KnowledgeBoat Logo
|
OPEN IN APP

Chapter 10

Algebraic Expressions and Identities — Multiple Choice Questions

Class - 8 ML Aggarwal Understanding ICSE Mathematics



Objective Type Questions - Multiple Choice Questions

Question 3

The literal coefficient of −9xyz2-9xyz^2 is

  1. -9

  2. xyxy

  3. xyz2xyz^2

  4. −9xy-9xy

Answer

Any factor of a term is called the coefficient of the remaining factor of the term. The constant part is the numerical coefficient and the remaining part is the literal coefficient.

In −9xyz2-9xyz^2, the numerical coefficient is -9 and the remaining part is xyz2xyz^2.

Hence, option 3 is the correct option.

Question 4

Which of the following algebraic expression is not a polynomial?

  1. 3x2−2x+73x^2 - 2x + 7

  2. 5x32x+3x2+8\dfrac{5x^3}{2x} + 3x^2 + 8

  3. 3x+2x+73x + \dfrac{2}{x} + 7

  4. 2x2+3x+6\sqrt{2}x^2 + \sqrt{3}x + \sqrt{6}

Answer

An algebraic expression is a polynomial if the powers of the variables in each term are non-negative integers.

Option 1: In 3x2−2x+73x^2 - 2x + 7 the powers of xx are 2, 1 and 0. So, it is a polynomial.

Option 2: 5x32x+3x2+8=52x2+3x2+8\dfrac{5x^3}{2x} + 3x^2 + 8 = \dfrac{5}{2}x^2 + 3x^2 + 8, in which the powers of xx are 2 and 0. So, it is a polynomial.

Option 3: In 3x+2x+73x + \dfrac{2}{x} + 7, the term 2x=2x−1\dfrac{2}{x} = 2x^{-1}, in which the power of xx is -1, a negative integer. So, it is not a polynomial.

Option 4: In 2x2+3x+6\sqrt{2}x^2 + \sqrt{3}x + \sqrt{6} the powers of xx are 2, 1 and 0. So, it is a polynomial.

Hence, option 3 is the correct option.

Question 5

Which of the following algebraic expression is not a monomial?

  1. 3x×y×z3x \times y \times z

  2. −5pq-5pq

  3. 8m2×n÷3l8m^2 \times n \div 3l

  4. 7x+y−z7x + y - z

Answer

An algebraic expression having only one term is called a monomial. Multiplication and division do not separate the terms of an algebraic expression.

Option 1: 3x×y×z3x \times y \times z has only one term, so it is a monomial.

Option 2: −5pq-5pq has only one term, so it is a monomial.

Option 3: 8m2×n÷3l8m^2 \times n \div 3l has only one term, so it is a monomial.

Option 4: 7x+y−z7x + y - z has three terms, so it is not a monomial. It is a trinomial.

Hence, option 4 is the correct option.

Question 6

Degree of the polynomial 7x2yz2+6x3y2z2−5x+8y7x^2yz^2 + 6x^3y^2z^2 - 5x + 8y is

  1. 4

  2. 5

  3. 6

  4. 7

Answer

In a polynomial in two or more variables, the degree is the greatest sum of the powers of the variables in a term.

The given polynomial is 7x2yz2+6x3y2z2−5x+8y7x^2yz^2 + 6x^3y^2z^2 - 5x + 8y

Sum of powers of 7x2yz2=2+1+2=57x^2yz^2 = 2 + 1 + 2 = 5

Sum of powers of 6x3y2z2=3+2+2=76x^3y^2z^2 = 3 + 2 + 2 = 7

Sum of powers of −5x=1-5x = 1

Sum of powers of 8y=18y = 1

The greatest sum is 7.

Hence, option 4 is the correct option.

Question 7

a(b−c)+b(c−a)+c(a−b)a(b - c) + b(c - a) + c(a - b) is equal to

  1. ab+bc+caab + bc + ca

  2. 0

  3. 2(ab+bc+ca)2(ab + bc + ca)

  4. none of these

Answer

Solving,

⇒a(b−c)+b(c−a)+c(a−b)⇒ab−ac+bc−ab+ac−bc⇒(ab−ab)+(−ac+ac)+(bc−bc)⇒0\Rightarrow a(b - c) + b(c - a) + c(a - b)\\[1em] \Rightarrow ab - ac + bc - ab + ac - bc\\[1em] \Rightarrow (ab - ab) + (-ac + ac) + (bc - bc)\\[1em] \Rightarrow 0

Hence, option 2 is the correct option.

