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Chapter 3

Decimals

Class - 7 RS Aggarwal Mathematics Solutions



Exercise 3(A)

Question 1(i)

Convert the following decimals into like decimals :

8.1, 9.4, 6.05, 12

Answer

Given:

8.1, 9.4, 6.05, 12

To convert into like decimals, we make the number of decimal places equal.

The maximum number of decimal places is 2 (in 6.05).

So,

8.1 = 8.10
9.4 = 9.40
6.05 = 6.05
12 = 12.00

∴ Like decimals are 8.10, 9.40, 6.05 and 12.00

Question 1(ii)

Convert the following decimals into like decimals :

6.35, 11.8, 9.125, 32.04, 9

Answer

Given:

6.35, 11.8, 9.125, 32.04, 9

The maximum number of decimal places is 3 (in 9.125).

So,

6.35 = 6.350
11.8 = 11.800
9.125 = 9.125
32.04 = 32.040
9 = 9.000

∴ Like decimals are 6.350, 11.800, 9.125, 32.040 and 9.000

Question 1(iii)

Convert the following decimals into like decimals :

6.005, 2, 0.6, 1.78, 14.3

Answer

Given:

6.005, 2, 0.6, 1.78, 14.3

The maximum number of decimal places is 3 (in 6.005).

So,

6.005 = 6.005
2 = 2.000
0.6 = 0.600
1.78 = 1.780
14.3 = 14.300

∴ Like decimals are 6.005, 2.000, 0.600, 1.780 and 14.300

Question 1(iv)

Convert the following decimals into like decimals :

0.72, 53.76, 16, 8.304, 2.3754

Answer

Given:

0.72, 53.76, 16, 8.304, 2.3754

Maximum decimal places = 4

So,

0.72 = 0.7200
53.76 = 53.7600
16 = 16.0000
8.304 = 8.3040
2.3754 = 2.3754

∴ Like decimals are 0.7200, 53.7600, 16.0000, 8.3040 and 2.3754

Question 2(i)

Write each of the following decimals into expanded form :

16.74

Answer

We have:

16.74 = 10 + 6 + 0.7 + 0.04 \hspace{2cm}[Separating according to place values]

=(1×10)+(6×1)+(7×110)+(4×1100)=10+6+710+4100= (1 \times 10) + (6 \times 1) + \Big(7 \times \dfrac{1}{10}\Big) + \Big(4 \times\dfrac{1}{100}\Big) \\[1em] = 10 + 6 + \dfrac{7}{10} + \dfrac{4}{100}

∴ The expanded form of 16.74 is (10+6+710+4100)\Big(10 + 6 + \dfrac{7}{10} + \dfrac{4}{100}\Big)

Question 2(ii)

Write each of the following decimals into expanded form :

243.689

Answer

We have:

243.689 = 200 + 40 + 3 + 0.6 + 0.08 + 0.009 [Separating according to place values]

=(2×100)+(4×10)+(3×1)+(6×110)+(8×1100)+(9×11000)=200+40+3+610+8100+91000= (2 \times 100) + (4 \times 10) + (3 \times 1) + \Big(6 \times \dfrac{1}{10}\Big) + \Big(8 \times \dfrac{1}{100}\Big) + \Big(9 \times \dfrac{1}{1000}\Big) \\[1em] = 200 + 40 + 3 + \dfrac{6}{10} + \dfrac{8}{100} + \dfrac{9}{1000}

∴ The expanded form of 243.689 is (200+40+3+610+8100+91000)\Big(200 + 40 + 3 + \dfrac{6}{10} + \dfrac{8}{100} + \dfrac{9}{1000}\Big)

Question 2(iii)

Write each of the following decimals into expanded form :

9.3578

Answer

We have:

9.3578 = 9 + 0.3 + 0.05 + 0.007 + 0.0008 [Separating according to place values]

=(9×1)+(3×110)+(5×1100)+(7×11000)+(8×110000)=9+310+5100+71000+810000= (9 \times 1) + \Big(3 \times \dfrac{1}{10}\Big) + \Big(5 \times \dfrac{1}{100}\Big) + \Big(7 \times \dfrac{1}{1000}\Big) + \Big(8 \times \dfrac{1}{10000}\Big) \\[1em] = 9 + \dfrac{3}{10} + \dfrac{5}{100} + \dfrac{7}{1000} + \dfrac{8}{10000}

∴ The expanded form of 9.3578 is (9+310+5100+71000+810000)\Big(9 + \dfrac{3}{10} + \dfrac{5}{100} + \dfrac{7}{1000} + \dfrac{8}{10000}\Big)

Question 2(iv)

Write each of the following decimals into expanded form :

2314.57

Answer

We have:

2314.57 = 2000 + 300 + 10 + 4 + 0.5 + 0.07 [Separating according to place values]

=(2×1000)+(3×100)+(1×10)+(4×1)+(5×110)+(7×1100)=2000+300+10+4+510+7100= (2 \times 1000) + (3 \times 100) + (1 \times 10) + (4 \times 1) + \Big(5 \times \dfrac{1}{10}\Big) + \Big(7 \times \dfrac{1}{100}\Big) \\[1em] = 2000 + 300 + 10 + 4 + \dfrac{5}{10} + \dfrac{7}{100}

∴ The expanded form of 2314.57 is (2000+300+10+4+510+7100)\Big(2000 + 300 + 10 + 4 + \dfrac{5}{10} + \dfrac{7}{100}\Big)

Question 3(i)

Express the following as a fraction in simplest form :

0.8

Answer

We have:

0.8

There is 1 decimal place, so we remove the decimal point and divide by 10.

=0.8=810=45[Dividing both by 2]\phantom{=} 0.8 = \dfrac{8}{10} \\[1em] = \dfrac{4}{5} \quad \text{[Dividing both by 2]}

∴ The answer is 45\dfrac{4}{5}

Question 3(ii)

Express the following as a fraction in simplest form :

0.45

Answer

We have:

0.45

There are 2 decimal places, so we remove the decimal point and divide by 100.

=0.45=45100=920[Dividing both by 5]\phantom{=} 0.45 = \dfrac{45}{100} \\[1em] = \dfrac{9}{20} \quad \text{[Dividing both by 5]}

∴ The answer is 920\dfrac{9}{20}

Question 3(iii)

Express the following as a fraction in simplest form :

1.6

Answer

We have:

1.6

There is 1 decimal place, so we remove the decimal point and divide by 10.

=1.6=1610=85[Dividing both by 2]=135\phantom{=} 1.6 = \dfrac{16}{10} \\[1em] = \dfrac{8}{5} \quad \text{[Dividing both by 2]} \\[1em] = 1\dfrac{3}{5}

∴ The answer is 1351\dfrac{3}{5}

Question 3(iv)

Express the following as a fraction in simplest form :

4.75

Answer

We have:

4.75

There are 2 decimal places, so we remove the decimal point and divide by 100.

=4.75=475100=194[Dividing both by 25]=434\phantom{=} 4.75 = \dfrac{475}{100} \\[1em] = \dfrac{19}{4} \quad \text{[Dividing both by 25]} \\[1em] = 4\dfrac{3}{4}

∴ The answer is 4344\dfrac{3}{4}

Question 3(v)

Express the following as a fraction in simplest form :

0.345

Answer

We have:

0.345

There are 3 decimal places, so we remove the decimal point and divide by 1000.

=0.345=3451000=69200[Dividing both by 5]\phantom{=} 0.345 = \dfrac{345}{1000} \\[1em] = \dfrac{69}{200} \quad \text{[Dividing both by 5]}

∴ The answer is 69200\dfrac{69}{200}

Question 3(vi)

Express the following as a fraction in simplest form :

64.015

Answer

We have:

64.015

There are 3 decimal places, so we remove the decimal point and divide by 1000.

=64.015=640151000=12803200[Dividing both by 5]=643200\phantom{=} 64.015 = \dfrac{64015}{1000} \\[1em] = \dfrac{12803}{200} \quad \text{[Dividing both by 5]} \\[1em] = 64\dfrac{3}{200}

∴ The answer is 64320064\dfrac{3}{200}

Question 3(vii)

Express the following as a fraction in simplest form :

12.725

Answer

We have:

12.725

There are 3 decimal places, so we remove the decimal point and divide by 1000.

=12.725=127251000=50940[Dividing both by 25]=122940\phantom{=} 12.725 = \dfrac{12725}{1000} \\[1em] = \dfrac{509}{40} \quad \text{[Dividing both by 25]} \\[1em] = 12\dfrac{29}{40}

∴ The answer is 12294012\dfrac{29}{40}

Question 3(viii)

Express the following as a fraction in simplest form :

0.0024

Answer

We have:

0.0024

There are 4 decimal places, so we remove the decimal point and divide by 10000.

=0.0024=2410000=31250[Dividing both by 8]\phantom{=} 0.0024 = \dfrac{24}{10000} \\[1em] = \dfrac{3}{1250} \quad \text{[Dividing both by 8]}

∴ The answer is 31250\dfrac{3}{1250}

Question 4(i)

Convert the following fraction into a decimal :

1910\dfrac{19}{10}

Answer

We have:

=1910=1910[Converting improper to mixed fraction]=1+910=1+0.9=1.9\phantom{=} \dfrac{19}{10} = 1\dfrac{9}{10} \quad \text{[Converting improper to mixed fraction]} \\[1em] = 1 + \dfrac{9}{10} \\[1em] = 1 + 0.9 \\[1em] = 1.9

∴ The answer is 1.9

Question 4(ii)

Convert the following fraction into a decimal :

243100\dfrac{243}{100}

Answer

We have:

=243100=243100[Converting improper to mixed fraction]=2+43100=2+0.43=2.43\phantom{=} \dfrac{243}{100} = 2\dfrac{43}{100} \quad \text{[Converting improper to mixed fraction]} \\[1em] = 2 + \dfrac{43}{100} \\[1em] = 2 + 0.43 \\[1em] = 2.43

∴ The answer is 2.43

Question 4(iii)

Convert the following fraction into a decimal :

51100\dfrac{51}{100}

Answer

We have:

51100=0.51\dfrac{51}{100} = 0.51

∴ The answer is 0.51

Question 4(iv)

Convert the following fraction into a decimal :

9100\dfrac{9}{100}

Answer

We have:

9100=0.09\dfrac{9}{100} = 0.09

∴ The answer is 0.09

Question 4(v)

Convert the following fraction into a decimal :

721000\dfrac{72}{1000}

Answer

We have:

721000=0.072\dfrac{72}{1000} = 0.072

∴ The answer is 0.072

Question 4(vi)

Convert the following fraction into a decimal :

35\dfrac{3}{5}

Answer

We have:

=35=3×25×2[Multiplying by 2 to get denominator 10]=610=0.6\phantom{=} \dfrac{3}{5} = \dfrac{3 \times 2}{5 \times 2} \quad \text{[Multiplying by 2 to get denominator 10]} \\[1em] = \dfrac{6}{10} \\[1em] = 0.6

∴ The answer is 0.6

Question 4(vii)

Convert the following fraction into a decimal :

78\dfrac{7}{8}

Answer

We have:

=78=7×1258×125[Multiplying by 125 to get denominator 1000]=8751000=0.875\phantom{=} \dfrac{7}{8} = \dfrac{7 \times 125}{8 \times 125} \quad \text{[Multiplying by 125 to get denominator 1000]} \\[1em] = \dfrac{875}{1000} \\[1em] = 0.875

