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Chapter 3

Decimals - Exercise 3(C)

Class - 7 RS Aggarwal Mathematics Solutions



Exercise 3(C)

Question 1(i)

Multiply :

6.5 x 10

Answer

We have:

6.5 x 10

On multiplying 6.5 by 10, the decimal point is shifted by one place to the right.

∴ 6.5 × 10 = 65

Question 1(ii)

Multiply :

0.8 x 10

Answer

We have:

0.8 x 10

On multiplying 0.8 by 10, the decimal point is shifted by one place to the right.

∴ 0.8 × 10 = 8

Question 1(iii)

Multiply :

9.07 x 10

Answer

We have:

9.07 x 10

On multiplying 9.07 by 10, the decimal point is shifted by one place to the right.

∴ 9.07 × 10 = 90.7

Question 1(iv)

Multiply :

2.345 x 10

Answer

We have:

2.345 x 10

On multiplying 2.345 by 10, the decimal point is shifted by one place to the right.

∴ 2.345 × 10 = 23.45

Question 1(v)

Multiply :

4.63 x 100

Answer

We have:

4.63 x 100

On multiplying 4.63 by 100, the decimal point is shifted by two places to the right.

∴ 4.63 × 100 = 463

Question 1(vi)

Multiply :

8.279 x 100

Answer

We have:

8.279 x 100

On multiplying 8.279 by 100, the decimal point is shifted by two places to the right.

∴ 8.279 × 100 = 827.9

Question 1(vii)

Multiply :

7.8 x 100

Answer

We have:

7.8 x 100

On multiplying 7.8 by 100, the decimal point is shifted by two places to the right.

∴ 7.8 × 100 = 780

Question 1(viii)

Multiply :

0.09 x 100

Answer

We have:

0.09 x 100

On multiplying 0.09 by 100, the decimal point is shifted by two places to the right.

∴ 0.09 × 100 = 9

Question 1(ix)

Multiply :

0.283 x 1000

Answer

We have:

0.283 x 1000

On multiplying 0.283 by 1000, the decimal point is shifted by three places to the right.

∴ 0.283 × 1000 = 283

Question 1(x)

Multiply :

6.25 x 1000

Answer

We have:

6.25 x 1000

On multiplying 6.25 by 1000, the decimal point is shifted by three places to the right.

∴ 6.25 × 1000 = 6250

Question 1(xi)

Multiply :

5.4 x 1000

Answer

We have:

5.4 x 1000

On multiplying 5.4 by 1000, the decimal point is shifted by three places to the right.

∴ 5.4 × 1000 = 5400

Question 1(xii)

Multiply :

0.3 x 1000

Answer

We have:

0.3 x 1000

On multiplying 0.3 by 1000, the decimal point is shifted by three places to the right.

∴ 0.3 × 1000 = 300

Question 2(i)

Multiply :

2.4 x 16

Answer

We have:

24 x 16 = 384

∴ 2.4 × 16 = 38.4 \quad [1 place of decimal]

The answer is 38.4

Question 2(ii)

Multiply :

3.45 x 17

Answer

We have:

345 × 17 = 5865

∴ 3.45 × 17 = 58.65 \quad [2 places of decimal]

The answer is 58.65

Question 2(iii)

Multiply :

0.86 x 14

Answer

We have:

86 × 14 = 1204

∴ 0.86 × 14 = 12.04 \quad [2 places of decimal]

The answer is 12.04

Question 2(iv)

Multiply :

2.68 x 30

Answer

We have:

268 × 30 = 8040

∴ 2.68 × 30 = 80.4 \quad [2 places of decimal]

The answer is 80.4

Question 2(v)

Multiply :

0.023 x 65

Answer

We have:

23 × 65 = 1495

∴ 0.023 × 65 = 1.495 \quad [3 places of decimal]

The answer is 1.495

Question 2(vi)

Multiply :

0.0006 x 15

Answer

We have:

6 × 15 = 90

∴ 0.0006 × 15 = 0.009 \quad [4 places of decimal]

The answer is 0.009

Question 3(i)

Find the product :

5.6 x 1.4

Answer

First we multiply 56 by 14

56×1422456×784\begin{matrix} & & 5 & 6 \\ \times & & 1 & 4 \\ \hline & 2 & 2 & 4 \\ & 5 & 6 & \times \\ \hline & \bold{7} & \bold{8} & \bold{4} \end{matrix}

Clearly, 56 × 14 = 784

Sum of decimal places in given decimals = (1 + 1) = 2

So, the product contains 2 places of decimal

∴ 5.6 × 1.4 = 7.84

Question 3(ii)

Find the product :

