Add the following integers :
(i) 64 and 36
(ii) 73 and -37
(iii) -26 and -45
(iv) -51 and 25
(v) 100 and -32
(vi) 0 and -21
Answer
(i)
We have
64 + 36
= 100
(ii)
We have
73 + (-37)
Since one integer is positive and the other is negative, we subtract their values and keep the sign of the greater number (73).
73 + (-37)
= 73 - 37
= 36
(iii)
We have
-26 + (-45)
Since both integers are negative, we add their values and keep the negative sign.
-26 + (-45)
= -26 - 45
= -71
(iv)
We have
−51 + 25
Since one integer is negative and the other is positive, we subtract their values and keep the sign of the greater number (−51).
−51 + 25
= −(51 − 25)
= −26
(v)
We have
100 + (−32)
Since one integer is positive and the other is negative, we subtract their values and keep the sign of the greater number (100).
100 + (−32)
= 100 − 32
= 68
(vi)
We have
0 + (-21)
Zero is the additive identity. Adding 0 to any integer does not change its value.
∴ 0 + (-21)
= -21
Find the additive inverse of :
(i) 23
(ii) -33
(iii) -1
(iv) -476
Answer
(i) 23
Since 23 + (−23) = 0
∴ the additive inverse of 23 is -23
(ii) -33
Since (−33) + 33 = 0
∴ the additive inverse of −33 is 33
(iii) -1
Since (−1) + 1 = 0
∴ the additive inverse of −1 is 1
(iv) -476
Since (−476) + 476 = 0
∴ the additive inverse of −476 is 476
Evaluate :
(i) 6 - 24
(ii) 18 - (-8)
(iii) (-16) - (-5)
(iv) (-20) - 6
(v) (-1) - (-19)
(vi) 8 - (-23)
Answer
(i)
We have
6 - 24
= 6 + (-24)
= -18
(ii)
We have
18 - (-8)
= 18 + 8
= 26 [∵ a - (-b) = a + b]
(iii)
We have
(-16) - (-5)
= -16 + 5
= -11
(iv)
We have
(-20) - 6
= (-20) + (-6)
= -26
(v)
We have
(-1) - (-19)
= (-1) + 19
= 18
(vi)
We have
8 - (-23)
= 8 + 23
= 31 [∵ a - (-b) = a + b]
Verify the following :
(-14) + 9 = 9 + (-14)
Answer
We have
(-14) + 9 = 9 + (-14)
LHS = (−14) + 9
= −5
RHS = 9 + (−14)
= −5
Since LHS = RHS,
∴ (-14) + 9 = 9 + (-14)
Verify the following :
(-8) + (-12) = (-12) + (-8)
Answer
We have
(-8) + (-12) = (-12) + (-8)
LHS = (−8) + (−12)
= −20
RHS = (−12) + (−8)
= −20
Since LHS = RHS,
∴ (-8) + (-12) = (-12) + (-8)
Verify the following :
(-6) + [(-8) + 12] = [(-6) + (-8)] + 12
Answer
We have
(-6) + [(-8) + 12] = [(-6) + (-8)] + 12
LHS = (−6) + [−8 + 12]
= (−6) + 4
= −2
RHS = [(−6) + (−8)] + 12
= (−14) + 12
= −2
Since LHS = RHS,
∴ (-6) + [(-8) + 12] = [(-6) + (-8)] + 12
Verify the following :
[(-9) + (-7)] + (-14) = (-9) + [(-7) + (-14)]
Answer
We have
[(-9) + (-7)] + (-14) = (-9) + [(-7) + (-14)]
LHS = [−9 + (−7)] + (−14)
= (−16) + (−14)
= −30
RHS = (−9) + [−7 + (−14)]
= (−9) + (−21)
= −30
Since LHS = RHS,
∴ [(-9) + (-7)] + (-14) = (-9) + [(-7) + (-14)]
Fill in the blanks:
(i) 8 + ............... = 0
(ii) (-10) + ............... = -10
(iii) (-6) + (-8) = (-8) + ...............
(iv) (-6) + ............... = -14
(v) (-11) + ............... = (-7)
(vi) (-9) + ............... = -1
Answer
(i) 8 + (-8) = 0
(ii) (-10) + 0 = -10
(iii) (-6) + (-8) = (-8) + (-6)
(iv) (-6) + (-8) = -14
(v) (-11) + 4 = (-7)
(vi) (-9) + 8 = -1
Subtract the sum of -137 and -43 from the sum of -103 and 27.
Answer
Calculate the sum of -137 and -43:
(-137) + (-43) = -180
Calculate the sum of -103 and 27:
(-103) + 27 = -76
Subtract the first sum from the second sum:
(-180) - (-76)
= -180 + 76
= -104
∴ The answer is -104
Subtract -29 from -53 and add -16 to the result.
Answer
Subtract -29 from -53:
-53 - (-29) = -53 + 29 = -24
Add -16 to the result: -24 + (-16) = -40
Final Answer is -40
The sum of two integers is 43. If one of them is -27, find the other.
Answer
Let the two integers be x and y.
Given that x + y = 43 and x = -27.
Substitute x in the below equation
x + y = 43
-27 + y = 23 (Substituting x)
y = 23 + 27 (Solve for y)
y = 23 + 27
y = 70
∴ The other integer is 70
Find the successor of :
(i) 30
(ii) -70
(iii) -206
(iv) -1
Answer
(i)
The successor of 30 is:
30 + 1 = 31
(ii)
The successor of -70 is:
-70 + 1 = -69
(iii)
The successor of -206 is:
-206 + 1 = -205
(iv)
The successor of -1 is:
-1 + 1 = 0
Find the predecessor of:
(i) 60
(ii) -351
(iii) 0
(iv) -99
Answer
(i)
The predecessor of 60 is:
60 - 1 = 59
(ii)
The predecessor of -351 is:
-351 - 1 = -352
(iii)
The predecessor of 0 is:
0 - 1 = -1
(iv)
The predecessor of -99 is:
-99 - 1 = -100