∴ The answer is 0.875

Question 4(viii)

Convert the following fraction into a decimal :

3740\dfrac{37}{40}

Answer

We have:

=3740=37×2540×25[Multiplying by 25 to get denominator 1000]=9251000=0.925\phantom{=} \dfrac{37}{40} = \dfrac{37 \times 25}{40 \times 25} \hspace{2cm}\text{[Multiplying by 25 to get denominator 1000]} \\[1em] = \dfrac{925}{1000} \\[1em] = 0.925

∴ The answer is 0.925

Question 4(ix)

Convert the following fraction into a decimal :

4384\dfrac{3}{8}

Answer

First, we convert the mixed fraction into an improper fraction:

=438=4×8+38=32+38=358\phantom{=} 4\dfrac{3}{8} = \dfrac{4 \times 8 + 3}{8} = \dfrac{32 + 3}{8} = \dfrac{35}{8}

Now, we divide 35 by 8. Since 35 is not exactly divisible by 8, we add a decimal point and zeros to continue the division:

4.3758)35.00032.0003000240060056040400\begin{array}{r} 4.375 \\ 8 \overline{) 35.000} \\ \underline{-32\phantom{.000}} \\ 30\phantom{00} \\ \underline{-24\phantom{00}} \\ 60\phantom{0} \\ \underline{-56\phantom{0}} \\ 40 \\ \underline{-40} \\ 0 \end{array}

358\dfrac{35}{8} = 4.375

4384\dfrac{3}{8} = 4.375

Question 4(x)

Convert the following fraction into a decimal :

91259\dfrac{1}{25}

Answer

First, we convert the mixed fraction into an improper fraction:

=9125=9×25+125=225+125=22625\phantom{=} 9\dfrac{1}{25} = \dfrac{9 \times 25 + 1}{25} = \dfrac{225 + 1}{25} = \dfrac{226}{25}

Now, we divide 226 by 25. Since 226 is not exactly divisible by 25, we add a decimal point and zeros to continue the division:

9.0425)226.00225001001000\begin{array}{r} 9.04 \\ 25 \overline{) 226.00} \\ \underline{-225\phantom{00}} \\ 100 \\ \underline{-100} \\ 0 \end{array}

22625\dfrac{226}{25} = 9.04

91259\dfrac{1}{25} = 9.04

Question 4(xi)

Convert the following fractions into a decimal :

29162\dfrac{9}{16}

Answer

First, we convert the mixed fraction into an improper fraction:

=2916=2×16+916=32+916=4116\phantom{=} 2\dfrac{9}{16} = \dfrac{2 \times 16 + 9}{16} = \dfrac{32 + 9}{16} = \dfrac{41}{16}

Now, we divide 41 by 16. We add a decimal point and zeros to continue the division:

2.562516)41.000032.00009000080000100000960040032080800\begin{array}{r} 2.5625 \\ 16 \overline{) 41.0000} \\ \underline{-32\phantom{.0000}} \\ 90\phantom{000} \\ \underline{-80\phantom{000}} \\ 100\phantom{00} \\ \underline{-096\phantom{00}} \\ 40\phantom{0} \\ \underline{-32\phantom{0}} \\ 80 \\ \underline{-80} \\ 0 \end{array}

4116\dfrac{41}{16} = 2.5625

29162\dfrac{9}{16} = 2.5625

Question 4(xii)

Convert the following fractions into a decimal :

4111254\dfrac{11}{125}

Answer

First, we convert the mixed fraction into an improper fraction:

411125=4×125+11125=500+11125=5111254\dfrac{11}{125} = \dfrac{4 \times 125 + 11}{125} = \dfrac{500 + 11}{125} = \dfrac{511}{125}

Now, we divide 511 by 125. We add a decimal point and zeros to continue the division:

4.088125)511.000500.0001100010000100010000\begin{array}{r} 4.088 \\ 125 \overline{) 511.000} \\ \underline{-500\phantom{.000}} \\ 1100\phantom{0} \\ \underline{-1000\phantom{0}} \\ 1000 \\ \underline{-1000} \\ 0 \end{array}

511125\dfrac{511}{125} = 4.088

4111254\dfrac{11}{125} = 4.088

Exercise 3(B)

Question 1(i)

Add:

9.67, 15.98

Answer

The maximum number of decimal places is 2. The numbers are already like decimals.

On adding column-wise, we get:

9.67+015.9825.65\begin{array}{r} 9.67 \\ +\phantom{0}15.98 \\ \hline 25.65 \\ \hline \end{array}

Hence, the sum is 25.65

Question 1(ii)

Add:

6.9, 23.84

Answer

Maximum number of decimal places in given decimals is 2. So, we convert them into like decimals, each having 2 places of decimal, by annexing zeros.

6.90+023.8430.74\begin{array}{r} 6.90 \\ +\phantom{0}23.84 \\ \hline 30.74 \\ \hline \end{array}

Hence, the sum is 30.74

Question 1(iii)

Add:

35.67, 18.794, 4.9, 31.82

Answer

Maximum number of decimal places in given decimals is 3. So, we convert them into like decimals, each having 3 places of decimal, by annexing zeros.

Thus, we get: 35.670, 18.794, 4.900 and 31.820

On adding column-wise, we get:

35.67018.7944.900+031.82091.184\begin{array}{r} 35.670 \\ 18.794 \\ 4.900 \\ +\phantom{0}31.820 \\ \hline 91.184 \\ \hline \end{array}

Hence, the sum is 91.184

Question 1(iv)

Add:

63.05, 24.839, 3.7, 16.85

Answer

Maximum number of decimal places in given decimals is 3. So, we convert them into like decimals, each having 3 places of decimal, by annexing zeros.

Thus, we get: 63.050, 24.839, 3.700 and 16.850

On adding column-wise, we get:

63.05024.8393.700+016.850108.439\begin{array}{r} 63.050 \\ 24.839 \\ 3.700 \\ +\phantom{0}16.850 \\ \hline 108.439 \\ \hline \end{array}

Hence, the sum is 108.439

Question 2(i)

Subtract :

2.975 from 8.23

Answer

Converting the given decimals into like decimals, we have to subtract 2.975 from 8.230.

Subtracting columnwise, we get:

8.23002.9755.255\begin{array}{r} 8.230 \\ -\phantom{0}2.975 \\ \hline 5.255 \\ \hline \end{array}

Hence, the answer is 5.255

Question 2(ii)

Subtract :

0.75 from 1.3

Answer

Converting the given decimals into like decimals, we have to subtract 0.75 from 1.30.

Subtracting columnwise, we get:

1.3000.750.55\begin{array}{r} 1.30 \\ -\phantom{0}0.75 \\ \hline 0.55 \\ \hline \end{array}

Hence, the answer is 0.55

Question 2(iii)

Subtract :

6.054 from 11.26

Answer

Converting the given decimals into like decimals, we have to subtract 6.054 from 11.260.

Subtracting columnwise, we get:

11.26006.0545.206\begin{array}{r} 11.260 \\ -\phantom{0}6.054 \\ \hline 5.206 \\ \hline \end{array}

Hence, the answer is 5.206

Question 2(iv)

Subtract :

134.68 from 201.3

Answer

Converting the given decimals into like decimals, we have to subtract 134.68 from 201.30.

Subtracting columnwise, we get:

201.30134.6866.62\begin{array}{r} 201.30 \\ -134.68 \\ \hline 66.62 \\ \hline \end{array}

Hence, the answer is 66.62

Question 3

Take out 6.345 from 8.1.

Answer

Converting the given decimals into like decimals, we have to subtract 6.345 from 8.100.

Subtracting columnwise, we get:

8.10006.3451.755\begin{array}{r} 8.100 \\ -\phantom{0}6.345 \\ \hline 1.755 \\ \hline \end{array}

Hence, the answer is 1.755

Question 4

What is the difference between 68.5 and 0.685?

Answer

Converting the given decimals into like decimals, we have to subtract 0.685 from 68.500.

Subtracting columnwise, we get:

68.50000.68567.815\begin{array}{r} 68.500 \\ -\phantom{0}0.685 \\ \hline 67.815 \\ \hline \end{array}

Hence, the answer is 67.815

Question 5

What is the excess of 90 over 53.865?

Answer

Converting the given decimals into like decimals, we have to subtract 53.865 from 90.000.

Subtracting columnwise, we get:

90.00053.86536.135\begin{array}{r} 90.000 \\ -53.865 \\ \hline 36.135 \\ \hline \end{array}

Hence, the answer is 36.135

Question 6

What should be subtracted from 50 to get 34.57?

Answer

Let the required number be x

50 - x = 34.57

x = 50 - 34.57

Converting the given decimals into like decimals, we have to subtract 34.57 from 50.00.

Subtracting columnwise, we get:

50.0034.5715.43\begin{array}{r} 50.00 \\ -34.57 \\ \hline 15.43 \\ \hline \end{array}

Hence, the answer is 15.43

Question 7

What should be added to 63.47 to get 91?

Answer

Let the required number be x

63.47 + x = 91

x = 91 - 63.47

Converting the given decimals into like decimals, we have to subtract 63.47 from 91.00.

Subtracting columnwise, we get:

91.0063.4727.53\begin{array}{r} 91.00 \\ -63.47 \\ \hline 27.53 \\ \hline \end{array}

Hence, the answer is 27.53

Question 8

Manish buys a ₹8.75 metro ticket with a ₹20 note. How much money does he get back?

Answer

Given:

Total money = ₹20.00

Cost of ticket = ₹8.75

Money received back = ?

∴ Money received back = (Total money) - (Cost of ticket)

Substituting the values in above, we get:

Money received back = ₹20.00 - ₹8.75

Converting the given decimals into like decimals, we have to subtract 8.75 from 20.00.

Subtracting columnwise, we get:

20.0008.7511.25\begin{array}{r} 20.00 \\ -\phantom{0}8.75 \\ \hline 11.25 \\ \hline \end{array}

Hence, he gets back ₹11.25

Question 9

A baby increases in weight from 5.58 kg to 6.16 kg. How much weight has the baby gained?

Answer

Given:

New weight = 6.16 kg

Previous weight = 5.58 kg

Weight gained = ?