2.35 x 7.2

Answer

First we multiply 235 by 72

235×724701645×16920\begin{matrix} & & 2 & 3 & 5 \\ \times & & & 7 & 2 \\ \hline & & 4 & 7 & 0 \\ 1 & 6 & 4 & 5 & \times \\ \hline \bold{1} & \bold{6} & \bold{9} & \bold{2} & \bold{0} \end{matrix}

Clearly, 235 × 72 = 16920

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 2.35 × 7.2 = 16.920 = 16.92

Question 3(iii)

Find the product :

0.37 x 0.26

Answer

First we multiply 37 by 26

37×2622274×962\begin{matrix} & & 3 & 7 \\ \times & & 2 & 6 \\ \hline & 2 & 2 & 2 \\ & 7 & 4 & \times \\ \hline & \bold{9} & \bold{6} & \bold{2} \end{matrix}

Clearly, 37 × 26 = 962

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.37 × 0.26 = 0.0962

Question 3(iv)

Find the product :

0.74 x 6.7

Answer

First we multiply 74 by 67

74×67518444×4958\begin{matrix} & & & 7 & 4 \\ \times & & & 6 & 7 \\ \hline & & 5 & 1 & 8 \\ & 4 & 4 & 4 & \times \\ \hline & \bold{4} & \bold{9} & \bold{5} & \bold{8} \end{matrix}

Clearly, 74 × 67 = 4958

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 0.74 × 6.7 = 4.958

Question 3(v)

Find the product :

5.64 x 0.08

Answer

First we multiply 564 by 8

564×84512\begin{matrix} & & 5 & 6 & 4 \\ \times & & & & 8 \\ \hline & \bold{4} & \bold{5} & \bold{1} & \bold{2} \end{matrix}

Clearly, 564 × 8 = 4512

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 5.64 × 0.08 = 0.4512

Question 3(vi)

Find the product :

2.75 x 1.7

Answer

First we multiply 275 by 17

275×171925275×4675\begin{matrix} & & 2 & 7 & 5 \\ \times & & & 1 & 7 \\ \hline & 1 & 9 & 2 & 5 \\ & 2 & 7 & 5 & \times \\ \hline & \bold{4} & \bold{6} & \bold{7} & \bold{5} \end{matrix}

Clearly, 275 × 17 = 4675

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 2.75 × 1.7 = 4.675

Question 3(vii)

Find the product :

0.04 x 0.36

Answer

First we multiply 4 by 36

36×4144\begin{matrix} & & 3 & 6 \\ \times & & & 4 \\ \hline & \bold{1} & \bold{4} & \bold{4} \end{matrix}

Clearly, 4 × 36 = 144

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.04 × 0.36 = 0.0144

Question 3(viii)

Find the product :

34.2 x 1.86

Answer

First we multiply 342 by 186

342×18620522736×342××63612\begin{matrix} & & 3 & 4 & 2 \\ \times & & 1 & 8 & 6 \\ \hline & 2 & 0 & 5 & 2 \\ 2 & 7 & 3 & 6 & \times \\ 3 & 4 & 2 & \times & \times \\ \hline \bold{6} & \bold{3} & \bold{6} & \bold{1} & \bold{2} \end{matrix}

Clearly, 342 × 186 = 63612

Sum of decimal places in given decimals = (1 + 2) = 3

So, the product contains 3 places of decimal

∴ 34.2 × 1.86 = 63.612

Question 3(ix)

Find the product :

0.028 x 0.9

Answer

First we multiply 28 by 9

28×9252\begin{matrix} & & 2 & 8 \\ \times & & & 9 \\ \hline & \bold{2} & \bold{5} & \bold{2} \end{matrix}

Clearly, 28 × 9 = 252

Sum of decimal places in given decimals = (3 + 1) = 4

So, the product contains 4 places of decimal

∴ 0.028 × 0.9 = 0.0252

Question 4(i)

Find the product :

2.3 x 0.23 x 0.1

Answer

First we multiply 23 by 23 and then by 1

23×236946×529\begin{matrix} & & 2 & 3 \\ \times & & 2 & 3 \\ \hline & & 6 & 9 \\ & 4 & 6 & \times \\ \hline & \bold{5} & \bold{2} & \bold{9} \end{matrix}

Clearly, 23 × 23 × 1 = 529

Sum of decimal places in given decimals = (1 + 2 + 1) = 4

So, the product contains 4 places of decimal

529 x 1 = 529

∴ 2.3 × 0.23 × 0.1 = 0.0529

Question 4(ii)

Find the product :

