(0.01)^-1/2 : 1. 10 2. 0.1 3. (0.1)^1/2 4. 0.0001

Simplifying the expression : Hence, Option 1 is the correct option.

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Mathematics

$(0.01)^{-\dfrac{1}{2}}$ :
10
0.1
$(0.1)^{\frac{1}{2}}$
0.0001

Indices

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Answer

Simplifying the expression :

$\Rightarrow (0.01)^{-\dfrac{1}{2}} = \Big(\dfrac{1}{100}\Big)^{-\dfrac{1}{2}} \\[1em] = \Big(\dfrac{1}{10^2}\Big)^{-\dfrac{1}{2}} = (10^{-2})^{-\dfrac{1}{2}} \\[1em] = 10^1 = 10.$

Hence, Option 1 is the correct option.

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10 Likes

Mathematics

$(0.01)^{-\dfrac{1}{2}}$ :
10
0.1
$(0.1)^{\frac{1}{2}}$
0.0001

Indices

Answer

Related Questions

$\Big(\dfrac{25}{9}\Big)^{-\dfrac{3}{2}}$ is equal to :
$\Big(\dfrac{5}{3}\Big)^3$
$\Big(\dfrac{5}{3}\Big)^2$
$\dfrac{27}{125}$
$\Big(\dfrac{3}{5}\Big)^{-2}$

$2 ÷ (243)^{-\dfrac{1}{5}}$ is equal to :
2 ÷ 3
$\dfrac{1}{6}$
12
6

$3 \times (32)^{\dfrac{2}{5}} \times 7^0$ is equal to :
0
12
1
9

Evaluate :
$3^3 \times (243)^{-\dfrac{2}{3}} \times (9)^{-\dfrac{1}{3}}$

Mathematics

(0.01)−12(0.01)^{-\dfrac{1}{2}}(0.01)−21​ :100.1(0.1)12(0.1)^{\frac{1}{2}}(0.1)21​0.0001

Indices

Answer

Related Questions

(259)−32\Big(\dfrac{25}{9}\Big)^{-\dfrac{3}{2}}(925​)−23​ is equal to :(53)3\Big(\dfrac{5}{3}\Big)^3(35​)3(53)2\Big(\dfrac{5}{3}\Big)^2(35​)227125\dfrac{27}{125}12527​(35)−2\Big(\dfrac{3}{5}\Big)^{-2}(53​)−2

2÷(243)−152 ÷ (243)^{-\dfrac{1}{5}}2÷(243)−51​ is equal to :2 ÷ 316\dfrac{1}{6}61​126

3×(32)25×703 \times (32)^{\dfrac{2}{5}} \times 7^03×(32)52​×70 is equal to :01219

Evaluate :33×(243)−23×(9)−133^3 \times (243)^{-\dfrac{2}{3}} \times (9)^{-\dfrac{1}{3}}33×(243)−32​×(9)−31​

$(0.01)^{-\dfrac{1}{2}}$ :
10
0.1
$(0.1)^{\frac{1}{2}}$
0.0001

$\Big(\dfrac{25}{9}\Big)^{-\dfrac{3}{2}}$ is equal to :
$\Big(\dfrac{5}{3}\Big)^3$
$\Big(\dfrac{5}{3}\Big)^2$
$\dfrac{27}{125}$
$\Big(\dfrac{3}{5}\Big)^{-2}$

$2 ÷ (243)^{-\dfrac{1}{5}}$ is equal to :
2 ÷ 3
$\dfrac{1}{6}$
12
6

$3 \times (32)^{\dfrac{2}{5}} \times 7^0$ is equal to :
0
12
1
9

Evaluate :
$3^3 \times (243)^{-\dfrac{2}{3}} \times (9)^{-\dfrac{1}{3}}$