∴ Weight gained = (New weight) - (Previous weight)

Substituting the values in above, we get:

Weight gained = 6.16 kg - 5.58 kg

Subtracting columnwise, we get:

6.165.580.58\begin{array}{r} 6.16 \\ -5.58 \\ \hline 0.58 \\ \hline \end{array}

Hence, the baby has gained 0.58 kg

Question 10(i)

Simplify :

67 + 13.85 - 29.904

Answer

Given expression:

= 67 + 13.85 - 29.904
= 67.000 + 13.850 - 29.904 \quad [Converting into like decimals]
= (67.000 + 13.850) - 29.904
= 80.850 - 29.904
= 50.546

67.00080.850+013.850029.90480.85050.946\begin{array}{r|r} 67.000 & 80.850 \\ +\phantom{0}13.850 & -\phantom{0}29.904 \\ \hline 80.850 & 50.946 \\ \hline \end{array}

Hence, the answer is 50.946

Question 10(ii)

Simplify :

16.753 + 4.06 - 13.89

Answer

Given expression:

= 16.753 + 4.06 - 13.89
= 16.753 + 4.060 - 13.890 \quad [Converting into like decimals]
= (16.753 + 4.060) - 13.890
= 20.813 - 13.890
= 6.923

16.75320.813+04.060013.89020.8136.923\begin{array}{r|r} 16.753 & 20.813 \\ +\phantom{0}4.060 & -\phantom{0}13.890 \\ \hline 20.813 & 6.923 \\ \hline \end{array}

Hence, the answer is 6.923

Question 10(iii)

Simplify :

1 - 10.5 + 12.213

Answer

Given expression:

= 1 - 10.5 + 12.213
= 1.000 - 10.500 + 12.213 \quad [Converting into like decimals]
= (1.000 + 12.213) - 10.500 \quad [Rearranging terms]
= 13.213 - 10.500
= 2.713

1.00013.213+012.213010.50013.2132.713\begin{array}{r|r} 1.000 & 13.213 \\ +\phantom{0}12.213 & -\phantom{0}10.500 \\ \hline 13.213 & 2.713 \\ \hline \end{array}

Hence, the answer is 2.713

Question 10(iv)

Simplify :

81 - 15.68 - 4.2

Answer

Given expression:

= 81 - 15.68 - 4.2
= 81.00 - 15.68 - 4.20 \quad [Converting into like decimals]
= (81.00) - (15.68 + 4.20) \quad [Rearranging terms]
= 81.00 - 19.88
= 61.12

15.6881.00+04.20019.8819.8861.12\begin{array}{r|r} 15.68 & 81.00 \\ +\phantom{0}4.20 & -\phantom{0}19.88 \\ \hline 19.88 & 61.12 \\ \hline \end{array}

Hence, the answer is 61.12

Question 10(v)

Simplify :

555 - 55.5 - 5.555

Answer

Given expression:

= 555 - 55.5 - 5.555
= 555.000 - 55.500 - 5.555 \quad [Converting into like decimals]
= 555.000 - (55.500 + 5.555) \quad [Rearranging terms]
= 555.000 - 61.055
= 493.945

55.500555.000+05.555061.05561.055493.945\begin{array}{r|r} 55.500 & 555.000 \\ +\phantom{0}5.555 & -\phantom{0}61.055 \\ \hline 61.055 & 493.945 \\ \hline \end{array}

Hence, the answer is 493.945

Question 10(vi)

Simplify :

100 - 32.5 - 46.74 - 12.925

Answer

Given expression:

= 100 - 32.5 - 46.74 - 12.925
= 100.000 - 32.500 - 46.740 - 12.925 \quad [Converting into like decimals]
= 100.000 - (32.500 + 46.740 + 12.925) \quad [Rearranging terms]
= 100.000 - 92.165
= 7.835

32.50079.240100.000 +046.740+012.925092.16579.24092.1657.835\begin{array}{r|r|r} 32.500 & 79.240 & 100.000\ +\phantom{0}46.740 & +\phantom{0}12.925 & -\phantom{0}92.165 \\ \hline 79.240 & 92.165 & 7.835 \\ \hline \end{array}

Hence, the answer is 7.835

Exercise 3(C)

Question 1(i)

Multiply :

6.5 x 10

Answer

We have:

6.5 x 10

On multiplying 6.5 by 10, the decimal point is shifted by one place to the right.

∴ 6.5 × 10 = 65

Question 1(ii)

Multiply :

0.8 x 10

Answer

We have:

0.8 x 10

On multiplying 0.8 by 10, the decimal point is shifted by one place to the right.

∴ 0.8 × 10 = 8

Question 1(iii)

Multiply :

9.07 x 10

Answer

We have:

9.07 x 10

On multiplying 9.07 by 10, the decimal point is shifted by one place to the right.

∴ 9.07 × 10 = 90.7

Question 1(iv)

Multiply :

2.345 x 10

Answer

We have:

2.345 x 10

On multiplying 2.345 by 10, the decimal point is shifted by one place to the right.

∴ 2.345 × 10 = 23.45

Question 1(v)

Multiply :

4.63 x 100

Answer

We have:

4.63 x 100

On multiplying 4.63 by 100, the decimal point is shifted by two places to the right.

∴ 4.63 × 100 = 463

Question 1(vi)

Multiply :

8.279 x 100

Answer

We have:

8.279 x 100

On multiplying 8.279 by 100, the decimal point is shifted by two places to the right.

∴ 8.279 × 100 = 827.9

Question 1(vii)

Multiply :

7.8 x 100

Answer

We have:

7.8 x 100

On multiplying 7.8 by 100, the decimal point is shifted by two places to the right.

7.80 x 100 = 780

∴ 7.8 × 100 = 780

Question 1(viii)

Multiply :

0.09 x 100

Answer

We have:

0.09 x 100

On multiplying 0.09 by 100, the decimal point is shifted by two places to the right.

∴ 0.09 × 100 = 9

Question 1(ix)

Multiply :

0.283 x 1000

Answer

We have:

0.283 x 1000

On multiplying 0.283 by 1000, the decimal point is shifted by three places to the right.

∴ 0.283 × 1000 = 283

Question 1(x)

Multiply :

6.25 x 1000

Answer

We have:

6.25 x 1000

On multiplying 6.25 by 1000, the decimal point is shifted by three places to the right.

∴ 6.25 × 1000 = 6250

Question 1(xi)

Multiply :

5.4 x 1000

Answer

We have:

5.4 x 1000

On multiplying 5.4 by 1000, the decimal point is shifted by three places to the right.

∴ 5.4 × 1000 = 5400

Question 1(xii)

Multiply :

0.3 x 1000

Answer

We have:

0.3 x 1000

On multiplying 0.3 by 1000, the decimal point is shifted by three places to the right.

∴ 0.3 × 1000 = 300

Question 2(i)

Multiply :

2.4 x 16

Answer

We have:

24 x 16 = 384

∴ 2.4 × 16 = 38.4 \hspace{2cm}[1 place of decimal]

The answer is 38.4

Question 2(ii)

Multiply :

3.45 x 17

Answer

We have:

345 × 17 = 5865

∴ 3.45 × 17 = 58.65 \hspace{2cm}[2 places of decimal]

The answer is 58.65

Question 2(iii)

Multiply :

0.86 x 14

Answer

We have:

86 × 14 = 1204

∴ 0.86 × 14 = 12.04 \hspace{2cm}[2 places of decimal]

The answer is 12.04

Question 2(iv)

Multiply :

2.68 x 30

Answer

We have:

268 × 30 = 8040

∴ 2.68 × 30 = 80.4 \hspace{2cm}[2 places of decimal]

The answer is 80.4

Question 2(v)

Multiply :

0.023 x 65

Answer

We have:

23 × 65 = 1495

∴ 0.023 × 65 = 1.495 \hspace{2cm}[3 places of decimal]

The answer is 1.495

Question 2(vi)

Multiply :

0.0006 x 15

Answer

We have:

6 × 15 = 90

∴ 0.0006 × 15 = 0.009 \hspace{2cm}[4 places of decimal]

The answer is 0.009

Question 3(i)

Find the product :

5.6 x 1.4

Answer

First we multiply 56 by 14

56×1422456×784\begin{matrix} & & 5 & 6 \\ \times & & 1 & 4 \\ \hline & 2 & 2 & 4 \\ & 5 & 6 & \times \\ \hline & \bold{7} & \bold{8} & \bold{4} \end{matrix}

Clearly, 56 × 14 = 784

Sum of decimal places in given decimals = (1 + 1) = 2

So, the product contains 2 places of decimal

∴ 5.6 × 1.4 = 7.84

Question 3(ii)

Find the product :

2.35 x 7.2

Answer

First we multiply 235 by 72

235×724701645×16920\begin{matrix} & & 2 & 3 & 5 \\ \times & & & 7 & 2 \\ \hline & & 4 & 7 & 0 \\ 1 & 6 & 4 & 5 & \times \\ \hline \bold{1} & \bold{6} & \bold{9} & \bold{2} & \bold{0} \end{matrix}

Clearly, 235 × 72 = 16920

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 2.35 × 7.2 = 16.920 = 16.92

Question 3(iii)

Find the product :

0.37 x 0.26

Answer

First we multiply 37 by 26

37×2622274×962\begin{matrix} & & 3 & 7 \\ \times & & 2 & 6 \\ \hline & 2 & 2 & 2 \\ & 7 & 4 & \times \\ \hline & \bold{9} & \bold{6} & \bold{2} \end{matrix}

Clearly, 37 × 26 = 962

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.37 × 0.26 = 0.0962

Question 3(iv)

Find the product :

0.74 x 6.7

Answer

First we multiply 74 by 67

74×67518444×4958\begin{matrix} & & & 7 & 4 \\ \times & & & 6 & 7 \\ \hline & & 5 & 1 & 8 \\ & 4 & 4 & 4 & \times \\ \hline & \bold{4} & \bold{9} & \bold{5} & \bold{8} \end{matrix}

Clearly, 74 × 67 = 4958

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 0.74 × 6.7 = 4.958

Question 3(v)

Find the product :

5.64 x 0.08

Answer

First we multiply 564 by 8

564×84512\begin{matrix} & & 5 & 6 & 4 \\ \times & & & & 8 \\ \hline & \bold{4} & \bold{5} & \bold{1} & \bold{2} \end{matrix}

Clearly, 564 × 8 = 4512

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 5.64 × 0.08 = 0.4512

Question 3(vi)

Find the product :

2.75 x 1.7

Answer

First we multiply 275 by 17

275×171925275×4675\begin{matrix} & & 2 & 7 & 5 \\ \times & & & 1 & 7 \\ \hline & 1 & 9 & 2 & 5 \\ & 2 & 7 & 5 & \times \\ \hline & \bold{4} & \bold{6} & \bold{7} & \bold{5} \end{matrix}

Clearly, 275 × 17 = 4675

Sum of decimal places in given decimals = (2 + 1) = 3

So, the product contains 3 places of decimal

∴ 2.75 × 1.7 = 4.675

Question 3(vii)

Find the product :

0.04 x 0.36

Answer

First we multiply 4 by 36

36×4144\begin{matrix} & & 3 & 6 \\ \times & & & 4 \\ \hline & \bold{1} & \bold{4} & \bold{4} \end{matrix}

Clearly, 4 × 36 = 144

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.04 × 0.36 = 0.0144

Question 3(viii)

Find the product :

34.2 x 1.86

Answer

First we multiply 342 by 186

342×18620522736×342××63612\begin{matrix} & & 3 & 4 & 2 \\ \times & & 1 & 8 & 6 \\ \hline & 2 & 0 & 5 & 2 \\ 2 & 7 & 3 & 6 & \times \\ 3 & 4 & 2 & \times & \times \\ \hline \bold{6} & \bold{3} & \bold{6} & \bold{1} & \bold{2} \end{matrix}

Clearly, 342 × 186 = 63612

Sum of decimal places in given decimals = (1 + 2) = 3

So, the product contains 3 places of decimal

∴ 34.2 × 1.86 = 63.612

Question 3(ix)

Find the product :

0.028 x 0.9

Answer

First we multiply 28 by 9

28×9252\begin{matrix} & & 2 & 8 \\ \times & & & 9 \\ \hline & \bold{2} & \bold{5} & \bold{2} \end{matrix}

Clearly, 28 × 9 = 252

Sum of decimal places in given decimals = (3 + 1) = 4

So, the product contains 4 places of decimal

∴ 0.028 × 0.9 = 0.0252

Question 4(i)

