2 = ....................

Answer

(i) 8x+5x=(8+5)x=13x8x + 5x = (8 + 5)x = \bm{13x}.

(ii) 8x−5x=(8−5)x=3x8x - 5x = (8 - 5)x = \bm{3x}.

(iii) 6xy2+9xy2=(6+9)xy2=15xy26xy^2 + 9xy^2 = (6 + 9)xy^2 = \bm{15xy^2}.

(iv) 6xy2−9xy2=(6−9)xy2=−3xy26xy^2 - 9xy^2 = (6 - 9)xy^2 = \bm{-3xy^2}.

(v) 8a+6a+5b=(8+6)a+5b=14a+5b8a + 6a + 5b = (8 + 6)a + 5b = \bm{14a + 5b}.

(vi) 5+7xy+6+3xy=(5+6)+(7+3)xy=11+10xy5 + 7xy + 6 + 3xy = (5 + 6) + (7 + 3)xy = \bm{11 + 10xy}.

(vii) 4a+3b−7a+4b=(4−7)a+(3+4)b=−3a+7b4a + 3b - 7a + 4b = (4 - 7)a + (3 + 4)b = \bm{-3a + 7b}.

(viii) −15x+13x+8=(−15+13)x+8=−2x+8-15x + 13x + 8 = (-15 + 13)x + 8 = \bm{-2x + 8}.

(ix) 6x2y+13xy2−4x2y+2xy2=(6−4)x2y+(13+2)xy2=2x2y+15xy26x^2y + 13xy^2 - 4x^2y + 2xy^2 = (6 - 4)x^2y + (13 + 2)xy^2 = \bm{2x^2y + 15xy^2}.

(x) 16x2−9x2=7x216x^2 - 9x^2 = \bm{7x^2} and 25xy2−17xy2=8xy225xy^2 - 17xy^2 = \bm{8xy^2}.

Question 2(i)

Add:

−9x,3x-9x, 3x and 4x4x

Answer

Solving,

⇒−9x+3x+4x⇒(−9+3+4)x⇒−2x\Rightarrow -9x + 3x + 4x \\[1em] \Rightarrow (-9 + 3 + 4)x \\[1em] \Rightarrow -2x

Hence, the required sum = −2x\bm{-2x}.

Question 2(ii)

Add:

23y2,8y223y^2, 8y^2 and −12y2-12y^2

Answer

Solving,

⇒23y2+8y2+(−12y2)⇒(23+8−12)y2⇒19y2\Rightarrow 23y^2 + 8y^2 + (-12y^2) \\[1em] \Rightarrow (23 + 8 - 12)y^2 \\[1em] \Rightarrow 19y^2

Hence, the required sum = 19y2\bm{19y^2}.

Question 2(iii)

Add:

18pq,−15pq18pq, -15pq and 3pq3pq

Answer

Solving,

⇒18pq+(−15pq)+3pq⇒(18−15+3)pq⇒6pq\Rightarrow 18pq + (-15pq) + 3pq \\[1em] \Rightarrow (18 - 15 + 3)pq \\[1em] \Rightarrow 6pq

Hence, the required sum = 6pq\bm{6pq}.

Question 3(i)

Simplify:

3m+12m−5m3m + 12m - 5m

Answer

Solving,

⇒3m+12m−5m⇒(3+12−5)m⇒10m\Rightarrow 3m + 12m - 5m \\[1em] \Rightarrow (3 + 12 - 5)m \\[1em] \Rightarrow 10m

Hence, the simplified expression = 10m\bm{10m}.

Question 3(ii)

Simplify:

7n2−9n2+3n27n^2 - 9n^2 + 3n^2

Answer

Solving,

⇒7n2−9n2+3n2⇒(7−9+3)n2⇒n2\Rightarrow 7n^2 - 9n^2 + 3n^2 \\[1em] \Rightarrow (7 - 9 + 3)n^2 \\[1em] \Rightarrow n^2

Hence, the simplified expression = n2\bm{n^2}.

Question 3(iii)

Simplify:

25zy−8zy−6zy25zy - 8zy - 6zy

Answer

Solving,

⇒25zy−8zy−6zy⇒(25−8−6)zy⇒11yz\Rightarrow 25zy - 8zy - 6zy \\[1em] \Rightarrow (25 - 8 - 6)zy \\[1em] \Rightarrow 11yz

Hence, the simplified expression = 11yz\bm{11yz}.

Question 3(iv)

Simplify:

−5ax2+7ax2−12ax2-5ax^2 + 7ax^2 - 12ax^2

Answer

Solving,

⇒−5ax2+7ax2−12ax2⇒(−5+7−12)ax2⇒−10ax2\Rightarrow -5ax^2 + 7ax^2 - 12ax^2 \\[1em] \Rightarrow (-5 + 7 - 12)ax^2 \\[1em] \Rightarrow -10ax^2

Hence, the simplified expression = −10ax2\bm{-10ax^2}.

Question 3(v)

Simplify:

−16am+4mx+4am−15mx+5am-16am + 4mx + 4am - 15mx + 5am

Answer

Solving,

⇒−16am+4mx+4am−15mx+5am⇒(−16+4+5)am+(4−15)mx⇒−7am−11mx\Rightarrow -16am + 4mx + 4am - 15mx + 5am \\[1em] \Rightarrow (-16 + 4 + 5)am + (4 - 15)mx \\[1em] \Rightarrow -7am - 11mx

Hence, the simplified expression = −7am−11mx\bm{-7am - 11mx}.

Question 4(i)

Add:

a+ba + b and 2a+3b2a + 3b

Answer

Solving,

a+b+2a+3b3a+4b\begin{array}{rrr} & a & + b \\ + & 2a & + 3b \\ \hline & 3a & + 4b \\ \end{array}

Hence, the required sum = 3a+4b\bm{3a + 4b}.

Question 4(ii)

Add:

2x+y2x + y and 3x−4y3x - 4y

Answer

Solving,

2x+y+3x−4y5x−3y\begin{array}{rrr} & 2x & + y \\ + & 3x & - 4y \\ \hline & 5x & - 3y \\ \end{array}

Hence, the required sum = 5x−3y\bm{5x - 3y}.

