Mathematics
If 0 - 9, 10 - 19, 20 - 29, …., are the classes of a grouped frequency distribution, then the width of each class is :
9
9.5
10
9 or 10
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Answer
Gap between classes = 10 - 9 = 1
Adjustment factor = 0.5
So the new class boundaries become
-0.5 - 9.5, 9.5 - 19.5, 19.5 - 29.5, …,
Class width = Upper boundary - Lower boundary
Considering second class :
Class width = 19.5 - 9.5 = 10
Similarly, for rest of the class intervals.
Hence, option 3 is the correct option.
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