Find the product :

2.3 x 0.23 x 0.1

Answer

First we multiply 23 by 23 and then by 1

23×236946×529\begin{matrix} & & 2 & 3 \\ \times & & 2 & 3 \\ \hline & & 6 & 9 \\ & 4 & 6 & \times \\ \hline & \bold{5} & \bold{2} & \bold{9} \end{matrix}

Clearly, 23 × 23 × 1 = 529

Sum of decimal places in given decimals = (1 + 2 + 1) = 4

So, the product contains 4 places of decimal

529 x 1 = 529

∴ 2.3 × 0.23 × 0.1 = 0.0529

Question 4(ii)

Find the product :

1.2 x 3.5 x 0.3

Answer

First we multiply 12 by 35 and then by 3

12×356036×420\begin{matrix} & & 1 & 2 \\ \times & & 3 & 5 \\ \hline & & 6 & 0 \\ & 3 & 6 & \times \\ \hline & \bold{4} & \bold{2} & \bold{0} \end{matrix}

∴ 12 × 35 = 420

420×31260\begin{matrix} & & 4 & 2 & 0 \\ \times & & & & 3 \\ \hline & \bold{1} & \bold{2} & \bold{6} & \bold{0} \end{matrix}

∴ 12 × 35 × 3 = 1260

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ 1.2 × 3.5 × 0.3 = 1.260 = 1.26

Question 4(iii)

Find the product :

0.6 x 1.5 x 0.7

Answer

First we multiply 6 by 15 and then by 7

15×690\begin{matrix} & 1 & 5 \\ \times & & 6 \\ \hline & \bold{9} & \bold{0} \end{matrix}

∴ 6 × 15 = 90

90×7630\begin{matrix} & 9 & 0 \\ \times & & 7 \\ \hline \bold{6} & \bold{3} & \bold{0} \end{matrix}

∴ 6 × 15 x 7 = 630

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ 0.6 × 1.5 × 0.7 = 0.630 = 0.63

Question 4(iv)

Find the product :

0.2 x 0.2 x 0.02

Answer

First we multiply 2 by 2 and then by 2

2×24\begin{matrix} & 2 \\ \times & 2 \\ \hline & \bold{4} \end{matrix}

∴ 2 × 2 = 4

4×28\begin{matrix} & 4 \\ \times & 2 \\ \hline & \bold{8} \end{matrix}

∴ 2 × 2 x 2 = 8

Sum of decimal places in given decimals = (1 + 1 + 2) = 4

So, the product contains 4 places of decimal

∴ 0.2 × 0.2 × 0.02 = 0.0008

Question 4(v)

Find the product :

1.1 x 0.1 x 0.11

Answer

First we multiply 11 by 1 and then by 11

11×111\begin{matrix} & 1 & 1 \\ \times & & 1 \\ \hline & \bold{1} & \bold{1} \end{matrix}

∴ 11 × 1 = 11

11×111111×121\begin{matrix} & & 1 & 1 \\ \times & & 1 & 1 \\ \hline & & 1 & 1 \\ & 1 & 1 & \times \\ \hline & \bold{1} & \bold{2} & \bold{1} \end{matrix}

∴ 11 × 1 x 11 = 121

Sum of decimal places in given decimals = (1 + 1 + 2) = 4

So, the product contains 4 places of decimal

∴ 1.1 × 0.1 × 0.11 = 0.0121

Question 4(vi)

Find the product :

0.6 x 0.06 x 0.006

Answer

First we multiply 6 by 6 and then by 6

6×636\begin{matrix} & & 6 \\ \times & & 6 \\ \hline & \bold{3} & \bold{6} \end{matrix}

∴ 6 × 6 = 36

36×6216\begin{matrix} & 3 & 6 \\ \times & & 6 \\ \hline \bold{2} & \bold{1} & \bold{6} \end{matrix}

∴ 6 × 6 × 6 = 216

Sum of decimal places in given decimals = (1 + 2 + 3) = 6

So, the product contains 6 places of decimal

∴ 0.6 × 0.06 × 0.006 = 0.000216

Question 5(i)

Evaluate :

(1.3)2

Answer

We have:

(1.3)2 = 1.3 × 1.3

First we multiply 13 by 13

13×133913×169\begin{matrix} & & 1 & 3 \\ \times & & 1 & 3 \\ \hline & & 3 & 9 \\ & 1 & 3 & \times \\ \hline & \bold{1} & \bold{6} & \bold{9} \end{matrix}

∴ 13 × 13 = 169

Sum of decimal places in given decimals = (1 + 1) = 2

So, the product contains 2 places of decimal

∴ (1.3)2 = 1.69

Question 5(ii)

Evaluate :

(0.06)2

Answer

We have:

(0.06)2 = 0.06 × 0.06

First we multiply 6 by 6

6×636\begin{matrix} & & 6 \\ \times & & 6 \\ \hline & \bold{3} & \bold{6} \end{matrix}

∴ 6 × 6 = 36

Sum of decimal places in given decimals = (2 + 2) = 4

So, the product contains 4 places of decimal

∴ (0.06)2 = 0.0036

Question 5(iii)

Evaluate :

(0.2)3

Answer

We have:

(0.2)3 = 0.2 × 0.2 × 0.2

First we multiply 2 × 2 × 2

2×24\begin{matrix} & 2 \\ \times & 2 \\ \hline & \bold{4} \end{matrix}

∴ 2 × 2 =4

4×28\begin{matrix} & 4 \\ \times & 2 \\ \hline & \bold{8} \end{matrix}

∴ 2 × 2 × 2 = 8

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ (0.2)3 = 0.008

Question 5(iv)

Evaluate :

(0.8)3

Answer

We have:

(0.8)3 = 0.8 × 0.8 × 0.8

First we multiply 8 × 8 × 8

8×864\begin{matrix} & & 8 \\ \times & & 8 \\ \hline & \bold{6} & \bold{4} \end{matrix}

∴ 8 × 8 = 64

64×8512\begin{matrix} & 6 & 4 \\ \times & & 8 \\ \hline \bold{5} & \bold{1} & \bold{2} \end{matrix}

∴ 8 × 8 × 8 = 512

Sum of decimal places in given decimals = (1 + 1 + 1) = 3

So, the product contains 3 places of decimal

∴ (0.8)3 = 0.512

Question 6

The cost of one pen is ₹42.25. Find the cost of one dozen such pens.

Answer

Given:

Cost of 1 pen = ₹42.25

Number of pens = 1 dozen = 12 pens

The cost of 1 dozen pens = (Cost of 1 pen) x (Number of pens)

Substituting the values in above, we get:

The cost of 1 dozen pens = ₹42.25 x 12

Sum of the decimal places in given decimals = 2 + 0 = 2

So, the product contains 2 places of decimal.

4225×1284504225×50700\begin{matrix} & & 4 & 2 & 2 & 5 \\ \times & & & & 1 & 2 \\ \hline & & 8 & 4 & 5 & 0 \\ & 4 & 2 & 2 & 5 & \times \\ \hline & \bold{5} & \bold{0} & \bold{7} & \bold{0} & \bold{0} \end{matrix}

∴ ₹42.25 × 12 = ₹507.00 = ₹507

Hence, the cost of one dozen pens = ₹507

Question 7

A car moves at a constant speed of 56.4 km per hour. How much distance does it cover in 3.5 hours?

Answer

Given:

Speed per hour = 56.4 km

Total time = 3.5 hours

Distance covered = ?

We know the formula,

Distance = Speed x Time

Substituting the values in above, we get:

Distance = 56.4 km x 3.5 hours

Sum of the decimal places in given decimals = 1 + 1 = 2

So, the product contains 2 places of decimal

564×3528201692×19740\begin{matrix} & & 5 & 6 & 4 \\ \times & & & 3 & 5 \\ \hline & 2 & 8 & 2 & 0 \\ 1 & 6 & 9 & 2 & \times \\ \hline \bold{1} & \bold{9} & \bold{7} & \bold{4} & \bold{0} \end{matrix}

∴ 56.4 km × 3.5 hours = 197.40 km = 197.4 km

Hence, the distance covered by the car = 197.4 km

Question 8

A room is 4.5 m long and 3.8 m broad. Calculate the area of the floor of the room.

Answer

Given:

Length of the room = 4.5 m

Breadth of the room = 3.8 m

Area of the floor = ?

The floor will be of rectangular shape

We know the formula,

Area = Length x Breadth

Substituting the values in above, we get:

Area = 4.5 m x 3.8 m

Sum of the decimal places in given decimals = 1 + 1 = 2

So, the product contains 2 places of decimal

45×38360135×1710\begin{matrix} & & 4 & 5 \\ \times & & 3 & 8 \\ \hline & 3 & 6 & 0 \\ 1 & 3 & 5 & \times \\ \hline \bold{1} & \bold{7} & \bold{1} & \bold{0} \end{matrix}

∴ 4.5 m × 3.8 m = 17.10 m2 = 17.1 m2

Hence, the area of the floor = 17.1 m2

Question 9

The cost of 1 litre of refined oil is ₹124.75. What is the cost of 6.2 litres of this oil?

Answer

Given:

Cost of 1 litre of refined oil = ₹124.75

Total quantity of oil = 6.2 litres

Cost of 6.2 litres of oil = ?

Cost of 6.2 litres of oil = (Cost of 1 litre) x (Total quantity)

Substituting the values in above, we get:

Cost of 6.2 litres of oil = (₹124.75) x (6.2 litres)

Sum of the decimal places in given decimals = 2 + 1 = 3

So, the product contains 3 places of decimal

12475×622495074850×773450\begin{matrix} & & 1 & 2 & 4 & 7 & 5 \\ \times & & & & & 6 & 2 \\ \hline & & 2 & 4 & 9 & 5 & 0 \\ & 7 & 4 & 8 & 5 & 0 & \times \\ \hline & \bold{7} & \bold{7} & \bold{3} & \bold{4} & \bold{5} & \bold{0} \end{matrix}

∴ 124.75 × 6.2 litres = ₹773.450 = ₹773.45

Hence, the cost of 6.2 litres of oil = ₹773.45

Exercise 3(D)

Question 1(i)

Divide :

2.8 ÷ 10

Answer

On dividing 2.8 by 10, the decimal point is shifted by one place to the left.

∴ 2.8 ÷ 10 = 0.28

Question 1(ii)

Divide :

0.63 ÷ 10

Answer

On dividing 0.63 by 10, the decimal point is shifted by one place to the left.

∴ 0.63 ÷ 10 = 0.063

Question 1(iii)

Divide :

3.05 ÷ 10

Answer

On dividing 3.05 by 10, the decimal point is shifted by one place to the left.

∴ 3.05 ÷ 10 = 0.305

Question 1(iv)

Divide :

245.6 ÷ 100

Answer

On dividing 245.6 by 100, the decimal point is shifted by two places to the left.

∴ 245.6 ÷ 100 = 2.456

Question 1(v)

Divide :

0.9 ÷ 100

Answer

On dividing 0.9 by 100, the decimal point is shifted by two places to the left.

∴ 0.9 ÷ 100 = 0.009

Question 1(vi)

Divide :

1.23 ÷ 100

Answer

On dividing 1.23 by 100, the decimal point is shifted by two place to the left.

∴ 1.23 ÷ 10 = 0.0123

Question 1(vii)

Divide :

134.2 ÷ 1000

Answer

On dividing 134.2 by 1000, the decimal point is shifted by three places to the left.

