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Chapter 14

Simple Linear Equations — Exercise 14(B)

Class - 7 Concise Mathematics Selina



Exercise 14(B)

Question 1

Solve :

8y4y8y - 4y = 20

Answer

Solving,

8y4y=204y=20y=204y=5.\Rightarrow 8y - 4y = 20 \\[1em] \Rightarrow 4y = 20 \\[1em] \Rightarrow y = \dfrac{20}{4} \\[1em] \Rightarrow y = 5.

Hence, y\bm{y} = 5.

Question 2

Solve :

9b4b+3b9b - 4b + 3b = 16

Answer

Solving,

9b4b+3b=16(94+3)b=168b=16b=168b=2.\Rightarrow 9b - 4b + 3b = 16 \\[1em] \Rightarrow (9 - 4 + 3)b = 16 \\[1em] \Rightarrow 8b = 16 \\[1em] \Rightarrow b = \dfrac{16}{8} \\[1em] \Rightarrow b = 2.

Hence, b\bm{b} = 2.

Question 3

Solve :

5y+8=8y185y + 8 = 8y - 18

Answer

Solving,

5y+8=8y185y8y=1883y=26y=263y=263y=823.\Rightarrow 5y + 8 = 8y - 18 \\[1em] \Rightarrow 5y - 8y = -18 - 8 \\[1em] \Rightarrow -3y = -26 \\[1em] \Rightarrow y = \dfrac{-26}{-3} \\[1em] \Rightarrow y = \dfrac{26}{3} \\[1em] \Rightarrow y = 8\dfrac{2}{3}.

Hence, y\bm{y} = 8238\dfrac{2}{3}.

Question 4

Solve :

6=7+2p56 = 7 + 2p - 5

Answer

Solving,

6=7+2p56=2+2p62=2p4=2p42=2p2p=2.\Rightarrow 6 = 7 + 2p - 5 \\[1em] \Rightarrow 6 = 2 + 2p \\[1em] \Rightarrow 6 - 2 = 2p \\[1em] \Rightarrow 4 = 2p \\[1em] \Rightarrow \dfrac{4}{2} = \dfrac{2p}{2} \\[1em] \Rightarrow p = 2.

Hence, p\bm{p} = 2.

Question 5

Solve :

87x=13x+88 - 7x = 13x + 8

Answer

Solving,

87x=13x+87x13x=8820x=0x=0.\Rightarrow 8 - 7x = 13x + 8 \\[1em] \Rightarrow -7x - 13x = 8 - 8 \\[1em] \Rightarrow -20x = 0 \\[1em] \Rightarrow x = 0.

Hence, x\bm{x} = 0.

Question 6

Solve :

4x5x+2x=28+3x4x - 5x + 2x = 28 + 3x

Answer

Solving,

4x5x+2x=28+3x(45+2)x=28+3xx=28+3xx3x=282x=28x=282x=14.\Rightarrow 4x - 5x + 2x = 28 + 3x \\[1em] \Rightarrow (4 - 5 + 2)x = 28 + 3x \\[1em] \Rightarrow x = 28 + 3x \\[1em] \Rightarrow x - 3x = 28 \\[1em] \Rightarrow -2x = 28 \\[1em] \Rightarrow x = \dfrac{28}{-2} \\[1em] \Rightarrow x = -14.

Hence, x\bm{x} = −14.

Question 7

Solve :

9+m=6m+8m9 + m = 6m + 8 - m

Answer

Solving,

9+m=6m+8m9+m=5m+8m5m=894m=1m=14m=14.\Rightarrow 9 + m = 6m + 8 - m \\[1em] \Rightarrow 9 + m = 5m + 8 \\[1em] \Rightarrow m - 5m = 8 - 9 \\[1em] \Rightarrow -4m = -1 \\[1em] \Rightarrow m = \dfrac{-1}{-4} \\[1em] \Rightarrow m = \dfrac{1}{4}.

Hence, m\bm{m} = 14\dfrac{1}{4}.