Question 8

75xy−23xy+89xy\dfrac{7}{5}xy - \dfrac{2}{3}xy + \dfrac{8}{9}xy is equal to

  1. 7345xy\dfrac{73}{45}xy

  2. −7345xy-\dfrac{73}{45}xy

  3. xyxy

  4. none of these

Answer

Solving,

⇒75xy−23xy+89xy⇒(75−23+89)xy⇒63−30+4045xy⇒7345xy\Rightarrow \dfrac{7}{5}xy - \dfrac{2}{3}xy + \dfrac{8}{9}xy\\[1em] \Rightarrow \Big(\dfrac{7}{5} - \dfrac{2}{3} + \dfrac{8}{9}\Big)xy\\[1em] \Rightarrow \dfrac{63 - 30 + 40}{45}xy\\[1em] \Rightarrow \dfrac{73}{45}xy

Hence, option 1 is the correct option.

Question 9

(3p2qr3)×(−4p3q2r2)×(7pq2r)(3p^2qr^3) \times (-4p^3q^2r^2) \times (7pq^2r) is equal to

  1. 84p6q6r684p^6q^6r^6

  2. −84p6q6r6-84p^6q^6r^6

  3. 84p6q5r684p^6q^5r^6

  4. −84p6q5r6-84p^6q^5r^6

Answer

Solving,

⇒(3p2qr3)×(−4p3q2r2)×(7pq2r)⇒(3×(−4)×7)×(p2×p3×p)×(q×q2×q2)×(r3×r2×r)⇒−84p(2+3+1)q(1+2+2)r(3+2+1)⇒−84p6q5r6\Rightarrow (3p^2qr^3) \times (-4p^3q^2r^2) \times (7pq^2r)\\[1em] \Rightarrow (3 \times (-4) \times 7) \times (p^2 \times p^3 \times p) \times (q \times q^2 \times q^2) \times (r^3 \times r^2 \times r)\\[1em] \Rightarrow -84p^{(2+3+1)}q^{(1+2+2)}r^{(3+2+1)}\\[1em] \Rightarrow -84p^6q^5r^6

Hence, option 4 is the correct option.

Question 10

3m×(2m2−5mn+4n2)3m \times (2m^2 - 5mn + 4n^2) is equal to

  1. 6m3+15m2n−12mn26m^3 + 15m^2n - 12mn^2

  2. 6m3−15m2n+12mn26m^3 - 15m^2n + 12mn^2

  3. 6m3−15m2n−12mn26m^3 - 15m^2n - 12mn^2

  4. 6m3+15m2n+12mn26m^3 + 15m^2n + 12mn^2

Answer

Solving,

⇒3m×(2m2−5mn+4n2)⇒3m×2m2−3m×5mn+3m×4n2⇒6m3−15m2n+12mn2\Rightarrow 3m \times (2m^2 - 5mn + 4n^2)\\[1em] \Rightarrow 3m \times 2m^2 - 3m \times 5mn + 3m \times 4n^2\\[1em] \Rightarrow 6m^3 - 15m^2n + 12mn^2

Hence, option 2 is the correct option.

Question 11

Volume of a rectangular box whose adjacent edges are 3x2y,4y2z3x^2y, 4y^2z and 5z2x5z^2x respectively is

  1. 60xyz60xyz

  2. 60x2y2z260x^2y^2z^2

  3. 60x3y3z360x^3y^3z^3

  4. none of these

Answer

Volume of a rectangular box = length × breadth × height

⇒3x2y×4y2z×5z2x⇒(3×4×5)×(x2×x)×(y×y2)×(z×z2)⇒60x3y3z3\Rightarrow 3x^2y \times 4y^2z \times 5z^2x\\[1em] \Rightarrow (3 \times 4 \times 5) \times (x^2 \times x) \times (y \times y^2) \times (z \times z^2)\\[1em] \Rightarrow 60x^3y^3z^3

Hence, option 3 is the correct option.

Question 12

(x+1)(x+2)(x + 1)(x + 2) is equal to

  1. 2x+32x + 3

  2. x2+2x+2x^2 + 2x + 2

  3. x2+3x+2x^2 + 3x + 2

  4. x2+2x+3x^2 + 2x + 3

Answer

(x+1)(x+2)(x + 1)(x + 2)

Using the identity (x+a)(x+b)=x2+(a+b)x+ab(x + a)(x + b) = x^2 + (a + b)x + ab,

⇒x2+(1+2)x+1×2⇒x2+3x+2\Rightarrow x^2 + (1 + 2)x + 1 \times 2\\[1em] \Rightarrow x^2 + 3x + 2

Hence, option 3 is the correct option.