∴ 134.2 ÷ 1000 = 0.1342

Question 1(viii)

Divide :

23.4 ÷ 1000

Answer

On dividing 23.4 by 1000, the decimal point is shifted by three places to the left.

∴ 23.4 ÷ 1000 = 0.0234

Question 1(ix)

Divide :

0.7 ÷ 1000

Answer

On dividing 0.7 by 1000, the decimal point is shifted by three places to the left.

∴ 0.7 ÷ 1000 = 0.0007

Question 2(i)

Divide :

20.79 ÷ 9

Answer

On dividing 20.79 by 9, we get:

2.319)20.7918.0027027009090.\begin{array}{r} 2.31 \\ 9 \overline{\smash{)} 20.79 } \\ \underline{18}\phantom{.00} \\ 27\phantom{0} \\ \underline{27}\phantom{0} \\ 09 \\ \underline{09} \\ 0 \phantom{.} \end{array}

Hence, 20.79 ÷ 9 = 2.31

Question 2(ii)

Divide :

78.48 ÷ 12

Answer

On dividing 78.48 by 12, we get:

6.5412)78.4872.006406000480480.\begin{array}{r} 6.54 \\ 12 \overline{\smash{)} 78.48 } \\ \underline{72}\phantom{.00} \\ 64\phantom{0} \\ \underline{60}\phantom{0} \\ 048 \\ \underline{048} \\ 0 \phantom{.} \end{array}

Hence, 78.48 ÷ 12 = 6.54

Question 2(iii)

Divide :

142.8 ÷ 21

Answer

On dividing 142.8 by 21, we get:

6.821)142.8126.01681680.\begin{array}{r} 6.8 \\ 21 \overline{\smash{)} 142.8 } \\ \underline{126}\phantom{.0} \\ 168 \\ \underline{168} \\ 0 \phantom{.} \end{array}

Hence, 142.8 ÷ 21 = 6.8

Question 2(iv)

Divide :

6.02 ÷ 7

Answer

On dividing 6.02 by 7, we get:

0.867)6.020.006015600420420.\begin{array}{r} 0.86 \\ 7 \overline{\smash{)} 6.02 } \\ \underline{0}\phantom{.00} \\ 60\phantom{1} \\ \underline{56}\phantom{0} \\ 042 \\ \underline{042} \\ 0 \phantom{.} \end{array}

Hence, 6.02 ÷ 7 = 0.86

Question 2(v)

Divide :

0.688 ÷ 8

Answer

On dividing 0.688 by 8, we get:

0.0868)0.6880.00068064048480.\begin{array}{r} 0.086 \\ 8 \overline{\smash{)} 0.688 } \\ \underline{0}\phantom{.000} \\ 68\phantom{0} \\ \underline{64}\phantom{0} \\ 48 \\ \underline{48} \\ 0 \phantom{.} \end{array}

Hence, 0.688 ÷ 8 = 0.086

Question 2(vi)

Divide :

0.125 ÷ 25

Answer

On dividing 0.125 by 25, we get:

0.00525)0.1250.0001251250.\begin{array}{r} 0.005 \\ 25 \overline{\smash{)} 0.125 } \\ \underline{0}\phantom{.000} \\ 125 \\ \underline{125} \\ 0 \phantom{.} \end{array}

Hence, 0.125 ÷ 25 = 0.005

Question 2(vii)

Divide :

0.992 ÷ 31

Answer

On dividing 0.992 by 31, we get:

0.03231)0.9920.00099093062620.\begin{array}{r} 0.032 \\ 31 \overline{\smash{)} 0.992 } \\ \underline{0}\phantom{.000} \\ 99\phantom{0} \\ \underline{93}\phantom{0} \\ 62 \\ \underline{62} \\ 0 \phantom{.} \end{array}

Hence, 0.992 ÷ 31 = 0.032

Question 2(viii)

Divide :

0.1728 ÷ 72

Answer

On dividing 0.1728 by 72, we get:

0.002472)0.17280.0000172014402882880.\begin{array}{r} 0.0024 \\ 72 \overline{\smash{)} 0.1728 } \\ \underline{0}\phantom{.0000} \\ 172\phantom{0} \\ \underline{144}\phantom{0} \\ 288 \\ \underline{288} \\ 0 \phantom{.} \end{array}

Hence, 0.1728 ÷ 72 = 0.0024

Question 2(ix)

Divide :

0.12749 ÷ 61

Answer

On dividing 0.12749 by 61, we get:

0.0020961)0.127490.0000012700122005495490.\begin{array}{r} 0.00209 \\ 61 \overline{\smash{)} 0.12749 } \\ \underline{0}\phantom{.00000} \\ 127\phantom{00} \\ \underline{122}\phantom{00} \\ 549 \\ \underline{549} \\ 0 \phantom{.} \end{array}

Hence, 0.12749 ÷ 61 = 0.00209

Question 3(i)

Divide :

2.24 ÷ 0.8

Answer

We have:

2.240.8=2.24×100.8×10=22.48\dfrac{2.24}{0.8} = \dfrac{2.24 \times 10}{0.8 \times 10} = \dfrac{22.4}{8}

On dividing 22.4 by 8, we get:

2.88)22.416.064640.\begin{array}{r} 2.8 \\ 8 \overline{\smash{)} 22.4 } \\ \underline{16}\phantom{.0} \\ 64 \\ \underline{64} \\ 0 \phantom{.} \end{array}

Hence, 2.240.8=22.48=2.8\dfrac{2.24}{0.8} = \dfrac{22.4}{8} = 2.8

Question 3(ii)

Divide :

1.242 ÷ 1.8

Answer

We have:

1.2421.8=1.242×101.8×10=12.4218\dfrac{1.242}{1.8} = \dfrac{1.242 \times 10}{1.8 \times 10} = \dfrac{12.42}{18}

On dividing 12.42 by 18, we get:

0.6918)12.4210801621620.\begin{array}{r} 0.69 \\ 18 \overline{\smash{)} 12.42 } \\ \underline{108\phantom{0}} \\ 162 \\ \underline{162} \\ 0 \phantom{.} \end{array}

Hence, 1.2421.8=12.4218=0.69\dfrac{1.242}{1.8} = \dfrac{12.42}{18} = 0.69

Question 3(iii)

Divide :

0.1575 ÷ 0.21

Answer

We have:

0.15750.21=0.1575×1000.21×100=15.7521\dfrac{0.1575}{0.21} = \dfrac{0.1575 \times 100}{0.21 \times 100} = \dfrac{15.75}{21}

On dividing 15.75 by 21, we get:

0.7521)15.7514701051050.\begin{array}{r} 0.75 \\ 21 \overline{\smash{)} 15.75 } \\ \underline{147\phantom{0}} \\ 105 \\ \underline{105} \\ 0 \phantom{.} \end{array}

Hence, 0.15750.21=15.7521=0.75\dfrac{0.1575}{0.21} = \dfrac{15.75}{21} = 0.75

Question 3(iv)

Divide :

0.0144 ÷ 0.12

Answer

We have:

0.01440.12=0.0144×1000.12×100=1.4412\dfrac{0.0144}{0.12} = \dfrac{0.0144 \times 100}{0.12 \times 100} = \dfrac{1.44}{12}.

On dividing 1.44 by 12, we get:

0.1212)1.441200240240.\begin{array}{r} 0.12 \\ 12 \overline{\smash{)} 1.44 } \\ \underline{12\phantom{0}} \\ 024 \\ \underline{024} \\ 0 \phantom{.} \end{array}

Hence, 0.01440.12=1.4412=0.12\dfrac{0.0144}{0.12} = \dfrac{1.44}{12} = 0.12

Question 3(v)

Divide :

0.0783 ÷ 0.9

Answer

We have:

0.07830.9=0.0783×100.9×10=0.7839\dfrac{0.0783}{0.9} = \dfrac{0.0783 \times 10}{0.9 \times 10} = \dfrac{0.783}{9}

On dividing 0.783 by 9, we get:

0.0879)0.7830.7200.0630.0630.\begin{array}{r} 0.087 \\ 9 \overline{\smash{)} 0.783 } \\ \underline{0.72}\phantom{0} \\ 0.063 \\ \underline{0.063} \\ 0 \phantom{.} \end{array}

Hence, 0.07830.9=0.7839=0.087\dfrac{0.0783}{0.9} = \dfrac{0.783}{9} = 0.087

Question 3(vi)

Divide :

0.1164 ÷ 0.012

Answer

We have:

0.11640.012=0.1164×10000.012×1000=116.412\dfrac{0.1164}{0.012} = \dfrac{0.1164 \times 1000}{0.012 \times 1000} = \dfrac{116.4}{12}.

On dividing 116.4 by 12, we get:

9.712)116.4108.084840.\begin{array}{r} 9.7 \\ 12 \overline{\smash{)} 116.4 } \\ \underline{108}\phantom{.0} \\ 84 \\ \underline{84} \\ 0 \phantom{.} \end{array}

Hence, 0.11640.012=116.412=9.7\dfrac{0.1164}{0.012} = \dfrac{116.4}{12} = 9.7

Question 3(vii)

Divide :

0.068 ÷ 0.17

Answer

We have:

0.0680.17=0.068×1000.17×100=6.817\dfrac{0.068}{0.17} = \dfrac{0.068 \times 100}{0.17 \times 100} = \dfrac{6.8}{17}.

On dividing 6.8 by 17, we get:

0.417)6.80.868. 68. 00\begin{array}{r} 0.4 \\ 17 \overline{\smash{)} 6.8 } \\ \underline{0}\phantom{.8} \\ 68 \phantom{.}\ \underline{68} \phantom{.}\ 0 \phantom{0} \end{array}

Hence, 0.0680.17=6.817=0.4\dfrac{0.068}{0.17} = \dfrac{6.8}{17} = 0.4

Question 3(viii)

Divide :

0.02324 ÷ 0.28

Answer

We have:

0.023240.28=0.02324×1000.28×100=2.32428\dfrac{0.02324}{0.28} = \dfrac{0.02324 \times 100}{0.28 \times 100} = \dfrac{2.324}{28}.

On dividing 2.324 by 28, we get:

0.08328)2.324224084840.\begin{array}{r} 0.083 \\ 28 \overline{\smash{)} 2.324 } \\ \underline{224\phantom{0}} \\ 84 \\ \underline{84} \\ 0 \phantom{.} \end{array}

Hence, 0.023240.28=2.32428=0.083\dfrac{0.02324}{0.28} = \dfrac{2.324}{28} = 0.083

Question 3(ix)

Divide :

0.03822 ÷ 0.049

Answer

We have:

0.038220.049=0.03822×10000.049×1000=38.2249\dfrac{0.03822}{0.049} = \dfrac{0.03822 \times 1000}{0.049 \times 1000} = \dfrac{38.22}{49}.

On dividing 38.22 by 49, we get:

0.7849)38.2234303923920.\begin{array}{r} 0.78 \\ 49 \overline{\smash{)} 38.22 } \\ \underline{343} \phantom{0} \\ 392 \\ \underline{392} \\ 0 \phantom{.} \end{array}

Hence, 0.038220.049=38.2249=0.78\dfrac{0.03822}{0.049} = \dfrac{38.22}{49} = 0.78

Question 4(i)

Simplify :

1.3×2.40.39\dfrac{1.3 \times 2.4}{0.39}

Answer

We have:

=1.3×2.40.39=3.120.39=3.12×1000.39×100=31239\phantom{=} \dfrac{1.3 \times 2.4}{0.39} = \dfrac{3.12}{0.39} = \dfrac{3.12 \times 100}{0.39 \times 100} = \dfrac{312}{39}

On dividing 312 by 39, we get:

839)3123120\begin{array}{r} 8 \\ 39 \overline{\smash{)} 312 } \\ \underline{312} \\ 0 \end{array}

Hence, the answer is 8.