Question 4(iii)

Add:

−3a+2b-3a + 2b and 3a+b3a + b

Answer

Solving,

−3a+2b+3a+b3b\begin{array}{rrr} & -3a & + 2b \\ + & 3a & + b \\ \hline & & 3b \\ \end{array}

Hence, the required sum = 3b\bm{3b}.

Question 4(iv)

Add:

4+x,5−2x4 + x, 5 - 2x and 6x6x

Answer

Solving,

4+x5−2x+6x9+5x\begin{array}{rrr} & 4 & + x \\ & 5 & - 2x \\ + & & 6x \\ \hline & 9 & + 5x \\ \end{array}

Hence, the required sum = 9+5x\bm{9 + 5x}.

Question 5(i)

Find the sum of:

3x+8y+7z,6y+4z−2x3x + 8y + 7z, 6y + 4z - 2x and 3y−4x+6z3y - 4x + 6z

Answer

Solving,

3x+8y+7z−2x+6y+4z+−4x+3y+6z−3x+17y+17z\begin{array}{rrrr} & 3x & + 8y & + 7z \\ & -2x & + 6y & + 4z \\ + & -4x & + 3y & + 6z \\ \hline & -3x & + 17y & + 17z \\ \end{array}

Hence, the required sum = −3x+17y+17z\bm{-3x + 17y + 17z}.

Question 5(ii)

Find the sum of:

3a+5b+2c,2a+3b−c3a + 5b + 2c, 2a + 3b - c and a+b+ca + b + c

Answer

Solving,

3a+5b+2c2a+3b−c+a+b+c6a+9b+2c\begin{array}{rrrr} & 3a & + 5b & + 2c \\ & 2a & + 3b & - c \\ + & a & + b & + c \\ \hline & 6a & + 9b & + 2c \\ \end{array}

Hence, the required sum = 6a+9b+2c\bm{6a + 9b + 2c}.

Question 5(iii)

Find the sum of:

4x2+8xy−2y24x^2 + 8xy - 2y^2 and 8xy−5y2+x28xy - 5y^2 + x^2

Answer

Solving,

4x2+8xy−2y2+x2+8xy−5y25x2+16xy−7y2\begin{array}{rrrr} & 4x^2 & + 8xy & - 2y^2 \\ + & x^2 & + 8xy & - 5y^2 \\ \hline & 5x^2 & + 16xy & - 7y^2 \\ \end{array}

Hence, the required sum = 5x2+16xy−7y2\bm{5x^2 + 16xy - 7y^2}.

Question 5(iv)

Find the sum of:

9x2−6x+7,5−4x9x^2 - 6x + 7, 5 - 4x and 6−3x26 - 3x^2

Answer

Solving,

9x2−6x+7−4x+5+−3x2+66x2−10x+18\begin{array}{rrrr} & 9x^2 & - 6x & + 7 \\ & & -4x & + 5 \\ + & -3x^2 & & + 6 \\ \hline & 6x^2 & - 10x & + 18 \\ \end{array}

Hence, the required sum = 6x2−10x+18\bm{6x^2 - 10x + 18}.

Question 5(v)

Find the sum of:

5x2−2xy+3y2,−2x2+5xy+9y25x^2 - 2xy + 3y^2, - 2x^2 + 5xy + 9y^2 and 3x2−xy−4y23x^2 - xy - 4y^2

Answer

Solving,

5x2−2xy+3y2−2x2+5xy+9y2+3x2−xy−4y26x2+2xy+8y2\begin{array}{rrrr} & 5x^2 & - 2xy & + 3y^2 \\ & -2x^2 & + 5xy & + 9y^2 \\ + & 3x^2 & - xy & - 4y^2 \\ \hline & 6x^2 & + 2xy & + 8y^2 \\ \end{array}

Hence, the required sum = 6x2+2xy+8y2\bm{6x^2 + 2xy + 8y^2}.

Question 5(vi)

Find the sum of:

a2+b2+2ab,2b2+c2+2bca^2 + b^2 + 2ab, 2b^2 + c^2 + 2bc and 4c2−a2+2ac4c^2 - a^2 + 2ac

Answer

Solving,

a2+b2+2ab2b2+c2+2bc+−a2+4c2+2ac3b2+5c2+2ab+2bc+2ac\begin{array}{rrrrrrr} & a^2 & + b^2 & & + 2ab & & \\ & & 2b^2 & + c^2 & & + 2bc & \\ + & -a^2 & & + 4c^2 & & & + 2ac \\ \hline & & 3b^2 & + 5c^2 & + 2ab & + 2bc & + 2ac \\ \end{array}

Hence, the required sum = 3b2+5c2+2ab+2bc+2ac\bm{3b^2 + 5c^2 + 2ab + 2bc + 2ac}.

Question 5(vii)

Find the sum of:

9ax−6bx+8,4ax+8bx−79ax - 6bx + 8, 4ax + 8bx - 7 and −6ax−4bx−3- 6ax - 4bx - 3

Answer

Solving,

9ax−6bx+84ax+8bx−7+−6ax−4bx−37ax−2bx−2\begin{array}{rrrr} & 9ax & - 6bx & + 8 \\ & 4ax & + 8bx & - 7 \\ + & -6ax & - 4bx & - 3 \\ \hline & 7ax & - 2bx & - 2 \\ \end{array}

Hence, the required sum = 7ax−2bx−2\bm{7ax - 2bx - 2}.

Question 5(viii)

Find the sum of:

abc+2ba+3ac,4ca−4ab+2bcaabc + 2ba + 3ac, 4ca - 4ab + 2bca and 2ab−3abc−6ac2ab - 3abc - 6ac

Answer

Solving,

abc+2ab+3ac2abc−4ab+4ac+−3abc+2ab−6acac\begin{array}{rrrr} & abc & + 2ab & + 3ac \\ & 2abc & - 4ab & + 4ac \\ + & -3abc & + 2ab & - 6ac \\ \hline & & & ac \\ \end{array}

Hence, the required sum = ac\bm{ac}.

