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Chapter 7

Ratio and Proportion — Multiple Choice Questions

Class - 7 Concise Mathematics Selina



Multiple Choice Questions

Question 1

The ratio of 2 m to 400 cm is:

  1. 1 : 2

  2. 2 : 1

  3. 1 : 200

  4. 200 : 1

Answer

As 1 m = 100 cm

2 m = 2 × 100 cm = 200 cm.

Ratio of 2 m to 400 cm = 200 : 400 = 1 : 2.

Hence, option 1 is the correct option.

Question 2

12:13\dfrac{1}{2} : \dfrac{1}{3} is equivalent to:

  1. 2 : 3

  2. 3 : 2

  3. 5 : 6

  4. 6 : 5

Answer

12:13\dfrac{1}{2} : \dfrac{1}{3}

Multiply both terms by 6

=12×6:13×6= \dfrac{1}{2} \times 6 : \dfrac{1}{3} \times 6

= 3 : 2.

Hence, option 2 is the correct option.

Question 3

If A : B = 3 : 5 and B : C = 15 : 23, then A : C is:

  1. 3 : 23

  2. 23 : 3

  3. 9 : 23

  4. 5 : 23

Answer

A : B = 3 : 5 and B : C = 15 : 23

AC=AB×BC=35×1523=45115=923\dfrac{A}{C} = \dfrac{A}{B} \times \dfrac{B}{C} = \dfrac{3}{5} \times \dfrac{15}{23} = \dfrac{45}{115} = \dfrac{9}{23}

So, A : C = 9 : 23

Hence, option 3 is the correct option.

Question 4

If A : B : C = 8 : 6 : 3 and C = 24, then B is equal to:

  1. 48

  2. 18

  3. 12

  4. none of these

Answer

Given, A : B : C = 8 : 6 : 3

Let A = 8x, B = 6x and C = 3x.

Given, C = 24

⇒ 3x = 24

⇒ x = 243\dfrac{24}{3} = 8

∴ B = 6x = 6 × 8 = 48

Hence, option 1 is the correct option.

Question 5

Mohit's salary increases in the ratio 4 : 7. If his original salary is ₹ 2,000; his new salary is:

  1. ₹ 4,000

  2. ₹ 6,000

  3. ₹ 7,000

  4. ₹ 3,500

Answer

Let the original salary be ₹ 4x and the new salary be ₹ 7x.

Original salary = ₹ 2,000

4x = 2000

x = 20004\dfrac{2000}{4} = 500

New salary = 7x = 7 × ₹ 500 = ₹ 3,500

Hence, option 4 is the correct option.

Question 6

If 8 : x = 13:12\dfrac{1}{3} : \dfrac{1}{2}, the value of x is:

  1. 12\dfrac{1}{2}

  2. 13\dfrac{1}{3}

  3. 12

  4. 48

Answer

Given,

8 : x = 13:12\dfrac{1}{3} : \dfrac{1}{2}

Product of extremes = Product of means

8×12=x×138 \times \dfrac{1}{2} = x \times \dfrac{1}{3}

4 = x3\dfrac{x}{3}

x = 12.

Hence, option 3 is the correct option.

Question 7

The fourth proportion to 6, 8 and 10 is:

  1. 340\dfrac{3}{40}

  2. 403\dfrac{40}{3}

  3. 4.8

  4. 152\dfrac{15}{2}

Answer

Let the fourth proportional to a, b and c be x, then a : b :: c : x, where a = 6, b = 8, c = 10.

⇒ 6 : 8 :: 10 : x

Here, the extremes are 6 and x, and the means are 8 and 10.

Product of extremes = Product of means

⇒ 6 × x = 8 × 10

x=8×106=806=403\Rightarrow x = \dfrac{8 \times 10}{6} \\[1em] = \dfrac{80}{6} \\[1em] = \dfrac{40}{3}

Hence, option 2 is the correct option.

Question 8

The third proportion to 2 : 1 is:

  1. 2

  2. 1

  3. 12\dfrac{1}{2}

  4. 13\dfrac{1}{3}

Answer

Let the third proportional to a and b be x, then a, b and x are in continued proportion, i.e. a : b :: b : x, where a = 2, b = 1.

⇒ 2 : 1 :: 1 : x

Here, the extremes are 2 and x, and the means are 1 and 1.