Question 4(ii)

Simplify :

2.5×40.450\dfrac{2.5 \times 40.4}{50}

Answer

We have:

=2.5×40.450=101.050=10150\phantom{=} \dfrac{2.5 \times 40.4}{50} = \dfrac{101.0}{50} = \dfrac{101}{50}

On dividing 101 by 50, we get:

2.0250)101.00100.001000001001000\begin{array}{r} 2.02 \\ 50 \overline{\smash{)} 101.00 } \\ \underline{100} \phantom{.00} \\ 10 \phantom{0} \\ \underline{00} \phantom{0} \\ 100 \\ \underline{100} \\ 0 \end{array}

Hence, the answer is 2.02

Question 4(iii)

Simplify :

6.30.3×0.1\dfrac{6.3}{0.3 \times 0.1}

Answer

We have:

6.30.03=6.3×1000.03×100=6303\dfrac{6.3}{0.03} = \dfrac{6.3 \times 100}{0.03 \times 100} = \dfrac{630}{3}

On dividing 630 by 3, we get:

2103)630600030300000\begin{array}{r} 210 \\ 3 \overline{\smash{)} 630 } \\ \underline{6} \phantom{00} \\ 03 \phantom{0} \\ \underline{3} \phantom{0} \\ 00 \\ \underline{0} \\ 0 \end{array}

Hence, the answer is 210

Question 5

A boy bought 8 pencils for ₹46.80. What is the cost of each pencil?

Answer

Given:

Cost of 8 pencils = ₹46.80

Number of pencils = 8

Cost of each pencil = ?

Cost of each pencil = (Total Cost) ÷ (Number of pencils)

Substituting the values:

Cost of each pencil = ₹46.80 ÷ 8

On dividing 46.80 by 8, we get:

5.858)46.8040.006806400400400\begin{array}{r} 5.85 \\ 8 \overline{\smash{)} 46.80 } \\ \underline{40} \phantom{.00} \\ 68 \phantom{0} \\ \underline{64} \phantom{0} \\ 040 \\ \underline{040} \\ 0 \end{array}

46.80 ÷ 8 = 5.85

Hence, the cost of each pencil is ₹5.85

Question 6

A car covers a distance of 276.75 km in 4.5 hours. What is the average speed of the car?

Answer

Given:

Distance = 276.75 km

Time = 4.5 hours

Speed = ?

We know the formula,

Speed = Distance ÷ Time

Substituting the values:

Speed = 276.75 km ÷ 4.5 hours

= 276.75×104.5×10\dfrac{276.75 \times 10}{4.5 \times 10}

= 2767.545\dfrac{2767.5}{45} \quad [Multiplying both sides by 10 to make denominator a whole number]

On dividing 2767.5 by 45, we get:

61.545)2767.5270.0067.045.022522500\begin{array}{r} 61.5 \\ 45 \overline{\smash{)} 2767.5 } \\ \underline{270} \phantom{.00} \\ 67 \phantom{.0} \\ \underline{45} \phantom{.0} \\ 225 \\ \underline{225} \\ 0 \phantom{0} \end{array}

276.75 ÷ 4.5 = 61.5

Hence, the average speed of the car is 61.5 km/h

Question 7

2.25 m of a cloth costs ₹326.25. What is the cost of 1 m of cloth?

Answer

Given:

Total Cost = ₹326.25

Total length = 2.25 m

Cost of 1 m cloth = ?

Cost of 1 m cloth = (Total Cost) ÷ (Total length)

Substituting the values:

Cost of 1 m cloth = ₹326.25 ÷ 2.25 m

= 326.25×1002.25×100\dfrac{326.25 \times 100}{2.25 \times 100}

= 32625225\dfrac{32625}{225} \quad [Multiplying both sides by 100 to make denominator a whole number]

On dividing 32625 by 225, we get:

145225)3262522500101209000112511250\begin{array}{r} 145 \\ 225 \overline{\smash{)} 32625 } \\ \underline{225} \phantom{00} \\ 1012 \phantom{0} \\ \underline{900} \phantom{0} \\ 1125 \\ \underline{1125} \\ 0 \end{array}

326.25 ÷ 2.25 = 145

Hence, the cost of 1 m of cloth is ₹145

Question 8

The product of two numbers is 52.8. If one of them is 8.25, find the other.

Answer

Let p and q be two numbers

Given:

Product of two numbers = 52.8

One number = p = 8.25

Other number = q = ?

p x q = 52.8

Substituting the values:

8.25 x q = 52.8

q = 52.8 ÷ 8.25 \quad [Solving for q]

= 52.8×1008.25×100\dfrac{52.8 \times 100}{8.25 \times 100}

= 5280825\dfrac{5280}{825} \quad [Multiplying both sides by 100 to make denominator a whole number]

On dividing 5280 by 825, we get:

6.4825)5280.04950.0330.0330.00\begin{array}{r} 6.4 \\ 825 \overline{\smash{)} 5280.0 } \\ \underline{4950} \phantom{.0} \\ 330.0 \\ \underline{330.0} \\ 0 \end{array}

52.8 ÷ 8.25 = 6.4

Hence, the other number is 6.4

Question 9

How many equal pieces, each of length 3.6 cm can be cut from a rope of length 61.2 cm?

Answer

Given:

Total length of rope = 61.2 cm

Length of each piece = 3.6 cm

Number of pieces = ?

Number of pieces = (Total length) ÷ (Length of each piece)

Substituting the values:

Number of pieces = 61.2 cm ÷ 3.6 cm

=61.2×103.6×10=61236= \dfrac{61.2 \times 10}{3.6 \times 10} = \dfrac{612}{36}

On dividing 612 by 36, we get:

1736)6123602522520\begin{array}{r} 17 \\ 36 \overline{\smash{)} 612 } \\ \underline{36} \phantom{0} \\ 252 \\ \underline{252} \\ 0 \end{array}

61.2 ÷ 3.6 = 17

Hence, 17 equal pieces can be cut from the rope.

Exercise 3(E)

Question 1(i)

Express the following as a recurring decimal:

203\dfrac{20}{3}

Answer

By actual division, we get:

6.666...3)20.00018.00020.0018.0020.018.02.\begin{array}{r} 6.666... \\ 3 \overline{\smash{)} 20.000 } \\ \underline{18} \phantom{.000} \\ 20 \phantom{.00} \\ \underline{18} \phantom{.00} \\ 20 \phantom{.0} \\ \underline{18} \phantom{.0} \\ 2 \phantom{.} \end{array}

203=6.666...=6.6\dfrac{20}{3} = 6.666... = 6.\overline{6}

Question 1(ii)

Express the following as a recurring decimal :

311\dfrac{3}{11}

Answer

By actual division, we get:

0.2727...11)3.000022.00080.0077.0030.022.080773\begin{array}{r} 0.2727... \\ 11 \overline{\smash{)} 3.0000 } \\ \underline{22} \phantom{.000} \\ 80 \phantom{.00} \\ \underline{77} \phantom{.00} \\ 30 \phantom{.0} \\ \underline{22} \phantom{.0} \\ 80 \phantom{} \\ \underline{77} \phantom{} \\ 3 \phantom{} \end{array}

311=0.2727...=0.27\dfrac{3}{11} = 0.2727... = 0.\overline{27}

Question 1(iii)

Express the following as a recurring decimal :

56\dfrac{5}{6}

Answer

By actual division, we get:

0.833...6)5.00048.0020.018.020182\begin{array}{r} 0.833... \\ 6 \overline{\smash{)} 5.000 } \\ \underline{48} \phantom{.00} \\ 20 \phantom{.0} \\ \underline{18} \phantom{.0} \\ 20 \phantom{} \\ \underline{18} \phantom{} \\ 2 \phantom{} \end{array}

56=0.833...=0.83\dfrac{5}{6} = 0.833... = 0.8\overline{3}

Question 1(iv)

Express the following as a recurring decimal :

1790\dfrac{17}{90}

Answer

By actual division, we get:

0.188...90)17.00090.00800.0720.080072080\begin{array}{r} 0.188... \\ 90 \overline{\smash{)} 17.000 } \\ \underline{90} \phantom{.00} \\ 800 \phantom{.0} \\ \underline{720} \phantom{.0} \\ 800 \phantom{} \\ \underline{720} \phantom{} \\ 80 \phantom{} \end{array}

1790=0.188...=0.18\dfrac{17}{90} = 0.188... = 0.1\overline{8}

Question 1(v)

Express the following as a recurring decimal :

137\dfrac{1}{37}

Answer

By actual division, we get:

0.027027...37)1.0000000.00000100.000074.0000260.000259.00010.000.00100.074.026\begin{array}{r} 0.027027... \\ 37 \overline{\smash{)} 1.000000 } \\ \underline{0} \phantom{.00000} \\ 100 \phantom{.0000} \\ \underline{74} \phantom{.0000} \\ 260 \phantom{.000} \\ \underline{259} \phantom{.000} \\ 10 \phantom{.00} \\ \underline{0} \phantom{.00} \\ 100 \phantom{.0} \\ \underline{74} \phantom{.0} \\ 26 \phantom{} \end{array}

137=0.027027...=0.027\dfrac{1}{37} = 0.027027... = 0.\overline{027}

Question 1(vi)

Express the following as a recurring decimal :

227\dfrac{22}{7}

Answer

By actual division, we get:

3.142857...7)22.00000021.0000010.00007.000030.00028.00020.0014.0060.056.0403550491\begin{array}{r} 3.142857... \\ 7 \overline{\smash{)} 22.000000 } \\ \underline{21} \phantom{.00000} \\ 10 \phantom{.0000} \\ \underline{7} \phantom{.0000} \\ 30 \phantom{.000} \\ \underline{28} \phantom{.000} \\ 20 \phantom{.00} \\ \underline{14} \phantom{.00} \\ 60 \phantom{.0} \\ \underline{56} \phantom{.0} \\ 40 \phantom{} \\ \underline{35} \phantom{} \\ 50 \phantom{} \\ \underline{49} \phantom{} \\ 1 \phantom{} \end{array}

227=3.14285714...=3.142857\dfrac{22}{7} = 3.14285714... = 3.\overline{142857}

Question 1(vii)

Express the following as a recurring decimal :

213\dfrac{2}{13}

Answer

By actual division, we get:

0.153846...13)2.00000013.0000070.000065.000050.00039.000110.00104.0060.052.080782\begin{array}{r} 0.153846... \\ 13 \overline{\smash{)} 2.000000 } \\ \underline{13} \phantom{.00000} \\ 70 \phantom{.0000} \\ \underline{65} \phantom{.0000} \\ 50 \phantom{.000} \\ \underline{39} \phantom{.000} \\ 110 \phantom{.00} \\ \underline{104} \phantom{.00} \\ 60 \phantom{.0} \\ \underline{52} \phantom{.0} \\ 80 \phantom{} \\ \underline{78} \phantom{} \\ 2 \phantom{} \end{array}