1.2 x 3.5 x 0.3

Answer

First we multiply 12 by 35 and then by 3

12×356036×420\begin{matrix} & & 1 & 2 \\ \times & & 3 & 5 \\ \hline & & 6 & 0 \\ & 3 & 6 & \times \\ \hline & \bold{4} & \bold{2} & \bold{0} \end{matrix}

∴ 12 × 35 = 420

420×31260\begin{matrix} & & 4 & 2 & 0 \\ \times & & & & 3 \\ \hline & \bold{1} & \bold{2} & \bold{6} & \bold{0} \end{matrix}

∴ 12 × 35 × 3 = 1260

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ 1.2 × 3.5 × 0.3 = 1.260 = 1.26

Question 4(iii)

Find the product :

0.6 x 1.5 x 0.7

Answer

First we multiply 6 by 15 and then by 7

15×690\begin{matrix} & 1 & 5 \\ \times & & 6 \\ \hline & \bold{9} & \bold{0} \end{matrix}

∴ 6 × 15 = 90

90×7630\begin{matrix} & 9 & 0 \\ \times & & 7 \\ \hline \bold{6} & \bold{3} & \bold{0} \end{matrix}

∴ 6 × 15 x 7 = 630

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ 0.6 × 1.5 × 0.7 = 0.630 = 0.63

Question 4(iv)

Find the product :

0.2 x 0.2 x 0.02

Answer

First we multiply 2 by 2 and then by 2

2×24\begin{matrix} & 2 \\ \times & 2 \\ \hline & \bold{4} \end{matrix}

∴ 2 × 2 = 4

4×28\begin{matrix} & 4 \\ \times & 2 \\ \hline & \bold{8} \end{matrix}

∴ 2 × 2 x 2 = 8

Sum of decimal places in given decimals = (1 + 1 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.2 × 0.2 × 0.02 = 0.0008

Question 4(v)

Find the product :

1.1 x 0.1 x 0.11

Answer

First we multiply 11 by 1 and then by 11

11×111\begin{matrix} & 1 & 1 \\ \times & & 1 \\ \hline & \bold{1} & \bold{1} \end{matrix}

∴ 11 × 1 = 11

11×111111×121\begin{matrix} & & 1 & 1 \\ \times & & 1 & 1 \\ \hline & & 1 & 1 \\ & 1 & 1 & \times \\ \hline & \bold{1} & \bold{2} & \bold{1} \end{matrix}

∴ 11 × 1 x 11 = 121

Sum of decimal places in given decimals = (1 + 1 + 2) = 4

So, the product contains 4 places of decimal

∴ 1.1 × 0.1 × 0.11 = 0.0121

Question 4(vi)

Find the product :

0.6 x 0.06 x 0.006

Answer

First we multiply 6 by 6 and then by 6

6×636\begin{matrix} & & 6 \\ \times & & 6 \\ \hline & \bold{3} & \bold{6} \end{matrix}

∴ 6 × 6 = 36

36×6216\begin{matrix} & 3 & 6 \\ \times & & 6 \\ \hline \bold{2} & \bold{1} & \bold{6} \end{matrix}

∴ 6 × 6 × 6 = 216

Sum of decimal places in given decimals = (1 + 2 + 3) = 6

So, the product contains 6 places of decimal

∴ 0.6 × 0.06 × 0.006 = 0.000216

Question 5(i)

Evaluate :

(1.3)2

Answer

We have:

(1.3)2 = 1.3 × 1.3

First we multiply 13 by 13

13×133913×169\begin{matrix} & & 1 & 3 \\ \times & & 1 & 3 \\ \hline & & 3 & 9 \\ & 1 & 3 & \times \\ \hline & \bold{1} & \bold{6} & \bold{9} \end{matrix}

∴ 13 × 13 = 169

Sum of decimal places in given decimals = (1 + 1) = 2

So, the product contains 2 places of decimal

∴ (1.3)2 = 1.69

Question 5(ii)

Evaluate :

(0.06)2

Answer

We have:

(0.06)2 = 0.06 × 0.06

First we multiply 6 by 6

6×636\begin{matrix} & & 6 \\ \times & & 6 \\ \hline & \bold{3} & \bold{6} \end{matrix}

∴ 6 × 6 = 36

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ (0.06)2 = 0.0036

Question 5(iii)

Evaluate :

(0.2)3

Answer

We have:

(0.2)3 = 0.2 × 0.2 × 0.2

First we multiply 2 × 2 × 2

2×24\begin{matrix} & 2 \\ \times & 2 \\ \hline & \bold{4} \end{matrix}

∴ 2 × 2 =4

4×28\begin{matrix} & 4 \\ \times & 2 \\ \hline & \bold{8} \end{matrix}

∴ 2 × 2 × 2 = 8

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ (0.2)3 = 0.008

Question 5(iv)