Question 8

Solve :

24 = y+2y+3+4yy + 2y + 3 + 4y

Answer

Solving,

24=y+2y+3+4y24=7y+3243=7y21=7y217=7y7y=3.\Rightarrow 24 = y + 2y + 3 + 4y \\[1em] \Rightarrow 24 = 7y + 3 \\[1em] \Rightarrow 24 - 3 = 7y \\[1em] \Rightarrow 21 = 7y \\[1em] \Rightarrow \dfrac{21}{7} = \dfrac{7y}{7} \\[1em] \Rightarrow y = 3.

Hence, y\bm{y} = 3.

Question 9

Solve :

19x+1312x+319x + 13 - 12x + 3 = 23

Answer

Solving,

19x+1312x+3=23(1912)x+(13+3)=237x+16=237x=23167x=7x=77x=1.\Rightarrow 19x + 13 - 12x + 3 = 23 \\[1em] \Rightarrow (19 - 12)x + (13 + 3) = 23 \\[1em] \Rightarrow 7x + 16 = 23 \\[1em] \Rightarrow 7x = 23 - 16 \\[1em] \Rightarrow 7x = 7 \\[1em] \Rightarrow x = \dfrac{7}{7} \\[1em] \Rightarrow x = 1.

Hence, x\bm{x} = 1.

Question 10

Solve :

6b+40=100b6b + 40 = -100 - b

Answer

Solving,

6b+40=100b6b+b=100407b=140b=1407b=20.\Rightarrow 6b + 40 = -100 - b \\[1em] \Rightarrow 6b + b = -100 - 40 \\[1em] \Rightarrow 7b = -140 \\[1em] \Rightarrow b = \dfrac{-140}{7} \\[1em] \Rightarrow b = -20.

Hence, b\bm{b} = −20.

Question 11

Solve :

65m1+3m6 - 5m - 1 + 3m = 0

Answer

Solving,

65m1+3m=0(61)+(5+3)m=052m=02m=5m=52m=52m=212.\Rightarrow 6 - 5m - 1 + 3m = 0 \\[1em] \Rightarrow (6 - 1) + (-5 + 3)m = 0 \\[1em] \Rightarrow 5 - 2m = 0 \\[1em] \Rightarrow -2m = -5 \\[1em] \Rightarrow m = \dfrac{-5}{-2} \\[1em] \Rightarrow m = \dfrac{5}{2} \\[1em] \Rightarrow m = 2\dfrac{1}{2}.

Hence, m\bm{m} = 2122\dfrac{1}{2}.

Question 12

Solve :

04x12=03x+060·4x - 1·2 = 0·3x + 0·6

Answer

Solving,

0.4x1.2=0.3x+0.60.4x0.3x=0.6+1.20.1x=1.8x=1.80.1x=181x=18.\Rightarrow 0.4x - 1.2 = 0.3x + 0.6 \\[1em] \Rightarrow 0.4x - 0.3x = 0.6 + 1.2 \\[1em] \Rightarrow 0.1x = 1.8 \\[1em] \Rightarrow x = \dfrac{1.8}{0.1} \\[1em] \Rightarrow x = \dfrac{18}{1} \\[1em] \Rightarrow x = 18.

Hence, x\bm{x} = 18.

Question 13

Solve :

6(x+4)6(x + 4) = 36

Answer

Solving,

6(x+4)=36(x+4)=366x+4=6x=64x=2.\Rightarrow 6(x + 4) = 36 \\[1em] \Rightarrow (x + 4) = \dfrac{36}{6} \\[1em] \Rightarrow x + 4 = 6 \\[1em] \Rightarrow x = 6 - 4 \\[1em] \Rightarrow x = 2.

Hence, x\bm{x} = 2.

Question 14

Solve :

9(a+5)+29(a + 5) + 2 = 11

Answer

Solving,

9(a+5)+2=119(a+5)=1129(a+5)=9(a+5)=99a+5=1a=15a=4.\Rightarrow 9(a + 5) + 2 = 11 \\[1em] \Rightarrow 9(a + 5) = 11 - 2 \\[1em] \Rightarrow 9(a + 5) = 9 \\[1em] \Rightarrow (a + 5) = \dfrac{9}{9} \\[1em] \Rightarrow a + 5 = 1 \\[1em] \Rightarrow a = 1 - 5 \\[1em] \Rightarrow a = -4.