Question 5(ix)

Find the sum of:

4a2+5b2−6ab,3ab,6a2−2b24a^2 + 5b^2 - 6ab, 3ab, 6a^2 - 2b^2 and 4b2−5ab4b^2 - 5ab

Answer

Solving,

4a2+5b2−6ab3ab6a2−2b2+4b2−5ab10a2+7b2−8ab\begin{array}{rrrr} & 4a^2 & + 5b^2 & - 6ab \\ & & & 3ab \\ & 6a^2 & - 2b^2 & \\ + & & 4b^2 & - 5ab \\ \hline & 10a^2 & + 7b^2 & - 8ab \\ \end{array}

Hence, the required sum = 10a2+7b2−8ab\bm{10a^2 + 7b^2 - 8ab}.

Question 5(x)

Find the sum of:

x2+x−2,2x−3x2+5x^2 + x - 2, 2x - 3x^2 + 5 and 2x2−5x+72x^2 - 5x + 7

Answer

Solving,

x2+x−2−3x2+2x+5+2x2−5x+7−2x+10\begin{array}{rrrr} & x^2 & + x & - 2 \\ & -3x^2 & + 2x & + 5 \\ + & 2x^2 & - 5x & + 7 \\ \hline & & -2x & + 10 \\ \end{array}

Hence, the required sum = −2x+10\bm{-2x + 10}.

Question 5(xi)

Find the sum of:

4x3+2x2−x+1,2x3−5x2−3x+6,x2+84x^3 + 2x^2 - x + 1, 2x^3 - 5x^2 - 3x + 6, x^2 + 8 and 5x3−7x5x^3 - 7x

Answer

Solving,

4x3+2x2−x+12x3−5x2−3x+6x2+8+5x3−7x11x3−2x2−11x+15\begin{array}{rrrrr} & 4x^3 & + 2x^2 & - x & + 1 \\ & 2x^3 & - 5x^2 & - 3x & + 6 \\ & & x^2 & & + 8 \\ + & 5x^3 & & - 7x & \\ \hline & 11x^3 & - 2x^2 & - 11x & + 15 \\ \end{array}

Hence, the required sum = 11x3−2x2−11x+15\bm{11x^3 - 2x^2 - 11x + 15}.

Question 6(i)

Find the sum of:

xx and 3y3y

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = x+3y\bm{x + 3y}.

Question 6(ii)

Find the sum of:

−2a-2a and +5

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = −2a+5\bm{-2a + 5}.

Question 6(iii)

Find the sum of:

−4x2-4x^2 and +7x+7x

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = −4x2+7x\bm{-4x^2 + 7x}.

Question 6(iv)

Find the sum of:

+4a+4a and −7b-7b

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = 4a−7b\bm{4a - 7b}.

Question 6(v)

Find the sum of:

x3,3x2yx^3, 3x^2y and 2y22y^2

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = x3+3x2y+2y2\bm{x^3 + 3x^2y + 2y^2} .

Question 6(vi)

Find the sum of:

11 and −by-by

Answer

Since the given terms are unlike terms, their sum cannot be simplified further.

Sum = 11−by\bm{11 - by}.

Question 7

The sides of a triangle are 2x+3y,x+5y2x + 3y, x + 5y and 7x−2y7x - 2y. Find its perimeter.

Answer

Perimeter of a triangle = sum of its three sides

Solving,

⇒(2x+3y)+(x+5y)+(7x−2y)⇒(2+1+7)x+(3+5−2)y⇒10x+6y\Rightarrow (2x + 3y) + (x + 5y) + (7x - 2y) \\[1em] \Rightarrow (2 + 1 + 7)x + (3 + 5 - 2)y \\[1em] \Rightarrow 10x + 6y

Hence, the perimeter of the triangle = 10x+6y\bm{10x + 6y}.

Question 8

The two adjacent sides of a rectangle are 6a+9b6a + 9b and 8a−4b8a - 4b. Find its perimeter.

Answer

Perimeter of a rectangle = 2 × (sum of two adjacent sides)

Solving,

⇒2×[(6a+9b)+(8a−4b)]⇒2×(14a+5b)⇒28a+10b\Rightarrow 2 \times [(6a + 9b) + (8a - 4b)] \\[1em] \Rightarrow 2 \times (14a + 5b) \\[1em] \Rightarrow 28a + 10b

Hence, the perimeter of the rectangle = 28a+10b\bm{28a + 10b}.

Question 9(i)

Subtract the second expression from the first:

2a+b,a+b2a + b, a + b

Answer

Solving,

⇒(2a+b)−(a+b)⇒2a+b−a−b⇒2a−a+b−b⇒a.\Rightarrow (2a + b) - (a + b) \\[1em] \Rightarrow 2a + b - a - b \\[1em] \Rightarrow 2a - a + b - b \\[1em] \Rightarrow a.

Hence, the required difference = a\bm{a}.

Question 9(ii)

Subtract the second expression from the first:

−2b+2c,b+3c-2b + 2c, b + 3c

Answer

Solving,

⇒(−2b+2c)−(b+3c)⇒−2b+2c−b−3c⇒−3b−c\Rightarrow (-2b + 2c) - (b + 3c) \\[1em] \Rightarrow -2b + 2c - b - 3c \\[1em] \Rightarrow -3b - c

Hence, the required difference = −3b−c\bm{-3b - c}.

Question 9(iii)

Subtract the second expression from the first:

5a+b,−6b+2a5a + b, - 6b + 2a

Answer

Solving,

⇒(5a+b)−(−6b+2a)⇒5a+b+6b−2a⇒3a+7b\Rightarrow (5a + b) - (-6b + 2a) \\[1em] \Rightarrow 5a + b + 6b - 2a \\[1em] \Rightarrow 3a + 7b

Hence, the required difference = 3a+7b\bm{3a + 7b}.

Question 9(iv)

Subtract the second expression from the first:

a3−1+a,3a−2a2a^3 - 1 + a, 3a - 2a^2

Answer

Solving,

⇒(a3−1+a)−(3a−2a2)⇒a3−1+a−3a+2a2⇒a3+2a2−2a−1\Rightarrow (a^3 - 1 + a) - (3a - 2a^2) \\[1em] \Rightarrow a^3 - 1 + a - 3a + 2a^2 \\[1em] \Rightarrow a^3 + 2a^2 - 2a - 1

Hence, the required difference = a3+2a2−2a−1\bm{a^3 + 2a^2 - 2a - 1}.