Product of extremes = Product of means

⇒ 2 × x = 1 × 1

x=1×12=12\Rightarrow x = \dfrac{1 \times 1}{2} \\[1em] = \dfrac{1}{2}

Hence, option 3 is the correct option.

Question 9

On a map, 22 m is represented by 3 cm, then what length on map represents 132 m?

  1. 12\dfrac{1}{2} cm

  2. 6 cm

  3. 48 cm

  4. none of these

Answer

Let the length on the map representing 132 m be x cm.

The actual lengths and the lengths on the map are in proportion.

⇒ 22 : 3 :: 132 : x

Product of extremes = Product of means

⇒ 22 × x = 3 × 132

x=3×13222=39622=18 cm\Rightarrow x = \dfrac{3 \times 132}{22} \\[1em] = \dfrac{396}{22} \\[1em] = 18 \text{ cm}

Since 18 cm is not among options 1, 2 and 3, the correct choice is "none of these".

Hence, option 4 is the correct option.

Question 10

13:16:18\dfrac{1}{3} : \dfrac{1}{6} : \dfrac{1}{8} is equivalent to:

  1. 3 : 6 : 8

  2. 8 : 6 : 3

  3. 6 : 3 : 8

  4. 8 : 4 : 3

Answer

L.C.M. of the denominators 3, 6 and 8 is 24.

Multiply each term by 24:

13×24:16×24:18×24\dfrac{1}{3} \times 24 : \dfrac{1}{6} \times 24 : \dfrac{1}{8} \times 24

= 8 : 4 : 3

Hence, option 4 is the correct option.

Question 11

If A = 2B = 3C then A : B : C is equal to:

  1. 1 : 2 : 3

  2. 3 : 2 : 1

  3. 6 : 3 : 2

  4. 2 : 3 : 6

Answer

Let A = 2B = 3C = k.

Then A = k, B = k2 and C=k3\dfrac{k}{2} \text{ and } C = \dfrac{k}{3}.

A : B : C = k:k2:k3=1:12:13k : \dfrac{k}{2} : \dfrac{k}{3} = 1 : \dfrac{1}{2} : \dfrac{1}{3}

Multiply each term by 6:

1×6:12×6:13×61 \times 6 : \dfrac{1}{2} \times 6 : \dfrac{1}{3} \times 6

= 6 : 3 : 2.

Hence, option 3 is the correct option.

Question 12

If A : B = 3 : 4 and A + B = 35, then B is equal to:

  1. 21

  2. 15

  3. 2

  4. 20

Answer

Let A = 3x and B = 4x.

A + B = 35

3x + 4x = 35

7x = 35

x = 357\dfrac{35}{7} = 5

B = 4x = 4 × 5 = 20

Hence, option 4 is the correct option.

Question 13

Which is greater, 2 : 3 or 3 : 4 ?

  1. 2 : 3

  2. 3 : 4

  3. none of these

Answer

2:3=23 and 3:4=34. L.C.M. of 3 and 4 is 12.23=2×43×4=81234=3×34×3=9122 : 3 = \dfrac{2}{3} \text{ and } 3 : 4 = \dfrac{3}{4}.\\[1em] \text { L.C.M. of 3 and 4 is 12.}\\[1em] \dfrac{2}{3} = \dfrac{2 \times 4}{3 \times 4} = \dfrac{8}{12}\\[1em] \dfrac{3}{4} = \dfrac{3 \times 3}{4 \times 3} = \dfrac{9}{12}\\[1em]

Clearly, 912>812\dfrac{9}{12} \gt \dfrac{8}{12}, so (3 : 4) > (2 : 3).

Hence, option 2 is the correct option.

Question 14

In a piece of paper, rectangular in shape, the ratio of its length to its breadth is 8 : 5. If the breadth is 12.5 cm; the length is:

  1. 20 cm

  2. 40 cm

  3. 37.5 cm

  4. 1.6 cm

Answer

Let the length be 8x and the breadth be 5x.

Breadth = 12.5 cm

5x = 12.5

x = 12.55\dfrac{12.5}{5} = 2.5

Length = 8x = 8 × 2.5 = 20 cm

Hence, option 1 is the correct option.

Question 15

The ratio of the number of faces of a cube to the number of edges in it is:

  1. 1 : 2

  2. 1 : 3

  3. 2 : 1

  4. 3 : 1

Answer

Number of faces of a cube = 6

Number of edges of a cube = 12

Ratio = 6 : 12 = 1 : 2

Hence, option 1 is the correct option.

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