Question 13

If x+1x=2x + \dfrac{1}{x} = 2, then x2+1x2x^2 + \dfrac{1}{x^2} is equal to

  1. 4

  2. 2

  3. 0

  4. none of these

Answer

Given, x+1x=2x + \dfrac{1}{x} = 2

Squaring both sides,

⇒(x+1x)2=22⇒x2+2×x×1x+1x2=4⇒x2+2+1x2=4⇒x2+1x2=4−2⇒x2+1x2=2\Rightarrow \Big(x + \dfrac{1}{x}\Big)^2 = 2^2\\[1em] \Rightarrow x^2 + 2 \times x \times \dfrac{1}{x} + \dfrac{1}{x^2} = 4\\[1em] \Rightarrow x^2 + 2 + \dfrac{1}{x^2} = 4\\[1em] \Rightarrow x^2 + \dfrac{1}{x^2} = 4 - 2\\[1em] \Rightarrow x^2 + \dfrac{1}{x^2} = 2

Hence, option 2 is the correct option.

Question 14

If x2+y2=9x^2 + y^2 = 9 and xy=8xy = 8, then x+yx + y is equal to

  1. 25

  2. 5

  3. -5

  4. ±5\pm5

Answer

Given,

x2+y2=9x^2 + y^2 = 9 and xy=8xy = 8

We know that,

(x+y)2=x2+y2+2xy(x + y)^2 = x^2 + y^2 + 2xy

Substituting the values,

⇒(x+y)2=9+2×8⇒(x+y)2=9+16⇒(x+y)2=25⇒x+y=±25⇒x+y=±5\Rightarrow (x + y)^2 = 9 + 2 \times 8\\[1em] \Rightarrow (x + y)^2 = 9 + 16\\[1em] \Rightarrow (x + y)^2 = 25\\[1em] \Rightarrow x + y = \pm\sqrt{25}\\[1em] \Rightarrow x + y = \pm 5

Hence, option 4 is the correct option.

Question 15

(102)2 - (98)2 is equal to

  1. 200

  2. 400

  3. 600

  4. 800

Answer

Using the identity,

a2−b2=(a+b)(a−b)a^2 - b^2 = (a + b)(a - b)

⇒ (102)2 - (98)2

⇒ (102 + 98)(102 - 98)

⇒ 200 × 4

⇒ 800

Hence, option 4 is the correct option.

Question 16

−50x3y2z2-50x^3y^2z^2 divided by −5xyz-5xyz is equal to

  1. 10xyz10xyz

  2. 10x2yz10x^2yz

  3. −10xyz-10xyz

  4. −10x2yz-10x^2yz

Answer

Solving,

⇒−50x3y2z2÷(−5xyz)⇒−50x3y2z2−5xyz⇒505×x3−1y2−1z2−1⇒10x2yz\Rightarrow -50x^3y^2z^2 \div (-5xyz)\\[1em] \Rightarrow \dfrac{-50x^3y^2z^2}{-5xyz}\\[1em] \Rightarrow \dfrac{50}{5} \times x^{3-1}y^{2-1}z^{2-1}\\[1em] \Rightarrow 10x^2yz

Hence, option 2 is the correct option.

Question 17

96×10496 \times 104 is equal to

  1. 9984

  2. 9974

  3. 9964

  4. none of these

Answer

96×104=(100−4)(100+4)96 \times 104 = (100 - 4)(100 + 4)

Using the identity (a−b)(a+b)=a2−b2(a - b)(a + b) = a^2 - b^2,

⇒(100)2−(4)2⇒10000−16⇒9984\Rightarrow (100)^2 - (4)^2\\[1em] \Rightarrow 10000 - 16\\[1em] \Rightarrow 9984

Hence, option 1 is the correct option.

Question 18

If the area of a rectangle is 24(x2yz+xy2z+xyz2)24(x^2yz + xy^2z + xyz^2) and its length is 8xyz8xyz, then its breadth is

  1. 3(x+y+z)3(x + y + z)

  2. 3xyz3xyz

  3. 3(x+y−z)3(x + y - z)

  4. none of these

Answer

Area of rectangle = length × breadth

⇒ Breadth = Area of rectangle ÷ length

⇒24(x2yz+xy2z+xyz2)8xyz⇒24xyz(x+y+z)8xyz⇒3(x+y+z)\Rightarrow \dfrac{24(x^2yz + xy^2z + xyz^2)}{8xyz}\\[1em] \Rightarrow \dfrac{24xyz(x + y + z)}{8xyz}\\[1em] \Rightarrow 3(x + y + z)

Hence, option 1 is the correct option.

PrevNext