213=0.153846153846...=0.153846\dfrac{2}{13} = 0.153846153846... = 0.\overline{153846}

Question 2(i)

Convert the following into a vulgar fraction :

0.6{0.\overline{6}}

Answer

Let x=0.6x = 0.\overline{6}. Then,

x = 0.6666... (i)

⇒ 10x = 6.6666... (ii)

On subtracting (i) from (ii), we get:

9x=6x=69=239x = 6 \\[1em] \Rightarrow x = \dfrac{6}{9} = \dfrac{2}{3}

Hence, 0.6=230.\overline{6} = \dfrac{2}{3}

Question 2(ii)

Convert the following into a vulgar fraction :

0.8{0.\overline{8}}

Answer

Let x=0.8x = 0.\overline{8}. Then,

x = 0.8888... (i)

⇒ 10x = 8.8888... (ii)

On subtracting (i) from (ii), we get:

9x=8x=899x = 8 \\[1em] \Rightarrow x = \dfrac{8}{9}

Hence, 0.8=890.\overline{8} = \dfrac{8}{9}

Question 2(iii)

Convert the following into a vulgar fraction :

0.34{0.\overline{34}}

Answer

Let x=0.34x = 0.\overline{34}. Then,

x = 0.343434... (i)

⇒ 100x = 34.343434... (ii)

On subtracting (i) from (ii), we get:

99x=34x=349999x = 34 \\[1em] \Rightarrow x = \dfrac{34}{99}

Hence, 0.34=34990.\overline{34} = \dfrac{34}{99}

Question 2(iv)

Convert the following into a vulgar fraction :

2.13{2.\overline{13}}

Answer

Let x = 2.132.\overline{13}.

Then,

x = 2.131313... (i)

⇒ 100x = 213.131313... (ii)

On subtracting (i) from (ii), we get:

99x=211x=21199x=2139999x = 211 \\[1em] \Rightarrow x = \dfrac{211}{99} \\[1em] \Rightarrow x = 2\dfrac{13}{99}

Hence, 2.13=213992.\overline{13} = 2\dfrac{13}{99}

Question 2(v)

Convert the following into a vulgar fraction :

1.243{1.\overline{243}}

Answer

Let x=1.243x = 1.\overline{243}. Then,

x = 1.243243243... (i)

⇒ 1000x = 1243.243243... (ii)

On subtracting (i) from (ii), we get:

999x=1242x=1242999x=1243999999x = 1242 \\[1em] \Rightarrow x = \dfrac{1242}{999} \\[1em] \Rightarrow x = 1\dfrac{243}{999} \\[1em]

Hence, 1.243=12439991.\overline{243} = 1\dfrac{243}{999}

Question 3(i)

Convert the following into a vulgar fraction :

0.16{0.1\overline{6}}

Answer

Let x=0.16=0.1666...x = 0.1\overline{6} = 0.1666...

Multiplying by 10 to move the non-repeating digit:

10x = 1.6666... \qquad..... (i)

Multiplying by 100 to move the decimal past the first repeating digit:

100x = 16.6666... \qquad..... (ii)

On subtracting (i) from (ii), we get:

90x=15x=1590=1690x = 15 \\[1em] \Rightarrow x = \dfrac{15}{90} = \dfrac{1}{6}

Hence, 0.16=160.1\overline{6} = \dfrac{1}{6}.

Question 3(ii)

Convert the following into a vulgar fraction :

0.143{0.1\overline{43}}

Answer

Let x=0.143=0.1434343...x = 0.1\overline{43} = 0.1434343...

Multiplying by 10 to move the decimal past the non-repeating digit:

10x = 1.434343... \qquad ..... (i)

Multiplying by 1000 to move the decimal past the first repeating block:

1000x = 143.434343... \qquad ..... (ii)

Subtracting (i) from (ii), we get:

990x=142x=142990=71495990x = 142 \\[1em] \Rightarrow x = \dfrac{142}{990} = \dfrac{71}{495}

Hence, 0.143=714950.1\overline{43} = \dfrac{71}{495}

Question 3(iii)

Convert the following into a vulgar fraction :

0.574{0.57\overline{4}}

Answer

Let x=0.574=0.57444...x = 0.57\overline{4} = 0.57444...

Multiplying by 100 to move the decimal past the non-repeating digits:

100x = 57.444..... (i)

Multiplying by 10 to move the decimal past the first repeating block:

1000x = 574.444..... (ii)

Subtracting (i) from (ii):

900x=517x=517900900x = 517 \\[1em] \Rightarrow x = \dfrac{517}{900}

Hence, 0.574=5179000.57\overline{4} = \dfrac{517}{900}

Question 3(iv)

Convert the following into a vulgar fraction :

0.1234{0.12\overline{34}}

Answer

Let x=0.1234=0.12343434...x = 0.12\overline{34} = 0.12343434...

Multiplying by 100 to move the decimal past the non-repeating digits:

100x = 12.343434..... (i)

Multiplying by 100 to move the decimal past the first repeating block:

10000x = 1234.343434..... (ii)

Subtracting (i) from (ii):

9900x=1222x=12229900=61149509900x = 1222 \\[1em] \Rightarrow x = \dfrac{1222}{9900} = \dfrac{611}{4950}

Hence, 0.1234=61149500.12\overline{34} = \dfrac{611}{4950}

Exercise 3(F)

Question 1(i)

Round off the following to the nearest whole number :

87.46

Answer

The given number is 87.46. Its whole number part is 87.

First digit to the right of decimal is 4 < 5.

∴ Required rounded off number is 87.

Question 1(ii)

Round off the following to the nearest whole number :

65.83

Answer

The given number is 65.83. Its whole number part is 65.

First digit to the right of decimal is 8 > 5.

So, we increase the whole number part by 1.

∴ Required rounded off number is 66.

Question 1(iii)

Round off the following to the nearest whole number :

71.54

Answer

The given number is 71.54. Its whole number part is 71.

First digit to the right of decimal is 5.

So, we increase the whole number part by 1.

∴ Required rounded off number is 72.

Question 1(iv)

Round off the following to the nearest whole number :

98.5

Answer

The given number is 98.5. Its whole number part is 98.

First digit to the right of decimal is 5.

So, we increase the whole number part by 1.

∴ Required rounded off number is 99.

Question 1(v)

Round off the following to the nearest whole number :

60.29

Answer

The given number is 60.29. Its whole number part is 60.

First digit to the right of decimal is 2 < 5.

∴ Required rounded off number is 60.

Question 2(i)

Round off :

6.342, correct to 2 decimal places

Answer

The given number is 6.342

This number up to 2 decimal places is 6.34

The third decimal place is 2 < 5

∴ The number correct to 2 decimal places is 6.34

Question 2(ii)

Round off :

8.1347, correct to 3 decimal places

Answer

The given number is 8.1347

This number up to 3 decimal places is 8.134

The fourth decimal place is 7 > 5

So, we increase the 3rd decimal place by 1

∴ The number correct to 3 decimal places is 8.135

Question 2(iii)

Round off :

0.845, correct to 2 decimal places

Answer

The given number is 0.845

This number up to 2 decimal places is 0.84

The third decimal place is 5

So, we increase the 2nd decimal place by 1

∴ The number correct to 2 decimal places is 0.85

Question 2(iv)

Round off :

1.732, correct to 1 decimal place

Answer

The given number is 1.732

This number up to 1 decimal place is 1.7

The second decimal place is 3 < 5

∴ The number correct to 1 decimal place is 1.7

Question 2(v)

Round off :

9.638, correct to 2 decimal places

Answer

The given number is 9.638

This number up to 2 decimal places is 9.63

The third decimal place is 8 > 5

So, we increase the 2nd decimal place by 1.

∴ The number correct to 2 decimal places is 9.64

Question 2(vi)

Round off :

0.047, correct to 2 decimal places

Answer

The given number is 0.047

This number up to 2 decimal places is 0.04

The third decimal place is 7 > 5

So, we increase the 2nd decimal place by 1.

∴ The number correct to 2 decimal places is 0.05

Question 3(i)

Write the value of :

7.451 to the nearest hundredths

Answer

The given number is 7.451

Up to hundredths place it is 7.45. The next place is 1 < 5

∴ The required number is 7.45

Question 3(ii)

Write the value of :

3.157 to the nearest tenths

Answer

The given number is 3.157

Up to tenths place it is 3.1. The next place is 5.

So, we increase the tenths place by 1.

∴ The required number is 3.2

Question 3(iii)

Write the value of :

0.6428 to the nearest thousandths

Answer

The given number is 0.6428

Up to thousandths place it is 0.642. The next place is 8 > 5

So, we increase the thousandths place by 1.

∴ The required number is 0.643

Question 3(iv)

Write the value of :

0.061 to the nearest tenths

Answer

The given number is 0.061

Up to tenths place it is 0.0. The next place is 6 > 5

So, we increase the tenths place by 1.

∴ The required number is 0.1

Question 3(v)

Write the value of :

0.136 to the nearest hundredths

Answer

The given number is 0.136

Up to hundredths place it is 0.13. The next place is 6 > 5

So, we increase the hundredths place by 1.

∴ The required number is 0.14

Question 4

Express 67\dfrac{6}{7} as a decimal, correct to 2 decimal places.

Answer

By actual division, we get:

0.857...7)6.00056.0040.035.050491\begin{array}{r} 0.857... \\ 7 \overline{\smash{)} 6.000 } \\ \underline{56} \phantom{.00} \\ 40 \phantom{.0} \\ \underline{35} \phantom{.0} \\ 50 \phantom{} \\ \underline{49} \phantom{} \\ 1 \phantom{} \end{array}

The given number up to 2 decimal places is 0.85

The third decimal place is 7 > 5

So, we increase the 2nd decimal place by 1.

67\dfrac{6}{7} correct to 2 decimal places is 0.86

Exercise 3(G) - Multiple Choice Questions

Question 1

The decimal 0.55 when expressed as a fraction in the simplest form is

  1. 511\dfrac{5}{11}

  2. 1120\dfrac{11}{20}

  3. 55100\dfrac{55}{100}

  4. 1150\dfrac{11}{50}

Answer

0.55=551000.55 = \dfrac{55}{100}

= 1120\dfrac{11}{20} \quad [Dividing both by 5]

Hence, option 2 is the correct option.

Question 2

The fraction 313831\dfrac{3}{8} converted to decimal is

  1. 24.125
  2. 24.625
  3. 31.375
  4. 31.675

Answer

3138=31+3831\dfrac{3}{8} = 31 + \dfrac{3}{8}

Dividing 3 by 8, we get:

0.3758)3.00024.0060.056.040400\begin{array}{r} 0.375 \\ 8 \overline{\smash{)} 3.000 } \\ \underline{24} \phantom{.00} \\ 60 \phantom{.0} \\ \underline{56} \phantom{.0} \\ 40 \phantom{} \\ \underline{40} \phantom{} \\ 0 \phantom{} \end{array}

31 + 0.375 = 31.375

Hence, option 3 is the correct option.

Question 3

What is to be subtracted from 5.1 to get 0.51?

  1. 0.44
  2. 0.99
  3. 4.59
  4. 5.49

Answer

Let the required number be x.

5.1 - x = 0.51

x = 5.1 - 0.51

x = 5.10 - 0.51 = 4.59

Hence, option 3 is the correct option.

