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Chapter 1

Integers — Exercise 1(A)

Class - 7 Concise Mathematics Selina



Exercise 1(A)

Question 1

Evaluate :

(i) 427 × 8 + 2 × 427

(ii) 394 × 12 + 394 × (-2)

(iii) 558 × 27 + 3 × 558

Answer

Using the distributive property a × b + a × c = a × (b + c) :

(i) Solving,

427 × 8 + 2 × 427

= 427 × (8 + 2)

= 427 × 10

= 4270.

∴ 427 × 8 + 2 × 427 = 4270.

(ii) Solving,

394 × 12 + 394 × (-2)

= 394 × {12 + (-2)}

= 394 × 10

= 3940.

∴ 394 × 12 + 394 × (-2) = 3940.

(iii) Solving,

558 × 27 + 3 × 558

= 558 × (27 + 3)

= 558 × 30

= 16740.

∴ 558 × 27 + 3 × 558 = 16740.

Question 2

Evaluate :

(i) 673 × 9 + 673

(ii) 1925 × 101 - 1925

Answer

(i) Solving,

673 × 9 + 673

= 673 × (9 + 1)

= 673 × 10

= 6730.

∴ 673 × 9 + 673 = 6730.

(ii) Solving,

1925 × 101 - 1925

= 1925 × (101 - 1)

= 1925 × 100

= 192500.

∴ 1925 × 101 - 1925 = 192500.

Question 3

Verify :

(i) 37 × {8 + (-3)} = 37 × 8 + 37 × (-3)

(ii) (-82) × {(-4) + 19} = (-82) × (-4) + (-82) × 19

(iii) {7 - (-7)} × 7 = 7 × 7 - (-7) × 7

(iv) {(-15) - 8} × -6 = (-15) × (-6) - 8 × (-6)

Answer

(i) 37 × {8 + (-3)} = 37 × 8 + 37 × (-3)

L.H.S. = 37 × {8 + (-3)} = 37 × 5 = 185

R.H.S. = 37 × 8 + 37 × (-3) = 296 + (-111) = 296 - 111 = 185

∴ L.H.S. = R.H.S.

Hence, verified.

(ii) (-82) × {(-4) + 19} = (-82) × (-4) + (-82) × 19

L.H.S. = (-82) × {(-4) + 19} = (-82) × 15 = -1230

R.H.S. = (-82) × (-4) + (-82) × 19 = 328 + (-1558) = 328 - 1558 = -1230

∴ L.H.S. = R.H.S.

Hence, verified.

(iii) {7 - (-7)} × 7 = 7 × 7 - (-7) × 7

L.H.S. = {7 - (-7)} × 7 = (7 + 7) × 7 = 14 × 7 = 98

R.H.S. = 7 × 7 - (-7) × 7 = 49 - (-49) = 49 + 49 = 98

∴ L.H.S. = R.H.S.

Hence, verified.

(iv) {(-15) - 8} × -6 = (-15) × (-6) - 8 × (-6)

L.H.S. = {(-15) - 8} × (-6) = (-23) × (-6) = 138

R.H.S. = (-15) × (-6) - 8 × (-6) = 90 - (-48) = 90 + 48 = 138

∴ L.H.S. = R.H.S.

Hence, verified.

Question 4

Evaluate :

(i) 15 × 8

(ii) 15 × (-8)

(iii) (-15) × 8

(iv) (-15) × -8

Answer

(i) 15 × 8 = 120.

(ii) 15 × (-8) = -120.

(iii) (-15) × 8 = -120.

(iv) (-15) × (-8) = 120.

Question 5

Evaluate :

(i) 4 × 6 × 8

(ii) 4 × 6 × (-8)

(iii) 4 × (-6) × 8

(iv) (-4) × 6 × 8

(v) 4 × (-6) × (-8)

(vi) (-4) × (-6) × 8

(vii) (-4) × 6 × (-8)

(viii) (-4) × (-6) × (-8)

Answer

(i) 4 × 6 × 8 = 24 × 8 = 192.

(ii) 4 × 6 × (-8) = 24 × (-8) = -192.