Evaluate :

(0.8)3

Answer

We have:

(0.8)3 = 0.8 × 0.8 × 0.8

First we multiply 8 × 8 × 8

8×864\begin{matrix} & & 8 \\ \times & & 8 \\ \hline & \bold{6} & \bold{4} \end{matrix}

∴ 8 × 8 = 64

64×8512\begin{matrix} & 6 & 4 \\ \times & & 8 \\ \hline \bold{5} & \bold{1} & \bold{2} \end{matrix}

∴ 8 × 8 × 8 = 512

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ (0.8)3 = 0.512

Question 6

The cost of one pen is ₹42.25. Find the cost of one dozen such pens.

Answer

Given:

Cost of 1 pen = ₹42.25

Number of pens = 1 dozen = 12 pens

The cost of 1 dozen pens = (Cost of 1 pen) x (Number of pens)

Substituting the values in above, we get:

The cost of 1 dozen pens = ₹42.25 x 12

Sum of the decimal places in given decimals = 2 + 0 = 2

So, the product contains 2 places of decimal.

4225×1284504225×50700\begin{matrix} & & 4 & 2 & 2 & 5 \\ \times & & & & 1 & 2 \\ \hline & & 8 & 4 & 5 & 0 \\ & 4 & 2 & 2 & 5 & \times \\ \hline & \bold{5} & \bold{0} & \bold{7} & \bold{0} & \bold{0} \end{matrix}

∴ ₹42.25 × 12 = ₹507.00 = ₹507

Hence, the cost of one dozen pens = ₹507

Question 7

A car moves at a constant speed of 56.4 km per hour. How much distance does it cover in 3.5 hours?

Answer

Given:

Speed per hour = 56.4 km

Total time = 3.5 hours

Distance covered = ?

We know the formula,

Distance = Speed x Time

Substituting the values in above, we get:

Distance = 56.4 km x 3.5 hours

Sum of the decimal places in given decimals = 1 + 1 = 2

So, the product contains 2 places of decimal

564×3528201692×19740\begin{matrix} & & 5 & 6 & 4 \\ \times & & & 3 & 5 \\ \hline & 2 & 8 & 2 & 0 \\ 1 & 6 & 9 & 2 & \times \\ \hline \bold{1} & \bold{9} & \bold{7} & \bold{4} & \bold{0} \end{matrix}

∴ 56.4 km × 3.5 hours = 197.40 km = 197.4 km

Hence, the distance covered by the car = 197.4 km

Question 8

A room is 4.5 m long and 3.8 m broad. Calculate the area of the floor of the room.

Answer

Given:

Length of the room = 4.5 m

Breadth of the room = 3.8 m

Area of the floor = ?

The floor will be of rectangular shape

We know the formula,

Area = Length x Breadth

Substituting the values in above, we get:

Area = 4.5 m x 3.8 m

Sum of the decimal places in given decimals = 1 + 1 = 2

So, the product contains 2 places of decimal

45×38360135×1710\begin{matrix} & & 4 & 5 \\ \times & & 3 & 8 \\ \hline & 3 & 6 & 0 \\ 1 & 3 & 5 & \times \\ \hline \bold{1} & \bold{7} & \bold{1} & \bold{0} \end{matrix}

∴ 4.5 m × 3.8 m = 17.10 m2 = 17.1 m2

Hence, the area of the floor = 17.1 m2

Question 9

The cost of 1 litre of refined oil is ₹124.75. What is the cost of 6.2 litres of this oil?

Answer

Given:

Cost of 1 litre of refined oil = ₹124.75

Total quantity of oil = 6.2 litres

Cost of 6.2 litres of oil = ?

Cost of 6.2 litres of oil = (Cost of 1 litre) x (Total quantity)

Substituting the values in above, we get:

Cost of 6.2 litres of oil = (₹124.75) x (6.2 litres)

Sum of the decimal places in given decimals = 2 + 1 = 3

So, the product contains 3 places of decimal

12475×622495074850×773450\begin{matrix} & & 1 & 2 & 4 & 7 & 5 \\ \times & & & & & 6 & 2 \\ \hline & & 2 & 4 & 9 & 5 & 0 \\ & 7 & 4 & 8 & 5 & 0 & \times \\ \hline & \bold{7} & \bold{7} & \bold{3} & \bold{4} & \bold{5} & \bold{0} \end{matrix}

∴ 124.75 × 6.2 litres = ₹773.450 = ₹773.45

Hence, the cost of 6.2 litres of oil = ₹773.45

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