Hence, a\bm{a} = −4.

Question 15

Solve :

4(x2)4(x - 2) = 12

Answer

Solving,

4(x2)=12(x2)=124x2=3x=3+2x=5.\Rightarrow 4(x - 2) = 12 \\[1em] \Rightarrow (x - 2) = \dfrac{12}{4} \\[1em] \Rightarrow x - 2 = 3 \\[1em] \Rightarrow x = 3 + 2 \\[1em] \Rightarrow x = 5.

Hence, x\bm{x} = 5.

Question 16

Solve :

3(a6)-3(a - 6) = 24

Answer

Solving,

3(a6)=24(a6)=243a6=8a=8+6a=2.\Rightarrow -3(a - 6) = 24 \\[1em] \Rightarrow (a - 6) = \dfrac{24}{-3} \\[1em] \Rightarrow a - 6 = -8 \\[1em] \Rightarrow a = -8 + 6 \\[1em] \Rightarrow a = -2.

Hence, a\bm{a} = −2.

Question 17

Solve :

7(x2)=2(2x4)7(x - 2) = 2(2x - 4)

Answer

Solving,

7(x2)=2(2x4)7x14=4x87x4x=8+143x=6x=63x=2.\Rightarrow 7(x - 2) = 2(2x - 4) \\[1em] \Rightarrow 7x - 14 = 4x - 8 \\[1em] \Rightarrow 7x - 4x = -8 + 14 \\[1em] \Rightarrow 3x = 6 \\[1em] \Rightarrow x = \dfrac{6}{3} \\[1em] \Rightarrow x = 2.

Hence, x\bm{x} = 2.

Question 18

Solve :

(x4)(2x+3)=2x2(x - 4) (2x + 3) = 2x^{2}

Answer

Solving,

(x4)(2x+3)=2x22x2+3x8x12=2x22x25x12=2x25x12=2x22x25x12=05x=12x=125x=125x=225.\Rightarrow (x - 4)(2x + 3) = 2x^{2} \\[1em] \Rightarrow 2x^{2} + 3x - 8x - 12 = 2x^{2} \\[1em] \Rightarrow 2x^{2} - 5x - 12 = 2x^{2} \\[1em] \Rightarrow -5x - 12 = 2x^{2} - 2x^{2} \\[1em] \Rightarrow -5x - 12 = 0 \\[1em] \Rightarrow -5x = 12 \\[1em] \Rightarrow x = \dfrac{12}{-5} \\[1em] \Rightarrow x = -\dfrac{12}{5} \\[1em] \Rightarrow x = -2\dfrac{2}{5}.

Hence, x\bm{x} = 225-2\dfrac{2}{5}.

Question 19

Solve :

213(b7)=b+2021 - 3(b - 7) = b + 20

Answer

Solving,

213(b7)=b+20213b+21=b+20423b=b+203bb=20424b=22b=224b=112b=512.\Rightarrow 21 - 3(b - 7) = b + 20 \\[1em] \Rightarrow 21 - 3b + 21 = b + 20 \\[1em] \Rightarrow 42 - 3b = b + 20 \\[1em] \Rightarrow -3b - b = 20 - 42 \\[1em] \Rightarrow -4b = -22 \\[1em] \Rightarrow b = \dfrac{-22}{-4} \\[1em] \Rightarrow b = \dfrac{11}{2} \\[1em] \Rightarrow b = 5\dfrac{1}{2}.

Hence, b\bm{b} = 5125\dfrac{1}{2}.

Question 20

Solve :

x(x+5)=x2+x+32x(x + 5) = x^{2} + x + 32

Answer

Solving,

x(x+5)=x2+x+32x2+5x=x2+x+32x2x2+5xx=324x=32x=324x=8.\Rightarrow x(x + 5) = x^{2} + x + 32 \\[1em] \Rightarrow x^{2} + 5x = x^{2} + x + 32 \\[1em] \Rightarrow x^{2} - x^{2} + 5x - x = 32 \\[1em] \Rightarrow 4x = 32 \\[1em] \Rightarrow x = \dfrac{32}{4} \\[1em] \Rightarrow x = 8.

Hence, x\bm{x} = 8.

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