Question 4

92.008 x 100 is equal to

  1. 0.92008
  2. 9.2008
  3. 92008
  4. 9200.8

Answer

When multiplying by 100, the decimal point shifts two places to the right.

∴ 92.008 x 100 = 9200.8

Hence, option 4 is the correct option.

Question 5

A batsman scored 574 runs in 8 innings. His average score per innings is

  1. 72.25
  2. 71.75
  3. 72.325
  4. 71.675

Answer

Given:

Total runs = 574

Total innings = 8

Average score = Total runs ÷ Total innings

Substituting the values in above, we get:

Average score = 574 ÷ 8

By actual division:

71.758)574.00564.0014.008.0060.056.040400\begin{array}{r} 71.75 \\ 8 \overline{\smash{)} 574.00 } \\ \underline{56} \phantom{4.00} \\ 14 \phantom{.00} \\ \underline{8} \phantom{.00} \\ 60 \phantom{.0} \\ \underline{56} \phantom{.0} \\ 40 \phantom{} \\ \underline{40} \phantom{} \\ 0 \phantom{} \end{array}

574 ÷ 8 = 71.75

Hence, option 2 is the correct option.

Question 6

The recurring decimal 0.450.4\overline{5} when converted to a vulgar fraction is

  1. 45100\dfrac{45}{100}

  2. 4599\dfrac{45}{99}

  3. 4190\dfrac{41}{90}

  4. 4199\dfrac{41}{99}

Answer

Let x = 0.4555... (i)

Multiplying both sides by 10 (to move the decimal point past the non-repeating digit):

10x = 4.5555... (ii)

Multiplying both sides by 10 (to move the decimal point past the first repeating digit):

100x = 45.5555... (iii)

On subtracting (ii) from (iii), we get:

(100x - 10x) = (45.5555...) - (4.5555...)

90x = 41

x=4190x = \dfrac{41}{90}

Hence, option 3 is the correct option.

Question 7

The decimal 371.6258 rounded off correct to two decimal places is

  1. 371.626
  2. 371.63
  3. 371.625
  4. 371.62

Answer

The given number is 371.6258

Up to two decimal places, it is 371.62

The third decimal digit is 5.

So, we increase the second decimal place by 1.

∴ The required number is 371.63.

Hence, option 2 is the correct option.

Exercise 3(G) - Mental Maths

Question 1

Fill in the blanks :

(i) For addition or subtraction of decimals, we shall first convert them into ............... .

(ii) When we multiply a decimal by 1000, we move the decimal ............... places to the right.

(iii) When we divide a decimal by 100, we move the decimal two places to the ............... .

(iv) When we multiply two decimals, the number of decimal places in the product is equal to the ............... of the decimal places in the given decimals.

(v) A decimal in which some of the digits in the decimal part are not repeated while all the rest are repeated, is called a ............... decimal.

Answer

(i) For addition or subtraction of decimals, we shall first convert them into like decimals.

(ii) When we multiply a decimal by 1000, we move the decimal three places to the right.

(iii) When we divide a decimal by 100, we move the decimal two places to the left.

(iv) When we multiply two decimals, the number of decimal places in the product is equal to the sum of the decimal places in the given decimals.

(v) A decimal in which some of the digits in the decimal part are not repeated while all the rest are repeated, is called a mixed recurring decimal.

Question 2

State True or False :

(i) Like decimals have the same decimal parts.

(ii) The part of a decimal that lies to the left of the decimal point is called the whole number part.

(iii) When we divide a decimal by another decimal, the number of decimal places in the quotient is equal to the difference in the number of decimal places in the two decimals.

(iv) A decimal is called a terminating decimal if its whole number part is 0.

(v) A recurring decimal is one in which all the digits in the decimal part are repeated.

Answer

(i) False.
Reason — Like decimals have the same number of decimal places, not necessarily the same digits in the decimal parts.

(ii) True.
Reason — The digits to the left of the decimal point represent the whole number part.

(iii) False.
Reason — When dividing decimals, we first make the divisor a whole number. The number of decimal places in the quotient does not depend on the difference in decimal places.

(iv) False.
Reason — A decimal is called terminating if the division ends with a remainder of zero, regardless of what the whole number part is.

(v) False.
Reason — This describes a pure recurring decimal; however, a recurring decimal can also be a mixed recurring decimal where only some digits repeat.

Exercise 3(G) - Case Study Based Questions

Question 1

The signboard provided alongside shows the costs for various articles available at the Hamburg Bakery shop. Sanya comes here to buy bakery items for her friends who would be visiting her home tonight. She prepares a list of all the items that she has to buy - 4 pineapple pastries, 5 patties, 2 doughnuts and a box of cookies. Each pineapple pastry costs ₹25.50, each patty costs ₹12.25, each doughnut costs ₹21.75 and the box of cookies costs ₹79.50 Sanya’s father gave her a 500 rupee note.

Represent each of the following on the number line: R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(1) What will be the bakery bill for Sanya?

  1. ₹192.75
  2. ₹286.25
  3. ₹166.50
  4. ₹225.00

(2) When Sanya gives the 500 rupee note to the bakery owner, what amount will she get in return after paying the bill?

  1. ₹307.25
  2. ₹333.50
  3. ₹275.00
  4. ₹213.75

(3) On the way back Sanya bought 6 pens, each costing ₹17.75. How much did she spend on pens?

  1. ₹106.50
  2. ₹95.25
  3. ₹124.00
  4. ₹84.75

(4) She returned all the money left with her to her father. How much did she return?

  1. ₹129
  2. ₹89.75
  3. ₹118.50
  4. ₹107.25

Answer

(1) Given:

Cost of one pineapple pastry = ₹25.50

Cost of one patty = ₹12.25

Cost of one doughnut = ₹21.75

Cost of a box of cookies = ₹79.50

Sanya buys:

4 pineapple pastries = 4 x ₹25.50 = ₹102.00

5 patties = 5 x ₹12.25 = ₹61.25

2 doughnuts = 2 x ₹21.75 = ₹43.50

A box of cookies = 1 x ₹79.50 = ₹79.50

Total Bill = ₹(102.00 + 61.25 + 43.50 + 79.50) = ₹286.25

Hence, option 2 is the correct option.

(2) Amount given = ₹500.00

Total Bill = ₹286.25 \quad [From previous step]

Amount received back = (Amount given) - (Total Bill)

Substituting the values in above, we get:

Amount received back = ₹500.00 - ₹286.25 = ₹213.75

Hence, option 4 is the correct option.

(3) Given:

No of pens = 6

Cost of one pen = ₹17.75

Cost of 6 pens = No of pens x Cost of one pen

Cost of 6 pens = 6 x ₹17.75 = ₹106.50

Hence, option 1 is the correct option.

(4) Total amount given = ₹500.00

Money spent on bakery = ₹286.25 \quad [From step 1]

Money spent on pens = ₹106.50 \quad [From step 3]

Final balance returned = ?

Total amount spent = Money spent on bakery + Money spent on pens

Total amount spent = ₹286.25 + ₹106.50 = ₹392.75

Final balance returned = Total amount given - Total amount spent

Substituting the values in above, we get:

Final balance returned = ₹500.00 - ₹392.75 = ₹107.25

Hence, option 4 is the correct option.

Question 2

There is a 0.37 km long jogging track in Laleh Park. Shruti lives 0.42 km away from the track. Every morning Shruti goes jogging to Laleh park. She usually starts jogging from home and after reaching the park, goes jogging 8 times around the track. She then returns home by a friend's car.

(1) How much distance does she jog every morning?

  1. 0.79 km
  2. 3.38 km
  3. 3.73 km
  4. 6.32 km

(2) How many rounds of the track make a distance of 4.44 km?

  1. 9
  2. 10
  3. 11
  4. 12

(3) On a particular day, she began jogging from her home and completed 10 rounds of the track. How much did she jog on that day?

  1. 3.28 km
  2. 4.12 km
  3. 4.57 km
  4. 7.9 km

(4) One day her friend could not come. So, she had to jog back home after completing 8 rounds of the track. How much did she jog on that day?

  1. 3.8 km
  2. 4.1 km
  3. 4.6 km
  4. 5.1 km

Answer

(1) Given:

Distance from home to park = 0.42 km

Length of track = 0.37 km

8 rounds of the track = 8 x 0.37 = 2.96 km

Total distance = Distance from home to park + 8 rounds of the track

Substituting the values in above, we get:

Total distance = 0.42 + 2.96 = 3.38 km

Hence, option 2 is the correct option.

(2) Number of rounds = ?

Distance = 4.44 km

Track length = 0.37 km

Number of rounds = Total distance ÷ Track length

Substituting the values in above, we get:

Number of rounds = 4.44 km ÷ 0.37 km = 12

Hence, option 4 is the correct option.

(3) Given:

Distance from home to park = 0.42 km

Length of track = 0.37 km

10 rounds of the track = 10 x 0.37 = 3.70 km

Total distance = Distance from home to park + 10 rounds of the track

Substituting the values in above, we get:

Total distance = 0.42 + 3.70 = 4.12 km

Hence, option 2 is the correct option.

(4) Given:

Distance to park = 0.42 km

Length of track = 0.37 km

8 rounds of track = 8 x 0.37 = 2.96 km

Distance back home = 0.42 km

Total distance = Distance to park + 8 rounds of track + Distance back home

Substituting the values in above, we get:

Total distance = 0.42 km + 2.96 km + 0.42 km = 3.8 km

Hence, option 1 is the correct option.

Exercise 3(G) - Assertions and Reasons

Question 1

Assertion: To multiply a decimal number by 1000, we move the decimal point in the number to the right by three places.

Reason: To multiply two decimals, we first convert them into fractions.

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. Assertion (A) is true but Reason (R) is false.
  4. Assertion (A) is false but Reason (R) is true.

Answer

Assertion (A) is true but Reason (R) is false.

Explanation

When we multiply a decimal by 1000, we shift the decimal point three places to the right.

Example:

2.45 × 1000 = 2450

The Reason is false.

To multiply two decimals, we do not need to convert them into fractions. We multiply the numbers normally and then place the decimal point according to the total number of decimal places.

Hence, option 3 is the correct option.

Question 2

Assertion: 0.2222 ............... is a recurring decimal.

Reason: In a decimal if a digit or a group of digits in the decimal part is repeated, continuously, then such a number is called a recurring decimal.

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. Assertion (A) is true but Reason (R) is false.
  4. Assertion (A) is false but Reason (R) is true.

Answer

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation

The Assertion is true.

0.2222...... has the digit 2 repeating continuously.

The Reason is also true.

A decimal in which a digit or group of digits repeats continuously is called a recurring decimal.

Since the digit 2 repeats continuously in 0.2222……, it is a recurring decimal.

Hence, option 1 is the correct option.

Question 3

Assertion: If we round off 15.406 to the nearest hundredths, we get 15.41.

Reason: To the nearest hundredths means, correct to 3 decimal places.

  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. Assertion (A) is true but Reason (R) is false.
  4. Assertion (A) is false but Reason (R) is true.

Answer

Assertion (A) is true but Reason (R) is false.

Explanation

In 15.406, the hundredths place is 0. The digit in the thousandths place is 6 > 5, so we increase the hundredths digit by 1 to get 15.41.

The Reason is false.

Nearest hundredths means correct to 2 decimal places, not 3 decimal places.

Hence, option 3 is the correct option.

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