Question 9(v)

Subtract the second expression from the first:

p+2,1p + 2, 1

Answer

Solving,

⇒(p+2)−1⇒p+1\Rightarrow (p + 2) - 1 \\[1em] \Rightarrow p + 1

Hence, the required difference = p+1\bm{p + 1}.

Question 9(vi)

Subtract the second expression from the first:

x+2y+z,−x−y−3zx + 2y + z, - x - y - 3z

Answer

Solving,

⇒(x+2y+z)−(−x−y−3z)⇒x+2y+z+x+y+3z⇒2x+3y+4z\Rightarrow (x + 2y + z) - (-x - y - 3z) \\[1em] \Rightarrow x + 2y + z + x + y + 3z \\[1em] \Rightarrow 2x + 3y + 4z

Hence, the required difference = 2x+3y+4z\bm{2x + 3y + 4z}.

Question 9(vii)

Subtract the second expression from the first:

3a2−8ab−2b2,3a2−4ab+6b23a^2 - 8ab - 2b^2, 3a^2 - 4ab + 6b^2

Answer

Solving,

⇒(3a2−8ab−2b2)−(3a2−4ab+6b2)⇒3a2−8ab−2b2−3a2+4ab−6b2⇒−4ab−8b2\Rightarrow (3a^2 - 8ab - 2b^2) - (3a^2 - 4ab + 6b^2) \\[1em] \Rightarrow 3a^2 - 8ab - 2b^2 - 3a^2 + 4ab - 6b^2 \\[1em] \Rightarrow -4ab - 8b^2

Hence, the required difference = −4ab−8b2\bm{-4ab - 8b^2}.

Question 9(viii)

Subtract the second expression from the first:

4pq−6p2−2q2,9p24pq - 6p^2 - 2q^2, 9p^2

Answer

Solving,

⇒(4pq−6p2−2q2)−9p2⇒4pq−6p2−2q2−9p2⇒4pq−15p2−2q2\Rightarrow (4pq - 6p^2 - 2q^2) - 9p^2 \\[1em] \Rightarrow 4pq - 6p^2 - 2q^2 - 9p^2 \\[1em] \Rightarrow 4pq - 15p^2 - 2q^2

Hence, the required difference = 4pq−15p2−2q2\bm{4pq - 15p^2 - 2q^2}.

Question 9(ix)

Subtract the second expression from the first:

10abc,2a2+2abc−4b210abc, 2a^2 + 2abc - 4b^2

Answer

Solving,

⇒10abc−(2a2+2abc−4b2)⇒10abc−2a2−2abc+4b2⇒−2a2+8abc+4b2\Rightarrow 10abc - (2a^2 + 2abc - 4b^2) \\[1em] \Rightarrow 10abc - 2a^2 - 2abc + 4b^2 \\[1em] \Rightarrow -2a^2 + 8abc + 4b^2

Hence, the required difference = −2a2+8abc+4b2\bm{-2a^2 + 8abc + 4b^2}.

Question 9(x)

Subtract the second expression from the first:

a2+ab+c2,a2−d2a^2 + ab + c^2, a^2 - d^2

Answer

Solving,

⇒(a2+ab+c2)−(a2−d2)⇒a2+ab+c2−a2+d2⇒ab+c2+d2\Rightarrow (a^2 + ab + c^2) - (a^2 - d^2) \\[1em] \Rightarrow a^2 + ab + c^2 - a^2 + d^2 \\[1em] \Rightarrow ab + c^2 + d^2

Hence, the required difference = ab+c2+d2\bm{ab + c^2 + d^2}.

Question 10(i)

Subtract:

4x4x from 8−x8 - x

Answer

Solving,

⇒(8−x)−4x⇒8−x−4x⇒8−5x\Rightarrow (8 - x) - 4x \\[1em] \Rightarrow 8 - x - 4x \\[1em] \Rightarrow 8 - 5x

Hence, the required difference = 8−5x\bm{8 - 5x}.

Question 10(ii)

Subtract:

−8c-8c from c+3dc + 3d

Answer

Solving,

⇒(c+3d)−(−8c)⇒c+3d+8c⇒9c+3d\Rightarrow (c + 3d) - (-8c) \\[1em] \Rightarrow c + 3d + 8c \\[1em] \Rightarrow 9c + 3d

Hence, the required difference = 9c+3d\bm{9c + 3d}.

Question 10(iii)

Subtract:

−5a−2b-5a - 2b from b+6cb + 6c

Answer

Solving,

⇒(b+6c)−(−5a−2b)⇒b+6c+5a+2b⇒5a+3b+6c\Rightarrow (b + 6c) - (-5a - 2b) \\[1em] \Rightarrow b + 6c + 5a + 2b \\[1em] \Rightarrow 5a + 3b + 6c

Hence, the required difference = 5a+3b+6c\bm{5a + 3b + 6c}.

Question 10(iv)

Subtract:

4p+p24p + p^2 from 3p2−8p3p^2 - 8p

Answer

Solving,

⇒(3p2−8p)−(4p+p2)⇒3p2−8p−4p−p2⇒2p2−12p\Rightarrow (3p^2 - 8p) - (4p + p^2) \\[1em] \Rightarrow 3p^2 - 8p - 4p - p^2 \\[1em] \Rightarrow 2p^2 - 12p

Hence, the required difference = 2p2−12p\bm{2p^2 - 12p}.

Question 10(v)

Subtract:

5a−3b+2c5a - 3b + 2c from 4a−b−2c4a - b - 2c

Answer

Solving,

⇒(4a−b−2c)−(5a−3b+2c)⇒4a−b−2c−5a+3b−2c⇒−a+2b−4c\Rightarrow (4a - b - 2c) - (5a - 3b + 2c) \\[1em] \Rightarrow 4a - b - 2c - 5a + 3b - 2c \\[1em] \Rightarrow -a + 2b - 4c

Hence, the required difference = −a+2b−4c\bm{-a + 2b - 4c}.