(iii) 4 × (-6) × 8 = (-24) × 8 = -192.

(iv) (-4) × 6 × 8 = (-24) × 8 = -192.

(v) 4 × (-6) × (-8) = (-24) × (-8) = 192.

(vi) (-4) × (-6) × 8 = 24 × 8 = 192.

(vii) (-4) × 6 × (-8) = (-24) × (-8) = 192.

(viii) (-4) × (-6) × (-8) = 24 × (-8) = -192.

Question 6

Evaluate :

(i) 2 × 4 × 6 × 8

(ii) 2 × (-4) × 6 × 8

(iii) (-2) × 4 × (-6) × 8

(iv) (-2) × (-4) × 6 × (-8)

(v) (-2) × (-4) × (-6) × (-8)

Answer

(i) 2 × 4 × 6 × 8 = 8 × 48 = 384.

(ii) 2 × (-4) × 6 × 8 = (-8) × 48 = -384.

(iii) (-2) × 4 × (-6) × 8 = (-8) × (-48) = 384.

(iv) (-2) × (-4) × 6 × (-8) = 8 × (-48) = -384.

(v) (-2) × (-4) × (-6) × (-8) = 8 × 48 = 384.

Question 7

Determine the integer whose product with '-1' is :

(i) -47

(ii) 63

(iii) -1

(iv) 0

Answer

We will use the property:

(-1) x a = -a

Since multiplying by -1 changes only the sign and not the value of an integer, the required integer has the same value as the given product but with the opposite sign .

(i) Product = -47

(-1) x 47 = -47

Hence, required integer = 47.

(ii) Product = 63

(-1) x -63 = 63

Hence, required integer = -63.

(iii) Product = -1

(-1) x 1 = -1

Hence, required integer = 1.

(iv) Product = 0

(-1) x 0 = 0

Hence, required integer = 0.

Question 8

Eighteen integers are multiplied together. What will be the sign of their product, if :

(i) 15 of them are negative and 3 are positive ?

(ii) 12 of them are negative and 6 are positive ?

(iii) 9 of them are positive and the remaining are negative ?

(iv) all are negative ?

Answer

The sign of the product depends on the number of negative integers. If the number of negative integers is even, the product is positive; if it is odd, the product is negative.

(i) Number of negative integers = 15, which is odd.

∴ The product will be negative.

(ii) Number of negative integers = 12, which is even.

∴ The product will be positive.

(iii) Number of negative integers = 18 - 9 = 9, which is odd.

∴ The product will be negative.

(iv) Number of negative integers = 18, which is even.

∴ The product will be positive.

Question 9

Find which is greater ?

(i) (8 + 10) × 15 or 8 + 10 × 15

(ii) 12 × (6 - 8) or 12 × 6 - 8

(iii) {(-3) - 4} × (-5) or (-3) - 4 × (-5)

Answer

(i) (8 + 10) × 15 = 18 × 15 = 270

8 + 10 × 15 = 8 + 150 = 158

Since 270 > 158,

∴ (8 + 10) × 15 is greater.

(ii) 12 × (6 - 8) = 12 × (-2) = -24

12 × 6 - 8 = 72 - 8 = 64

Since 64 > -24,

∴ 12 × 6 - 8 is greater.

(iii) {(-3) - 4} × (-5) = (-7) × (-5) = 35

(-3) - 4 × (-5) = -3 - (-20) = -3 + 20 = 17

Since 35 > 17,

∴ {(-3) - 4} × (-5) is greater.

Question 10

State true or false :

(i) product of two different integers can be zero.

(ii) product of 120 negative integers and 121 positive integers is negative.

(iii) a × (b + c) = a × b + c

(iv) (b - c) × a = b - c × a.

Answer

(i) True. If one of the two different integers is 0, their product is 0. For example, 0 × 5 = 0.

(ii) False. The number of negative integers is 120, which is even, so the product is positive (positive integers do not change the sign).

(iii) False. By the distributive property, a × (b + c) = a × b + a × c, not a × b + c.

(iv) False. By the distributive property, (b - c) × a = b × a - c × a, not b - c × a.

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