Question 10(vi)

Subtract:

−xy+yz−zx-xy + yz - zx from xy−yz+xzxy - yz + xz

Answer

Solving,

⇒(xy−yz+xz)−(−xy+yz−zx)⇒xy−yz+xz+xy−yz+zx⇒2xy−2yz+2xz⇒2(xy−yz+xz)\Rightarrow (xy - yz + xz) - (-xy + yz - zx) \\[1em] \Rightarrow xy - yz + xz + xy - yz + zx \\[1em] \Rightarrow 2xy - 2yz + 2xz \\[1em] \Rightarrow 2(xy - yz + xz)

Hence, the required difference = 2(xy−yz+xz)\bm{2(xy - yz + xz)}.

Question 10(vii)

Subtract:

2x2−7xy−y22x^2 - 7xy - y^2 from 3x2−5xy+3y23x^2 - 5xy + 3y^2

Answer

Solving,

⇒(3x2−5xy+3y2)−(2x2−7xy−y2)⇒3x2−5xy+3y2−2x2+7xy+y2⇒x2+2xy+4y2\Rightarrow (3x^2 - 5xy + 3y^2) - (2x^2 - 7xy - y^2) \\[1em] \Rightarrow 3x^2 - 5xy + 3y^2 - 2x^2 + 7xy + y^2 \\[1em] \Rightarrow x^2 + 2xy + 4y^2

Hence, the required difference = x2+2xy+4y2\bm{x^2 + 2xy + 4y^2}.

Question 10(viii)

Subtract:

a2−3ab−6b2a^2 - 3ab - 6b^2 from 2b2−a2+2ab2b^2 - a^2 + 2ab

Answer

Solving,

⇒(2b2−a2+2ab)−(a2−3ab−6b2)⇒2b2−a2+2ab−a2+3ab+6b2⇒−2a2+5ab+8b2\Rightarrow (2b^2 - a^2 + 2ab) - (a^2 - 3ab - 6b^2) \\[1em] \Rightarrow 2b^2 - a^2 + 2ab - a^2 + 3ab + 6b^2 \\[1em] \Rightarrow -2a^2 + 5ab + 8b^2

Hence, the required difference = −2a2+5ab+8b2\bm{-2a^2 + 5ab + 8b^2}.

Question 10(ix)

Subtract:

4x2−5x2y+y24x^2 - 5x^2y + y^2 from −3y2+5xy2−7x2−9x2y- 3y^2 + 5xy^2 - 7x^2 - 9x^2y

Answer

Solving,

⇒(−3y2+5xy2−7x2−9x2y)−(4x2−5x2y+y2)⇒−3y2+5xy2−7x2−9x2y−4x2+5x2y−y2⇒(−7−4)x2+(−9+5)x2y+5xy2+(−3−1)y2⇒−11x2−4x2y+5xy2−4y2\Rightarrow (-3y^2 + 5xy^2 - 7x^2 - 9x^2y) - (4x^2 - 5x^2y + y^2) \\[1em] \Rightarrow -3y^2 + 5xy^2 - 7x^2 - 9x^2y - 4x^2 + 5x^2y - y^2 \\[1em] \Rightarrow (-7 - 4)x^2 + (-9 + 5)x^2y + 5xy^2 + (-3 - 1)y^2 \\[1em] \Rightarrow -11x^2 - 4x^2y + 5xy^2 - 4y^2

Hence, the required difference = −11x2−4x2y+5xy2−4y2\bm{-11x^2 - 4x^2y + 5xy^2 - 4y^2}.

Question 10(x)

Subtract:

6m3+4m2+7m−36m^3 + 4m^2 + 7m - 3 from 3m3+43m^3 + 4

Answer

Solving,

⇒(3m3+4)−(6m3+4m2+7m−3)⇒3m3+4−6m3−4m2−7m+3⇒−3m3−4m2−7m+7\Rightarrow (3m^3 + 4) - (6m^3 + 4m^2 + 7m - 3) \\[1em] \Rightarrow 3m^3 + 4 - 6m^3 - 4m^2 - 7m + 3 \\[1em] \Rightarrow -3m^3 - 4m^2 - 7m + 7

Hence, the required difference = −3m3−4m2−7m+7\bm{-3m^3 - 4m^2 - 7m + 7}.

Question 11

Subtract −5a2−3a+1- 5a^2 - 3a + 1 from the sum of 4a2+3−8a4a^2 + 3 - 8a and 9a−79a - 7.

Answer

Sum of 4a2+3−8a4a^2 + 3 - 8a and 9a−79a - 7,

⇒(4a2+3−8a)+(9a−7)⇒4a2+(−8+9)a+(3−7)⇒4a2+a−4\Rightarrow (4a^2 + 3 - 8a) + (9a - 7) \\[1em] \Rightarrow 4a^2 + (-8 + 9)a + (3 - 7) \\[1em] \Rightarrow 4a^2 + a - 4

Now, subtracting −5a2−3a+1-5a^2 - 3a + 1 from this sum,

⇒(4a2+a−4)−(−5a2−3a+1)⇒4a2+a−4+5a2+3a−1⇒9a2+4a−5\Rightarrow (4a^2 + a - 4) - (-5a^2 - 3a + 1) \\[1em] \Rightarrow 4a^2 + a - 4 + 5a^2 + 3a - 1 \\[1em] \Rightarrow 9a^2 + 4a - 5

Hence, the required difference = 9a2+4a−5\bm{9a^2 + 4a - 5}.

Question 12

By how much does 8x3−6x2+9x−108x^3 - 6x^2 + 9x - 10 exceed 4x3+2x2+7x−34x^3 + 2x^2 + 7x - 3?

Answer

Solving,

⇒(8x3−6x2+9x−10)−(4x3+2x2+7x−3)⇒8x3−6x2+9x−10−4x3−2x2−7x+3⇒(8−4)x3+(−6−2)x2+(9−7)x+(−10+3)⇒4x3−8x2+2x−7\Rightarrow (8x^3 - 6x^2 + 9x - 10) - (4x^3 + 2x^2 + 7x - 3) \\[1em] \Rightarrow 8x^3 - 6x^2 + 9x - 10 - 4x^3 - 2x^2 - 7x + 3 \\[1em] \Rightarrow (8 - 4)x^3 + (-6 - 2)x^2 + (9 - 7)x + (-10 + 3) \\[1em] \Rightarrow 4x^3 - 8x^2 + 2x - 7

Hence, the required excess = 4x3−8x2+2x−7\bm{4x^3 - 8x^2 + 2x - 7}.

Question 13

What must be added to 2a3+5a−a2−62a^3 + 5a - a^2 - 6 to get a2−a−a3+1a^2 - a - a^3 + 1?

Answer

Solving,

⇒(a2−a−a3+1)−(2a3+5a−a2−6)⇒a2−a−a3+1−2a3−5a+a2+6⇒(−1−2)a3+(1+1)a2+(−1−5)a+(1+6)⇒−3a3+2a2−6a+7\Rightarrow (a^2 - a - a^3 + 1) - (2a^3 + 5a - a^2 - 6) \\[1em] \Rightarrow a^2 - a - a^3 + 1 - 2a^3 - 5a + a^2 + 6 \\[1em] \Rightarrow (-1 - 2)a^3 + (1 + 1)a^2 + (-1 - 5)a + (1 + 6) \\[1em] \Rightarrow -3a^3 + 2a^2 - 6a + 7

Hence, the required expression = −3a3+2a2−6a+7\bm{-3a^3 + 2a^2 - 6a + 7}.

Question 14

What must be subtracted from a2+b2+2aba^2 + b^2 + 2ab to get −4ab+2b2- 4ab + 2b^2?

Answer

Solving,

⇒(a2+b2+2ab)−(−4ab+2b2)⇒a2+b2+2ab+4ab−2b2⇒a2+(1−2)b2+(2+4)ab⇒a2−b2+6ab\Rightarrow (a^2 + b^2 + 2ab) - (-4ab + 2b^2) \\[1em] \Rightarrow a^2 + b^2 + 2ab + 4ab - 2b^2 \\[1em] \Rightarrow a^2 + (1 - 2)b^2 + (2 + 4)ab \\[1em] \Rightarrow a^2 - b^2 + 6ab

Hence, the required expression = a2−b2+6ab\bm{a^2 - b^2 + 6ab}.

Question 15

Find the excess of 4m2+4n2+4p24m^2 + 4n^2 + 4p^2 over m2+3n2−5p2m^2 + 3n^2 - 5p^2.

Answer

Solving,

⇒(4m2+4n2+4p2)−(m2+3n2−5p2)⇒4m2+4n2+4p2−m2−3n2+5p2⇒(4−1)m2+(4−3)n2+(4+5)p2⇒3m2+n2+9p2\Rightarrow (4m^2 + 4n^2 + 4p^2) - (m^2 + 3n^2 - 5p^2) \\[1em] \Rightarrow 4m^2 + 4n^2 + 4p^2 - m^2 - 3n^2 + 5p^2 \\[1em] \Rightarrow (4 - 1)m^2 + (4 - 3)n^2 + (4 + 5)p^2 \\[1em] \Rightarrow 3m^2 + n^2 + 9p^2

Hence, the required excess = 3m2+n2+9p2\bm{3m^2 + n^2 + 9p^2}.

Question 16

By how much is 3x3−2x2y+xy2−y33x^3 - 2x^2y + xy^2 - y^3 less than 4x3−3x2y−7xy2+2y34x^3 - 3x^2y - 7xy^2 + 2y^3?

Answer

Solving,

⇒(4x3−3x2y−7xy2+2y3)−(3x3−2x2y+xy2−y3)⇒4x3−3x2y−7xy2+2y3−3x3+2x2y−xy2+y3⇒(4−3)x3+(−3+2)x2y+(−7−1)xy2+(2+1)y3⇒x3−x2y−8xy2+3y3\Rightarrow (4x^3 - 3x^2y - 7xy^2 + 2y^3) - (3x^3 - 2x^2y + xy^2 - y^3) \\[1em] \Rightarrow 4x^3 - 3x^2y - 7xy^2 + 2y^3 - 3x^3 + 2x^2y - xy^2 + y^3 \\[1em] \Rightarrow (4 - 3)x^3 + (-3 + 2)x^2y + (-7 - 1)xy^2 + (2 + 1)y^3 \\[1em] \Rightarrow x^3 - x^2y - 8xy^2 + 3y^3

Hence, the required difference = x3−x2y−8xy2+3y3\bm{x^3 - x^2y - 8xy^2 + 3y^3}.

Question 17

Subtract the sum of 3a2−2a+53a^2 - 2a + 5 and a2−5a−7a^2 - 5a - 7 from the sum of 5a2−9a+35a^2 - 9a + 3 and 2a−a2−12a - a^2 - 1.

Answer

Sum of 5a2−9a+35a^2 - 9a + 3 and 2a−a2−12a - a^2 - 1,

⇒(5a2−9a+3)+(2a−a2−1)⇒(5−1)a2+(−9+2)a+(3−1)⇒4a2−7a+2\Rightarrow (5a^2 - 9a + 3) + (2a - a^2 - 1) \\[1em] \Rightarrow (5 - 1)a^2 + (-9 + 2)a + (3 - 1) \\[1em] \Rightarrow 4a^2 - 7a + 2

Sum of 3a2−2a+53a^2 - 2a + 5 and a2−5a−7a^2 - 5a - 7,

⇒(3a2−2a+5)+(a2−5a−7)⇒(3+1)a2+(−2−5)a+(5−7)⇒4a2−7a−2\Rightarrow (3a^2 - 2a + 5) + (a^2 - 5a - 7) \\[1em] \Rightarrow (3 + 1)a^2 + (-2 - 5)a + (5 - 7) \\[1em] \Rightarrow 4a^2 - 7a - 2

Now, subtracting the second sum from the first sum,

⇒(4a2−7a+2)−(4a2−7a−2)⇒4a2−7a+2−4a2+7a+2⇒4\Rightarrow (4a^2 - 7a + 2) - (4a^2 - 7a - 2) \\[1em] \Rightarrow 4a^2 - 7a + 2 - 4a^2 + 7a + 2 \\[1em] \Rightarrow 4

Hence, the required difference = 4\bm{4}.

Question 18

The perimeter of a rectangle is 28x3+16x2+8x+428x^3 + 16x^2 + 8x + 4. One of its sides is 8x2+4x8x^2 + 4x. Find the other side.

Answer

Let the length and the breadth of the rectangle be ll and bb.

Perimeter = 2(l+b)2(l + b)

⇒l+b=Perimeter2⇒l+b=28x3+16x2+8x+42⇒l+b=14x3+8x2+4x+2\Rightarrow l + b = \dfrac{\text{Perimeter}}{2} \\[1em] \Rightarrow l + b = \dfrac{28x^3 + 16x^2 + 8x + 4}{2} \\[1em] \Rightarrow l + b = 14x^3 + 8x^2 + 4x + 2

Other side = (l+b)(l + b) − (given side)

⇒(14x3+8x2+4x+2)−(8x2+4x)⇒14x3+8x2+4x+2−8x2−4x⇒14x3+2\Rightarrow (14x^3 + 8x^2 + 4x + 2) - (8x^2 + 4x) \\[1em] \Rightarrow 14x^3 + 8x^2 + 4x + 2 - 8x^2 - 4x \\[1em] \Rightarrow 14x^3 + 2

Hence, the other side of the rectangle = 14x3+2\bm{14x^3 + 2}.

Question 19

The perimeter of a triangle is 14a2+20a+1314a^2 + 20a + 13. Two of its sides are 3a2+5a+13a^2 + 5a + 1 and a2+10a−6a^2 + 10a - 6. Find its third side.

Answer

Sum of the two given sides,

⇒(3a2+5a+1)+(a2+10a−6)⇒(3+1)a2+(5+10)a+(1−6)⇒4a2+15a−5\Rightarrow (3a^2 + 5a + 1) + (a^2 + 10a - 6) \\[1em] \Rightarrow (3 + 1)a^2 + (5 + 10)a + (1 - 6) \\[1em] \Rightarrow 4a^2 + 15a - 5

Third side = Perimeter − (sum of the two given sides)

⇒(14a2+20a+13)−(4a2+15a−5)⇒14a2+20a+13−4a2−15a+5⇒10a2+5a+18\Rightarrow (14a^2 + 20a + 13) - (4a^2 + 15a - 5) \\[1em] \Rightarrow 14a^2 + 20a + 13 - 4a^2 - 15a + 5 \\[1em] \Rightarrow 10a^2 + 5a + 18

Hence, the third side = 10a2+5a+18\bm{10a^2 + 5a + 18}.

Question 20

If x=4a2+b2−6ab,y=3b2−2a2+8abx = 4a^2 + b^2 - 6ab, y = 3b^2 - 2a^2 + 8ab and z=6a2+8b2−6abz = 6a^2 + 8b^2 - 6ab, find:

(i) x+y+zx + y + z

(ii) x−y−zx - y - z

Answer

Given, x=4a2+b2−6ab,y=3b2−2a2+8abx = 4a^2 + b^2 - 6ab, y = 3b^2 - 2a^2 + 8ab and z=6a2+8b2−6abz = 6a^2 + 8b^2 - 6ab.

(i) x+y+zx + y + z

⇒(4a2+b2−6ab)+(3b2−2a2+8ab)+(6a2+8b2−6ab)⇒(4−2+6)a2+(1+3+8)b2+(−6+8−6)ab⇒8a2+12b2−4ab\Rightarrow (4a^2 + b^2 - 6ab) + (3b^2 - 2a^2 + 8ab) + (6a^2 + 8b^2 - 6ab) \\[1em] \Rightarrow (4 - 2 + 6)a^2 + (1 + 3 + 8)b^2 + (-6 + 8 - 6)ab \\[1em] \Rightarrow 8a^2 + 12b^2 - 4ab

Hence, x+y+z=8a2+12b2−4ab\bm{x + y + z = 8a^2 + 12b^2 - 4ab}.

(ii) x−y−zx - y - z

⇒(4a2+b2−6ab)−(3b2−2a2+8ab)−(6a2+8b2−6ab)⇒4a2+b2−6ab−3b2+2a2−8ab−6a2−8b2+6ab⇒(4+2−6)a2+(1−3−8)b2+(−6−8+6)ab⇒−10b2−8ab\Rightarrow (4a^2 + b^2 - 6ab) - (3b^2 - 2a^2 + 8ab) - (6a^2 + 8b^2 - 6ab) \\[1em] \Rightarrow 4a^2 + b^2 - 6ab - 3b^2 + 2a^2 - 8ab - 6a^2 - 8b^2 + 6ab \\[1em] \Rightarrow (4 + 2 - 6)a^2 + (1 - 3 - 8)b^2 + (-6 - 8 + 6)ab \\[1em] \Rightarrow -10b^2 - 8ab

Hence, x−y−z=−10b2−8ab\bm{x - y - z = -10b^2 - 8ab}.

Question 21

If m=9x2−4xy+5y2m = 9x^2 - 4xy + 5y^2 and n=−3x2+2xy−y2n = - 3x^2 + 2xy - y^2, find:

(i) 2m−n2m - n

(ii) m+2nm + 2n

(iii) m−3nm - 3n.

Answer

Given, m=9x2−4xy+5y2m = 9x^2 - 4xy + 5y^2 and n=−3x2+2xy−y2n = -3x^2 + 2xy - y^2.

(i) 2m−n2m - n

⇒2(9x2−4xy+5y2)−(−3x2+2xy−y2)⇒18x2−8xy+10y2+3x2−2xy+y2⇒21x2−10xy+11y2\Rightarrow 2(9x^2 - 4xy + 5y^2) - (-3x^2 + 2xy - y^2) \\[1em] \Rightarrow 18x^2 - 8xy + 10y^2 + 3x^2 - 2xy + y^2 \\[1em] \Rightarrow 21x^2 - 10xy + 11y^2

Hence, 2m−n=21x2−10xy+11y2\bm{2m - n = 21x^2 - 10xy + 11y^2}.

(ii) m+2nm + 2n

⇒(9x2−4xy+5y2)+2(−3x2+2xy−y2)⇒9x2−4xy+5y2−6x2+4xy−2y2⇒3x2+3y2\Rightarrow (9x^2 - 4xy + 5y^2) + 2(-3x^2 + 2xy - y^2) \\[1em] \Rightarrow 9x^2 - 4xy + 5y^2 - 6x^2 + 4xy - 2y^2 \\[1em] \Rightarrow 3x^2 + 3y^2

Hence, m+2n=3x2+3y2\bm{m + 2n = 3x^2 + 3y^2}.

(iii) m−3nm - 3n

⇒(9x2−4xy+5y2)−3(−3x2+2xy−y2)⇒9x2−4xy+5y2+9x2−6xy+3y2⇒18x2−10xy+8y2\Rightarrow (9x^2 - 4xy + 5y^2) - 3(-3x^2 + 2xy - y^2) \\[1em] \Rightarrow 9x^2 - 4xy + 5y^2 + 9x^2 - 6xy + 3y^2 \\[1em] \Rightarrow 18x^2 - 10xy + 8y^2

Hence, m−3n=18x2−10xy+8y2\bm{m - 3n = 18x^2 - 10xy + 8y^2}.

Question 22(i)

Simplify:

3x+5(2x+6)−7x3x + 5(2x + 6) - 7x

Answer

Solving,

⇒3x+5(2x+6)−7x⇒3x+10x+30−7x⇒6x+30\Rightarrow 3x + 5(2x + 6) - 7x \\[1em] \Rightarrow 3x + 10x + 30 - 7x \\[1em] \Rightarrow 6x + 30

Hence, the simplified expression = 6x+30\bm{6x + 30}.

Question 22(ii)

Simplify:

3(4y−10)+2(y−1)3(4y - 10) + 2(y - 1)

Answer

Solving,

⇒3(4y−10)+2(y−1)⇒12y−30+2y−2⇒14y−32\Rightarrow 3(4y - 10) + 2(y - 1) \\[1em] \Rightarrow 12y - 30 + 2y - 2 \\[1em] \Rightarrow 14y - 32

Hence, the simplified expression = 14y−32\bm{14y - 32}.

Question 22(iii)

Simplify:

−(7+6x)−7(x+2)-(7 + 6x) - 7(x + 2)

Answer

Solving,

⇒−(7+6x)−7(x+2)⇒−7−6x−7x−14⇒−21−13x\Rightarrow -(7 + 6x) - 7(x + 2) \\[1em] \Rightarrow -7 - 6x - 7x - 14 \\[1em] \Rightarrow -21 - 13x

Hence, the simplified expression = −21−13x\bm{-21 - 13x}.

Question 22(iv)

Simplify:

x−(x−y)−y−(y−x)x - (x - y) - y - (y - x)

Answer

Solving,

⇒x−(x−y)−y−(y−x)⇒x−x+y−y−y+x⇒x−y\Rightarrow x - (x - y) - y - (y - x) \\[1em] \Rightarrow x - x + y - y - y + x \\[1em] \Rightarrow x - y

Hence, the simplified expression = x−y\bm{x - y}.

Question 22(v)

Simplify:

4x+7y−[5y−8]−2x4x + 7y- [5y - 8] - 2x

Answer

Solving,

⇒4x+7y−[5y−8]−2x⇒4x+7y−5y+8−2x⇒2x+2y+8\Rightarrow 4x + 7y - [5y - 8] - 2x \\[1em] \Rightarrow 4x + 7y - 5y + 8 - 2x \\[1em] \Rightarrow 2x + 2y + 8

Hence, the simplified expression = 2x+2y+8\bm{2x + 2y + 8}.

Question 22(vi)

Simplify:

−2m+5+4(m−3)-2m + 5 + 4(m - 3)

Answer

Solving,

⇒−2m+5+4(m−3)⇒−2m+5+4m−12⇒2m−7\Rightarrow -2m + 5 + 4(m - 3) \\[1em] \Rightarrow -2m + 5 + 4m - 12 \\[1em] \Rightarrow 2m - 7

Hence, the simplified expression = 2m−7\bm{2m - 7}.

Question 22(vii)

Simplify:

2x−y+5−(x−y)2x - y + 5 - (x - y)

Answer

Solving,

⇒2x−y+5−(x−y)⇒2x−y+5−x+y⇒x+5\Rightarrow 2x - y + 5 - (x - y) \\[1em] \Rightarrow 2x - y + 5 - x + y \\[1em] \Rightarrow x + 5

Hence, the simplified expression = x+5\bm{x + 5}.

Question 22(viii)

Simplify:

2(x−y)−(x−8)2(x - y) - (x - 8)

Answer

Solving,

⇒2(x−y)−(x−8)⇒2x−2y−x+8⇒x−2y+8\Rightarrow 2(x - y) - (x - 8) \\[1em] \Rightarrow 2x - 2y - x + 8 \\[1em] \Rightarrow x - 2y + 8

Hence, the simplified expression = x−2y+8\bm{x - 2y + 8}.

Question 22(ix)

Simplify:

4(3x−8)−3(5x+3)−2(6x−8)4(3x - 8) - 3(5x + 3) - 2(6x - 8)

Answer

Solving,

⇒4(3x−8)−3(5x+3)−2(6x−8)⇒12x−32−15x−9−12x+16⇒(12−15−12)x+(−32−9+16)⇒−15x−25\Rightarrow 4(3x - 8) - 3(5x + 3) - 2(6x - 8) \\[1em] \Rightarrow 12x - 32 - 15x - 9 - 12x + 16 \\[1em] \Rightarrow (12 - 15 - 12)x + (-32 - 9 + 16) \\[1em] \Rightarrow -15x - 25

Hence, the simplified expression = −15x−25\bm{-15x - 25}.

Question 22(x)

Simplify:

5(x−4)−3(x−4)+7(x−4)5(x - 4) - 3(x - 4) + 7(x - 4)

Answer

Solving,

⇒5(x−4)−3(x−4)+7(x−4)⇒(5−3+7)(x−4)⇒9(x−4)⇒9x−36\Rightarrow 5(x - 4) - 3(x - 4) + 7(x - 4) \\[1em] \Rightarrow (5 - 3 + 7)(x - 4) \\[1em] \Rightarrow 9(x - 4) \\[1em] \Rightarrow 9x - 36

Hence, the simplified expression = 9x−36\bm{9x - 36}.

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